Answer:
3x^3+ 12x^2-15x
Step-by-step explanation:
First, you would have to distribute the 3x to everything in the parentheses. So you can write it out as (3x*x^2)+(3x*4x)+(3x*5). Solving this will give you the answer. We'll start off with (3x*x^2). Because we are MULTIPLYING, this part will equal to 3x^3. There is ONE x with 3x (think of it as 3x^1) and 2 x's in x^2, having a total of 3 x's, or x^3. Since the 3 is being multiplied as well, we can write it as 3x^3.
Second, we will solve (3x*4x). We are multiplying, so first we multiply 3*4 and then x*x. 3*4 is 12 and x*x is x^2. There are 2 x's being mutipled by each other, so the x becomes squared. Now we finish and multiply 12*x^2 wich is 12x^2.
Lastly, we solve (3x*5). 3x is being multiplied 5 times which gives us 15x.
I hope this helped :)
Can y’all help me what do I do here please I’ll give you brainliest
Answer:
1, 2, -3, 51
Step-by-step explanation:
0 ÷ 2 = 0
0 + 1 = 1
2 ÷ 2 = 1
1 + 1 = 2
-8 ÷ 2 = -4
-4 + 1 = -3
100 ÷ 2 = 50
50 + 1 = 51
i would love if you could answer very soon
Which ordered pair is a solution to the system of inequalities?
S y> -2
x + y < 4
Answer:
4
Step-by-step explanation: you have t do y plus 10 and then add 4 minus -2
An object dropped from the top of a tall building falls y = 4.9t^2 meters in the first t seconds. What is the object’s average speed during the first 4 seconds?
A.) 4.9 m/s
B.) 9.8 m/s
C.) 19.6 m/s
D.) 39.2 m/s
E.) 78.4 m/s
What is the objects instantaneous speed at t=4 seconds?
A.) 4.9 m/s
B.) 9.8 m/s
C.) 19.6 m/s
D.) 39.2 m/s
E.) 78.4 m/s
Answer:
Average Speed
C.) 19.6 m/s
Instantaneous Speed
D.) 39.2 m/s
Step-by-step explanation:
Given the function to represent the distance traveled by the object in [tex]t[/tex] seconds:
[tex]y = 4.9t^2[/tex]
To find:
Object's average speed during the first 4 seconds ?
Instantaneous speed at t = 4 seconds
Solution:
Average speed of a moving object is given by, Total Distance covered divided by Total time taken.
[tex]\text{Average Speed = }\dfrac{\text{Total Distance traveled}}{\text{Total Time Taken}}[/tex]
Let us find the distance traveled in 4 seconds by putting t = 4 in the equation [tex]y = 4.9t^2[/tex]
[tex]y = 4.9\times 4^2 = 78.4\ m[/tex]
Now, let us put the values in the formula:
[tex]\text{Average Speed = }\dfrac{78.4}{4} = \bold{19.6\ m/s}[/tex]
For instantaneous speed, we need to differentiate y w.r.to t:
[tex]Speed = \dfrac{d}{dt}y = 4 \times 4.9 t^{2-1}\\\Rightarrow Speed = \dfrac{d}{dt}y = 4 \times 4.9 t[/tex]
Now, let us put t = 4 seconds
Speed = [tex]4\times 4.9\times 4[/tex] = 39.2 m/s
The answers are:
Average Speed
C.) 19.6 m/s
Instantaneous Speed
D.) 39.2 m/s
Identify the factors of the terms of the expression.
3). 5+6a+11b
4). 13m-2n
Answer:
factors are 5, 6, a, 11, b
Step-by-step explanation:
3) 5 + 6a + 11b
Algebraic expressions: 5 + 6a + 11b
Are combinations of numbers, variables, and at least one arithmetic.
Term are: 5, 6a, 11b
Each expression is made up of terms. A term can be a signed number, a variable, or a constant multiplied by a variable(s).
Factors are: 5, 6, a, 11, b
Something which is multiplied by something else. A factor can be a variable, number, a term, or a longer expression.
Coefficient: 6, 11
The numerical factor of a multiplication expression that contains a variable.
Constant: 5
A number that cannot change its value.
4). 13m-2n (note: it applies as above)
g ( h + 3/5 ) = 11 solve for h
Answer:
h = 11/g - 3/5
Step-by-step explanation:
[tex]g ( h + \frac{3}{5} ) = 11 \\\\Divide\:both\:sides\:of\:the\:equation\:by\:g \:;\\\frac{g(h+\frac{3}{5}) }{g} = \frac{11}{g} \\\\h + \frac{3}{5} = \frac{11}{g} \\\\Move\: 3/5\: to\: the\: right\:and\:change\:its\:sign\\h = \frac{11}{g} -\frac{3}{5}[/tex]
A store charges $120 for a bicycle. The store is now going out of business and is
selling all of the bicycles at a 30% discount. What is the sale price of the bicycle?
Answer:
$84
Step-by-step explanation:
So, if the store is selling the bicycles at a 30% discount, that means that the bike is at 70% of it's original value. SO we can do 120*.7=84.
Find the arc length of the semicircle.
Either enter an exact answer in terms of it or use 3.14 for IT and enter your answer as a decimal.
A semicircle is a half of a circle.
Find the circumference of a full circle then divide in half.
Circumference = pi x r x 2
Circumference = 3.14 x 9 x 2 = 56.52
Semicircle = 56.52/2 = 28.26
What is a Metric prefix?
Answer:
Step-by-step explanation:
A metric prefix is a unit prefix that precedes a basic unit of measure to indicate a multiple or submultiple of the unit. All metric prefixes used today are decadic. Each prefix has a unique symbol that is prepended to any unit symbol.
This is the definition
Eric and his two sisters shared an amount of money in the ratio 2:7 respectively. If Eric had $ 300 and the remaining amount shared equally among the sisters, how much did each sister get?
Answer:each sister get will get $525
Step-by-step explanation:
1st step
Eric and his sisters shared amount x in the ratio 2:7
total ratio = 2+7 = 9
2nd step ;
Total amount of money shared since Eric received $300
(ratio of Eric/ Total ratio ) x Shared amount X = share of Eric
2/9 x X= 300
X=(300 x 9) / 2 = $1,350
Total money = $1,350
3rd step:
two sisters will receive
(ratio of two sisters/ Total ratio ) x Shared amount x = share of two sisters
7/9 x $1,350 = 9,450/9 = 1,050
share of two sisters= $1050
if they share equally , each will receive $1050/2 = $525
Find the smallest number which when divided by 12,15,18&27 leaves as remainder 8,11,14,23 respectively.
Answer:
[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{536}}}}}[/tex]
Step-by-step explanation:
Solution :
Here, 12 - 8 = 4
15 - 11 = 4
18 - 14 = 4
27 - 23 = 4
Thus, every divisor is greater than its remainder by 4. So, the required smallest number is the difference of the L.C.M of the given number and 4
Finding the L.C.M
First of find the prime factors of each numbers
12 = 2 × 2 × 3
15 = 3 × 5
18 = 3 × 3 × 3
27 = 3 × 3 × 3
Take out the common prime factors : 3 , 3 and 3
Also take out the other remaining prime factors : 2 , 2 and 5
Now, Multiply those all prime factors and obtain L.C.M
L.C.M = Common factors × Remaining factors
= 3 × 3 × 3 × 2 × 2 × 5
= 540
L.C.M of 12 , 15 , 18 and 27 = 540
So, The required smallest number = 540 - 4
= 536
Hope I helped!
Best regards!!
A passenger car weighs 4.5 times 10 Superscript 3 units. Which unit of measure was used?
Answer:
pounds
Source:
Trust me bro
Evaluate 2 4ac if b = 5, a = -2, and c = 0
Answer:0
Step-by-step explanation:2 4ac
2×4×-2×0=0
Add the polynomials (7x3−2x2−12)+(−3x3−8x2+10x)
Answer:
See below
Step-by-step explanation:
● (7x^3 - 2x^2 -12) + (-3x^3 - 8x^2 +10x)
● 7x^3 - 2x^2 - 12- 3x^3 - 8x^2 + 10x
Combine like terms
● 7x^3 - 3x^3 -2x^2 - 8x^2 -12 + 10x
● 4x^3 - 10x^3 +10x -12
Answer:
Addition:::::4x^3-10x^2+10x-12
Felicity accidentally overdrew her bank account by $24.65. She then deposited a birthday check from her grandma for $25.00, paid her phone bill of $46.75, and deposited $32.80 she found in her wallet. What was the final balance of her account? Plz Answer!
Answer:
It would be -13.6
Step-by-step explanation:
I used my calculator for this,
-24.65 +25 - 46.75 + 32.80 = -13.6
5 + 2x < 2x + 6
what is x?
Answer:
x = infinite amount of solutions
Step-by-step explanation:
Step 1: Write out inequality
5 + 2x < 2x + 6
Step 2: Solve
5 < 6
Since we can see that 6 is indeed bigger than 5, it makes the inequality true. If you plug in any number x, it will still be true. Therefore, we have an infinite amount of solutions,
The total cost for buying new sneakers for the basketball team an be found by using the function y=25x + 65, is where x is the number of players. If between 9 and 16 players need new sneakers. Find the domain and range of this situation
Answer:
[tex]Domain\ =\ \{x: 9,10,11....16\}[/tex]
[tex]Range\ =\ \{y:290, 315,340.....465\}[/tex]
Step-by-step explanation:
Given
[tex]y = 25x + 65[/tex]
Required
Determine the range and domain when x = 9 to 16
The domain is the set of
[tex]Domain\ =\ \{x: 9,10,11....16\}[/tex]
Solving for the range;
When x = 9
[tex]y = 25 * 9 + 65[/tex]
[tex]y = 225 + 65[/tex]
[tex]y = 290[/tex]
When x = 10
[tex]y = 25 * 10 + 65[/tex]
[tex]y = 250 + 65[/tex]
[tex]y = 315[/tex]
When x = 11
[tex]y = 25 * 11 + 65[/tex]
[tex]y = 275 + 65[/tex]
[tex]y = 340[/tex]
You continue till you get to x = 16
---
--
-
When x = 16
[tex]y = 25 * 16 + 65[/tex]
[tex]y = 400 + 65[/tex]
[tex]y = 465[/tex]
Hence; the range is
[tex]Range\ =\ \{y:290, 315,340.....465\}[/tex]
Consider the geometric sequence: 8, 4, 2, 1, \dots8,4,2,1,…8, comma, 4, comma, 2, comma, 1, comma, dots If nnn is an integer, which of these functions generate the sequence? Choose all answers that apply: Choose all answers that apply: (Choice A, Checked) A a(n)=8\left(\dfrac12\right)^na(n)=8( 2 1 ) n a, left parenthesis, n, right parenthesis, equals, 8, left parenthesis, start fraction, 1, divided by, 2, end fraction, right parenthesis, start superscript, n, end superscript for n\geq1n≥1n, is greater than or equal to, 1 (Choice B) B b(n)=32\left(\dfrac12\right)^nb(n)=32( 2 1 ) n b, left parenthesis, n, right parenthesis, equals, 32, left parenthesis, start fraction, 1, divided by, 2, end fraction, right parenthesis, start superscript, n, end superscript for n\geq2n≥2n, is greater than or equal to, 2 (Choice C) C c(n)=64\left(\dfrac12\right)^nc(n)=64( 2 1 ) n c, left parenthesis, n, right parenthesis, equals, 64, left parenthesis, start fraction, 1, divided by, 2, end fraction, right parenthesis, start superscript, n, end superscript for n\geq3n≥3n, is greater than or equal to, 3 (Choice D, Checked) D d(n)=128\left(\dfrac12\right)^nd(n)=128( 2 1 ) n d, left parenthesis, n, right parenthesis, equals, 128, left parenthesis, start fraction, 1, divided by, 2, end fraction, right parenthesis, start superscript, n, end superscript for n\geq4n≥4
Answer:
C AND D
Step-by-step explanation:
KHAN ACADEMY.
C: c(n)= 64(1/2)^n for n greater than or equal to 3
D: d(n)= 128(1/2)^n for n greater than or equal to 4
The correct series is being generated by options B and D
What is geometric series?A geometric series is a series for which the ratio of each two consecutive terms is a constant term called the common ratio.
How to find which of the given functions generate the given sequence?We know that nth term of a Geometric series can be written as [tex]ar^{n-1}[/tex] where a is the first term and r is the common ratio.The given series is 8 , 4 , 2 , 1......
Here the first term is 8 and the common ratio is 1/2Here, we should check the options one by one
The first option does not generate the series after putting values which are greater than or equal to 1So, option A is wrong.
Now, if we put n = 2, 3 ... values in second function, we can see the series being generated.So, option B is correct.
In option 3 if we put n = 3 then c(n) is coming as 8 but again on putting n = 4 , c(n) is coming 2.So the series in not getting generated here.Hence option C is wrong.
In option 4, we can see that the series is getting generated after putting the values n = 4,5.....So, option D is correct.
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-0.07p-0.6=5 please help!!!!
Answer:
p= -80
Step-by-step explanation:
DON'T FORGET TO INCLUDE THE NEGATIVE
1. Isolate the p
2. Bring the .6 to the other side by doing the opposite. In this case adding.
3. You now should have -0.07=5.6
4. You are going to continue to isolate the variable.
5. You are going to do the opposite of multiplication to the -0.07. (Didn't know how to word this part)
6. You are going to divide both sides by -0.07. Which would give you -80.
DON'T FORGET TO INCLUDE THE NEGATIVE
Add. Write your answers in simplest form.
10 1/6+12 1/10
Jonah starts jogging at a constant speed of 6 miles per hour, Five minutes later, Sory jogging from the sa me place along the same trail. Sory jogs at a constant speed of 7.5 miles per hour. How far apart are they after Sory jogs for 12 minutes?
Answer:
0.2 miles
Step-by-step explanation:
Given that Jonah starts jogging at a constant speed of 6 miles per hour, Five minutes later, Jonah must have covered a distance of;
Distance = speed × time
Distance = 6 × 5/60
Distance = 0.5 miles
Distance covered in 12 minute will be
Distance = 6 × 12/60
Distance = 1.2 miles
Total distance covered by Jonah will be 0.5 + 1.2 = 1.7 miles
Sory jogging from the same place along the same trail. Sory jogs at a constant speed of 7.5 miles per hour.
If Sory jogs for 12 minute, then sory distance covered will be
Distance = speed × time
Distance = 7.5 × 12/60
Distance = 1.5
The distance between Jonah and Sory will be:
1.7 - 1.5 = 0.2 miles
Therefore, they are 0.2 miles apart after 12 minutes
Can someone help me with #s 16 18 19 20 I WILL GIVE BRAINLIEST
Answers & Step-by-step explanation:
PEMDAS (Parenthesis, exponents, multiplication, division, addition, subtraction)Now let's solve your problems!
___________________________________________________16.First, we see if there are any parentheses. Since there are no parentheses, we will evaluate the exponent 3² first.
After this, our problem now looks like this:
[tex]\frac{41 - 9}{6 * 3 -26}[/tex]Next, since multiplication (not subtraction) is next on the list, we will evaluate 6 × 3, which equals 18.
After that, we will subtract:
41 - 9 = 32
18 - 26 = -8
We now have 32/-8 or 4/-1 or simply -4.
The answer is: -4___________________________________________________17.With this, one, note the parentheses. This means that we will do these operations first.
(21 - 4²) = 5
(3 + 1) = 4
The problem now looks like this:
[tex]\frac{5 * 4}{8^{2}-44}[/tex]
Next, we do the exponents:
8² = 64
After that, we do the multiplication of 5 x 4, which equals 20.
We now have 20/64 - 44, which simplifies to 20/20 or 1/1 or 1.
The answer is: 1___________________________________________________18.Again, we see parentheses, so that means we need to do these operations first.
(6² - 20) = 16
We now have:
48 ÷ 16 + 5
48/16 = 3 and 3 + 5 = 8
The answer is: 8___________________________________________________19.Here, we see an exponent 3³, so we'll need to evaluate this first.
3³ = 27
We now have:
4 × 27 ÷ 18 + 14
4 × 27 = 108
108/18 = 6
And finally:
6 + 14 = 20
The answer is: 20___________________________________________________20.Here we again see the parentheses, which means we need to evaluate the subtraction first.
3 - 8 = -5
We now have:
11 + 2 (-5)
2 × -5 = -10
11 + -10 (same as 11 - 10) = 1
The answer is: 1___________________________________________________I AM ALWAYS HAPPY TO HELP :)good morning :) Which expression is equal to 20 minus 9 divided by 3? A.) 20 minus 3 B.) 11 divided by 3 C.) 23 minus 9 D.) 20 minus 9
Answer:
A.20_ 3=17..
option A is the answer
Answer:
A) 20 - 3
Step-by-step explanation:
20 - 9÷3
Use PEMDAS.
First Division should be done
So, 20 - 9÷3 = 20 - 3
2) (G3-4 pts) Find the area of the shaded figure in square feet. Round to the nearest tenth if
necessary. Circle the correct answer.
|--5---
18 ft
---5ft
A. 478.5 ft?
B. 311.2 ft
8 ft
C. 351.2 ft?
D. 438.5 ft?
Answer:
Area of both triangles = 8*5 = 40
Rectangle Area = 8*18 = 144
Semi Circle Area = Pi*r^2 / 2 = (3.14159*81)/2 = 127.34
40 + 144 + 127.34 = 311.34 square feet
answer is B
Step-by-step explanation:
there is a number that if you multiple it by 5 first, and then add 6 to the result, you get 91. what’s the number?
Answer:
Step-by-step explanation:
Do 91-6 which equals 85. Then do 85/5 which equals 17
answer: 17
Answer:
17
Step-by-step explanation:
So first we write an equation
5x+6=91
subtract 6 from both sides
5x=85
divide by 5
so x=17
(plz give me brainliest)
Write the phrase as an expression
the quotient of 22 and a number a
Answer:
22/a
Step-by-step explanation:
The quotient of 22 and a number = 22/a
the sum of the arithmetic series: a1 = 9, a3 = 17, s5 =?
[tex]\huge\underline\bold\blue{ƛƝƧƜЄƦ}[/tex]
Given[tex]\blue\star[/tex]a1 = 9. eq1
[tex]\blue\star[/tex]a2 = 17. eq2
Firstly we have to find d
[tex]\blue\star[/tex]d = a2 -a1
we dont have a2 so we can do this by other method
split a3 into a+2d
Now add equation 1 and 2
[tex]\blue\star[/tex] a+a+2d = 17 +9
[tex]\blue\star[/tex] 18 + 2d = 26. [we have a = 9]
[tex]\blue\star[/tex] 2d = 8
[tex]\blue\star[/tex] d = 4
Now we have to find a5
[tex]\blue\star[/tex] a5 = a+(n-1)d
[tex]\blue\star[/tex] a5 = 9 + (5-1)4
[tex]\blue\star[/tex] a5 = 25
now we can easily find s5
[tex]\blue\star[/tex]s5 = n\2(a+l)
[tex]\blue\star[/tex] s5 =5\2(9+25)
[tex]\blue\star[/tex] s5 = 85
[tex]\huge\boxed{S5 = 85}[/tex]
Check
s5 = a1 + a2 + a3 +a4 +a5
s5 = 9 +13+17+21+25= 85
Hope it helps
The sum of the arithmetic sequence [tex]S_5=85[/tex]
Explanation :
Arithmetic series, a1 = 9, a3 = 17
We need to find out sum of 5 terms
The formula to find sum of arithmetic series is
[tex]S_n=\frac{n}{2} (2a+(n-1)d)[/tex]
where 'a' is the first term
'd' is the common difference and n is the number of terms
a1=9,, first term is 9
formula for nth term is [tex]a_n=a_1+(n-1)d[/tex]
a3=17, it means third term is 17
lets find out 'd' using third term
[tex]a_3=a_1+(3-1)d\\17=9+2d\\17-9=2d\\8=2d\\d=4[/tex]
So value of d=4
Now use sum formula to find out S5
[tex]S_n=\frac{n}{2} (2a+(n-1)d)\\n=5, d=4, a_1=9\\\\S_5=\frac{5}{2} (2(9)+(5-1)4)\\S_5=\frac{5}{2}\cdot \:34\\S_5=85[/tex]
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Windows are cleaned at a house every 7 days.
Milk is delivered to the same house every 3 days.
On the 3rd June, the windows are cleaned and milk is delivered.
What is the next date when both happen on the same day?
Answer: 24th
7-14-21
3-6-9-12-15-18-21
plus the three extra days gets you the 24th
Which represents a function? y x y -3 -5 10 {(-8, -2), (-4,1). (0,-2), (2, 3), (4,-4)} -2 -3 5 {(-12,4),(-6, 10), (-4, 15).(-8, 18). (-12, 24) -2 -3 4 0 -1 0 0 0 0 5 -10 1 -1
The tabular data shown in the image attached does not represent a function.
What is function?A function is a relation between a dependent and independent variable. We can write the examples of function as -
y = f(x) = ax + b
y = f(x, y, z) = ax + by + cz
Given is to find which of the given tables represent a function.
For a table to represent a function, for every unique value of {x}, there should be only one possible value of {y}. This means that if for a function f(x), at {x} = 1, there exists two or more values of {y}, then it is not a function. From the image, it can be seen that the relations given in tables does not represent a function. This is because -
Table {1} -
for {x} = - 3, there exists two values of y
Table {3} -
for {x} = 0, there exists two values of y
Therefore, the tabular data shown in the image attached does not represent a function.
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1. 8x-x
solve
I NEED HELPPP ASAP
Answer:
7xStep-by-step explanation:
[tex]8x-x\\\mathrm{Add\:similar\:elements:}\:8x-x=7x[/tex]
Answer:
7x
Step-by-step explanation:
it is quite clear and also very easy look...
8x -1x = 7x
whenever it's only x, p y etc. remember it is always 1x, 1p, 1y etc. and then just do the operations
so easy hope you found it helpful
plz rate and mark the brainliest if you found it helpful....
HELP PLEASEEEE!!!!!!!!
Answer:
C
Step-by-step explanation:
We can easily rule out B and D because they have dotted lines and both equations are greater than or equal to and less than or equal to.
Answer:
C - with explanation
Step-by-step explanation:
First, when you graph an inequality that uses a < or > it's plotted with a dashed line to show the line isn't included in the region.
Inequalities with a [tex]\leq or \geq[/tex] are plotted with a solid line to show the line is included in the region.
You can eliminate B and D because they are showing a graph using < or >
Now we know it's either A or C.
To figure out each, let's pick 4 random points, one in each quadrant and color.
Let's pick (3,3) (3, -3) (-3,3) (-3,-3) For an easier visual they would be
|
(-3,3) | (3,3)
___________|____________
|
(-3,-3) | (3,-3)
|
Plus in the values for each inequality:
(3,3) x + 2y [tex]\leq[/tex] 4 3x - y [tex]\geq[/tex] 2
3 +[tex]\geq[/tex] 2(3) 3(3) - 3
3 + 6 = 9 9 - 3 = 6
9 is not [tex]\leq[/tex] to 4 6 is [tex]\geq[/tex] 2
So this is a valid point because it works in the 2nd equation.
We got lucky and the first point we chose eliminates option A because (3,3) is a point that works and option A shows that area as being "out of bounds."
To test option C let's pick a point in the undefined area. Let's choose (-1,3)
(-1,3) x + 2y [tex]\leq[/tex] 4 3x - y [tex]\geq[/tex] 2
-1 +[tex]\geq[/tex] 2(3) 3(-1) - 3
-1 + 6 = 5 -3 - 3 = - 6
5 is not [tex]\leq[/tex] to 4 -6 is not [tex]\geq[/tex] 2
So this point in the white area is not valid for either inequality.
Now we know for sure the correct option is C.