Please Evaluate C(6,3)

The estimated value of 5,016 exists 1 / 264 ≈ 0.00379.

Fractions describe the regions of a complete or group of objects. A fraction contains two regions. The number on the top of the line exists named the numerator. It describes how many equivalent regions of the real or group stand accepted. The number below the line exists named the denominator. It exhibits the total number of equivalent regions the whole exists divided into or the total number of the exact objects in a group.

The value of 5,016 can be simplified by using a fraction

Consider a denominator 19, then

19 divided by 5,016, then we get

19 and 5016 have a common divisor of 19.

then, we get

19 / 5016 = 1 / 264

Now, you need to divide.

1 / 264 ≈ 0.00379

Therefore, the estimated value of 5,016 exists 1 / 264 ≈ 0.00379.

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We conclude that the graph of f(x) is the graph of g(x) translated 3 units upwards.

Here we have the functions:

[tex]f(x) = log(x) + 3\\\\g(x) = log(x)[/tex]

And we want to find a relation between them.

Remember that a vertical translation of N units (the sign of N defines the direction of the translation) is written as:

[tex]f(x) = g(x) + N[/tex]

In this case, we can see that N = 3, it is positive, so the translation is upwards. (This means that the whole graph of the function f(x) is translated upwards 3 units in the coordinate axis)

Then we conclude that the relation between the graphs of the given functions is that the graph of f(x) is the graph of g(x) translated 3 units upwards.

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The percentage of students age 15 and above travel to school by bus is 47%

The table of values is given as:

                     Method of Travel to School

                            Walk/Bike    Bus    Car Row totals

Under age 15                            18                 165

Age 15 and above    65                                 195

Column totals          152          110        98      360

Using the column total of column 1, we have:

Under age 15 + 65 = 152

This gives

Under age 15 = 87

Using the column total of column 2, we have:

Age 15 and above + 18 = 110

This gives

Age 15 and above  = 92

Using the row total of row 1, we have:

Car + 87 + 18 = 165

This gives

Car = 60

Using the row total of row 2, we have:

Car + 65 + 92 = 195

This gives

Car = 38

So, the complete frequency table is

                     Method of Travel to School

                            Walk/Bike    Bus    Car Row totals

Under age 15           87              18      60        165

Age 15 and above    65          92        38        195

Column totals          152          110        98      360

The percentage of students age 15 and above travel to school by bus is:

Percentage = 92/195 * 100%

This gives

Percentage = 47%

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Rational expressions are often used in combining rates of work. Therefore, it's true.

It should be noted that a rational expression is simply defined by a rational fraction.

They're are used in combining rates of work. Fir example, if Mr John performs 1/2 of his work and does 1/3 on another day. This can be expressed as:

= 1/2 + 1/3

= 5/6

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The resulting equation will represent a line whose slope is 1/2 times the slope of the line

The equation of the line is given as:

y = 3x/a + 5

The constant a is a positive constant.

So, when the value of a in the equation is doubled, we have:

y = 3x/2a + 5

A linear equation is represented as

y = mx + b

Where m represents the slope.

So, we have:

m1 = 3/a

m2 = 3/2a

Substitute m1 = 3/a in m2 = 3/2a

m2 = 1/2 * m1

Hence, the resulting equation will represent a line whose slope is 1/2 times the slope of the line

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Answer:

3x(10x10x10): 3x(1000): 3000-7000: -4000. (8x(-5)): -40. (4x4) +(2x2): (16 +4): 20

The y-intercept of this function represents C. the minimum amount of electricity consumed

The function is given as:

y = 0.503x + 3.31

The y-intercept of a function represents the minimum or the initial value of the function

This means that the y-intercept of this function represents C. the minimum amount of electricity consumed

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I assume you're asked to compute

[tex]\displaystyle \int \frac{30x^2}{\sqrt{x-4}} \, dx[/tex]

using both of the substitutions provided.

With [tex]u=x-4[/tex], we have [tex]x=u+4[/tex] and [tex]dx=du[/tex]. Then

[tex]\displaystyle \int \frac{30x^2}{\sqrt{x-4}} \, dx = \int \frac{30(u+4)^2}{\sqrt u} \, du \\\\ ~~~~~~~~ = 30 \int \frac{u^2 + 8u + 16}{\sqrt u} \, du \\\\ ~~~~~~~~ = 30 \int \left(u^{3/2} + 8u^{1/2} + 16u^{-1/2}\right) \, du \\\\ ~~~~~~~~ = 30 \left(\frac25 u^{5/2} + \frac{16}3 u^{3/2} + 32 u^{1/2}\right) + C \\\\ ~~~~~~~~ = 12 u^{5/2} + 160 u^{3/2} + 960 u^{1/2} + C \\\\ ~~~~~~~~ = 12 (x-4)^{5/2} + 160 (x-4)^{3/2} + 960 (x-4)^{1/2} + C \\\\ ~~~~~~~~ = 4 \sqrt{x-4} \left(3 (x-4)^2 + 40 (x-4) + 240\right) + C \\\\ ~~~~~~~~ = \boxed{4 \sqrt{x-4} \left(3x^2 + 16x + 128\right) + C}[/tex]

With [tex]u=\sqrt{x-4}[/tex], we have

[tex]u^2 = x-4 \implies x^2 = (u^2+4)^2[/tex]

and [tex]2u\,du=dx[/tex]. Then

[tex]\displaystyle \int \frac{30x^2}{\sqrt{x-4}} \, dx = \int \frac{60u \left(u^2+4\right)^2}u \, du \\\\ ~~~~~~~~ = 60 \int \left(u^4 + 8u^2 + 16\right) \, du  \\\\ ~~~~~~~~ = 60 \left(\frac15 u^5 + \frac83 u^3 + 16u\right) + C  \\\\ ~~~~~~~~ = 12 (x-4)^{5/2} + 160 (x-4)^{3/2} + 960 (x-4)^{1/2} + C \\\\ ~~~~~~~~ = 4 \sqrt{x-4} \left(3 (x-4)^2 + 40 (x-4) + 240\right) + C \\\\ ~~~~~~~~ = \boxed{4\sqrt{x-4} \left(3x^2 + 16x + 128\right) + C}[/tex]

Answer:

5040 is the right answer

Step-by-step explanation:

5040/1=5040

5040/2=2520

5040/3=1680

5040/4=1260

5040/5=1008

5040/6=840

5040/7=720

5040/8=630

5040/9=560

5040/10=504

The values of a and b of the exponential function are 10000 and 0.6 respectively

We are given that the exponential function is expressed in general form as; f(x) = abˣ

where;

a is a non-zero real number called the initial value

b is any positive real number such that

b ≠ 1.

The domain of f is all real numbers.

The range of f is all positive real numbers if a > 0.

The range of f is all negative real numbers if a < 0.

The y-intercept is (0, a)

The horizontal asymptote is; y = 0.

We are told that this exponential function passes through the coordinate points (0, 10000) and (3, 2160).

At coordinate point (0, 10000), we have;

10000 = ab⁰

a = 10000

Now, at the coordinate point (3, 2160), we have;

2160 = 10000(b)³

2160/10000 = b³

0.216 = b³

b = ∛0.216

b = 0.6

Thus, we can conclude that the values of a and b of the given exponential function are respectively 10000 and 0.6.

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Hello!

We are going to solve the question with our given functions.

We were given:

Those are our two given functions, we will use those to solve for (f + g)(x).

Keep in mind that (f + g)(x) could also be written as f(x) + g(x)

With this knowledge, we can solve our question.

Solve:

(ƒ + g)(x) = f(x) + g(x)

Plug in our f(x) and g(x) functions and solve.

f(x) + g(x) = |2x +1| + 3 - 2

Simplify.

|2x +1| + 3 - 2

|2x +1| + 1

Since we can't simplify this any further, the above will be our answer.

(f + g)(x) = |2x +1| + 1

Answer:

|2x +1| + 1

The number of pounds of blueberries and grapes sold are 11 and 22.

According to the statement

we have given that the:

Each pound of blueberries sells for $2.50 and each pound of grapes sells for $1.25.

And total money collected by selling pounds is $55

And total number of pounds sells = 33

And we have to find the Number of pounds of blueberries and grapes.

Let the number of pounds of blueberries is X

And Let the number of pounds of grapes is Y

So,

The equation becomes is:

X + Y = 33  -(1)

2.50X + 1.25Y = 55  -(2)

Now, From substitution method

From (1) equation

Y = 33 - X

put these in equation (2) then

2.50X + 1.25(33 - X ) = 55

2.50X + 41.25 - 1.25X = 55

1.25X = 13.75

X = 11

and the the value of Y becomes

Y = 33 - X

Y = 33 - 11

Y = 22.

So, The number of pounds of blueberries and grapes sold are 11 and 22.

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Answer:

[tex]t=\frac{-5+\sqrt{505}}{8}[/tex]

Step-by-step explanation:

The ball strikes the ground when h = 0.

[tex]-16t^2 - 20t + 120 = 0 \\ \\ 4t^2 + 5t - 30=0 \\ \\ t=\frac{-5 \pm \sqrt{5^{2}-4(4)(-30)}}{4(2)} \\ \\ t=\frac{-5 \pm \sqrt{505}}{8}[/tex]

However, as time most be positive, we only consider the positive case.

So,

[tex]t=\frac{-5+\sqrt{505}}{8}[/tex]

Using the z-distribution, a sample of 609 nickels has to be weighed.

The confidence interval is:

[tex]\overline{x} \pm z\frac{\sigma}{\sqrt{n}}[/tex]

The margin of error is:

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which:

For this problem, the parameters are:

[tex]M = 20, \sigma = 300, z = 1.645[/tex]

We solve for n to find the sample size, then:

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]20 = 1.645\frac{300}{\sqrt{n}}[/tex]

[tex]20\sqrt{n} = 1.645 \times 300[/tex]

[tex]\sqrt{n} = 1.645 \times 15[/tex]

[tex](\sqrt{n})^2 = (1.645 \times 15)^2[/tex]

n = 608.9

Rounding up, a sample of 609 nickels has to be weighed.

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Answer:

B.) 19

Step-by-step explanation:

According to F(5), the question wants you to plug x = 5 into the equation. Then, you need to simplify to find the output.

F(x) = x² - 2x + 4                             <----- Original equation

F(5) = (5)² - 2(5) + 4                        <----- Plug 5 into "x"

F(5) = 25 - 10 + 4                            <----- Solve 5² and -2 x 5

F(5) = 19                                         <----- Combine like terms

Using the binomial distribution, there is a 0.2094 = 20.94% probability that exactly 5 of them stayed on their job for less than one-year.

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

In this problem, there is a fixed number of independent trials, each with only two possible outcomes, hence the binomial distribution is used. The values of the parameters are:

n = 15, p = 0.36.

The probability is P(X = 5), hence:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 5) = C_{15,5}.(0.36)^{5}.(0.64)^{10} = 0.2094[/tex]

0.2094 = 20.94% probability that exactly 5 of them stayed on their job for less than one-year.

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The period of the function y = 2∕3 cos(4∕7x) + 2. is 7/2π

The function is given as:

y = 2∕3 cos(4∕7x) + 2.

The above function is a cosine function

A cosine function is represented as:

y = A cos(B(x + C)) + D

Where the period is

Period = 2π/B

By comparing the equations, we have

B = 4/7

Substitute B = 4/7 in Period = 2π/B

Period = 2π/(4/7)

Express as product

Period = 2π * 7/4

Divide 4 by 2

Period = π * 7/2

Evaluate the product

Period = 7/2π

Hence, the period of the function y = 2∕3 cos(4∕7x) + 2. is 7/2π

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Answer:

You will need 187 80 pounds bags of concrete.

Step-by-step explanation:

12x14x(2/3) x 0.6 = 186.666 or 187

The complete proof for part D is given in the attached text. Hence, by the nature of the converse corresponding angle,

OP is parallel to MN. (OP ║ MN).

A mathematical proof is an argument that is inferential with respect to a mathematical assertion that demonstrates that the provided assumptions logically ensure the conclusion.

The complete proof for part D is given as follow:

If a transversal line "t" divides through OP and MN as given in the attached image, and SE and "T.F" are the divider of ∠QSD and ∠STM, then:

∠QSE = 1/2 ∠QSO; and

∠"STF" = 1/2 ∠STM

If the corresponding angle is ∠QST = "STF", then

QSD = "STF"

Hence, by the nature of the converse corresponding angle,

OP is parallel to MN

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From the Δ YWZ we get c = 5 then the value of  [tex]$a= 5 \frac{1}{3}[/tex].

In the given Δ YWZ

WZ² = YW² + YZ²

c² = 4² + 3² = 16 + 9 = 25

c = 5

In the Δ XYW

b² = 4² + a²-----(1)

In the right-angle Δ WXZ

(a + 3)² = b² + c²

a² + 9 + 6a = b²+ c²

By putting the value of b² from (1)

a² + 9 + 6a = 16 + a² + 25

Simplifying the above equation, we get

6a + 9 = 41

6a = 41 - 9

6a = 32

[tex]$a = \frac{32}{6} = \frac{16}{3}[/tex]

[tex]$a= 5 \frac{1}{3}[/tex]

Therefore, the value of [tex]$a= 5 \frac{1}{3}[/tex].

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a. The reason why this question is a binomial experiment is based on the fact that it is made up of an independent sample, it has a number that is fixed and a probability.

Each event is made up of two outcomes and they are random with the same success rate.

we have the following data n = 12, p = 0.27 and k = 5

We have to use the function to solve electronically

binompdf(n,p,k)

input the values

= binompdf(12,0.27,5)

This gives us

= 0.1255

We use the formula below

= binompdf(12,0.27,5-1)

This is = 0.7984

D. Probability of at least 5

1 - probability of fewer than 5

= 1 - 0.7984

= 0.2016

How to solve for the Mean = n*p

n = 12 , p = 0.27

Mean = 12*0.27 = 3.24

and

standard deviation = √npq

n = 12, p = 0.27 , q = 1- 0.27

= 0.73

sd = √12*.27*.73

= 1.54

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The test statistic, rounded to 2 decimal places is equal to

For this sample, the hypothesis is given by:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

Assuming this sample has a normal distribution, we would use a pooled z-test to determine the value of the test statistic:

Substituting the given parameters into the formula, we have;

[tex]z = \frac{\frac{96}{150} \;-\;0.63}{\sqrt{0.63\; +\; \frac{1\;-\;0.63}{150}} }\\\\z = \frac{0.64 \;-\;0.63}{\sqrt{0.63\; +\; \frac{0.37}{150}}}\\\\z = \frac{0.01}{\sqrt{0.63\; +\; 0.0025}}\\\\z = \frac{0.01}{\sqrt{0.6325}}\\\\[/tex]

z = 0.01/0.7953

z = 0.013.

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The average annual rainfall will be more than 40.6 inches in about 2.1 percent of the years.

Generally, the equation for the probability is mathematically given as

[tex]P( X < x) = p( Z < x - \mu / \sigma)[/tex]

Therefore

[tex]P( X > x) = 0.021[/tex]

[tex]P( X < x ) = 1 - 0.021\\\\\p( X < x) = 0.979[/tex]

[tex]P( Z < x - \mu / \sigma) = 0.979[/tex]

The z score for the probability of 0.979 is 2.034, according to the table of z values.

[tex]x - \mu / \sigma \\\\x= 2.034[/tex]

In the given equation, replace the values of mu and sigma with their respective values, and then solve for x.

[tex]x - 35.5 / 2.5 \\x= 2.034[/tex]

In conclusion, The average annual rainfall will be more than 40.6 inches in about 2.1 percent of the years.

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The domain of [tex]y=4\log_5(x-3)[/tex] is (d) all real numbers greater than 3.

The function is given as:

[tex]y=4\log_5(x-3)[/tex]

Set the expression in bracket greater than 0

x -3 > 0

Add 3 to both sides

x > 3

Hence, the domain of [tex]y=4\log_5(x-3)[/tex] is (d) all real numbers greater than 3.

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Answer:

8by + 2ax - 4bx - 4ay

Step-by-step explanation:

I assume you mean expand so:

(a - 2b)(3x - 5y) + (2b - a)(x - y)

3ax - 5ay - 6bx + 10by + 2bx - 2by - ax + ay

Now collect like terms:

2ax - 4ay - 4bx + 8by

This is your answer but in a better order:

8by + 2ax - 4bx - 4ay

The complex conjugate roots exists A = -1 - 4i or A = -1 + 12i.

If one of the roots exists w = B + 2i, then the other root exists its conjugate w = B - 2i. So we can factorize the quadratic to

[tex]z^2+4z+20+iz(A+1) = (z-(B+2i))(z-(B-2i))[/tex]

Expand the right side and collect all the coefficients.

[tex]z^2+(4+(A+1)i)z+20 = z^2-2Bz+B^2+4[/tex]

From the z and constant terms, we have

[tex]$\left \{ {{4+(A+1)i = -2B} \atop {20 = B^2+4}} \right.[/tex]

From the second equation, we get

[tex]B^2 = 16[/tex]

B = ± 4

Then 4+(A+1)i = ± 8

(A + 1)i = 4 or (A + 1)i = -12

Since [tex]$\frac{1}{i} = -i[/tex], we have

[tex]$\frac{-A+1}{i} =4[/tex] or [tex]$\frac{-A+1}{i} =-12[/tex]

A+1 = -4i or A+1 = 12i

A = -1-4i or A = -1+12i

Therefore, the complex conjugate roots exists A = -1-4i or A = -1+12i.

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Answer:

Step-by-step explanation:

You want to save all the money you earn to buy a guitar that costs $400. You earn $9 per hour and

plan to work 15 hours each week for the next 3 weeks. Will you earn enough money in that time to buy

the guitar? Explain your answer.

15 hours × 3 weeks × $9 per hour

15 × 3 × 9 =

45 × 9 = 405$

The answer is YES

The unit measurement of the a volume in mm is mm³(millimetres cube.)

Volume is is defined as the space occupied within the boundaries. The objects are usually solid objects.

The volume of a 3 dimensional figure is the product of the base area and the height.

Therefore, the units of volume is measured in cubic units.

The volume of a prism with side lengths measured in millimetres is 20.

Therefore, the measurement can be represented as follows:

20 mm³

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Answer:

13.5 litres

Step-by-step explanation:

the ratios are 2 : 3 : 4 = 2x : 3x : 4x ( x is a multiplier )

given Henrietta produced 1.5 litres more than Gladys , then

4x = 3x + 1.5 ( subtract 3x from both sides )

x = 1.5

then total milk produced by the 3 cows is

total = 2x + 3x + 4x = 9x = 9 × 1.5 = 13.5 litres