PLEASE HELP!
Determine which of the following points lies on the graph of y=[tex]\sqrt{x} x+4[/tex]
I have been working on this all morning. I have used different calculators and the answers that I am getting do not match any of the choices I am given on my homework. I can choose from (0,4), (5,3), (-3,0), and (12,5).

Answers

Answer 1

Answer:

-

Step-by-step explanation:

Forget using calculators.

Test each point by plugging its coordinates into the equation, and checking if the equation holds true.

Don't bother testing (-3,0), because you can't take the square root of -3.

PLEASE HELP!Determine Which Of The Following Points Lies On The Graph Of Y=[tex]\sqrt{x} X+4[/tex]I Have

Related Questions

50q + 43 > −11q + 70

Answers

Answer:

q > 27/61

Step-by-step explanation:

50q + 43 > −11q + 70

Add 11 q to each side

50q+11q + 43 > −11q+11q + 70

61q+43> 70

Subtract 43 from each side

61q> 27

Divide each side by 61

61q/61> 27/61

q > 27/61

Solve -9 < 4x + 3 5 19.

Answers

Answer:

C  -3 < x ≤ 4

Step-by-step explanation:

-9 < 4x + 3 ≤ 19.

Subtract 3 from all sides

-9-3 < 4x + 3-3 ≤ 19-3

-12 < 4x  ≤ 16

Divide by 4

-12/4 < 4x/4 ≤ 16/4

-3 < x ≤ 4

find the area of the triangle

Answers

9514 1404 393

Answer:

  108 cm²

Step-by-step explanation:

The area of a triangle is given by the formula ...

  A = 1/2bh

where b represents the base length, and h represents the height--the perpendicular distance from the base to the opposite vertex. The area of this triangle is ...

  A = 1/2(12 cm)(18 cm) = 108 cm²

Can someone please help !

Answers

In functions; transformations are used to move lines, points, curves or shapes across the graph (i.e. up, down, right or left). After the transformation of [tex]f(x) = \log\ x[/tex], the resulting function is [tex]g(x) = 2\log\ (-x + 4) - 6[/tex]

Given that:

[tex]f(x) = \log\ x[/tex]

When translated 4 units left, the rule of translation is:

[tex](x,y) \to (x + 4,y)[/tex]

So, we have:

[tex]f'(x) = \log\ (x + 4)[/tex]

When translated 3 units down, the rule of translation is:

[tex](x,y) \to (x,y-3)[/tex]

So, we have:

[tex]f"(x) = \log\ (x + 4) - 3[/tex]

When reflected about the y-axis, the rule of reflection is:

[tex](x,y) \to (-x,y)[/tex]

So, we have:

[tex]f'"(x) = \log\ (-x + 4) - 3\\[/tex]

Lastly, when it is vertically stretched by 2; the rule is:

[tex](x,y) \to (x,2y)[/tex]

So, we have:

[tex]g(x) = 2[\log\ (-x + 4) - 3][/tex]

Open bracket

[tex]g(x) = 2\log\ (-x + 4) - 6[/tex]

See attachment for the graph of function f(x) and the new function g(x)

Read more about function transformations at:

https://brainly.com/question/24369847

Tom is afraid of heights above 9 feet. He is asked to repair a side of a high deck. The bottom of the ladder must be placed 6 feet from a deck. The ladder is 10 feet long. How far above the ground does the ladder touch the deck? Is Tom afraid of the height?

Answers

Answer:

8 ftno

Step-by-step explanation:

The height on the side of the deck (h) can be found using the Pythagorean theorem. It tells you ...

  6^2 + h^2 = 10^2

  h = √(10^2 -6^2) = √64 = 8

The ladder touches the deck 8 feet above the ground. Tom is not afraid of that height.

solve for x in the equation:log6-2logx=1.4​

Answers

9514 1404 393

Answer:

  x = (√6)/10^0.7 ≈ 0.488737

Step-by-step explanation:

It can work reasonably well to take antilogs first.

  [tex]\log(6)-2\log(x)=1.4\\\\\dfrac{6}{x^2}=10^{1.4}\\\\\dfrac{6}{10^{1.4}}=x^2\\\\x=\dfrac{\sqrt{6}}{10^{0.7}}\approx0.488737[/tex]

I have a circle that has a radius of 8 in. What is the circumference of the circle? What is the area of the circle? ( use 3.14 for pi).Explain your steps. Please Give A clear explanation The best answer gets brainliest.

Answers

Answer:

The circumference is 50.24 in. and the area is 200.96 in².

Step-by-step explanation:

The circumference formula is C = 2πr where C = Circumference, π = pi and r = radius. We know that r = 8 and π = 3.14 and that we're solving for C, so we can substitute those values into the equation to get C = 2 * 3.14 * 8 = 50.24 in.

The area formula is A = πr² where A = Area, π = pi and r = radius. Again, we're solving for A and we know that r = 8 and π = 3.14 so A = 3.14 * 8² = 3.14 * 64 = 200.96 in².

Answer:

The circumference is 50.24 in. and the area is 200.96 in².

Step-by-step explanation:

MARK SNOG AS BRAINLIEST

HELP MEEEE FAST PLZ

MY MOM THINKS IM SMART BUT I DON'T GET THIS AHHHH HELP

Answers

Answer:

10

Step-by-step explanation:

-3 = 7 - 10

-3 = -3

Find m∠DFC.

A. 23
B. 167
C. 46
D. 69

Answers

Answer:

A.23

maaf kalosalah !(!)!(!)!(!)!(!)!(!)!(!)!(!)!(!)!

Which equation represents the data shown in the table provided in the image?

A. y = 2x + 1

B. y = 3x — 1

C. y = 2.5x

D. y = 2.5x + 1

Please include ALL work! <3

Answers

The correct answer is A. y = 2x +1

Explanation:

An equation is a statement that shows equality. In this context, the equation should lead to two equal numbers even if the values of y and x change. In this context, the correct equation is y= 2X + 1 because this is the only one, in which, the value of Y is always equivalent to 2x + 1. To prove this, let's replace y and x for the values of the table.

First  column

5 = 2 · 2 + 1

5 = 4 + 1

5 = 5

Second Column

9 = 2 · 4 + 1

9 = 8 + 1

9 = 9

Third column

13 = 6 · 2 + 1

13 = 12 + 1

13 =  13

Fourth column

17 = 8 · 2 + 1

17 = 16 + 1

17 = 17

find the value of x and y​

Answers

Answer:

x=50 and y=80

Step-by-step explanation:

ATQ, x+50+y=180 and y+2x=180. x=50 and y=80

the point p(-3,4) is reflected in the line x +2=0. find the coordinate of the image x​

Answers

Answer:

(- 1, 4 )

Step-by-step explanation:

The line x + 2 = 0 can be expressed as

x + 2 = 0 ( subtract 2 from both sides )

x = - 2

This is the equation of a vertical line parallel to the y- axis and passing through all points with an x- coordinate of - 2

Thus (- 3, 4 ) is 1 unit to the left of - 2

Under a reflection in the line x = - 2

The x- coordinate will be the same distance from x = - 2 but on the other side while the y- coordinate remains unchanged.

Thus

(- 3, 4 ) → (- 1, 4 )

find the response of the function at * (t=4) using Laplace transform (y() + 2y" + y = sint) y(0)=1, y (0)=-2, y"(0)=3 , y"(0)=0

Answers

Considering you have four initial conditions (the last of which should probably read [tex]y'''(0)=0[/tex]), I'm assuming the ODE is

[tex]y^{(4)}(t)+2y''(t)+y(t)=\sin t[/tex]

with [tex]y(0)=1[/tex], [tex]y'(0)=-2[/tex], [tex]y''(0)=3[/tex], and [tex]y'''(0)=0[/tex].

Take the Laplace transform of both sides, denoting the transform of [tex]y(t)[/tex] by [tex]Y(s)[/tex]:

[tex](s^4Y(s)-s^3y(0)-s^2y'(0)-sy''(0)-y'''(0))+2(s^2Y(s)-sy(0)-y'(0))+Y(s)=\dfrac1{s^2+1}[/tex]

Solve for [tex]Y(s)[/tex]:

[tex](s^4+2s^2+1)Y(s)-s^3+2s^2-5s+4=\dfrac1{s^2+1}[/tex]

[tex]Y(s)=\dfrac{1+(s^3-2s^2+5s-4)(s^2+1)}{(s^2+1)(s^4+2s^2+1)}[/tex]

Notice that

[tex]s^4+2s^2+1=(s^2+1)^2[/tex]

[tex]\implies Y(s)=\dfrac{1+(s^3-2s^2+5-4)(s^2+1)}{(s^2+1)^3}[/tex]

and simplify a bit to get

[tex]Y(s)=\dfrac{s^5-2s^4+6s^3-6s^2+5s-3}{(s^2+1)^3}[/tex]

Decompose [tex]Y(s)[/tex] into partial fractions:

[tex]\dfrac{s^5-2s^4+6s^3-6s^2+5s-3}{(s^2+1)^3}=\dfrac{a_0+a_1s}{s^2+1}+\dfrac{b_0+b_1s}{(s^2+1)^2}+\dfrac{c_0+c_1s}{(s^2+1)^3}[/tex]

[tex]s^5-2s^4+6s^3-6s^2+5s-3=(a_0+a_1s)(s^2+1)^2+(b_0+b_1s)(s^2+1)+(c_0+c_1s)[/tex]

[tex]s^5-2s^4+6s^3-6s^2+5s-3=a_1s^5+a_0s^4+(2a_1+b_1)s^3+(2a_0+b_0)s^2+(a_1+b_1+c_1)s+(a_0+b_0+c_0)[/tex]

[tex]\implies\begin{cases}a_1=1\\a_0=-2\\2a_1+b_1=6\\2a_0+b_0=-6\\a_1+b_1+c_1=5\\a_0+b_0+c_0=-3\end{cases}[/tex]

[tex]\implies a_0=-2,a_1=1,b_0=-2,b_1=4,c_0=1,c_1=0[/tex]

So we have

[tex]Y(s)=\dfrac{s-2}{s^2+1}+\dfrac{4s-2}{(s^2+1)^2}+\dfrac1{(s^2+1)^3}[/tex]

Split up the first term to get two easy inverse transforms:

[tex]L^{-1}\left[\dfrac s{s^2+1}\right]=\cos t[/tex]

[tex]L^{-1}\left[-\dfrac2{s^2+1}\right]=-2\sin t[/tex]

Also split up the second term, but use the convolution theorem, which says

[tex]L\left[(\alpha \ast \beta)(t)\right]=A(s)\cdot B(s)[/tex]

where [tex]A(s)[/tex] and [tex]B(s)[/tex] are the Laplace transforms of [tex]\alpha(t)[/tex] and [tex]\beta(t)[/tex], respectively, and the convolution is defined by

[tex](\alpha \ast \beta)(t)=\displaystyle\int_0^t\alpha(\tau)\beta(t-\tau)\,\mathrm d\tau[/tex]

Take

[tex]A(s)=\dfrac{4s}{s^2+1}\text{ and }B(s)=\dfrac1{s^2+1}[/tex]

so that

[tex]\alpha(t)=4\cos t\text{ and }\beta(t)=\sin t[/tex]

and their convolution is

[tex]L^{-1}\left[\dfrac{4s}{(s^2+1)^2}\right]=(\alpha \ast \beta)(t)=2t\sin t[/tex]

Next, take

[tex]A(s)=-\dfrac2{s^2+1}\text{ and }B(s)=\dfrac1{s^2+1}[/tex]

[tex]\implies \alpha(t)=-2\sin t\text{ and }\beta(t)=\sin t[/tex]

[tex]\implies L^{-1}\left[-\dfrac2{(s^2+1)^2}\right]=t\cos t-\sin t[/tex]

You can treat the third term similarly, but with an extra step. First compute

[tex]L^{-1}\left[\dfrac1{(s^2+1)^2}\right][/tex]

by taking

[tex]A(s)=B(s)=\dfrac1{s^2+1}[/tex]

[tex]\implies \alpha(t)=\beta(t)=\sin t[/tex]

Then

[tex]L^{-1}\left[\dfrac1{(s^2+1)^2}\right]=\dfrac{\sin t-t\cos t}2[/tex]

Next, take

[tex]A(s)=\dfrac1{(s^2+1)^2}\text{ and }B(s)=\dfrac1{s^2+1}[/tex]

[tex]\implies \alpha(t)=\dfrac{\sin t-t\cos t}2\text{ and }\beta(t)=\sin t[/tex]

[tex]\implies L^{-1}\left[\dfrac1{(s^2+1)^3}\right]=\dfrac{(3-t^2)\sin t-3t\cos t}8[/tex]

Thus we end up with the solution,

[tex]y(t)=(\cos t-2\sin t)+(2t\sin t+t\cos t-\sin t)+\dfrac{(3-t^2)\sin t-3t\cos t}8[/tex]

[tex]\boxed{y(t)=\dfrac{(8+5t)\cos t+(-21+16t-t^2)\sin t}8}[/tex]

A line passes through (-5, -3) and is parallel to -3x - 7y = 10. The equation of the line in slope-intercept form is _____

Answers

Answer:

-3x - 7y = 36

Step-by-step explanation:

The given line -3x - 7y = 10 has an infinite number of parallel lines, all of the form -3x - 7y = C.

If we want the equation of a line parallel to -3x - 7y = 10 that passes through (-5, -3), we substitute -5 for x in -3x - 7y = 10 and substitute -3 for y in -3x - 7y = 10:

-3(-5) - 7(-3) = C, or

15  + 21 = C, or C = 36

Then the desired equation is -3x - 7y = 36.

Write "six and thirty-four thousandths" as a decimal

Answers

Answer:

6.034

Step-by-step explanation:

6 is a whole number.

.034 because it is 34 thousandths, not 34 hundredths.

identify(describe) each part of the ellipse as labeled by a letter​

Answers

Answer: see below

Step-by-step explanation:

A) y has the smaller radius so this is the Minor Axis

B) y has the smaller radius so these are the CoVertices

C) x has the bigger radius so these are the Vertices

D) This is the Center of the ellipse.

F & G) These are the Foci (plural for Focus)

H) x has the bigger radius so this is the Major Axis

Estimate the mean exam score for the 50 students in Prof. Burke's class.

Score

f

40 but less than 50

21



50 but less than 60

39



60 but less than 70

40



70 but less than 80

34



80 but less than 90

28



Total

162



Group of answer choices

63.78

62.34

64.89

65.56

Answers

Answer:  D) 65.56

==========================================================

Explanation:

The interval [tex]40 \le x < 50[/tex] has the midpoint (40+50)/2 = 90/2 = 45 which represents the average value from this interval. We don't know what the exact 21 values are from this interval, but the best guess we can make is each value is on average 45.

Similarly, the interval [tex]50 \le x < 60[/tex] has the midpoint (50+60)/2 = 110/2 = 55 which represents the average value in this interval.

The set of all midpoints is: {45, 55, 65, 75, 85}. You start at 45 and add 10 to each term to get the next term. Let's say x represents the midpoint. We'll multiply each x value with its corresponding frequency (f) to get a new column of values you see in the table below.

For example, in the first row, we have 45*21 = 945

Add up everything in the x*f column and we'll get this sum:

945+2145+2600+2550+2380 = 10,620

We'll divide this over the total frequency, which is the sum of the frequency column (21+39+40+34+28 = 162)

We then arrive at this estimated final answer: (10,620)/(162) = 65.55555... where the '5's go on forever. This rounds to 65.56

Please help!! find the value of the expression

Answers

Answer: 7
(3x-12)+1/2(xy-10)
(3•4-12)+1/2(4•6-10)
(12-12)+1/2•14
7

Answer:

7

Step-by-step explanation:

First plug in the variable amounts so the expression now looks like this:

(3 × 4 - 12) + 1/2(4 × 6 - 10)

Now, start by solving the multiplication parts first, so it now looks like this:

(12 - 12) + 1/2(24 - 10)

Now, apply the rules of order of operation, so start by solving what's in parenthesis. It should now look like this: (0) + 1/2(14)

Next, solve the multiplication part, so it now looks like this: 0 + 7

Solve that and the answer is 7.

5/7 minus 2/9 please

Answers

Answer:

[tex]\large \boxed{31/63}[/tex]

Step-by-step explanation:

5/7 - 2/9

Make denominators equal by LCM.

(5 × 9)/(7 × 9) - (2 × 7)/(9 × 7)

45/63 - 14/63

Subtract fractions since denominators are equal.

(45 - 14)/63

31/63

Answer:

[tex]\frac{31}{63}[/tex]

Step-by-step explanation:

Find the LCM of 7 and 9: 63Find how much we increased each number to get to 63: we increased 7 by 9, and we increased 9 by 7Multiply the numerators by the corresponding increase numbers: 5 × 9 = 45, and 2 × 7 = 14Put the new numerators over the new denominators, so it looks like this: [tex]\frac{45}{63}[/tex] and [tex]\frac{14}{63}[/tex] Finally, subtract one from the other and here's what you get: [tex]\frac{31}{63}[/tex]

Therefore, the answer is [tex]\frac{31}{63}[/tex].

I will mark u brainleiest if u help me and 5 stars

Answers

Answer:

[tex]\boxed{50}[/tex]

Step-by-step explanation:

Because the initial temperature is 40 degrees and it increases by 10, add the two values together to get the final temperature.

40 + 10 = 50

Therefore, the final answer is 50 degrees.

Answer:

50

Step-by-step explanation:

If it starts at 40 degrees and increases 10 degrees, it is going to be 50 degrees.  Increases means adding, so it is asking you to add 10 to 40 which is 50.  If it asks decreases in the future you will have to subtract.

What is the congruence correspondence, if any, that will prove the given triangles congruent?

A. ASA
B. SSS
C. SAS
B. HL

Answers

Answer:

HL

Step-by-step explanation:

The congruence correspondence between the two given triangles is HL as one leg and hypotenuse are given equal.

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OAmalOHopeO

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determine the coordinator of the point
of intersection of lines
3x-2y=13 and 2y+x+1=0​

Answers

Answer:

(3,-2)

Step-by-step explanation:

Given equations of line

3x-2y=13

2y+x+1=0​

=> x = -1 -2y

Point of intersection will coordinates where both equation have same value of (x,y)

top get that we have to solve the both equations by using method of substitution of simultaneous equation.

using this value of x in 3x-2y=13, we have

3(-1-2y) -2y = 13

=> -3 -6y-2y = 13

=> -8y = 13+3 = 16

=> y = 16/-8 = -2

x = -1 - 2y = -1 -2(-2) = -1+4= 3

Thus, point of intersection of line is (3,-2)

Margaret drives 188 miles
with 8 gallons of gas. Find the unit rate

Answers

The unit rate will be "23.5 miles/gallon". In the below segment, a further solution to the given question is provided.

Given values in the question are:

Total distance,

= 188 miles

Total gas used,

= 8

Now,

⇒ The rate of gas consumption will be:

= [tex]\frac{Total \ distance}{Total \ gas \ used}[/tex]

By putting the given values in the above formula, we get

= [tex]\frac{188}{8}[/tex]

= [tex]23.5 \ miles/gallon[/tex]

Thus the above is the appropriate solution.

Learn more about gas consumption here:

https://brainly.com/question/17321062

Simplify cube root of 7 over fifth root of 7. 7 to the power of one fifth 7 to the power of eight fifteenths 7 to the power of five thirds 7 to the power of two fifteenths

Answers

Answer:

[tex]\huge\boxed{7^{\frac{2}{15}}}[/tex]

Step-by-step explanation:

[tex]\dfrac{\sqrt[3]7}{\sqrt[5]7}\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\=\dfrac{7^\frac{1}{3}}{7^\frac{1}{5}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=7^{\frac{1}{3}-\frac{1}{5}}\qquad\text{find the common denominator (15)}\\\\=7^{\frac{(1)(5)}{(3)(5)}-\frac{(1)(3)}{(5)(3)}}=7^{\frac{5-3}{15}}=7^{\frac{2}{15}}[/tex]

Answer:

D. 7 to the power of two fifteenths

Step-by-step explanation:

What is the error in this problem

Answers

Answer:

The error is the use of wrong trigonometric ratio formula.

Sine was used instead of tangent.

It should be: [tex] tan(A) = \frac{36}{84} [/tex]

Step-by-step explanation:

Side length, 36, is opposite to <A. Side length, 84, is the adjacent side. Therefore, the right trigonometric ratio formula to use is:

[tex] tan(A) = \frac{opposite}{adjacent} [/tex]

[tex] tan(A) = \frac{36}{84} [/tex]

[tex] A = tan^{-1}(\frac{36}{84}) [/tex]

m<A ≈ 23°

The error made was the use of wrong trigonometric ratio formula.

The balances in two separate bank accounts that grow each month at different rales are represented by the functions f(x) and gix) In what month do the funds in the f(x) bank account exceed those in the glx)
bank account?
Month (x) f(x) = 2* g(x) = 4x + 12
1
2
16
2.
4
20
O Month 3
O Month 4
O Month 5
O Month 6​

Answers

Answer:

The balance in two separate bank accounts grows each month at different rates. the growth rates for both accounts are represented by the functions f(x) = 2x and g(x) = 4x 12. in what month is the f(x) balance greater than the g(x) balance?

Answer:

6 months

function is a relationship between inputs where each input is related to exactly one output.

x = 5,

f(5) = [tex]2^5\\[/tex] = 32

g(5) = 4 x 5 + 12 = 20 + 12 = 32

x = 6,

f(6) = [tex]2^6[/tex] = 64

g(6) = 4 x 6 + 12 = 24 + 12 = 36

At month 6 the funds in the f(x) bank account exceed those in the g(x) bank account.

What is a function?

function is a relationship between inputs where each input is related to exactly one output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

f(x) = [tex]2^{x}[/tex]

g(x) = 4x + 12

x = number of months

Now,

x = 3,

f(3) = 2³ = 8

g(3) = 4 x 3 + 12 = 12 + 12 = 24

x = 4,

f(4) = [tex]2^4[/tex] = 16

g(4) = 4 x 4 + 12 = 16 + 12 = 28

x = 5,

f(5) = [tex]2^5\\[/tex] = 32

g(5) = 4 x 5 + 12 = 20 + 12 = 32

x = 6,

f(6) = [tex]2^6[/tex] = 64

g(6) = 4 x 6 + 12 = 24 + 12 = 36

We see that,

At x = 6,

f(5) = 64

g(5) = 36

Thus,

At month 6 the funds in the f(x) bank account exceed those in the g(x) bank account.

Learn more about functions here:

https://brainly.com/question/28533782

#SPJ2

How do I solve? Show with steps.

Answers

Step-by-step explanation:

or,[(√-x-1)+(√x+9)]^2=4^2

or,(√-x-1)^2+2√(-x-1)(x+9)+(√x+9)^2=16

or,-x-1+2√-x^2-10x-9 +x+9=16

or,2√-x^2-10x-9=8

or,√-x^2-10x-9=4

squaring on both sides

or,-x^2-10x-9=16

or,-x^2-10x=25

or,-x(x+10)=25

Either,

x=-25 or, x=15.

Consider the surface f(x,y) = 21 - 4x² - 16y² (a plane) and the point P(1,1,1) on the surface.

Required:
a. Find the gradient of f.
b. Let C' be the path of steepest descent on the surface beginning at P, and let C be the projection of C' on the xy-plane. Find an equation of C in the xy-plane.
c. Find parametric equations for the path C' on the surface.

Answers

Answer:

A) ( -8, -32 )

Step-by-step explanation:

Given function : f (x,y) = 21 - 4x^2 - 16y^2

point p( 1,1,1 ) on surface

Gradient of F

attached below is the detailed solution

HELP ME PLEASE!!!!!!!!! WORTH 100 POINTS WILL FOLLOW AND RATE BRAINLIEST ANSWER!!!!!!!!!!!! If the function f(x) has a domain of (a,b] and a range of [c,d), then what is the domain and range of g(x)=m×f(x)+n?(1 point) A.The domain of g(x) is (ma+n,mb+n], and the range is [c,d). B.The domain of g(x) is (a,b], and the range is [mc+n,md+n). C.The domain of g(x) is (a,b], and the range is [c,d). D.The domain of g(x) is (ma+n,mb+n], and the range is [mc+n,md+n).

Answers

Greetings from Brasil...

If  domain is (a,b] and the range is [c,d), so:

f(a) = c

f(b) = d

so

g(x) = m × f(x) + n

g(a) = m × f(a) + n       how f(a) = c, then

g(a) = mc + n

g(b) = m × f(b) + n

g(b) = md + n

So

Domain = (a; b]Range = [mc + n; md + n)

graph the linear equation. Find three points that solve the equation, the plot them on the graph. -2y= 5x +11

Answers

Answer:

Three points are (0,-5.5), (-1,-3), (-2.2,0) and graph is shown below.

Step-by-step explanation:

The given equation is

[tex]-2y=5x+11[/tex]

We need to find three points that solve the equation.

Put x=0,

[tex]-2y=5(0)+11[/tex]

[tex]-2y=11[/tex]

[tex]y=-5.5[/tex]

Put x=-1,

[tex]-2y=5(-1)+11[/tex]

[tex]-2y=6[/tex]

[tex]y=-3[/tex]

Put y=0,

[tex]-2(0)=5x+11[/tex]

[tex]5x=-11[/tex]

[tex]x=-2.2[/tex]

So, three points (0,-5.5), (-1,-3) and (-2.2,0) are the solutions of the given equation.

Plot these points on a coordinate plane and connect them by a straight line as shown below.

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