(PLEASE HELP ITS URGENT)
What is the measure of angle x?

A) 60°
B) 30°
C) 45°
D) 90°

Answer:

If the total perimeter of square is 48 cm, then the length of one side is equal to 48 divided by 4, since all sides of a square are the same.

So, the correct answer is 12.

Let me know if this helps!

The length of each side is 12cm.

Explanation:

The perimeter of a square is calculated by the formula:

P = 4a , where  P = perimeter, and a = length of any side, all sides being equal in a square.

From the given data we write:

48 = 4a

Divide both sides by

4.12 = a

The length of each side is 12cm.

Answer:

9n² - 12mn + 4m²

Step-by-step explanation:

(a+b)² = a² + 2ab + b²

(3n - 2m )² = (3n-2m)(3n-2m) = 3n*3n + 3n*-2m -2m*3n - 2m*-2m

= 9n² - 6nm -6mn + 4m²

= 9n² - 12mn + 4n²

Answer:

Once you simplify the given expression, your answer will be 9n² - 12mn + 4m

Step-by-step explanation:

In this problem, we are given an expression.

(3n - 2m)²

when an expression or equation is raised to the power of 2, then you are going to multiply the base term by itself. For example, if you have 2² or 16², then would you do 2 × 2 and 16 × 16 in order to solve the expressions. We will do the same for this expression.

(3n - 2m)² = (3n - 2m) × (3n - 2m)

We will use the foil method to solve this expression

(3n - 2m)(3n - 2m)

9n² - 6mn - 6mn + 4m

Combine like terms together.

9n² - 12mn + 4m

So, the simplified form of the expression is 9n² - 12mn + 4m

Answer:

L = 13.3649

Step-by-step explanation:

We are given;

x = t − 2 sin(t)

dx/dt = 1 - 2 cos(t)

Also, y = 1 − 2 cos(t)

dy/dt = 2 sin(t)

0 ≤ t ≤ 2π

The arc length formula is;

L = (α,β)∫√[(dx/dt)² + (dy/dt)²]dt

Where α and β are the boundary points. Thus, applying this to our question, we have;

L = (0,2π)∫√((1 - 2 cos(t))² + (2 sin(t))²)dt

L = (0,2π)∫√(1 - 4cos(t) + 4cos²(t) + 4sin²(t))dt

L = (0,2π)∫√(1 - 4cos(t) + 4(cos²(t) + sin²(t)))dt

From trigonometry, we know that;

cos²t + sin²t = 1.

Thus;

L = (0,2π)∫√(1 - 4cos(t) + 4)dt

L = (0,2π)∫√(5 - 4cos(t))dt

Using online integral calculator, we have;

L = 13.3649

Answer:

D

Step-by-step explanation:

Answer:

Gain%=12.5%

Step-by-step explanation:

I ASSUMED COST PRICE=Rs.100

It asks for partial derivative, and you have to derive it with respect to 'y' variable.

[tex]f_y(x,y)=\frac{\partial f}{\partial y}=\frac{\partial}{\partial y}( 6x+2y+4)=2[/tex]

Answer:

  5/2

Step-by-step explanation:

Let u = sin(t). Then this is the integral ...

  [tex]\displaystyle\int_0^{\frac{\pi}{2}}{5u}\,du=\left.\dfrac{5u^2}{2}\right|_0^{\frac{\pi}{2}}=\dfrac{5}{2}(\sin(\frac{\pi}{2})^2-\sin(0)^2)=\dfrac{5}{2}(1-0)=\boxed{\dfrac{5}{2}}[/tex]

Answer:

23.6

Step-by-step explanation:

cos38=x/30

x= 30cos38= 23.6 (nearest tenth)

Answer:

a. Which number is greater? 1/4 or 5/4 -3/4 or 5/8:

answer: 5/4

b. Which number is farther from 0? 1/4 or 5/4 -3/4 or 5/8:

answer: 5/4

c. Is the number that is farther from 0 always the greater number?:

answer: nah really.

A number can be further from zero but when it's a negative or positive. But negative value is less than zero.

[tex] {}^{ - } \infin \leqslant 0 \leqslant {}^{ + } \infin[/tex]

(a) answer is 5/4

(b) answer is 5/4

(c) No , when dealing with negative numbers , the number closer to zero is the bigger number . zero has the unique distinction of being neither positive nor negative . zero separates the positive number from the negative ones .

hope this will help you

mrk above ans braniliest

Answer:

∠POT = 78°

Step-by-step explanation:

If POQ is straight then

x + 18° + 50° + x + 24° = 180° add like terms

2x + 92° = 180°

2x = 180° - 92°

2x = 88° and x = 44 If we say SOT is a straight line then

∠POT + 50° + x + 18° = 180°

∠POT + 102° = 180°

∠POT = 78°

The easy thing to do is notice that 1^4 = 1, 2^4 = 16, 3^4 = 81, and so on, so the sequence follows the rule [tex]n^4+1[/tex]. The next number would then be fourth power of 7 plus 1, or 2402.

And the harder way: Denote the n-th term in this sequence by [tex]a_n[/tex], and denote the given sequence by [tex]\{a_n\}_{n\ge1}[/tex].

Let [tex]b_n[/tex] denote the n-th term in the sequence of forward differences of [tex]\{a_n\}[/tex], defined by

[tex]b_n=a_{n+1}-a_n[/tex]

for n ≥ 1. That is, [tex]\{b_n\}[/tex] is the sequence with

[tex]b_1=a_2-a_1=17-2=15[/tex]

[tex]b_2=a_3-a_2=82-17=65[/tex]

[tex]b_3=a_4-a_3=175[/tex]

[tex]b_4=a_5-a_4=369[/tex]

[tex]b_5=a_6-a_5=671[/tex]

and so on.

Next, let [tex]c_n[/tex] denote the n-th term of the differences of [tex]\{b_n\}[/tex], i.e. for n ≥ 1,

[tex]c_n=b_{n+1}-b_n[/tex]

so that

[tex]c_1=b_2-b_1=65-15=50[/tex]

[tex]c_2=110[/tex]

[tex]c_3=194[/tex]

[tex]c_4=302[/tex]

etc.

Again: let [tex]d_n[/tex] denote the n-th difference of [tex]\{c_n\}[/tex]:

[tex]d_n=c_{n+1}-c_n[/tex]

[tex]d_1=c_2-c_1=60[/tex]

[tex]d_2=84[/tex]

[tex]d_3=108[/tex]

etc.

One more time: let [tex]e_n[/tex] denote the n-th difference of [tex]\{d_n\}[/tex]:

[tex]e_n=d_{n+1}-d_n[/tex]

[tex]e_1=d_2-d_1=24[/tex]

[tex]e_2=24[/tex]

etc.

The fact that these last differences are constant is a good sign that [tex]e_n=24[/tex] for all n ≥ 1. Assuming this, we would see that [tex]\{d_n\}[/tex] is an arithmetic sequence given recursively by

[tex]\begin{cases}d_1=60\\d_{n+1}=d_n+24&\text{for }n>1\end{cases}[/tex]

and we can easily find the explicit rule:

[tex]d_2=d_1+24[/tex]

[tex]d_3=d_2+24=d_1+24\cdot2[/tex]

[tex]d_4=d_3+24=d_1+24\cdot3[/tex]

and so on, up to

[tex]d_n=d_1+24(n-1)[/tex]

[tex]d_n=24n+36[/tex]

Use the same strategy to find a closed form for [tex]\{c_n\}[/tex], then for [tex]\{b_n\}[/tex], and finally [tex]\{a_n\}[/tex].

[tex]\begin{cases}c_1=50\\c_{n+1}=c_n+24n+36&\text{for }n>1\end{cases}[/tex]

[tex]c_2=c_1+24\cdot1+36[/tex]

[tex]c_3=c_2+24\cdot2+36=c_1+24(1+2)+36\cdot2[/tex]

[tex]c_4=c_3+24\cdot3+36=c_1+24(1+2+3)+36\cdot3[/tex]

and so on, up to

[tex]c_n=c_1+24(1+2+3+\cdots+(n-1))+36(n-1)[/tex]

Recall the formula for the sum of consecutive integers:

[tex]1+2+3+\cdots+n=\displaystyle\sum_{k=1}^nk=\frac{n(n+1)}2[/tex]

[tex]\implies c_n=c_1+\dfrac{24(n-1)n}2+36(n-1)[/tex]

[tex]\implies c_n=12n^2+24n+14[/tex]

[tex]\begin{cases}b_1=15\\b_{n+1}=b_n+12n^2+24n+14&\text{for }n>1\end{cases}[/tex]

[tex]b_2=b_1+12\cdot1^2+24\cdot1+14[/tex]

[tex]b_3=b_2+12\cdot2^2+24\cdot2+14=b_1+12(1^2+2^2)+24(1+2)+14\cdot2[/tex]

[tex]b_4=b_3+12\cdot3^2+24\cdot3+14=b_1+12(1^2+2^2+3^2)+24(1+2+3)+14\cdot3[/tex]

and so on, up to

[tex]b_n=b_1+12(1^2+2^2+3^2+\cdots+(n-1)^2)+24(1+2+3+\cdots+(n-1))+14(n-1)[/tex]

Recall the formula for the sum of squares of consecutive integers:

[tex]1^2+2^2+3^2+\cdots+n^2=\displaystyle\sum_{k=1}^nk^2=\frac{n(n+1)(2n+1)}6[/tex]

[tex]\implies b_n=15+\dfrac{12(n-1)n(2(n-1)+1)}6+\dfrac{24(n-1)n}2+14(n-1)[/tex]

[tex]\implies b_n=4n^3+6n^2+4n+1[/tex]

[tex]\begin{cases}a_1=2\\a_{n+1}=a_n+4n^3+6n^2+4n+1&\text{for }n>1\end{cases}[/tex]

[tex]a_2=a_1+4\cdot1^3+6\cdot1^2+4\cdot1+1[/tex]

[tex]a_3=a_2+4(1^3+2^3)+6(1^2+2^2)+4(1+2)+1\cdot2[/tex]

[tex]a_4=a_3+4(1^3+2^3+3^3)+6(1^2+2^2+3^2)+4(1+2+3)+1\cdot3[/tex]

[tex]\implies a_n=a_1+4\displaystyle\sum_{k=1}^3k^3+6\sum_{k=1}^3k^2+4\sum_{k=1}^3k+\sum_{k=1}^{n-1}1[/tex]

[tex]\displaystyle\sum_{k=1}^nk^3=\frac{n^2(n+1)^2}4[/tex]

[tex]\implies a_n=2+\dfrac{4(n-1)^2n^2}4+\dfrac{6(n-1)n(2n)}6+\dfrac{4(n-1)n}2+(n-1)[/tex]

[tex]\implies a_n=n^4+1[/tex]

Answer:

[tex]\huge\boxed{13}[/tex]

Step-by-step explanation:

m²-2m + 5

Given that m = -2

[tex]\sf (-2)^2-2(-2)+5\\4 +4 + 5\\13[/tex]

Answer:

13

Step-by-step explanation:

m^2 − 2m + 5

Let m = -2

(-2)^2 -2(-2) +5

4 +4 +5

13

Answer:

a) Pr(drug user| positive test) = 0.3333

b) The probability that he will failed his first test = 0.9703

c) the probability that he is a drug user since  failed his second drug test

= 0.961165

Step-by-step explanation:

From the given information:

Suppose that 1% of the employees of a certain company use illegal drugs.

Probability of illegal drug user = 0.01

Probability of user that do not use drug = 1 - 0.01 = 0.99

From the person that is a illegal drug user, the company performs random drug tests that return positive results = 0.99

Therefore, the negative result for illegal drug user = 1 - 0.99 = 0.01

However, it also has a 2% false positive rate.

i.e the probability of the user that do not use drug has a positive result of 2% = 0.02

Thus, the probability of the user that do not use drug has a negative result of = 1 - 0.02

= 0.98

We are tasked to answer the following questions.

a) Steve, an employee at the company, has a positive test. What is the probability that he is a drug user?

i.e This employee we are taking about is a drug user and he has a positive test.

Thus;

Pr(drug user| positive test) = [tex]\dfrac{0.99 \times 0.01}{0.99 \times 0.01+ 0.02 \times 0.99}[/tex]

Pr(drug user| positive test) = [tex]\dfrac{0.0099}{0.0099+0.0198}[/tex]

Pr(drug user| positive test) = [tex]\dfrac{0.0099}{0.0297}[/tex]

Pr(drug user| positive test) = 0.3333

b) Knowing he failed his first test, what is the probability that Steve will fail his next drug test?

The probability that he will failed his first test = ((0.01 × 0.01) + (0.99×0.98))

The probability that he will failed his first test = ( 1 × 10⁻⁴ + 0.9702)

The probability that he will failed his first test = 0.9703

c)  Steve just failed his second drug test. Now, what is the probability that he is a drug user?

the probability that he is a drug user since he  failed his second drug test using Bayes theorem can be expressed as:

= [tex]\dfrac{0.01 \times(0.99\times 0.99)}{0.01 \times (0.99 \times0.99)+ 0.99(0.02 \times0.02)}[/tex]

the probability that he is a drug user since failed his second drug test

= [tex]\dfrac{0.01 \times(0.9801)}{0.01 \times (0.9801)+ 0.99(4 \times 10^{-4})}[/tex]

the probability that he is a drug user since  failed his second drug test

= [tex]\dfrac{0.009801}{0.009801+ 3.96 \times 10^{-4}}[/tex]

the probability that he is a drug user since  failed his second drug test

= 0.961165

Answer:

Step-by-step explanation:

Consider principle =Rs.P, Time (T)=4 years

Consider principle =Rs.P, Time (T)=4 yearsRate =6

Consider principle =Rs.P, Time (T)=4 yearsRate =6 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P×

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =4000

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200Therefore, Principle =Rs.3200

Answer: What are we supposed to do ???

When you evaluate [tex]3(\frac{4}{5})[/tex] you will have [tex]\frac{12}{5}[/tex]

In this exercise, you're required to evaluate the given whole number and fraction [tex]3(\frac{4}{5})[/tex]

First of all, you will notice that there is a bracket which signifies multiplication. Therefore, we would open up the bracket by multiplying the two numbers.

Opening the bracket;

[tex]3 * \frac{4}{5}[/tex]

Multiplying the whole number by the numerator;

[tex]3(\frac{4}{5}) = \frac{12}{5}[/tex]

Find more information on how to evaluate mathematical expressions: https://brainly.com/question/24373783

The correct answer is $750

Explanation:

The total of food the Masmin family spend according to the graph is 15%. Now, to know the amount of money this represents, it is necessary to find the 15% of $5000, which is the total budget. The steps to do this are shown below.

1. To calculate the percentage of a given number, first, write all values

5000 = 100%

 x       =  15%

2. Use cross multiplication, this means you multiply 5000 by 15 and x by 15

x 100 = 75000

3. Solve the equation to find x or the 15% of 5000

x = 75000 ÷ 100

x = 750

Answer:

the answer is a and d

Step-by-step explanation:

6 + 6 + 2 +2 = 16

3 + 3 + 5 + 5 = 16

to find perimeter, double each factor and add :)

Answer:

A

  [tex]t = 10.1[/tex]

B

  [tex]p-value = p(t > 10.1)= 0.000[/tex]

C

  [tex]0.4714 < p_1 - p_2 <0.6988[/tex]

D

  The  oxygen treatment  is effective because

1 the is no 0 in the interval telling us that the treatments are different

 2 the upper and the lower limit are positive tell us that the proportion of those treated by the oxygen treatment is greater

Step-by-step explanation:

From the question we are told that

    The  first sample size is  [tex]n_1 = 140[/tex]

     The  number of patient which the oxygen cured is k = 113  

     The second sample size is  [tex]n_2 = 158[/tex]

     The number of patient that  placebo cured is  l =  35

The first sample proportion is

           [tex]\r p_1 = \frac{ 113}{140 }[/tex]

           [tex]\r p_1 = 0.8071[/tex]

The second sample proportion is  

           [tex]\r p_2 = \frac{ 35}{ 158 }[/tex]

          [tex]\r p_2 = 0.222[/tex]

The null hypothesis is  [tex]H_o : p_1 = p_2[/tex]

 The  alternative hypothesis is  [tex]H_a : p_1 > p_2[/tex]

Let assume the level of significance be[tex]\alpha = 0.05[/tex]

Generally the pooled proportion is mathematically evaluated as

    [tex]p = \frac{p1 * n1 + p2 * n2}{n1 + n2}[/tex]

substituting values

     [tex]p = \frac{0.8071 * 140 + 0.222 * 158}{140 + 158}[/tex]

      [tex]p = 0.4969[/tex]

Generally the standard error is mathematically represented

      [tex]SE = \sqrt{ p(1- p ) * [ \frac{1}{n_1} + \frac{1}{n_1}] }[/tex]

      substituting values

     [tex]SE = \sqrt{ 0.4969(1- 0.4969 ) * [ \frac{1}{140} + \frac{1}{158}] }[/tex]

     [tex]SE = 0.0580[/tex]

Generally the test statistics is mathematically represented as

       [tex]t = \frac{ \r p_1 - \r p_2}{ SE}[/tex]

       [tex]t = \frac{ 0.8071 -0.222}{ 0.0580}[/tex]

       [tex]t = 10.1[/tex]

The  p-value is from the normal distribution table as  

      [tex]p-value = p(t > 10.1)= 0.000[/tex]

given that [tex]t< \alpha[/tex] the null hypothesis is rejected

From the normal distribution table the critical value of  [tex]\frac{\alpha }{2}[/tex]  is  

     [tex]Z_{\frac{\alpha }{2} } = 1.96[/tex]

Generally the margin of error is mathematically the represented as

         [tex]E = Z_{\frac{\alpha }{2} } * SE[/tex]      

         [tex]E = 1.96 * 0.0580[/tex]      

          [tex]E = 0.1137[/tex]

The 95% confidence interval is mathematically  represented as

           [tex](\r p_1 - \r p_2) - E < p_1 - p_2 < (\r p_1 - \r p_2) + E[/tex]

substituting value

             [tex](0.8071 - 0.222) - 0.1137 < p_1 - p_2 < (0.8071 - 0.222) + 0.1137[/tex]

             [tex]0.4714 < p_1 - p_2 <0.6988[/tex]

The  oxygen treatment  is effective because

1 the is no 0 in the interval telling us that the treatments are different

 2 the upper and the lower limit are positive tell us that the proportion of those treated by the oxygen treatment is greater

Answer:

see below

Step-by-step explanation:

1.) 26 times 26^8 = 26^1 * 26^8 = 26^(1+8) = 26^9

2.) (-5)^5/(-5)^-6 = (-5)^(5 - -6) = (-5)^(5+6) = (-5)^11

3.) 8^15 divided by 8^-3 = 8^(15 - -3) = 8^(15+3) = 8^18

4.) Which expressions are equivalent to 1? Select all that apply.

~-(5/8)^0   - (1)  no

~-(-3141)^0  - (1) no

~1291^0  1  yes

~0^1  yes

~(1/3)^0  yes

~(-0.0008)^0  yes

Answer:

Step-by-step explanation:

(17). g(x) = x³ + 4x

f(x) = 4x + 1

( f × g )( x ) = ( x³ + 4x )( 4x + 1 ) = 4 [tex]x^{4}[/tex] + x³ + 16x² + 4x

(19). f(t) = 4t - 4

g(t) = t - 2

( 4f + 3g )( t ) = 4(4t - 4) + 3(t - 2) = 16t - 16 + 3t - 6 = 19t - 22

(21). h(t) = t + 3

g(t) = 4t + 1

h(t - 2) + g(t - 2) = ( t - 2 ) + 3 + 4( t - 2 ) + 1 = t + 4t - 2 + 3 - 8 + 1 = 5t - 6

Note that the characteristic solutions to this ODE are [tex]e^{-2x/5}[/tex] and [tex]e^{2x}[/tex], so we can safely assume a particular solution of the form

[tex]y_p=(ax+b)e^{3x}[/tex]

with derivatives

[tex]{y_p}'=ae^{3x}+3(ax+b)e^{3x}=(3ax+a+3b)e^{3x}[/tex]

[tex]{y_p}''=3ae^{3x}+3(3ax+a+3b)e^{3x}=(9ax+6a+9b)e^{3x}[/tex]

Substitute these expressions into the ODE and solve for a and b. Notice that each term on either side contains a factor of [tex]e^{3x}[/tex], which we can cancel.

[tex]-\dfrac54(9ax+6a+9b)+2(3ax+a+3b)+(ax+b)=3x[/tex]

[tex]-\dfrac{17a}4x-\left(\dfrac{11a}2+\dfrac{17b}4\right)=3x[/tex]

[tex]\implies\begin{cases}-\frac{17a}4=3\\\frac{11a}2+\frac{17b}4=0\end{cases}[/tex]

[tex]\implies a=-\dfrac{12}{17}\text{ and }b=\dfrac{264}{289}[/tex]

So the particular solution is

[tex]y_p=\left(-\dfrac{12x}{17}+\dfrac{264}{289}\right)e^{3x}=\boxed{\dfrac{12}{289}(22-17x)e^{3x}}[/tex]

Answer:

  146/45

Step-by-step explanation:

Let x represent the value of the number of interest. Then we can do the following math to find its representation as a fraction.

  [tex]x=3.2\overline{4}\\10x=32.4\overline{4}\\10x-x=9x=32.4\overline{4}-3.2\overline{4}=29.2\\\\x=\dfrac{29.2}{9}=\boxed{\dfrac{146}{45}}[/tex]

__

Comment on procedure

The power of 10 that we multiply by (10x) is the number of repeated digits. Here, there is a 1-digit repeat, so we multiply by 10^1. If there were a 2-digit repeat, we would compute 10^2x -x = 99x to rationalize the number.

Answer:

y = -7x - 16

Step-by-step explanation:

The formula for the equation of a line is y=mx+b, where m is the slope and b is the y-intercept. Since we already know the slope, all that is left is the value of b, which can be found by substituting the values of the point (-1, -9) into the equation and solving:

[tex]-9=-7(-1)+b[/tex]

[tex]-9=7+b[/tex]

[tex]b=-9-7=-16[/tex]

With this, we get the value -16, making the equation y = -7x - 16

Answer: 4150

Step-by-step explanation:

You take the 50, becuse the amount earned increases once you surpass 40 you do 40 x 10 and that = 4000 then you take the remaining 10 and times that by 15 (becuse after 40 it is 1.5 of what you where earning before you hit 40 hours and half of ten is 5 so you do 10 plus 5 and times that by 10) then add both numbers together and you have 4150! Hope that helped!

Answer:

Angle E.

Step-by-step explanation:

Hope this helps!

Answer:

63.5

Step-by-step explanation:

Answer:

Surface area of prism is 48km^2

Answer:

(a) Probility Distribution

Outcome   probability

$1               5/15 = 1/3

$5              4/15

$10             3/15 = 1/5

$20            5/15 = 1/3

(b) P($9 or less) =  3/5

Step-by-step explanation:

(a) Probility Distribution

Outcome   probability

$1               5/15 = 1/3

$5              4/15

$10             3/15 = 1/5

$20            5/15 = 1/3

Any other denomination

                  0

(b)

ways to draw $9 or less in a single draw

P($1) = 1/3

P($5) = 4/15

P($9 or less) = P($1) + P($5) = 1/3 + 4/15 = 9/15 = 3/5

Answer:

[tex]41.89\ cm^2[/tex]

Step-by-step explanation:

[tex]We\ are\ given:\\In\ two\ concentric\ circles,\\OD=3\ cm\\BC=4\ cm\\\angle DOB=\angle AOC=120\\Now,\\We\ know\ that:\\Area\ of\ a\ sector\ with\ a\ central\ angle\ \theta\ and\ a\ radius\ r\ is:\\A=\frac{\theta}{360}* \pi r^2\\Here,\\Area\ between\ the\ sectors=Area\ of\ Larger\ Sector - Area\ of\ smaller\ sector=\frac{\theta}{360}*\pi(R^2-r^2),\ where\ R\ and\ r\ are\ radii\ of\ the\ respective\ circles\ and\\ \theta\ is\ the\ common\ central\ angle.\\Here,\\R=4+3=7\ cm\\r=3\ cm\\ \theta=120\\ Hence,[/tex]

[tex]Area\ of\ the\ shaded\ region=\frac{120}{360}*\pi(7^2-3^2)=\frac{1}{3}*\pi(49-9)=\frac{1}{3}*\pi(40) \approx 41.89\ cm^2[/tex]