solve the equation: 14<2x−1≤20

Answer:

The equation to be solved is missing in the question.

I will explain power series and ways to find the radius and interval of convergence of a powers series in the attached image.

Step-by-step explanation:

Answer:

Hey there!

This is an obtuse isosceles, because two sides are congruent, and one angle is greater than 90 degrees.

Let me know if this helps :)

Answer:

[tex]\Large \boxed{\mathrm{C. \ obtuse \ isosceles }}[/tex]

Step-by-step explanation:

An isosceles triangle has two equal angles. This triangle has two base angles equal.

An obtuse triangle has an angle measuring greater than 90 degrees. This triangle has an angle measuring 136 degrees.

This triangle is an obtuse isosceles triangle.

Answer:

x= -20

Step-by-step explanation:

x/2=3x/4+5

Multiply both sides of the equation by 4, the least common multiple of 2,4.

2x=3x+20

Subtract 3x from both sides.

2x−3x=20

Combine 2x and −3x to get −x.

−x=20

Multiply both sides by −1.

x=−20

Answer:

The probability of getting an offspring pea that is green is is 0.733

YES, the probability is reasonably close to the expected value of 3/4 (0.750)

Step-by-step explanation:

The formula for calculating the probability of an event is;

P = Favorable Outcome / Sample space

Let A be an event of getting an offspring green peas, B be an event of getting an offspring yellow peas and N be the total number of peas.

number of green peas in an offspring are 350

number of yellow peas in an offspring are 127

total number of peas are 477    

So in the genetic experiment, the number of times event A occurs is 350 and the number times event B occurs is 127

Now the probability of getting an offspring pea that is green is

P = number of green peas / total number of peas

p = n(A)/N

p = 350/477

p = 0.733

So YES, the probability is reasonably close to 3/4 ( 0.750 )

The probability of getting an offspring pea that is green is is 0.733.

YES, the probability is reasonably close to the expected value of 3/4 (0.750)

Answer:

x = - 4, x = 2

Step-by-step explanation:

Given

3x² + 6x - 24 = 0 ( divide through by 3 )

x² + 2x - 8 = 0 ← in standard form

(x + 4)(x - 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

x - 2 = 0 ⇒ x = 2

Answer: Negative sign

Adding two negative values results in another negative value.

-1.69 + (-1.69) = -3.38

It's like starting $1.69 in debt and then adding 1.69 dollars of more debt. You'll slide further into debt being $3.38 in debt total.

The sign is negative as the value of -1.69 + (-1.69) is -3.38.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

-1.69 + (-1.69)

= -1.69 - 1.69

= -3.38

This means,

The sign is negative.

Thus,

The value of -1.69 + (-1.69) is -3.38.

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Answer:

The addition should be divided by 4 and not 3 since there are 4 meals.

Step-by-step explanation:

Its a binomial

[tex]\\ \sf\longmapsto x^2-6x+5=0[/tex]

If zeros be alpha and beta

[tex]\\ \sf\longmapsto \alpha+\beta=\dfrac{-b}{a}[/tex]

[tex]\\ \sf\longmapsto \alpha+\beta=\dfrac{-(-6)}{1}[/tex]

[tex]\\ \sf\longmapsto \alpha+\beta=6[/tex]

the sum of the factors of the trinomial [tex]x^2-6x+5[/tex] is -6

Given :

A trinomial [tex]x^2-6x+5[/tex]

The given trinomial is in the form of [tex]ax^2+bx+c[/tex]

Compare the given trinomial with standard form and write the value of a,b,c

a=1, b=-6 and c=5

Sum of the factors of the trinomial is [tex]\frac{b}{a} =-\frac{-6}{1} =-6[/tex]

So, the sum of the factors of the trinomial is -6

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Answer:

2.7 in²

Step-by-step explanation:

Since ∆BAC and ∆EDF are similar, therefore, the ratio of their area = square of the ratio of their corresponding side lengths.

Thus, if area of ∆EDF = x, area of ∆BAC = 6 in², EF = 2 in, BC = 3 in, therefore:

[tex] \frac{6}{x} = (\frac{3}{2})^2 [/tex]

[tex] \frac{6}{x} = (1.5)^2 [/tex]

[tex] \frac{6}{x} = 2.25 [/tex]

[tex] \frac{6}{x}*x = 2.25*x [/tex]

[tex] 6 = 2.25x [/tex]

[tex] \frac{6}{2.25} = \frac{2.25x}{2.25} [/tex]

[tex] 2.67 = x [/tex]

[tex] x = 2.7 in^2 [/tex] (nearest tenth)

Answer:

  (3ab)/(2(b-a))

Step-by-step explanation:

The n-th term of an arithmetic progression is ...

  an = a1 +d(n -1)

Then the value of n is ...

  n = (an -a1)/d +1

The sum of an arithmetic progression is the product of the number of terms and the average of the first and last terms. In this sequence, the common difference d is ...

  d = (b -a)

So, the sum is ...

  Sn = (a +2a)/2·((2a -a)/(b -a) +1)

  Sn = (3ab)/(2(b-a)) . . . . sum of the arithmetic progression

__

Example:

The sequence 1, 1.5, 2 has ...

  a = 1, b = 1.5

Its sum is given by the above formula as ...

  Sn = 3(1)(1.5)/(2(1.5 -1)) = 4.5/(2(.5)) = 4.5 = 1 + 1.5 + 2 . . . . yes

Answer:

683,280 hours is what I caculated. Is that right?

Step-by-step explanation:

Answer:

There are (365 x 24) hours for each year.

and 365 x 24 are 8760.

and 8760 x 78 are 683,280.

so, the average person does not live at least 1 Million hours, but they live more than 500 thousand hours, or 5 x 10^5 hours.

Hope it helps!

Bye!

P.S. Please give me Brainliest...

I desperately need one more Brainliest...

Answer:

824

Step-by-step explanation:

Số quạt đã chuyển đi:

927 x 1/9 = 103 (chiếc)

Số quạt còn lại trong kho hàng là:

927-103 = 824 (chiếc)

We are given the equations:

x - 3y = 2

3x - 4y = 0

writing the system as matrices

[tex]\left[\begin{array}{ccc}1&-3\\3&-4\end{array}\right][/tex][tex]\left[\begin{array}{ccc}x\\y\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}2\\0\\\end{array}\right][/tex]

which is in the form:

AX = B

solving for X(the matrix holding the variables), we get:

X = (A⁻¹)B

Finding A⁻¹:

now, to do this, we need to find the inverse of A

[tex]\left[\begin{array}{ccc}w&x\\y&z\end{array}\right]^{-1} = \frac{1}{wz-xy}\left[\begin{array}{ccc}z&-x\\-y&w\end{array}\right][/tex]

using this formula to find the inverse of matrix A:

[tex]A^{-1} = \frac{1}{(1*-4)-(-3*3)}\left[\begin{array}{ccc}-4&3\\-3&1\end{array}\right][/tex]

[tex]A^{-1} = \frac{1}{5}\left[\begin{array}{ccc}-4&3\\-3&1\end{array}\right][/tex]

Matrix X:

We know that:

X = A⁻¹B

[tex]X = \frac{1}{5}\left[\begin{array}{ccc}-4&3\\-3&1\end{array}\right] * \left[\begin{array}{ccc}2\\0\end{array}\right][/tex]

[tex]X = \frac{1}{5}\left[\begin{array}{ccc}-8\\-6\end{array}\right][/tex]

since matrix X is just a matrix with the variables

[tex]\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}\frac{-8}{5}\\\frac{-6}{5}\end{array}\right][/tex]

x = -8/5

y = -6/5

Answer:

25x^2 + 40x + 16

Step-by-step explanation:

area = 5x * 5x + 5x * 4 + 5x * 4 + 4 * 4

area = 25x^2 + 40x + 16

25x² + 40x + 16 is the required equation in variable x.

What is mensuration ?

Mensuration is a branch of mathematics where we calculate length, width, area, volume, lateral surface area, total surface area.

The sum of the areas of the shaded rectangles is the total area.

By observation we can see that the four shaded rectangles together form a square.

We all know that the area of the square is (side)²

= (5x + 4)²

= 25x² + 40x + 16  this is the required equation.

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Answer: You will need 8 cup scales

Step-by-step explanation:

kg=1000 grams

2000/250=8

Answer:

b

Step-by-step explanation:

Answer:

[tex]106 \frac{3}{5}[/tex]

Explanation:

Convert any mixed numbers to fractions.

Reduce fractions where possible.

Then your initial equation becomes:

[tex]\frac{26}{5} \times \frac{-31}{3}[/tex]

Next, apply the fractions formula for multiplication. Formula below:

[tex]\dfrac{a}{b} \times \dfrac{c}{d} = \dfrac{a \times c}{b \times d}[/tex]

[tex]= \frac{26 \times -41}{5 \times 2}= \frac{-1066}{10}[/tex]

Simplifying -1066/10, (you can do this by using division) the answer is:  

[tex]106 \frac{3}{5}[/tex]

Answer:

-3 1/3

Step-by-step explanation:

5 2/10 x -10 1/3

10/10 x -10/3

1 x-10/3

-10/3

-3 1/3

your question is unclear. I think I understand it correctly

Answer:

Here is the answer

I hope it xa helping u

Answer:

0.99%

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

There will be five equal part because Iyene takes 2 parts and nokob takes 3 parts

Thus, the total parts which have been shared is 2+3=5

Further more, every part is

[tex] \frac{280}{5} = 56[/tex]

Hence, there is 5 parts have been shared and every part is 56 dollars

Answer:

5 equal parts

Because one of the dudes will get 2 and the other one will get 3 parts

3+2 is 5

280/5=56 (1 part)

so iyene will get 56*2=112 and nokob will get 56*3=168

Answer:

Last one

Step-by-step explanation:

The function f is:

● f (x)= √(4x+6)

The function g is:

● g(x) = √(4x-6)

Add them together:

● f+g (x)= √(4x+6 )+ √(4x-6)

Answer:

[tex]\large \boxed{{\sqrt{4x+6} + \sqrt{4x-6} }}[/tex]

Step-by-step explanation:

[tex]f(x)=\sqrt{4x+6}[/tex]

[tex]g(x)=\sqrt{4x-6}[/tex]

[tex](f+g)(x)[/tex]

[tex]f(x)+g(x)[/tex]

Add both functions.

[tex](\sqrt{4x+6} )+ (\sqrt{4x-6} )[/tex]

Answer:

a. 4

Step-by-step explanation:

-1(-4) = 4

Answer:

A 4

Step-by-step explanation:

opposite of –4 = 4

Answer:

what three options bro where are the options

Answer:

9 hours, 11 hours, 19 hours.

Answer: Find answer in the attachment

Step-by-step explanation:

Answer:

75

Step-by-step explanation:

4:3

4x25=100

3x25=75

Answer:

[tex]1)\ \ 4h^2-13h+6\\2)\ \ 7x^3y^2-x^2y+1\\3)\ \ -7n+2\\4)\ \ -8m+4[/tex]

Step-by-step explanation:

1.

Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.

[tex]2h^2-7h+2h^2-h+6+4h-9h[/tex]

[tex](2h^2+2h^2)+(-7h-h+4h-9h)+(6)[/tex]

[tex]4h^2-13h+6[/tex]

2.

Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.

[tex]8x^3y^2-7x^2y+8x-4-x^3y^2+2x^2y+4x^2y-8x+5[/tex]

[tex](8x^3y^2-x^3y^2)+(-7x^2y+2x^2y+4x^2y)+(8x-8x)+(-4+5)[/tex]

[tex]7x^3y^2-x^2y+1[/tex]

3.

Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following ([tex]a(b+c)=(a)(b)+(a)(c)=ab+ac[/tex]). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,

[tex]-2(8n+1)-(5-9n)+3^2[/tex]

[tex]-2(8n+1)-(5-9n)+(3*3)[/tex]

[tex]-2(8n+1)-(5-9n)+9[/tex]

[tex](-2)(8n)+(-2)(1)+(-)(5)+(-)(-9n)+9[/tex]

[tex]-16n-2-5+9n+9[/tex]

[tex](-16n+9n)+(-2-5+9)[/tex]

[tex]-7n+2[/tex]

4.

The same method used to solve problem (3) can be applied to this problem.

[tex]\frac{1}{2}(10-8m+6m^2)-(3m^2+4m-7)-2^3[/tex]

[tex]\frac{1}{2}(10-8m+6m^2)-(3m^2+4m-7)-(2)(2)(2)[/tex]

[tex](\frac{1}{2})(10)+(\frac{1}{2})(-8m)+(\frac{1}{2})(6m^2})+(-)(3m^2)+(-1)(4m)+(-1)(-7)-8[/tex]

[tex]5-4m+3m^2-3m^2-4m+7-8[/tex]

[tex](-3m^2-3m^2)+(-4m-4m)+(5+7-8)[/tex]

[tex]-8m+4[/tex]

Answer:

45

Step-by-step explanation:

2 digit number starts from 10 ends at 99

between 10 and 19 there is only one number whose tens digit is more than ones digit.

that is 10

between 20 and 29 there are two numbers

20 and 21

like the same

between 30 and 39 there are 3 numbers

10–19. 1

20–29. 2

30–39. 3

40–49. 4

50–59. 5

60–69. 6

70–79. 7

80–89. 8

99–99. 9

sum of first n natural numbers is n(n+1)/2

9(9+1)/2=45

Three numbers between 10 and 99 have tens places that are precisely three times larger than their one's places.

The foundation of our whole number system is place value. In this approach, the value of a digit in a number is determined by where it appears in the number.

The tens digit must be three times larger than the units digit in order to meet the requirement. The units digit can have one of the following values: 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9.

Since we are seeking two-digit integers, it is not possible if the unit digit is zero for the tens digit also be zero.

In the case when the unit digit is 1, the tens digit must be 3, resulting in the number 31. Similar to the previous example, if the unit digit is 2, the tens digit must be 6, resulting in the number 62.

As we proceed, we discover the following integers meet the condition:

31, 62, 93

Therefore, there are three numbers from 10 to 99 that have a tens place exactly 3 times greater than their one's place.

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Answer:

Step-by-step explanation:

Hello,

[tex]f(g(x))=\dfrac{8}{x^2}+4[/tex]

So if we take

[tex]f(x)=\dfrac{8}{x}+4 \ \ and \\\\g(x)=x^2\\ \\f(g(x))=\dfrac{8}{g(x)}+4=\dfrac{8}{x^2}+4[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

No solution

Step-by-step explanation:

Given equation is,

[tex]\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}-\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}=0[/tex]

[tex]\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}=\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}[/tex]

[tex]\frac{(x+1)}{\sqrt{x}(1-x)}+\frac{(\sqrt{x}-1)}{\sqrt{x}(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}[/tex]

[tex]\frac{(\sqrt{x}+1)(x+1)+(\sqrt{x}-1)(1-x)}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}[/tex]

[tex]\frac{x\sqrt{x}+x+\sqrt{x}+1+\sqrt{x}-1-x\sqrt{x}+x}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}[/tex]

[tex]\frac{2x+2\sqrt{x}}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}[/tex]

[tex]\frac{2(\sqrt{x}+1)}{(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}[/tex]

[tex]\frac{2}{1-x}=(\frac{4+x}{1-x})^\frac{1}{2}[/tex]  if x ≠ ±1

[tex](\frac{2}{1-x})^2=\frac{4+x}{1-x}[/tex]  [Squaring on both the sides of the equation]

[tex]\frac{4}{(1-x)}=(4+x)[/tex]

4 = (1 - x)(4 + x)

4 = 4 - 4x + x - x²

0 = -3x - x²

x² + 3x = 0

x(x + 3) = 0

x = 0, -3

But both the solutions x = 0 and x = -3 are extraneous solutions, given equation has no solution.

Answer:

Could you please help me Genius??????