As soon as a candle is lit, the air just above the flame begins to warm up. As a result, the air becomes hotter and rises. This is caused by the convectional process of heat transfer, and the hot air stream is referred to as a convection current.
The air is heated by the candle, and the heat rises to the hand. The hand eventually pulls away from the candle because it becomes too hot.The heated air that rises toward the ceiling in your home is an excellent illustration of a convection current. Convection currents are prevalent in the air. The process takes place because warmer air is thought to be less dense than colder air. Wind is another excellent illustration of convection circulation.When a candle burns, the oxygen in the air and the hydrogen and carbon from the wax mix to form carbon dioxide and water vapor. These two gases make up the majority of the material in the candle.To know more about convection
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4. In a physics lab, Kate and Rob use a hanging mass and pulley system to exert a 2.45 N
rightward force on a 0.500-kg cart to accelerate it across a low-friction track. If the total
resistance force to the motion of the cart is 0.72 N, then what is the cart's acceleration?
Fgrav = 4.90 N; Fnorm = 4.90 N; Fnet = 1.73 N, then the acceleration of the cart is (a) = 3.46 m/s/s,
What is acceleration and its types?Acceleration is defined as a vector quantity, the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity. It can be either positive, negative, or zero depending upon the velocity and its direction. Three types of acceleration are Uniform acceleration, non-uniform acceleration, and average acceleration.
Formula
{a} = v - v0/t =Δv/Δ t
{a} = average acceleration
v = final velocity
v_0 = starting velocity
t = elapsed time
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If it takes more force for an object with more mass to accelerate because it has more inertia and objects with less mass have more acceleration (because a∝1/m in Newton's Second Law F=ma), then why do objects with more mass and objects with less mass accelerate at the same rate towards Earth (about 9.8m/s^2)?
Explanation:
Gravity is the only force acting on an object in free-fall. According to Newton's second law, the force is equal to mg, so the mass is taken into account there.
2) Calculate the Energy of each of the following
a) Radio waves with a wavelength of 3.0 x 10¹¹ nm (6.626 x 10-28 J)
b) Microwaves with a wavelength of 3.0 x 107 nm (6.626 x 10-24 J)
c) X-Ray at 1nm (1.99 x 10-¹6J)
d) Violet at 400nm (4.97 x 10-¹⁹ J)
e) Red at 700nm (2.84 x 10-¹⁹J)
f) Gamma rays at 1nm (1.98 x 10-¹6J)
The energy, E of the given waves are as follows:
a. Energy, E = 6.63 * 10⁻²⁸ J
b. Energy, E = 6.63 * 10⁻²⁴ J
c. Energy, E = 1.99 * 10⁻¹⁶ J
d. Energy, E = 4.97 * 10⁻¹⁹ J
e. Energy, E = 2.84 * 10⁻¹⁹J
f. Energy, E = 1.99 * 10⁻¹⁶ J
What is the formula to calculate the energy of a wave?The formula to calculate the energy of a wave s given below as follows:
Energy, E = hc / λwhere;
h is Planck's constant = 6.63 * 10⁻³⁴ Js
c is the velocity of light = 3.0 * 10⁸ m/s
λ is the wavelength of the light
The energies of the waves are calculated as follows:
a. λ = 3.0 x 10¹¹ nm or 3.0 * 10² m
E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 3.0 * 10²
E = 6.63 * 10⁻²⁸ J
b. λ = 3.0 x 10⁷ nm or 3.0 x 10⁻² m
E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 3.0 * 10⁻²
E = 6.63 * 10⁻²⁴ J
c. λ = 1 nm or 1.0 x 10⁻⁹ m
E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 1.0 x 10⁻⁹ m
E = 1.99 * 10⁻¹⁶ J
d. λ = 400 nm or 4.0 x 10⁻⁷ m
E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 4.0 x 10⁻⁷ m
E = 4.97 * 10⁻¹⁹ J
e. λ = 700 nm or 7.0 x 10⁻⁷ m
E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 7.0 x 10⁻⁷ m
E = 2.84 * 10⁻¹⁹J
f. λ = 1 nm or 1.0 x 10⁻⁹ m
E = 6.63 * 10⁻³⁴ * 3.0 * 10⁸ / 1.0 x 10⁻⁹ m
E = 1.99 * 10⁻¹⁶ J
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Two objects have a gravitational force of attraction to each other, equal to 10 Newtons. What is their gravitational force if the distance between them is halved?
I have the answer, however I do not know how to get to it. Please explain.
The gravitational force when the distance between them is halved is 40 N
How to determine the gravitational force?Newton's law of universal gravity states as follow:
F = GM₁M₂ / r²
Where
F is the force of attraction K is the electrical constant M₁ and M₂ are the masses of the objects r is the distance apartFinding a relationship between force and distance, the following were obtained:
F = GM₁M₂ / r²
Cross multiply
Fr² = GM₁M₂
GM₁M₂ = constant
F₁r₁² = F₂r₂²
Now, we can obtain the new gravitational force of as illustrated below:
Initial gravitational force (F₁) = 10Initial distance (r₁) = rNew distance (r₂) = 1/2r = 0.5rNew gravitational force (F₂) =?F₁r₁² = F₂r₂²
10 × r² = F₂ × (0.5r)²
10r² = F₂ × 0.25r²
Divide both side by 0.25r²
F₂ = 10r² / 0.25r²
F₂ = 10 / 0.25
F₂ = 40 N
Thus, the gravitaional force is 40 N
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A 5 -kg ball hangs at one end of a string that is attached to a support on a railroad boxcar. When the boxcar
accelerates to the right, the string makes an angle of 30° with the vertical. The acceleration of gravity is 9.8 m/s
and air resistance is negligible. Find the acceleration of the boxcar
The acceleration of the boxcar is 5.586m/s².
Explain what an acceleration is.We refer to any process where the velocity changes as acceleration. You can only accelerate by changing your speed, direction, or both since velocity is a function of both speed and direction.
Positive acceleration is a property of objects that are accelerating and moving in the right direction. In the first illustration, positive acceleration was demonstrated by the moving car. The acceleration is occurring in the same direction that the vehicle is moving forward and accelerating.
θ = ma/mg
tanθ = a/g
a = tanθ g
a = tan 30×9.8
a = 0.57×9.8
a = 5.586m/s².
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How much energy must a stove transfer to completely heat 1g of liquid water from 1o C to 25o C?
The energy needed by a stove to transfer heat completely to 1 g of liquid water fro 1 °C to 25 °C is 100.37 J.
What is energy?Energy is the ability or the capacity to do work.
To calculate the amount of energy, we use the formula below.
Formula:
Q = cm(t₂-t₁).............. Equation 1Where:
Q = Amount of energyc = Specific heat capacity of the waterm = mass of the watert₂ = Final temperaturet₁ = Initial temperatureFrom the question,
Given:
m = 1 g = 0.001 kgc = 4182 J/kg°Ct₁ = 1 °Ct₂ = 25 °CSubstitute these values into equation 1
Q = 0.001(4182)(25-1)Q = 100.37 JHence, The energy required is 100.37 J.
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Taking into account the definition of calorimetry, the energy that a stove must transfer to completely heat 1 g of liquid water from 1 °C to 25 °C is 100.416 J.
Definition of calorimetryCalorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.
When heat added or removed from a substance causes a temperature change in it without affecting its molecular structure, it is called sensible heat.
So, the expression that allows to calculate heat exchanges is:
Q = c× m× ΔT
where:
Q is the heat exchanged by a body of mass m.c is the specific heat substance.ΔT is the temperature variation.Energy in this caseIn this case, you know:
Q= ?c= 4.184 J/gCm= 1 gΔT= Tfinal - Tinitial= 25 C - 1 C= 24 CReplacing in the definition of calorimetry:
Q = 4.184 J/gC× 1 g× 24 C
Solving:
Q= 100.416 J
Finally, the energy needed is 100.416 J.
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Consider a wooden cylinder of density 0.75g/cm³ floating in water with its axis perpendicular to the surface and the height is 15cm. How much of the cylinder will be under water?. If the radius were 10cm, how much would be under water? Suppose the cylinder is completely submerged and anchor in the water by a string, for the cylinder nof 10cm radius, what will be the force on the string?. Where g=9.8m/s, density of water=1g/cm³.
6923 N is the force on the string, Where g=9.8m/s, density of water=1g/cm³.
volume=2πrh
volume= 942 cm³
density= mass/volume
mass=density× volume
mass=0.75g/cm³× 942 cm³
mass=706 kg
F= mg
F=706×9.8
F= 6923 N
Every action that attempts to maintain, modify, or change the motion of a body is referred to as a force in mechanics. In his Principia Mathematica, Isaac Newton frequently used his three laws of motion to demonstrate the concept of force (1687).
According to Newton's first law, a body will remain in either its resting or equally moving condition along a straight route in the absence of an external force. The second law states that when an external force acts on a body, the body accelerates (changing velocity) in the direction of the force.
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what is the work done by a 20 newton force applied at an angle of 45.0° to move a box horizontal distance of 40 meters
The work done by a 20-newton force applied at an angle of 45.0° is 565.69 J.
Calculation:-
Force = 20 N
distance = 40 meters
angle = cos 45°
Work done = F.d cosθ
= 20×40 × 1/√2
= 800 / √2
= 565.69 J
Force is a push or pulls upon an item because of the object's interaction with some other object. pressure is a power that can exchange the motion of an object. A force can reason an object with mass to alternate its speed, i.e., to boost up. pressure also can be described intuitively as a push or a pull. A force has each significance and course, making it a vector amount.
The phrase 'Force' has a unique meaning. At this degree, it is absolutely appropriate to describe a force as a push or a pull. A force is not something that an object consists of or 'has in it. A force is exerted on one object through another. The concept of a force isn't always restricted to living matters or non-living matters.
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If the maximum tension the rope can with- stand before breaking is 132.3 N, what is the maximum tangential speed the ball can have?
Answer in units of m/s.
The Maximum tangential speed the ball can have would be = 5.3m/s.
What is tangential speed?A tangential speed is defined as the speed of an object that has an angular velocity with respect to an instantaneous velocity.
The formula used to calculate the maximum tension;
T = mv²/r
Where T = Maximum tension = 132.3N
M = mass= 4kg
r = radius = 0.86m
V= tangential speed = x
Make v the subject of formula;
V = √Tr/m
V = √ 132.3 × 0.86/4
V = √113.778/4
V= √28.4445
V = 5.3 m/s.
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Complete question:
An athlete swings a 4.00 kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.860 m at an angular speed of 0.660 rev/s. If the maximum tension the rope can withstand before breaking is 132.3 N, what is the maximum tangential speed the ball can have?
The total energy of a system remains___.
Answer:
It remains Stationary
Explanation:
stationary.
In a dentist’s x-ray machine, electrons may be subjected to a net force of 1X10-13 The mass of an electron is about 1X10-30 kg. What is the acceleration of the electrons? How long does it take the electrons to be accelerated from rest across a gap of 10 cm?
The net force on the electron is F = 1X10-13 N.
The mass of the electron is m = 1X10-30 kg.
The distance covered by an electron is S = 10 cm.
The acceleration of an electron can be calculated as:
F = ma
a = F/m
Substitute the values in the above expression.
[tex]a = (\frac{1 * 10^{-13}N }{1* 10^{-30kg} } ) \\[/tex]
a = [tex]1*[/tex][tex]10^{-17} m/s^{2}[/tex]
Thus. the acceleration of the electron is. [tex]a = 1*10^{-17} m/s^{2}[/tex]
The expression of time taken by the electron is given by,
S = ut + [tex]\frac{1}{2} at^{2}[/tex]
Here, u is the electron's initial velocity, whose value is zero because the electron is initially at rest.
Substitute the values in the above expression.
(10cm x 1m/100cm) = 0 x t + 1/2 x (1 x [tex]10^{17}[/tex] m/s²) x t²
(0.1m) x 2 = (1 x [tex]10^{17}[/tex] m/s²)x t²
[tex]t = \sqrt{\frac{0.2m}{(1*10^{17} m/s^{2} )} }[/tex]
t = 1.414 x [tex]10^{-9}[/tex]s
Thus, the time taken by the electrons to be accelerated from rest is t = 1.414 x [tex]10^{-9}[/tex]s
Electrons are accelerated from rest by a potential difference of V volts. The speed of individual electrons in metal wires is typically millions of kilometers per hour. In contrast, drift velocities are typically only a few meters per hour, while signal velocities are 100 million to 1 billion kilometers per hour.
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Part G
List several examples of applied force, normal force, and friction?
Examples of following forces mentioned -
Normal Force :- Book kept on the table , Girl standing on floor, ...infact every object experience a normal force in the universe.Applied Force :- this term literally means force responsible for the movements in the object or changes in the object , like throwing stones , playing ball , pushing an object , moving a pen from desk to chair..etc...Friction force :-Force responsible for the resistance in the flow of system's work , For example air resistance a type of obstruction experienced in air when a Paper ball is thrown from terrace of a society , Viscosity of honey is also an example of liquid friction / viscous drag...Sometimes friction is useful for the stability of universe. But some times its necessary. It is due to this force we walk without collapsing into the core of earth as earth is a market of gravitational field. To substantiate the field effect , friction is necessary to necessitate the life in planet. Rubbing of hands in winter season is also another example.To Know more about different forces -
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what is the conclusion for the physics lesson acceleration and free falling objects grade 9
The simple conclusion I can make from the task given above is that all the objects in the universe possess constant acceleration under the influence of a free fall is actually due to gravity.
How objects free falling objects has the same acceleration under the influence of gravity.It has been practically proven that all objects or bodies; regardless of their masses have the same acceleration as long as they are under a free fall as a result of the Earth's gravitational force.
So therefore, it can now be deduced with understanding that all free falling objects have the same acceleration due to gravity.
Complete question:
What conclusion can you make on acceleration and free falling objects grade?
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explain the impact covid had had on the rate of cardiovascular disease
The inner walls of veins and arteries can be affected by coronavirus infection, which can result in blood vessel inflammation, harm to extremely small vessels, and blood clots leading to the risks of cardiovascular diseases.
How covid had an impact on the rate of cardiovascular diseases?The mechanisms by which the COVID-19 pandemic might change trends in cardiovascular health have been the subject of numerous ideas. People with COVID-19 have a worse prognosis when they have established CVD and atherosclerosis cardiovascular disease risk factors.
Like other viral illnesses, such as some flu strains, the coronavirus may directly infect and harm the heart's muscular tissue. The body's immune system's response could also indirectly harm and inflame the heart.Less oxygen can enter the circulation as the virus induces inflammation plus fluid to clog the air sacs of the lungs. Blood pumping through the body requires more effort from the heart, which can be problematic for those who already have heart disease.Therefore, covid had a great impact on cardiovascular diseases and increased the overall disease rate.
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which of the following are decomposition reactions?
a. CH^4 (g) + 20^2 (g) ->CO^2 (g) + 2H^2O (g)
b. CaCO^3 (s) -> CaO (s) + CO^2 (g)
c. N^2 (g) + 3H^2 (g) -> 2NH^3 (g)
d. 2H^2O (i) -> 2H^2 (g) + O^2 (g)
Check all that apply
The correction options indicating a decomposition reaction are:
B. CaCO₃ -> CaO + CO₂D. 2H₂O -> 2H₂ + O₂What is a decomposition reaction?This a reaction in which a compound breaks down into smaller elements or compound by the application of heat. Example is given below:
AB₂ -> A + B₂
We can see that AB₂ decomposed to produce A and B₂
With the above information in mind, we can easily determine which reaction is decomposition reaction from the given options.
The options from the question are:
A. CH₄ + 2O₂ -> CO₂ + 2H₂OB. CaCO₃ -> CaO + CO₂C. N₂ + 3H₂ -> 2NH₃D. 2H₂O -> 2H₂ + O₂Observing the given options with the knowledge of decomposition reaction, we can conclude that the correct options are:
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A rod slides along a metal frame. The earth’s magnetic field is 3.5 × 10−5 T at right angles to the plane of the frame. The rod is of length 0.23 m inside the frame and moves at 0.68 m/s. What is the motional EMF produced by the rod? Answer in units of V.
The motional EMF produced by the rod is 5.474 × 10⁻⁶ V.
What is electromotive force?When no current is flowing, electromotive force (EMF) equals the terminal potential difference.
Despite the fact that both EMF and terminal potential difference (V) are expressed in volts, they are not the same thing. EMF is the quantity of energy (E) that the battery supplies to each coulomb of charge (Q) that passes through.
Given parameters:
The earth’s magnetic field; B= 3.5 × 10⁻⁵ T
The length of the rod; l = 0.23 m.
Speed of the rod; v = 0.68 m/s.
So, the motional EMF produced by the rod = Blv
= 3.5 × 10⁻⁵ × 0.23 × 0.68
= 5.474 × 10⁻⁶ V.
Hence, motional EMF produced by the rod is 5.474 × 10⁻⁶ V.
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In the remote version of the lab you completed this week’s students both their own ramps. One student made their room from a board game that was lifted 0.215m on one end. The length of the box is 0.400m. Starting from rest, they let a solid wall with a radius of 0.0535 m and a mass of 1.20 kg roll down the ramp without slipping.
Question: When the ball reaches the bottom of the homemade ramp what is its speed? SHOW WORKING OUT
The speed ball when it reaches the bottom of the homemade ramp is 1.68 m/s.
What is the speed of the ball at the bottom of the ramp?The speed of the ball at the bottom of the ramp is determined by applying the principle of conservation of energy as follows;
total kinetic energy = total potential energy
rotational kinetic energy + translational kinetic energy = total potential energy
¹/₂Iω² + ¹/₂mv² = mgh
where;
I is the moment of inertia of the ballv is the speed of the ballω is the angular speed of the ballm is mass of the ball¹/₂I(v/r)² + ¹/₂mv² = mgh
¹/₂Iv²/r² + ¹/₂mv² = mgh
I = ¹/₂mr²
¹/₂(¹/₂mr²)v²/r² + ¹/₂mv² = mgh
¹/₄mv² + ¹/₂mv² = mgh
¹/₄v² + ¹/₂v² = gh
v² + 2v² = 4gh
3v² = 4gh
v² = 4gh/3
v = √(4gh/3)
where;
h is the height g is accelerationv = √(4 x 9.8 x 0.215/3)
v = 1.68 m/s
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In the article the study author recommends going on a photo hunt what was the purpose of this activity with choices becoming less introvered
Becoming less neurotic
Becoming more extroverted
Becoming more assertive
In the article the study author recommends going on a photo hunt and the purpose of this activity is Becoming more assertive.
What is the reason why the author gave the recommedation about going for the photo hunt ?The reason why the author gave the recommedation about going for the photo hunt is that the activity can bring about assertiveness which has not been seen in the participants before.
It should be noted that with the assertion, there will be display of confident as well as forceful personality as they are taking part in the photo hunt, because it involves the activity whereby the participants will be competing with themselves in the collection of the greatest number of objects which is been goteen from the predetermined list.
In conclsion, the recomedation about going to the photo hunts by te author was made so that they can become more assertive.
Therefore , the last option is correct.
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Metals are great conductors because
the electrons in the atoms are tightly bound and unable to move between other atoms
the electrons are able to move freely between the different energy levels within the atom
their atoms can move freely between other atoms
their atoms are tightly bound in their shells, which makes them unable to move between other atoms
Metals are great conductors because the electrons are able to move freely between the different energy levels within the atom.
What are conductors?
A substance or material that has the capability of conducting electricity or allows the passage of electricity to flow through it is known as conductor or electric conductor. The electrical charge carriers i.e., electrons or ions move easily from one atom to another when a voltage is applied on it.
The outer bound electrons of the metals are loosely bound as the nucleus gets very less attracted on the electrons present on the outermost shell and because of this the charge carriers in them can move the current applied easily when there is a potential difference. Therefore, metals are considered to be the best conductors.
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A cylinder is rolling along the ground at 2m/s . It comes to a hill and starts going up.Assuming no losses to friction, how high does it get before it stops
The maximum height reached by the cylinder at the given initial velocity is 0.2 m.
What is the maximum height travelled by the cylinder?
The maximum height travelled by the cylinder is calculated by applying the following kinematic equation as shown below.
v² = u² - 2gh
where;
u is the initial velocity of the cylinderv is the final velocity of the cylinder at the maximum heighth is the maximum height travelled by the cylinderg is acceleration due to gravityAt maximum height, the final velocity of the cylinder = 0
v² = u² - 2gh
0 = u² - 2gh
2gh = u²
h = u²/2g
h = (2²) / (2 x 9.8)
h = 0.2 m
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Astronauts in training are subjected to extreme acceleration forces by the centripental forces in againt centrifuge the radius of the centrifuge appriximately 5m calculate the approximate centripetal force on an astronaut of mass 80Kg if the centrifuge rotates once every 2s
The approximate centripetal force on an astronaut of mass 80Kg if the centrifuge rotates once every 2s is 3.94 KN
ac = v² / r
v = 2 π r / T
ac = Centripetal acceleration
v = Linear / Tangential velocity
T = Time period
r = Radius
r = 5 m
T = 2 s
v = 2 * 3.14 * 5 / 2
v = 15.7 m / s
ac = 15.7 * 15.7 / 5
ac = 49.298 m / s²
Fc = m ac
m = Mass
m = 80 kg
Fc = 80 * 49.298
Fc = 3943.8 N
Fc = 3.94 KN
Therefore, the approximate centripetal force on the astronaut is 3.94 KN
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A body of mass 2kg falls freely from rest through a height 8m onto a hard floor bounces back to a height of 2m. calculate the change of momentum, if the bady is in contact with the floor for 0.1s, what is the force exerted on the body? (g=10ms^2)
The force exerted on the body is 12.66 N.
Linear momentum, translational momentum, or clearly momentum is the made of the mass and velocity of an item. it's miles a vector amount, possessing significance and a path. If m is an object's mass and v is its speed.
Given;
mass = 2 kg
height = 8m
bounce height = 2 m
let velocity just before striking the floor is initial velocity 12.65 m/s
the potential energy at 8 m = mgh
= 2 ×10× 8
= 160 J
same converted into kinetic energy 160 J = 1/2 mv²
V² = 320/2
v = 12.65 m/s
Final velocity
mgh = 1/2 mv²
2×10×2 = 1/2×2 × v²
v² = 6.32 m/s
Acceleration = change in velocity per unit of time
= - 6.32 - (-12.65) = 6.33 m/s² / 0.1
Force = mass × acceleration
= 2 × 6.33 m/s²
= 12.66 N
Momentum may be described as a mass in motion. All objects have mass; so if an object is transferring, then it has momentum - it has its mass in movement. the quantity of momentum that an item has depends upon variables: how an awful lot of stuff is moving and the way speedy the stuff is moving.
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An SUV crashes into a wall. The mass of the vehicle is 2,150 kg and the crumple zone rigidity is 342 kN. Assuming the safety cell is perfectly rigid, what will be the acceleration of the SUV during a crash as the crumple zone is collapsing?
The acceleration of the SUV during crash as the crumple zone is collapsing is 0.0063 m/s².
What is acceleration?Acceleration is the ratio of the force on a body to the mass of the body.
To calculate the acceleration of the SUV, we use the formula below.
Formula:
F = ma............ Equation 1Where:
F = Crumple zone rigiditym = Mass of the vehiclea = Acceleration of the SUVMake a the susbject of the equation
a = F/m................. Equation 2From the question,
Given:
m = 2150 kgF = 342 kN = 342000 NSubstitute these values into equation 2
a = 2150/342000a = 0.0063 m/s²Hence, the acceleration of the SUV is 0.0063 m/s².
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Use the equation GPE = mx 9.8 m/sxh to calculate the gravitational potential of a 10-kg
sack of groceries on a shelf 1 m above the floor?
A 10-kg bag of goods on a shelf one meter above the ground has a gravitational potential of GPE= (10 kg)(9.8 m/s2) (1 m) GPE= 98 J
How to compute gravitational potential energyThe formula for gravitational force is P.E. = mgh, where m represents the mass in kilograms, ga is the acceleration caused by gravity (9.8 m/s2 at the earth's surface), and h is the height in meters. Keep in mind that the gravitational potential energy is measured in the same units as kinetic energy, namely kg m2/s2.
What exactly is gravitational potential?The amount of labor required to dispense a body of unit mass form infinity to a certain point in a body's gravitational field is known as the gravitational potential. It is designated with the letter V.
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science class is conducting an investigation to see how gravity affects objects of different masses. They drop three balls from the same height. They
me how long it takes the balls to hit the ground. What are the students comparing? (1 point)
O the time it takes for each ball to fall
O the height from which each ball is dropped
O the gravitational attraction of each ball
O the mass of each ball
Answer:
the gravitational attraction of each ball, so technically the others too lol
Patrick walks 6 meters to the south, 3 meters west, 2 meters to the north, and 5 meters to the east. Which of the following is true?
A. His displacement was 4 meters.
B. His distance traveled was 6 meters.
C. His distance traveled was 16 meters.
D.His displacement was 17 meters.
Which has the most momentum?
C: 150 g object at 5 m/s
D: 200 kg object at 2 m/s
A: 50 kg object at 5 m/s
B: 100 kg object at 10 m/s
Option D) 200 kg object at 2 m/s has the highest momentum.
What is momentum?
Momentum is calculated using Newtonian mechanics by multiplying an object's mass by its velocity.As a vector quantity with both a magnitude and a direction, it has both. Considering that an object's mass is m and its speed is v (also a vector quantity),Momentum formula, P = mv
p = momentum
m = mass \ velocity
The newton-second is a unit of measurement for momentum in the International System of Units (SI), and the kilogram metre per second (kg m/s) is its SI counterpart.
A) 50 kg object at 5 m/s
m = 50 kg
v = 5 m/s
Momentum, p = m x v
= 50 x 5
= 250 kg m/s
B) 100 kg object at 10 m/s
m = 100 kg
v = 10 m/s
Momentum, p = m x v
= 100 x 10
= 1000 kg m/s
C) 150 g object at 5 m/s
m = 150 g
= 0.15 kg
v = 5 m/s
Momentum, p = m x v
= 0.15 x 5
= 0.75 kg m/s
D) 200 kg object at 2 m/s
m = 200 kg
v = 2 m/s
Momentum, p = m x v
= 200 x 2
= 400 kg m/s
Hence, Option B has the highest momentum.
To learn more about momentum from the given link
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Aside from density, what other information from the table of planetary data can help someone decide if a planet is terrestrial, jovian, or dwarf?
Jovian planets are less dense than terrestrial planets.
The ratio of these two characteristics—an object's mass divided by its volume is that determines its density.The Jovian planets lack solid surfaces, in contrast to the terrestrial planets that make up our inner solar system—Mercury, Venus, Earth, and Mars. They are made mostly of hydrogen and helium instead, with minute amounts of other gases like methane, ammonia, water, and others in their atmospheres.
Terrestrial planets formed from metal and rock-based planetesimals, but they were ultimately too small to hold much of the solar nebula's rich hydrogen and helium gas. The Jovian planets, on the other hand, originated distant from the Sun where there were abundant ices and rocks.
To know more about Jovian planets
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What is the critical angle for light traveling from ice (n=1.309) into air?
a. 39.8⁰
c. 59.8⁰
b. 49.8⁰
d.
69.8°
Answer:
b. 49.8
Explanation:
θc = sin^-1(1/1.309) = 49.81
16. [-/1 Points] DETAILS SERCP11 8.6.P.069.
MY NOTES
ASK YOUR TEACHER
A solid, horizontal cylinder of mass 12.2 kg and radius 1.00 m rotates with an angular speed of 5.50 rad/s about a fixed vertical axis through its center. A 0.250-kg piece of putty is
dropped vertically onto the cylinder at a point 0.900 m from the center of rotation and sticks to the cylinder. Determine the final angular speed of the system.
rad/s
PRACTICE ANOTHER
The final angular speed of the system that contains a solid, horizontal cylinder of mass 12.2 kg and radius 1.00 m rotates with an angular speed of 5.50 rad/s about a fixed vertical axis through its center is 5.33 rad / s
Let M and R be mass and radius of the cylinder. Let m and r be mass and distance of piece of putty.
M = 12.2 kg
R = 1 m
ω = 5.5 rad / s
m = 0.25 kg
r = 0.9 m
According to law of conservation of angular momentum,
1 / 2 M R² ω = ( 1 / 2 M R² + m r² ) ω'
1 / 2 * 12.2 * 1 * 5.5 = [ ( 1 / 2 * 12.2 * 1 ) + ( 0.25 * 0.9² ) ] ω'
ω' = 33.55 / 6.3
ω' = 5.33 rad / s
Therefore, the final angular speed of the system is 5.33 rad / s
To know more about angular speed
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