Answer:
From the data we know that runner A and runner B are 11 km apart from the start because (6+5) km
So the runner from the east direction has distance as unknown km, rate= 9 k/h ; time= d/r=x/9 hr
So runner towards the west will be
distance = 11-x, rate= 8 k/h, time = d/r = (11-x)/8
So equating east and west time we have
x/9= (11-x)/8
8x=99-9x
17x=99
x=5.92 km
That is the distance covered by runner towards the east and he will meet the runner toward the west at
6-5.92=0.08 km west of the flagpole.
X-rays with wavelength of 2.0 nm scatter from a NaCL crystal with plane spacing of 0.281 nm. Find the scattering angle for the second order maxima.
Explanation:
Wavelength of x-rays = 2 nm
Plane spacing, d = 0.281 nm
It is assumed to find the scattering angle for second order maxima.
For 2nd order, Bragg's law is given by :
[tex]2dsin\theta =n\lambda[/tex]
For second order, n = 2
[tex]sin\theta =\frac{n\lambda}{2d} \\Sin\theta =\frac{2\times2}{2\times0.281} \\\theta =\arcsin (7.14)[/tex]
Here, θ is not defined. Also, the wavelength of x-rays is more than the plane spacing. It means that it cannot produce any diffraction maximum.
define polarization in reference in the simple cell
Answer:polarization pertains to the act or process of producing a positive electrical charge and a negative electrical charge such that between a nerve cell internal electrical charge..................
Explanation:
A cannonball falls at a rate of about 10 m/s2 due to gravity. It has a mass of 200 kg. What is the total force of the
cannonball?
[tex]\star[/tex][tex]\blue\star[/tex]
[tex]\blue\star[/tex]Givenmass = 200kgacceleration = 10m\s^2Star coding
[tex]\blue\star[/tex]As we know that force = mass × accelerationF = m×aF = 200 ×10F = 2000N[tex]\blue\star[/tex]so mate here is ur ans force is equal to 2000N.Hope it helps
Alice and Bob are bicycle-racing, on a two-mile track. Bob rides the first mile at 50 mph,
and the second mile at 71 mph. Calculate the time in minutes) that he travels the two
miles.
Answer:
2.04 minutes
Explanation:
He travels the first mile at 50 mph so:
[tex]60/50=1.2[/tex]
so it takes 1.2 minutes to travel each mile when going 50 miles per hour
and for the second mile he travels at 71 mph so:
[tex]60/71=0.84[/tex] (this answer is rounded)
so it takes him 0.84 minutes to travels each mile while going 71 mph.
If you ad them together his total times while biking two miles was 2.04 minutes.
A kitten runs 24 x 10⁻² m away from its master in a straight line in 12.6 s, and then run halfway back in one-third the time. Calculate its average velocity.
Answer:
1.43 × 10^-2 m/s
Explanation:
Given the following :
Distance covered away from it's master = D1 = 24×10^-2 m
Time taken to cover the distance = t1 = 12.6s
Then runs halfway back D2 =
D1/ 2 = (24× 10^-2m) / 2 = 12 ×10^-2m
Time taken =T2 = T1/3 = 12.6/3 = 4.2s
Since the kitten ran in a straight line, the it is linear :
Average speed
Linear Average Velocity:
Change in distance / change in time
(D1 - D2) / (T2 - T1)
(24 - 12)×10^-2 / (12.6 - 4.2)
(12 × 10^-2)m / 8.4s
1.4285 × 10^-2
= 1.43 × 10^-2m/s
A 7600 kg satellite is in a circular orbit around Earth at a height of 2300 km above Earth's surface. What is this satellite's speed
Answer:
6779.7m/s
Explanation:
Using
GMm/(Re +h)² = mv²/ (Re+h)
So making v subject we have
V= √GM/Re+h
So
V = √ 6.67*10^-11 x 5.97*10^24/(6371+2300)*10^3
V= 6779.7m/s
Note h = height of satellite
Re= radius of the earth
M = mass of the earth
If a baseball travels a distance of 4 meters in 5 seconds, what is its average speed
Answer:
speed=d/t.
s=4/5=0.8m/s.
what magnetic field strength will allow the electron to pass between the plates without being deflected
Complete Question
An electron travels with speed 2.0 X 10^7 m/s between two parallel charged plates. The plates are separated by 2.0 cm and are charged by a 400V battery. What magnetic field strength and direction will allow the electron to pass between the plates without being deflected.?
Answer:
The value [tex]B = 0.001 \ T[/tex]
Explanation:
From the question we are told that
The speed of the electron is [tex]v = 2.0 *10^{7} \ m/s[/tex]
The voltage is [tex]V = 400 \ V[/tex]
The distance of separation is [tex]d= 2.0 \ cm = 0.02 \ m[/tex]
Generally the electric field is mathematically represented as
[tex]E = \frac{V}{d }[/tex]
=> [tex]E = \frac{400}{0.02 }[/tex]
=> [tex]E = 20000 V/m[/tex]
Generally for the electron to pass without deflection then
[tex]F_B = F_E[/tex]
Where [tex]F_B[/tex] is the maximum magnetic force acting on the electron which is mathematically represented as
[tex]F_B = evBsin (\theta )[/tex]
Since we are considering maximum magnetic field then [tex]\theta = 90^o[/tex]
=> [tex]F_B = evB[/tex]
And
[tex]F_E[/tex] is the electric force on the electron which is mathematically represented as
[tex]F_E = e * E[/tex]
Here e is the charge on the electron with the value [tex]e = 1.60 *10^{-19} \ C[/tex]
=> [tex]F_E = 1.60*10^{-19} * 20000[/tex]
=> [tex]F_E = 3.2*10^{-15} \ N[/tex]
So
[tex]3.2*10^{-15} = q* v B[/tex]
=> [tex]B = \frac{3.2*10^{-15}}{ 2.0*10^7 * 1.6*10^{-19}}[/tex]
=> [tex]B = 0.001 \ T[/tex]
Which of the following does NOT cause acceleration?
A change in the magnitude of the velocity
A change in the direction of the velocity
Constant speed
Increasing speed
Decreasing spped
Answer:
Constant speed
Explanation:
Acceleration is a change of magnitude and (or) direction of velocity, it will cause increase or decrease, or changing of the direction of the velocity.
What operation do you apply to the position function of a particle to compute the particles velocity
Answer:
the derivative with respect to time
Explanation:
This is an exercise in kinematics, where the velocity is defined as a function of the position of a body of the form
v = dx/dt
where v is the velocity of the body, x is the position that we assume is a continuous and differentiable function.
The function written in the equation is the derivative with respect to time
It takes Serina 4.44 hours to drive to school. Her route is 15 km long. What is Serina’s average speed on her drive to school?
Answer: 3.38 km per hour
Explanation:
the effect on any force depends on what two things
Answer: mass and distance
Explanation: Two major factors, mass and distance, affect the strength of gravitational force on an object. You witness the first factor in everyday life - more massive objects are heavier. The second factor, distance, is less familiar, as it takes a distance of many thousands of kilometers to significantly weaken the pull of Earth's gravity.
Answer:
The factor of a force depends on two things:
1. the amount of a force applied. The more the force applied the greater the effect.
2.the area on which the force is applied. The smaller the area the force is applied on, the greater the effect.
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A-0.06 C charge that moves downward is in a uniform electric field with a strength of 200 N/C. What is the
magnitude and direction of the force on the charge?
O 12 Nup
O 12 N down
O 3333 Nup
O 3333 N down
Answer:
its B
Explanation:
i just took the test
The correct option is B. The magnitude of the force on the charge is 12N and the direction is downward.
The electric field is a region of space where electric force can be felt. The formula for calculating the magnitude of a force in an electric field is expressed as:
[tex]\overline F=qE[/tex] where:
q is the charge measured in CoulombsE is the electric field intensity measured in N/CGiven the following parameters:
q = -0.06C
E = 200N/C
Substitute the given parameters into the formula as shown:
[tex]\overline F = -0.06 * 200\\\overline F = -12N\\[/tex]
Since the modulus of the force is in the negative sense, hence the direction will be downward.
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when would a swimmer have the most potential energy due to her position
Answer: A
Explanation:
A swimmer have the most potential energy due to her position.When he is sitting on the highest diving board at the pool.
What is potential energy?The potential energy is the due to the virtue of the position and the height. The unit for the potential energy is joule.
The potential energy is found as;
[tex]\rm PE = mgh[/tex]
The potential energy is mainly depending upon the height of the object.
When the swimmer is at the highest position, the height is maximum. Therefore, the potential energy is also maximum.
Hence, a swimmer have the most potential energy due to her position.When he is sitting on the highest diving board at the pool.
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A toy police car moves across the room in 10 seconds. The distance the car traveled is
450 centimeters. At what speed did the car travel?
Answer:
45cm/s
Explanation:
If the distance traveled is 450 centimeters we can assume the speed is 45cm/s by taking the distance and dividing by the time, in this case that is 450 and 10
so our answer would be 45cm/s
If the steam in the engine is able to raise a 30 kg piston to a height of 0.68 m, how much work has been done by the steam?
Answer:
199.92joules
Explanation:
workdone = Mgh
mass x height x acceleration due to gravity
How much power is used by a hair dryer if it does 40,000 J of work in 40 seconds?
Answer:
40000÷40=1000 joules is required to work in 40 seconds
An electron moving parallel to the x axis has an initial speed of 4.10 106 m/s at the origin. Its speed is reduced to 1.76 105 m/s at the point x = 2.00 cm.
Required:
a. Calculate the electric potential difference between the origin and that point.
b. Which point is at the higher potential?
Answer:
a
[tex]V = -47.65 N/C[/tex]
b
At the origin
Explanation:
From the question we are told that
The initial speed is [tex]v_1 = 4.10 *10^{6} \ m/s[/tex]
The speed at (x = 2.00 cm) is [tex]v_f = 1.76 *10^{5} \ m/s[/tex]
Generally the electric potential difference is mathematically represented as
[tex]V = \frac{W}{q}[/tex]
Here W is the work-done which is mathematically represented as
[tex]W = K_f - K_i[/tex]
Here [tex]K_f[/tex] is the kinetic energy at x = 2.00 cm mathematically expressed as
[tex]K_f = \frac{1}{2} * m* v^2_f[/tex]
and
[tex]K_i[/tex] is the kinetic energy at origin mathematically expressed as
[tex]K_f = \frac{1}{2} * m* v^2_i[/tex]
So
[tex]V = \frac{1}{q} [ \frac{1}{2} mv_f^2 - \frac{1}{2} mv_i^2][/tex]
[tex]V = \frac{m}{2q} [v_f^2 - v_i^2][/tex]
Here m is the mass of electron with value [tex]m = 9.1*10^{-31} \ kg[/tex]
q is the charge on the electron with value [tex]q = 1.60*10^{-19} \ C[/tex]
So
[tex]V = \frac{(9.1 *10^{-31})}{2(1.60*10^{-19})} [(1.76*10^{5})^2 - (4.10*10^{6})^2][/tex]
[tex]V = -47.65 N/C[/tex]
So given that the difference is negative then potential is higher at the origin
A variable is defined as anything that
The x-component of vector R is Rx = −28.2 units and its y-component is Ry = 19.6 units. What are its magnitude and direction? Give the direction as an angle measured counterclockwise from the +x-direction.
Answer:
Explanation:
Rx = -28.2 units
Ry = 19.6 units
magnitude of R = √ [( - 28.2 )² + ( 19.6 ) ]
= √ ( 795.24 + 384.16 )
= 34.34 units
If θ be the angle measured counterclockwise from the +x-direction
Tanθ = 19.6 / - 28.2 = -0.695
θ = 180 - 34.8
= 145.2° .
As the frequency of the ac voltage across an inductor approaches zero, the inductive reactance of that coil Group of answer choices
Answer:
The inductive reactance also approaches zero
Explanation:
This is because from the relation
XL = 2πfL
Meaning frequency f and inductive reactance XL are directly proportional so as one approaches zero so does the other
Robert pushes the box to the left at constant speed. In doing so, Robert does ______ work on the box. A. positive B. negative C. zero
Answer:
He does postive work
Explanation:
Because W= F xS sinစ
So since work is done such that Force and distance have the Sam direction
Thus စ=0
Then work is positive in value
Effect of thunder storm
Answer:
Some of the most severe weather occurs when a single thunderstorm affects one location for an extended time. Thunderstorms can bring heavy rains (which can cause flash flooding), strong winds, hail, lightning, and tornadoes. Severe thunderstorms can cause extensive damage to homes and property.
Explanation:
Find the value of x in the triangle shown below.
9
C
3
You want to create an electric field vector E = < 0, 5 104, 0> N/C at location < 0, 0, 0>. Where would you place a proton to produce this field at the origin?
Answer:
1.696 × 10^(-7) m on the y axis.
Explanation:
We are given the electric field as;
E = < 0, 5 × 10⁴, 0> N/C
This is written in (x, y, z) co-ordinates. So it means that it lies on the y-axis.
So,
E = 5 × 10⁴ N/C in the y direction.
Formula for Electric field is;
E = kq/r²
where;
k is a constant with a value of 8.99 x 10^(9) N.m²/C²
q is charge on the proton = 1.6 × 10^(-19) C
r is the distance
Thus, making r the subject gives;
r = √(kq/E)
Plugging in the relevant values gives;
r = √(8.99 × 10^(9) × 1.6 × 10^(-19)/(5 × 10⁴))
r = 1.696 × 10^(-7) m on the y axis.
The proton to produce this field at the origin should be put on [tex]1.696 \times 10^{(-7)} [/tex]m on the y axis.
The calculation is as follows:We are given the electric field as;
[tex]E = < 0, 5 \times 10^{4}, 0> N/C[/tex]
This is written in (x, y, z) co-ordinates. So it means that it lies on the y-axis.
So,
[tex]E = 5 \times 10^{4} N/C[/tex] in the y direction.
The Formula for Electric field is;
E = kq/r²
where;
k is a constant with a value of 8.99 x 10^(9) N.m²/C²
q is charge on the proton = 1.6 × 10^(-19) C
r is the distance
Thus, making r the subject gives;
r = √(kq/E)
Now Plugging in the relevant values gives;
r = √(8.99 × 10^(9) × 1.6 × 10^(-19)/(5 × 10⁴))
r = 1.696 × 10^(-7) m on the y axis.
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When a circuit is arranged in parallel
A. There are multiple paths that electrons can take through the circuit, and it is possible for the electron to pass through one circuit component but not another.
B. There is only one path the electrons can take through the circuit, and they must pass through all circuit components
Answer:
A. There are multiple paths that electrons can take through the circuit, and it is possible for the electron to pass through one circuit component but not another.
Explanation:
Parallel arrangement of components in an electric circuit puts different parts of the circuit on different branches. In a parallel connection, there are multiple paths for the electrons to take, and it is possible for electrons to pass through on circuit component without going through another. This is the reason why If there is a break in one branch of the circuit, electrons can still flow in other branches, and the same reason why one bulb going off in your home does prevent the other components in your home from coming on (your home is wired in a parallel electric circuit).
Acceleration of 1.5 ms expressed in km /hr2?
Find the tension between the 4 kg and the 6 kg blocks once the system is released from rest and the 9 kg block accelerates downward.
Answer:
Tension on the string is 48 N
Explanation:
Mass of A = 6 kg
mass of B = 4 kg
If the 9 kg accelerates downwards then the equation for the 6 kg mass side of the pulley will be
6g - T = 6a ....1
where
g is acceleration due to gravity = 10 m/s^2
a is the acceleration of the body
T is the tension in the string.
For the 4 kg mass side of the string, we have
T - 4g = 4a ....2
transposing, we have
T = 4a + 4g ....3
substitute equation 3 in equation 1, we have
6g - (4a + 4g) = 6a
6g - 4a - 4g = 6a
6g - 4g = 6a + 4a
2g = 10a
but g = 10 m/s^
2 x 10 = 10a
20 = 10a
acceleration a = 20/10 = 2 m/s^2
substitute value of a in equation 1
6g - T = 6a
6(10) - T = 6(2)
60 -T = 12
60 - 12 = T
T = 48 N
What is the toy's total energy at any point of its motion? Express your answer with the appropriate units.]
The complete question is as follows:
A 0.150-kg toy is undergoing SHM on the end of a horizontal spring with force constant k = 300 N/m. When the toy is 0.0120 m from its equilibrium position, it is observed to have a speed of 0.400 m/s.
Answer:
The correct answer is 0.034 J.
Explanation:
Given :
mass of the toy is m = 0.15 kg.
The force constant of restoring force k = 300 Nm⁻¹
When the position of the toy from the equilibrium is x = 0.012m, then the
speed of the toy vx = 0.4m s
The total mechanical energy in SHM is given by
E= 1/2 (mv²+ kx²) = 1/2 kA²
(here, m = mass of the object, vx = velocity, k = force constant
of restoring force, and A = amplitude of SHM.)
Hence by substituting the numerical values in equation 1, we get
[tex]E= \frac{1}{2} (0.15* 0.4) + \frac{1}{2} (300* 0.012)[/tex]
= 0.034 J
Thus, the correct answer is 0.034 J.
A particle moves along a line so that its velocity at time t is ( | |. Find the displacement of the particle during the time period .
Complete question is;
A particle moves along a line so that its velocity at time t is
v(t) = t² − t − 6
(measured in meters per second).
(a) Find the displacement of the particle during the time period 1 ⩽ t ⩽ 4.
(b) Find the distance traveled during this time period.
Answer:
A) -4.5 m
B) 10.17 m
Explanation:
We are given;
v(t) = t² − t − 6
We know that v = ds/dt
Thus,
S = v dt
s(4) - s(1) = (4,1)∫t² − t − 6 dt
= (4,1)[(t³/3) - (t²/2) - 6t]
= ((4³/3) - (4²/2) - 6(4)) - ((1³/3) - (1²/2) - 6(1))
= 64/3 - 8 - 24 - 1/3 + 1/2 + 6
= -4.5 m
B) Since v(t) = t² − t − 6, then factorizing we can write it as;
v(t) = (t + 2)(t - 3)
Thus, v(t) ⩽ 0 at the interval (1, 3) and v(t) ≥ 0 at the interval (3, 4)
Thus;
-x1 = (1, 3)∫t² − t − 6 dt
-x1 = (1,3)(t³/3 - t²/2 - 6t)
-x1 = (3³/3 - 3²/2 - 6(3)) - (1³/3 - 1²/2 - 6(1))
-x1 = 9 - 9/2 - 18 - 1/3 + 1/2 + 6
-x1 = -3 - 4 - 1/3
-x1 = -22/3 m
x1 = 22/3 m
x2 = (3, 4)∫t² − t − 6 dt
x2 = (3, 4)(t³/3 - t²/2 - 6t)
x2 = ((4³/3) - (4²/2) - 6(4)) - (3³/3 - 3²/2 - 6(3))
x2 = 64/3 - 8 - 24 - 9 + 9/2 + 18
x2 = -23 + 64/3 + 9/2
x2 = (-138 + 128 + 27)/6
x2 = 17/6 m
Thus, total distance = x1 + x2 = 22/3 + 17/6 = 10.17m