The magnitude of Mars' gravitational field is 3.66 N/kg.
The approximate acceleration due to gravity experienced by the spacecraft is 3.66 m/s².
What is the gravitational fields?
The gravitational fields of the Mars is calculated by applying the following equation;
E = F/m = GM/r²
where;
G is universal gravitation constantM is the mass of Marsr is the radius of Mars F is gravitational forceE = (6.626 x 10⁻¹¹ x 6.39 x 10²³) / (3.4 x 10⁶)²
E = 3.66 N/kg
The approximate acceleration due to gravity experienced by the spacecraft is calculated as follows;
F = mg = GmM/r²
g = GM/r²
where;
G is universal gravitation constantM is the mass of Marsr is the radius of Mars F is gravitational forceg is acceleration due to gravityg = (6.626 x 10⁻¹¹ x 6.39 x 10²³) / (3.4 x 10⁶)²
g = 3.66 m/s²
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Which of acceleration, age, speed, temperature, and velocity are vector quantities?.
Speed, temperature, and age are not vector numbers, whereas velocity and acceleration are vector quantities.
Define vector quantity.Vector is quantity has both magnitude and direction. It is represented by an arrow whose length is proportional to the quantity's magnitude and whose direction is the same as the quantity.
While a vector lacks position, it does have magnitude and direction. Since they have a magnitude and a direction, velocity and acceleration are both vector quantities.
An object is accelerating if its speed doesn't change but its direction does. It's critical to keep in mind that acceleration and velocity don't necessarily follow the same path.
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What are the primary forces that act upon a baseball and a bat during their collision with each other
A. The force of ball on bat and the force of gravity ball
B. The force of gravity on the bat and the force of friction on the ball
C. The normal force of the ball and the force of friction on the bat
D. The force of ball on bat and the force of the bat on ball
The correct answer is D. (The force of ball on bat and the force of the bat on ball.
Baseball is a game that we need to hit the ball using bat as hard as we can to make the ball fly as far as we can when other player will throw the ball as fast as possible to make it hard to hit.
The ball that pitcher throw has a velocity and acceleration. a ball with velocity will have some Force according to Newton's second Law. On the other side, batter will hit the ball using force from his swing. When the ball and the bat make contact, each force will negate each other. So, in order to make the ball fly high the batter need to give higher force than the force that the ball has.
Newton's Second Law tell us about that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the object’s mass.
From that statement we can conclude that the force of an object will get bigger when they move faster
what is the speed of the 0.100 kg sphere when it has moved 0.400 m to the right from its initial position?
6.01 × 10⁻⁵ m/s is speed of 0.100 kg sphere when it has moved 0.400 m to right from its initial position.
What is conservation of energy?The conservation of energy principle states that in a closed system, the energy of interacting objects or particles remains constant. Kinetic energy, sometimes known as the energy of motion, was the first type of energy to be identified. The sum of the kinetic energy of the particles before collision and the sum of the kinetic energy of the particles after collision are equal in some particle collisions, known as elastic collisions. Progressively, more types of energy were added to the definition of energy.
We have from the conservation of energy,
[tex]E_{i}[/tex] = [tex]E_{f}[/tex]
[tex]E_{i}[/tex] = [tex]\frac{-G(5*0.1)}{0.4}[/tex] - [tex]\frac{G(10*0.1)}{0.6}[/tex]
[tex]E_{i}[/tex] = [tex]\frac{-G(5*0.1)}{0.8}[/tex] - [tex]\frac{G(10*0.1)}{0.2}[/tex] + 1/2 × 0.1v²
∵ [tex]E_{i}[/tex] = [tex]E_{f}[/tex]
= 1/2 × 0.1 × v² = G (5×0.1) (1/0.8 - 1/0.4) + G (10 × 0.1) (1/0.2 - 1/0.6)
∴ v = 6.01 × 10⁻⁵ m/s
Speed of the object moved from its initial position is 6.01 × 10⁻⁵ m/s.
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Gravity obeys an inverse square relation. This statement implies that the force due to gravity betweentwo massesa.will increase as the distance between the two masses increases.*b.will decrease as the square of the distance between the two masses increases.c.will cause the two masses to move away from each other.d.will cause the two masses to move in a straight line.e.will cause the two masses to orbit each other.
The inverse square relation implies that force resulting from gravity between two masses will decrease as the square of the distance between the two masses increases.
The force of gravity between any two objects is given by,
F = GM₁M₂/R²
Where,
M₁ and M₂ are the masses of the bodies.
R is the distance between them.
We know, if the masses are constant. then the force of gravity will be inversely proportional to the square of the distance between them.
This is what inverse square relation means here.
As the force of gravity and the square of the distance are inversely proportional to each other,
So, when the square of the distance between the masses increases, the force of gravity between the decreases.
Hence of all the options provided, b is the correc0,t which says, the force will decrease on increasing the inverse square of the distance.
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starting from rest, a disk rotates about its central axis with constant angular acceleration. in 5.0 s, it rotates 25 rad. during that time, what are the magnitudes of (a) the angular acceleration and (b) the average angular velocity?
a) The angular acceleration of a disk is 2.0 rad/s².
b) The average angular velocity of the disk is 5 rad/s.
What is angular acceleration?The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement is radians per second per second.
Rotational acceleration is another name for angular acceleration. It is a numerical representation of the variation in angular velocity over time.
A pseudoscalar, angular acceleration, exists. If the angular speed rises counterclockwise, the sign of angular acceleration is taken to be positive; if it grows clockwise, it is taken to be negative. Angular acceleration is used to study the motion of rotating objects like the wheel, fan, and earth.
Assume that the sense of rotation is positive.
This means that w, α, and other quantities will then be positive also.
a) we know,
25 rad = 1/2 α 5²
α = 2.0 rad/s²
∴ the angular acceleration of a disk is 2.0 rad/s².
b) w avg = Δθ/Δt
w avg = 25rad/5s
w avg = 5rad/s
∴ the average angular velocity of the disk is 5 rad/s.
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if the moon is setting at 6 a.m., the phase of the moon must be if the moon is setting at 6 a.m., the phase of the moon must be waning crescent. first quarter. third quarter. new. full.
Considering that sunrise will be visible at 6 A.m, the moon will be in the full moon phase at that time.
Explain about the Full moon?The line formed by the sun, Earth, and moon occurs when the moon has shifted 180 degrees from its new moon position. It is called a full moon when the moon's disc is as close to being completely illuminated by the sun as it can possibly be.
Waning Crescent is the phase of the Moon for today and tonight. The ideal time to watch this phase is immediately before sunrise in the western sky.
A full moon may also cause a reduction in deep sleep and a postponement of the onset of REM sleep, according to some research. Furthermore, several investigations have revealed a minor alteration in cardiovascular conditions during a full moon. Researchers are still looking at how the moon affects many physiological and psychological processes.
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A basketball hoop is 3.05 m above the playing surface. A basket is made. The ball reached a maximum height that was 2.00 m above the height of the basket hoop. The basketball was launched from a height of 1.95 m. If the ball traveled a horizontal distance of 5.20 m in 2.00 seconds, what was the initial velocity of the basketball?
Answer:
In this question, we have given a basketball hoop that is 3.05 m above the playing surface and the basket is made. The basketball was launched from a height of 1.95 And if the ball travels the original distance of 5.2 m in two seconds, then we have to find the initial velocity of the basketball. So we can find given data is we have given the horizontal distance traveled, that is d is equals to 5.2 m Per meter. And we have given the time taken to cover this distance, that is T equals to two seconds. So we can find the original velocity. So we can see that horizontal velocity that is three X is equal to, this is 5.2 upon two, and this will come out to be 2.6 meter per second. Now we can see that as we have given That the basketball hoop is 3.05 m above the playing surface. So we can say that the height covered, that is delta edges 3.5 minus 1.95. And this will comes out to be 1.10 m. So, using the equation of motion, we can find the vertical velocity Y. So we can say that that is is, we can apply in and wind direction. So we can say that delta edge is equals to this is initial velocity in y direction into time, T plus half into exhalation in y direction into T square. So we can say this is equals to 1.10, that is we're not y and to time is two seconds blood half into disease. Here, exploration is the gravitational acceleration and it is acting downwards. So this is equal to -3, which is -9.8 into two square. So from here we can find the value of velocity in the Y direction. That is 10.35 m/s. So we have the velocity in X direction and velocity in the Y direction. So we can see that the initial velocity that is we note is equal to this under root of we're not in extraction plus we're not wise square. So we can say this is equal to under root of 2.60 sq Plus 10.35 ft sq. And this will comes out to be 10.67 m/s. But this is the answer of arguing cushion. Thank you.
general questions: in order to lift a bucket of concrete, you must pull up harder on the bucket than the bucket pulls down on you.
In order to lift a bucket of concrete, you must pull up harder on the bucket than the bucket pulls down on you this statement is true.
What is meant by newtons law?According to Newton's first law, unless pushed to alter its condition by the operation of an external force, every object will continue to be at rest or in uniform motion in a straight line. Inertia is the propensity to resist changes in a condition of motion.
The motion of an item is related to the forces operating on it by Newton's equations of motion. According to the first law, until a force acts on an item, it will not alter its motion. According to the second law, an object's force is determined by multiplying its mass by its acceleration.
Newton's first law states that unless a net external force acts on an object, it will either remain at rest or continue moving at a constant speed.
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the top of a ladder slides down a vertical wall at a rate of 0.15 mys. at the moment when the bottom of the ladder is 3 m from the wall, it slides away from the wall at a rate of 0.2 mys. how long is the ladder?
The length of the ladder which is placed 3 meters from the wall is 5 meters
The rate of the change of ladder decreasing in vertical wall = - 0.15 m/s
The distance between the bottom of the ladder and the wall = 3 meter
The rate of change of the bottom of the ladder away from the wall = 0.2 m/s.
The length of the ladder can be found using the Pythagoras theorem,
x² + y² = L²
where x is the distance between the bottom of the ladder and the wall
y is the distance from the top of the ladder to the bottom of the wall.
L is the length of the ladder
Let us differentiate in terms of the rate of change in the above equation,
2x dx/dt + 2y dy/dt = 0
Now let us substitute the known values,
2(3)(0.2) + 2y(-0.15) = 0
1.2 - 0.3y = 0
0.3y = 1.2
y = 1.2 / 0.3
= 4
Then, the length of the ladder is
3² + 4² = L²
9 + 16 = L²
L = √25
L = 5
Therefore, the length of the ladder is 5 meters
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Dr. Amari is investigating whether automobile accidents in her city increase, decrease, or stay the same 24 hours after daylight savings (this is when the time changes to one hour earlier). She looks up public records at the police station and documents any accidents and notes the dates and times.
Dr. Amari discovers a trend. She finds that accidents do seem to increase right after clocks are reset to an hour earlier.
Which one of the following research techniques is Dr. Amari using?
A. naturalistic observational research
B. archival research
C. experimental research
D. survey research
Since Dr. Amari finds that accidents do seem to increase right after clocks are reset to an hour earlier. The research techniques that Dr. Amari using is B. archival research.
What is archival research?Archival research is any investigation that looks for, locates, and extracts data and proof from original archives. Archives are documents, records, and other sources pertaining to the actions and claims of people, groups, or both that are historical and not current.
Note that The term "data collection techniques" refers to procedures for gathering and analyzing various types of data. Examining papers pertaining to a topic, as well as conducting interviews and observations, are common methods of gathering data.
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What is the potential energy of a 25 kg bicycle resting at the top of a hill 3 m high? (Formula: PE = mgh)
The potential energy of a 25 kg bicycle resting at the top of a hill 3 m high will be 735 J
potential energy = m*g*h
where
m = mass
g = acceleration due to gravity
h = height
potential energy = 25 * 9.8 * 3 = 735 J
The potential energy of a 25 kg bicycle resting at the top of a hill 3 m high will be 735 J
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a car speeds up from 22 m/s to 26 m/s in 2 seconds. what is the average acceleration of the car
Answer:
2 m/s^2
Explanation:
Acceleration is change in velocity over change in time
(26-22) m/s / 2 s = 2 m/s^2
I need help with question 1
Answer:
V = 140 km/h
Explanation:
Velocity is the change in position over time.
We can use the equation V = Δx / t
Note that V is the average velocity.
We are given Δx and t. Lets solve for V.
[tex]V=\frac{540}{4}[/tex]
[tex]V=140[/tex]
[tex]\frac{km}{hour}[/tex]
V = 140 km/h
when you measure gravity at any location on this equipotential surface you would get the same result?
There are an infinite number of points where the gravitational potential is always the same. They are called equipotential surfaces. Of course, mean sea level itself is not an equipotential surface.
Forces other than gravity, such as temperature, salinity, ocean currents, and wind, are at work. The size of the gradient vector field (which describes the steepness of the gradient) is not the same for all points on the contour. Therefore, the strength of gravity varies along the geoid, and the geoid is not, as one blogger put it, "the same shape of gravity wherever you stand."
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3.-A 10 newton forces gives a mass m1 an acceleration a. A 20 newton force gives another mass m2 the same acceleration a. What is the ratio of m1 to m2?
Answer:
1/2
Explanation:
We know that F = ma, so F1 = m1.a1 and F2 = m2.a2.
F1 = 10
F2 = 20
To simplify things consider a1 = a2 = 1
To find m1 divide by a to both sides; m1 = F/a = 10/1 = 10.
To find m2 divide by a to both sides; 21 = F/a = 20/1 = 20.
Ratio of m1 to m2 = 10/20 = 1/2
when astronomers have examined rich clusters of galaxies with their instruments, they have found that these clusters
Astronomers have examined rich clusters of galaxies with their instruments, They have found that these clusters have giant elliptical galaxies than poor clusters
what are giant elliptical galaxies?Elliptical galaxies are the most abundant type of galaxies found in the universe but because of their age and dim qualities, they're frequently outshone by younger, brighter collections of stars.
Elliptical galaxies lack the swirling arms of their more well-known siblings, spiral galaxies. Instead, they bear the rounded shape of an ellipse, a stretched-out circle.
One of the most famous elliptical galaxies is Cygnus A, which is located roughly 600 million light-years from Earth and is an extremely bright radio source. Cygnus A is not only well-known to astronomers, but has a place in science fiction; it was featured in the 1985 novel "Contact," a Carl Sagan story that later inspired a Hollywood movie of the same name.
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kinetic energy problem an 82-kg stunt man falls off the top of a large building. after falling for 65 meters he has a speed of 22 m/s. assuming he was initially at rest, what was the average force of air resistance exerted on the stunt man during his fall?
The average force of air resistance exerted on the stunt man during his fall is 305.29 N
How do I determine the average force?We'll beging by obtaining the kinetic energy of the stunt man. This can be obtained as follow:
Mass (m) = 82 KgVelocity (v) = 22 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 82 × 22²
KE = 41 × 484
KE = 19844 J
Finally, we shall determine the average force of air resistance exerted on the stunt. This can be obtained as follow:
Distance = 65 metersEnergy = 19844 JAverage force =?Energy = work
Work (W) = force (F) × distance (d)
W = Fd
Thus,
E = W = Fd
19844 = F × 65
Divide both sides 65
F = 19844 / 65
F = 305.29 N
Thus, from the above calculation, we can conclude that the average force is 305.29 N
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a pitcher throws a baseball with a mass of 5.13 oz (0.145 kg) at a velocity of 95.0 mph (42.5 m/s). using the correct si units, calculate the kinetic energy of the baseball
The kinetic energy of the baseball thrown by the pitcher is 103.8 Joules.
Th kinetic energy of any moving body is given by,
K = 1/2mv²
Where,
K is the kinetic energy,
m is the mass of the body,
v is the speed of the body.
Here, the mass of the baseball is given to be 0.145 kg and the speed of the baseball is given to be 42.5 m/s.
Putting all the values accordingly,
K = 1/2(0.145)(42.5)²
K = 1/2 x 0.145 x 1806.25
K = 103.8 Joules.
So, the kinetic energy of the baseball is 103.8 Joules.
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in an emergency stop to avoid an accident, a shoulder strap seat belt holds a 60 kg passenger firmly in place. if the car were initially traveling at 90 km/h and came to a stop in 5.5 s along a straight, level road, what was the average force applied to the passenger by the seat belt?
Answer:
272.727N
Explanation:
Force is equal to the product of mass and acceleration. We know the mass of the person (60kg), so we just need to find how much they are decelerating when coming to a stop.
We do this using the motion equation v=u+at, where v is the final velocity, u is initial velocity, a is acceleration, and t is time. Noting 90km/hr=25m/s, we get:
0=25+5.5a
a=-4.5454545m/s^2
Force = mass * acceleration = 60 * 4.545 = 272.727N
a hot air balloon is rising vertically with a velocity of 10.0 feet per second. a very small ball is released from the hot air balloon at the instant when it is 1280 feet above the ground. use a(t)
the final velocity of the hot air balloon before touching the ground is 286.16 ft/s.
the final velocity can be calculated as follows:
initial velocity of the sphere, u = 10 ft/s
Acceleration due to gravity, g = 32 ft/s²
Ground clearance, h = 1280 feet
The time it takes for the ball to hit the ground is calculated as:
[tex]h= ut +\frac{1}{2}gt^2\\ 1280= 10t + (0.5X 32 )t^2\\1280 = 10t +16t^2\\16t^2+ 10t-960 = 0[/tex]
then we can solve the quadratic equation using formula method
[tex]t=\frac{ -b+/- \sqrt{b^2-4ac} }{2a} \\t = \frac{ -10+/- \sqrt{10^2-4(16X1280)} }{2(16)}\\t= 8.63[/tex]
The final velocity of a hot air balloon is calculated as:
v = u + gt
v = 10 + (8.63 × 32)
v = 286.16 ft/sec
therefore, the final velocity of the hot air balloon before touching the ground is 286.16 ft/s.
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if you swing a bucket of water fast enough in a vertical circle, at the highest point the water does not spill out because an outward force balances the pull of gravity on the water. if you swing a bucket of water fast enough in a vertical circle, at the highest point the water does not spill out because an outward force balances the pull of gravity on the water. true false
We must understand both inertia and gravity to find a solution.
What is inertia?
The matter has an attribute called inertia that makes it resist changes in velocity (speed and direction). Newton's first law of motion states that an object moving at a certain speed will stay there unless an outside force acts upon it.
What is gravity?
A planet or other body's gravitational field pulls objects toward its center. The force of gravity is what keeps every planet in its orbit around the sun.
A vertical circle spun while holding a bucket full of water prevents the water from spilling out due to inertia.
Keep the bucket in place as the water tries to fly off.
Therefore we can conclude that it is false.
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a gyroscope flywheel of radius 2.83 cm is accelerated from rest at 14.2 rad/s2 until its angular speed is 2760 rev/min. (a) what is the tangential acceleration of a point on the rim of the flywheel during this spin-up process? (b) what is the radial acceleration of this point when the flywheel is spinning at full speed? (c) through what distance does a point on the rim move during the spin-up?
The tangential acceleration of the gyroscope flywheel is 40.186 x [tex]10^{-2[/tex] m/[tex]s^2[/tex], Radial acceleration of gyroscope flywheel is 2364.08 [tex]m/s^2[/tex] and During the spin up process the distance moved by a point on rim is 83.24 m.
What is meant by tangential acceleration?The centripetal force causes an acceleration known as radial acceleration, which is measured in radians per square second. Radial acceleration is directed toward the center.Tangential acceleration occurs when a body or object moves at a speed that is not uniform.a gyroscope flywheel of radius, R = 2.83 cm =2.83 x [tex]10^{-2}[/tex] m
[tex]\omega_0 = 0[/tex]
[tex]\omega = 2760 X \frac{2\pi}{60} rad/sec[/tex]
[tex]\alpha = 14.2 rad/ sec^2[/tex]
The tangential acceleration :
[tex]a_t = R\alpha[/tex] =2.83 x [tex]10^{-2}[/tex] m x 14.2 [tex]rad/s^2[/tex] =40.186 x [tex]10^{-2[/tex] m/[tex]s^2[/tex]
The radial Acceleration :
[tex]a_r = R\omega^2\\=(2.83 X 10^-2) (2760 X \frac{\pi}{30} )^2[/tex] =2364.08 [tex]m/s^2[/tex]
During the spin up process the distance moved by a point on rim
d = [tex]R\theta[/tex]
where [tex]\theta =\frac{ \omega^2 - \omega_0^{2}}{2\alpha}[/tex]
= [tex]\frac{(2760 X \pi/30)^2}{2 X 14.2}[/tex] =2941.42 rad
d = 2.83 x [tex]10^{-2}[/tex] x 2941.42 =83.24.m
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The temperature, pressure, and precipitation conditions of the atmosphere for a specific place on a given day is called , whereas a longer term view of these same factors, typically taken over a period of many years, is called.
The temperature, pressure and precipitation condition of the atmosphere for a specific place on a given day is called weather, whereas are long term view of the same factors, typically taken over a period of many years, is called climate.
The basic difference between climate and weather is that climate exist for a very long period of time while weather can change in just a few hours.
Weather is just a way to way information about the temperature, pressure and precipitation condition of a atmosphere on a day today basis.
While climate is a kind weather information which provides information about the weather of a reason for a long period of time.
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radio waves travel at the speed of light, 300,000 km/s. the wavelength of a radio wave received at 100 megahertz is group of answer choices 3.0 m. 300 m. none of these
At 300,000 km/s, radio waves move at the speed of light. At 100 megahertz, a radio wave has a wavelength of 3.0 m.
How do you pronounce wavelength?The space between two successive troughs or peaks of the light wave is referred to as the wavelength of light. The Greek letter lambda (), which stands for it. Consequently, the wavelength is the separation between one wave's crest or trough and the following wave.
Does speed imply wavelength?An electromagnetic wave's wavelength has no bearing on how quickly it moves. There is no difference in the speed of Wave C versus Wave D. Changes in the characteristics of the medium a wave travels through are the only things that can change its speed.
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a hoop with a radius r and a mas m has a momentum of inertia i. what would be the moment of inertia of a second hoop with the same radius but twice the mass?
The momentum of inertia of second hoop will be twice of first hoop
The moment of inertia of a hoop will be = m[tex]r^{2}[/tex]
first hoop:
radius = r1
mass = m1
inertia = I1 = m1[tex]r1^{2}[/tex]
second hoop
radius = r2 = r1
mass = m2 = 2m1
inertia = I2 = m2 * [tex]r2^{2}[/tex]
= 2m1 [tex]r1^{2}[/tex] = 2 I1
The momentum of inertia of second hoop will be twice of first hoop
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with the time base set to 500 ns/div, four cycles of a waveform occupies10 divisions. what is the period and the frequency of the waveform
The period of this waveform is 2 milliseconds and its frequency is 2 kilohertz.
The period of a waveform is the time it takes for one complete cycle. The frequency of a waveform is the number of times that cycle repeats per second.
The time base is set to 500 ns/div, which means that each division represents 500 nanoseconds. Four cycles of a waveform occupies 10 divisions, so we can calculate the frequency as follows:
1) 4 cycles = 4x500ns
= 2ms
2) 2ms = 2 x 1/2 ms
3) 1/2 ms = 1/2 x 1 ms
4) 1ms = 1000us
5) 1000us / 500 ns / div = 2000 Hz
In conclusion, the period of this waveform is 2 milliseconds and its frequency is 2 kilohertz.
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suppose the state machine shown below is in state c and receives the string 100010. what is its ending state?
B is its ending state for the state machine shown below is in state c and receives the string 100010.
A state machine is difficult to explain.A state machine reads a set of inputs and switches states in response to those inputs. A system is said to be in a state when it is waiting to make a transition. A transition is a sequence of steps to carry out when a condition is met or an event is received.
State machines are a type of programming architecture that enable dynamic flow between states based on values from earlier states or user inputs. Applications that can be categorized as a combination of the following fit well with this architecture: States. When to relocate to a specific state, using decision-making logic.
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A ball rolls down a ramp for 5 seconds. If the ball started with no speed and ended with a speed of 15 m/s, what was the acceleration of the ball?
Answer:
3 m/s^2
Explanation:
Acceleration = change in speed / change i time
= 15 m/s / 5 s = 3 m/s^2
how far from the lens should you hold the print to see a final virtual image 30 cm from the lens (at the eye's near point)?
m= near point/ s.
s=4.28 cm ( the distance of the contract from the magnifying glasses)
Near point = 30cm
so m= 30/4.28= 7
Thus, far from the lens should you hold the print to see a final virtual image 30 cm from the lens (at the eye's near point) is 7
how much energy must be transferred into 2kg of iron to raise its temperature by 5C?
Answer:
Explanation:
Around 500 volt energy