Shawn graphed the points listed below.

(0, 0) (1, -1) (3, 0) (4, 4) (4, 5) (5, 4) (6, -2)

Which pair of points could be used to show that the points Shawn graphed do not represent a function?

A. (4, 4) and (4, 5)

B. (4, 4) and (5, 4)

C. (0, 0) and (3, 0)

D. (1, -1) and (6, -2)​

The equation passing through the point ()8, 2 and parallel to 6x - 9y = -7 is y = 6 / 7x - 2 / 7

The equation of the line passes through the point (8, 2) and it is parallel to 6x  - 7y = -7.

The equation of a line can be represented as follows;

y = mx + b

where

m = slope

b = y-intercept

Therefore, parallel line have the same slope.

6x  - 7y = -7

7y = 6x + 7

y = 6 / 7 x + 1

m = 6 / 7

Hence, using (8, 2)

2 = 6 / 7 (8) + b

2 = 16 / 7 + b

b = 2 - 16 / 7

b =  14 - 16/ 7

b = - 2 / 7

Hence, the equation is y = 6 / 7x - 2 / 7

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Answer:

  7

Step-by-step explanation:

A 2-way table can be useful for recording the given information and for finding the missing numbers.

The attached table shows the numbers of families booking in July and August, and also counted by destination. Totals are at the right and bottom, and the grand total is the number 100 at the lower right.

Underlined numbers are those in the problem statement. The remaining numbers are computed so as to make the totals be correct.

Overall, 30+35 = 65 went to Portugal or France, so 100-65 = 35 went to Spain. Of those, 20 booked in August, so 15 booked to Spain in July.

59 booked in August, so a total of 41 booked in July.

Now we know 19 booked for France and 15 booked for Spain in July, so the remaining 7 booked for Portugal in July.

The true statement is David's calculations are incorrect, he used the circumference and the height to find the volume.

Correct calculation:

C = 2πr

8.6 = 2 × 3.14 × r

8.6 = 6.28r

r = 8.6/6.28

r = 1.36942675159235 inches

convert 1.36942675159235 inches to cm

= 3.478343949044569 cm

Approximately,

r = 3.5 cm

Volume = πr²h

= 3.14 × 3.5² × 15.2

= 3.14 × 12.25 × 15.2

= 584.668 cm³

Approximately,

volume = 584.7 cm³

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The error in the measurement of its volume is 3%.

The error in the measurement of its volume is:​

Volume[tex]=\frac{4\pi r^{3} }{3}[/tex]

Δv/v*100=3 ΔR/R*100

[tex]3*\frac{1}{100} *100[/tex]

=3

The error in the measurement of its volume is 3%.

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Answer:160ft^3

Step-by-step explanation:

Volume=(bh/2)h

V=(5ftx8ft/2)8ft

V=20x8=160

Volume=160ft^3

HOPE YOU GET IT RIGHT:)!

The graph of y=sin(x-3π/2) is the graph of the y =sinx shifted right by 3π/2 units.

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

If we have a parent function y = Sin(x), the function

y = Sin(x-b) would be the parent shifted b units right

y = Sin (x+b) would be the parent shifted b units left

The function given is y=sin(x-3π/2)

So from the rules, we can clearly say that it is parent function shifted right by 3π/2 units.

Hence, the graph of y=sin(x-3π/2) is the graph of the y =sinx shifted right by 3π/2 units.

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Answer:

  x^4 +2 +x^-4

Step-by-step explanation:

The square of a binomial is a form worthy of memorization.

  (a +b)² = a² +2ab +b²

Here, you have a binomial with a=x² and b=1/x². Using these values in the pattern, we have ...

  [tex]\left(x^2+\dfrac{1}{x^2}\right)^2=(x^2)^2+2(x^2)\dfrac{1}{x^2}+\left(\dfrac{1}{x^2}\right)^2\\\\=\boxed{x^4+2+\dfrac{1}{x^4}}[/tex]

There are 625 different 4-digit codes only made with odd numbers.

To find the total number of combinations, we need to find the number of options for each one of the digits.

There are 4 digits, such that each digit can only be an odd number.

The total number of different combinations is given by the product between the numbers of options, so we have:

C = 5*5*5*5 = 625.

There are 625 different 4-digit codes only made with odd numbers.

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The correct option is (d) cotФ.

As, cosineФ/sineФ = cotФ.

Trigonometric Identities are equality statements that hold true for all values of the variables in the equation and that use trigonometry functions.

There are numerous distinctive trigonometric identities that relate a triangle's side length and angle.

The basic trigonometric identities are-

Solution for the given trigonometric function; (cosineФ/sineФ)

Use formula of tanФ

tanФ = sineФ/cosineФ

Also, from basic trigonometric ratios.

tanФ = 1/cotФ

Substitute sineФ/cosineФ to get the result

1/cotФ = sineФ/cosineФ

Further simplify,

cotФ = cosineФ/sineФ

Therefore, the value of cosineФ/sineФ = cotФ

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Which of the following is a simpler way to write StartFraction cosine theta Over sine theta EndFraction-

(a) tanФ

(b) secФ

(c) cosecФ

(d) cotФ

Answer: D, cot o

Step-by-step explanation:

edge :-]

Answer:

-3/2

Step-by-step explanation:

Slope=rise/run

Pick any 2 points and you can see that for every increase in 2 increases for x, there are 3 decreases for y.

The probability that emission of both CO and hydrocarbon is in excess is 0.8.

The proportion of favorable cases to all possible cases used to determine how likely an event is to occur.

Let, A be the event in which cars are emitting excess CO:

P(A) = 0.12

Let, B be the event in which cars are emitting excess hydrocarbons:

P(B) = 0.15

The cars which emit both CO and Hydrocarbons in:

P(A∩B) = 0.8

The probability that emission of both CO and hydrocarbon is in excess is 0.8.

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Considering the given stem-and-leaf plot, the outlier is given by:

A - 40

The stem-and-leaf plot lists all the measures in a data-set, with the first number as the key, for example:

4|5 = 45.

Outliers are usually the lowest or the highest value in the data-set. In this problem:

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Answer:

x=5

h = 5 sqrt 2

Step-by-step explanation:

isosceles right triangles are always 45-45-90, ratio of those triangles are always x:x:x*sqrt 2

[tex]{\large{\textsf{\textbf{\underline{\underline{Question \: 1 :}}}}}}[/tex]

[tex]\diamond\:{\boxed{\tt{\purple{{ part \:(i) :}}}}}[/tex]

❍ Prime factorisation :-

‣ Prime factors of 12 -

[tex]\begin{gathered}\begin{gathered}{\begin{array}{ c|c}2&12 \\\hline 2&6 \\ \hline 3&3\\ \hline &1\end{array}} \end{gathered}\end{gathered}[/tex]

‣ Prime factors of 18 -

[tex]\begin{gathered}\begin{gathered}{\begin{array}{ c|c}2&18 \\\hline 3&9\\\hline 3&3 \\ \hline &1\end{array}} \end{gathered}\end{gathered} [/tex]

Therefore,

[tex]\star \: 12 = {2}^{2} \times {3}^{1}[/tex]

[tex]\star \: 18= {2}^{1} \times {3}^{2}[/tex]

✧ LCM of 12 and 18 = [tex]\sf {2}^{2} \times {3}^{2}[/tex]

[tex]\implies 36[/tex]

✧ HCF of 12 and 18 = [tex]\sf {2}^{1} \times {3}^{1}[/tex]

[tex] \implies 6[/tex]

[tex] \diamond\:{\boxed{\tt{\red{{ part \:(ii) :}}}}}[/tex]

❍ Prime factorisation :-

‣ Prime factors of 12 -

[tex]\begin{gathered}\begin{gathered}{\begin{array}{ c|c}2&12 \\\hline 2&6 \\ \hline 3&3\\ \hline &1\end{array}} \end{gathered}\end{gathered}[/tex]

‣ Prime factors of 15 -

[tex]\begin{gathered}\begin{gathered}{\begin{array}{ c|c}3&15 \\\hline 5&5 \\ \hline &1\end{array}} \end{gathered}\end{gathered}[/tex]

‣ Prime factors of 21 -

[tex]\begin{gathered}\begin{gathered}{\begin{array}{ c|c}3&21 \\\hline 7&7 \\ \hline &1\end{array}} \end{gathered}\end{gathered}[/tex]

Therefore,

[tex]\star \: 12 = {2}^{2} \times {3}^{1}[/tex]

[tex] \star \: 15 = {3}^{1} \times {5}^{1}[/tex]

[tex]\star \: 21 = {3}^{1} \times {7}^{1}[/tex]

✧ LCM of 12, 15 and 21 = [tex]\sf {2}^{2} \times {3}^{1} \times {5}^{1} \times {7}^{1}[/tex]

[tex] \implies 420[/tex]

✧ HCF of 12, 15 and 21 = [tex]\sf {3}^{1} [/tex]

[tex] \implies 3[/tex]

[tex] {\large{\textsf{\textbf{\underline{\underline{Question \: 2 :}}}}}}[/tex]

Using,

LCM × HCF = Product of two given numbers

Putting the values,

[tex]\longrightarrow \sf 48 \times 12 = 16 \times y[/tex]

[tex]\longrightarrow \sf \dfrac{ \cancel{48} _{3} \times 12}{ \cancel{16}{ _1} } = y[/tex]

[tex]\longrightarrow \sf y = 3 \times 12[/tex]

[tex] \longrightarrow {\sf{{{\boxed{\green{\bold {\sf y = 36 }}}}}}}[/tex]

Therefore,

The value of y = 36

[tex]{\large{\textsf{\textbf{\underline{\underline{Important \: points :}}}}}}[/tex]

• A natural number "P" > 1 having only two factor one and "P" itself is called prime number.

• A prime number is never negative.

• H.C.F is the product of smallest power of each common prime factor.

• L.C.M is the product of greatest power of each prime factor.

• HCF is always a factor of LCM.

[tex]\underline{\rule{300pts}{3pt}}[/tex]

Answer:

17,500,000 people

Step-by-step explanation:

70% can be rewritten as 0.7 time 25 million

0.7*25,000,000 = 17,500,000

Answer: II only: (-1, 4)

Step-by-step explanation:

x^2 - 3x - 4 is a parabolic function. When you factor the equation, it comes out to f(x) = (x-4)(x+1). Thus, the function as zeros at -1 and 4. Since the a value is positive, the parabola points up. Therefore, if you graph the function, it is negative between -1 and 4, so the answer is II only

Based on the definition of complementary angles, the two angles are: 49.4° and 40.6°.

Angles that are complementary angles have a sum of 90 degrees.

Let the angle be represented as x

Complement of the angle = (90 - x)

Therefore, we would have:

x = (90 - x) + 8.8

x = 90 - x + 8.8

x = 98.8 - x

x + x = 98.8

2x = 98.8

x = 98.8/2

x = 49.4°

The second angle would be: 90 - 49.4 = 40.6°

The angles are 49.4° and 40.6°.

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Answer:

  54°

Step-by-step explanation:

The ratio values can be used to find the angles, then the desired difference can be found. Alternatively, the desired difference can be figured in terms of the ratio units given.

The number of ratio units representing the largest angle is 5. The number of ratio units representing the smallest angle is 2. The difference of these is 5 -2 = 3.

The total number of ratio units is 3 +2 +5 = 10. This is the number of ratio units representing the straight angle, 180°.

The difference is 3 of those 10 ratio units:

  3/10 × 180° = 54° . . . . . . largest - smallest difference

There are 10 ratio units in total (3+2+5=10), so each represents 180°/10 = 18°. Multiplying the given ratios by 18° gives the angle values:

  3×18° : 2×18° : 5×18° = 54° : 36° : 90°

The difference between the largest and smallest is ...

  90° -36° = 54° . . . . . . largest - smallest difference

Answer:

no solution

Step-by-step explanation:

Your question is in the form:

absval of something

= a NEGATIVE number



The absolute value is always positive. So it can never be negative.

There are no values that x can be that will make this math sentence true.

It's not really a trick question, but the course/teacher/book/program just wants you to recognize that an absolute value CANNOT be negative.

The two equivalent forms of [tex]sec^2x[/tex] are [tex]\frac{1}{cos^2x}[/tex] and [tex]1+tan^2x[/tex]

The given trigonometric expression is:

[tex]sec^2x[/tex]

Note that:

[tex]sec(x)=\frac{1}{cos(x)}[/tex]

Substitute this equivalence to the given expression

[tex]sec^2(x)=\frac{1}{cos^2(x)}[/tex]

Also from [tex]cos^2(x)+sin^2(x)=1[/tex]

Divide through by [tex]cos^2x[/tex]

[tex]\frac{cos^2x}{cos^2x} +\frac{sin^2x}{cos^2x}=\frac{1}{sin^2x}[/tex]

Simplifying the resulting expression:

[tex]1+tan^2x=sec^2x\\\\sec^2x=1+tan^2x[/tex]

Therefore, the two equivalent forms of [tex]sec^2x[/tex] are [tex]\frac{1}{cos^2x}[/tex] and [tex]1+tan^2x[/tex]

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Answer:

(B). 25.25

Step-by-step explanation:

z + 54° + (3z + 1)° + 204° = 360°

4z + 259 = 360

z = 101 ÷ 4

z = 25.25  (B).

The intercepts are x intercept: (-1/7,0) and y intercept: (0,1/4)

The function is given as:

7x-5=4y-6

Set y = 0 to determine the x-intercept

7x - 5 = -6

Add 5 to both sides

7x = -1

Divide by 7

x = -1/7

Set x = 0 to determine the y-intercept

- 5 = 4y - 6

Add 6 to both sides

4y = 1

Divide by 4

y = 1/4

Hence, the intercepts are x intercept: (-1/7,0) and y intercept: (0,1/4)

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The graph that is used to represent this probability distribution is the graph of b.

In mathematics and the field of statistics, the probability is used tp denote likelihood of an event occurring.

The sample space is given as

S = {GGG, GGO, GOG, OGG, GOO, OGO, OOG, OOO}.

X=0, the Probability of having Orange(O), in GGG  is given to be 1/8

X=1, we have to get the probability, in G G O , GOG,and O G G, this gives a total of 3 =  3/8

X=2, Probability of Orange O, in GOO , OGO, oog =   3/8

X=3, Probability of Orange O in all is also given as 1. Hence the probability is = 1/8

A spinner has two equal sections, one green and one orange. The spinner is spun three times, resulting in the sample space S = {GGG, GGO, GOG, OGG, GOO, OGO, OOG, OOO}. If the random variable X represents the number of times orange, O, is spun, which graph represents the probability distribution?

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The tabular values can be used to derive the formula relationship between x and P which gives the percentage commission of Zachary as 1%

From the above table, we have;

Where;

y = The fixed percentage commission Zachary makes

b = Zachary's base pay

Therefore;

Subtracting equation (1) from (2), gives;

110 - 105 = (3500 - 3000) × y + b - b = 0

5 = 500•y

y = 5/500 = 0.01 = 1%

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Answer:

The box is 8 feet long.

Step-by-step explanation:

1 inch = 2 feet.

Multiply 4 by 2.

4×2=8

I multiplied 4 by 2 because 1-inch equals 2 feet, which means if we multiply both terms by 4, you will get 4 inch = 8 feet.

Hope this helps!

Answer:

BT = 18, DA = 6

Step-by-step explanation:

- EBT and SDA are similar triangles

- EBT has a perimeter of 63

- SDA has a perimeter of 21

- BT = 6x

- DA = x+3

We know that EBT has side lengths that are three times bigger than the side lengths of SDA since 63 = 21 x 3.

so

6x is equal to 3(x+3).

6x = 3x + 9

3x = 9

x = 3

Now we know that:

BT = 18

and

DA = 6

Answer:

x= 10 y=14 : 10 3 point, 14 5 point

Step-by-step explanation:

Write your equation down vertically,

3x + 5y = 100

 x + y   =  24

Next find multiply bottom equation by one number from the tops opposite,

3x + 5y = 100

(-3)x +(-3)y = (-3)24

3x + 5y = 100

-3x - 3y= -72

Add the two functions to isolate y

2y= 28 y=14

Plug y back into original and solve

3x +5(14) =100 --> 3x + 70 =100 --> 3x = 30 x=10

Answer:

Step-by-step explanation:

hello

calculate x : 3x+2 =5

means : 3x+2-2 =5-2

3x = 3

so : x = 3/3 =1

1 is the  element in domain has the image 5 under function f(x)= 3x+ 2

Hello,

[tex]( \frac{1}{3} ) {}^{3} = \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1 {}^{3} }{3 {}^{3} } = \frac{1}{27} [/tex]

Hi! ⋇

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

[tex]\sf\color{darkblue}{( \frac{1}{3}) ^{3} = \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1} {27} }[/tex]