Answers
The magnitude of the tension in the string marked A is 39.5 N.
What is the tension in A?The tension in A is determined thus:
The angle at A, θ = tan⁻¹(3/8) = 20.56
When extrapolated below negative x, the angle at B, α = tan⁻¹(5/4) = 51.34
When extrapolated below negative x, the angle at C, β = tan⁻¹(1/6) = 9.46
Taking the horizontal components of tension;
56.3cos(9.46) = A * cos(20.56) + B * cos(51.34)
0.6247B= 55.53 - 0.936A
B = (55.53 - 0.936A)/0.6247 ----(1)
Taking the vertical components of tension;
56.3 * sin(9.46) + A * sin(20.6) = B * sin(51.3)
9.25 + 0.35A = 0.78B ---- (2)
substitute the value (1) in (2)
9.25 + 0.35A = 0.78{(55.53 - 0.936A)/0.6247}
(9.25 + 0.35A) * 0.6247 = 43.31 - 0.73A
0.22A + 0.73A = 43.31 - 5.78
0.93A = 37.53
A = 39.5 N
In conclusion, the tension in A is determined by solving for the vertical and horizontal components of tension.
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Related Questions
What is the x-component of a vector with a magnitude of 115 km at an angle of 22°?
Answers
The x-component of a vector are < 106.6, 43.07 >
Depending on the angle we are provided, the x-component of a vector can either be cos or sin. Cos always corresponds to the right triangle's side that contacts the specified angle.
If a vector v with magnitude ||v|| makes an angle θ with the positive x-axis then,
v = ||v|| cos θi + ||v|| sin θj
= < ||v|| cos θ , ||v|| sin θ >
Magnitude p = 115 km
Angle = 22°
p = ||p|| < cos θ, sin θ >
p = 115 < cos 22°, sin 22° >
p = 115 < 0.927, 0.3746 >
p = < 106.6, 43.07 >
Therefore, the x-component of a vector are < 106.6, 43.07 >
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The light beam shown in the figure below makes an angle of = 24.8° with the normal line NN' in the linseed oil. Determine the angles and '. (The refractive index for linseed oil is 1.48.)
Answers
The angle of refraction of the light beam is determined as 16.46 ⁰.
Angle of refraction of the light beamn = sin i / sin r
where;'
n is refractive indexi is angle of incidencer is angle of refractionAngle between the ray and the normal = incident angle = 24.8⁰
1.48 = sin (24.8) / (sin r)
sin r = sin (24.8) / (1.48)
sin r = 0.283
r = sin ⁻¹(0.283)
r = 16.46 ⁰
Thus, the angle of refraction of the light beam is determined as 16.46 ⁰.
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The Earth’s diameter is about 8,000 miles; our Moon’s diameter is about 2,000 miles; how
many Moon’s would fit inside of the volume of the Sun?
Answers
Three moons can fit inside the volume of the sun.
What is the moon?The moon is a non luminous body found in the space. It could cause a solar eclipse when it comes between the sun and the earth.
Since the Earth’s diameter is about 8,000 miles and the Moon’s diameter is about 2,000 miles, to obtain the number of moons that could fit inside the sun we have;
8,000 miles/ 2,000 miles = 3
Hence, three moons can fit inside the volume of the sun.
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Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a spitting cobra rears up to a height of 0.420 m above the ground and launches venom at 2.50 m/s, directed 35.0° above the horizon. Neglecting air resistance, find the horizontal distance (in m) traveled by the venom before it hits the ground.
Answers
The horizontal distance traveled by the venom before it hits the ground is 0.6 m
What is Projectile ?A stone or ball or anything projected is known as a projectile.
Given that a spitting cobra rears up to a height of 0.420 m above the ground and launches venom at 2.50 m/s, directed 35.0° above the horizon.
Assuming air resistance is neglected, the parameters to be considered are;
Height h = 0.42 mVelocity v = 2.5 m/sAngle Ф = 35°The ball we reach the ground at the same time when it is dropped vertically or horizontally.
In a vertical direction,
h = 1/2g[tex]t^{2}[/tex]
Substitute all the parameters into the formula
0.42 = 1/2 x 9.8 x [tex]t^{2}[/tex]
0.42 = 4.9[tex]t^{2}[/tex]
[tex]t^{2}[/tex] = 0.42/4.9
[tex]t^{2}[/tex] = 0.0857
t = [tex]\sqrt{0.0857}[/tex]
t = 0.29 s
The horizontal distance traveled by the venom before it hits the ground will be
Distance = ucosФ x t
Distance = 2.5cos35 x 0.29
Distance = 0.599 m
Distance = 0.6 m
Therefore, the horizontal distance (in m) traveled by the venom before it hits the ground is 0.6 m
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9.80 1. The density of mercury is 13600 kg/m³. What is this value in g/cm³? 2. Find the mass of water which will fit in a large tank measuring 2 m x 1 m x 20 cm. Density of water is 1000 kg/m³ or 1.0 g/cm³. 3. Find the volume of a lump of softwood whose mass is 120 g. Density of softwood is 0.6 gcm-3 or 600 kgm-³. -3
Answers
Answer:
1. 13..6 grams per centimeters cubed.
2. Mass = 400kg
3. Volume = 200cm = 2m
Explanation:
1. The conversion for kg/m^3 to g/cm^3 is divide by 1000.
2. [tex]density=\frac{mass}{volume}[/tex]
[tex]1000=\frac{mass}{2 * 1 * 0.2}[/tex]
[tex]1000*0.4=mass[/tex]
[tex]400kg = mass[/tex]
3. [tex]density=\frac{mass}{volume}[/tex]
[tex]0.6=\frac{120}{volume}[/tex]
[tex]volume=\frac{120}{0.6}[/tex]
[tex]volume= 200cm[/tex]
Two builders carry a sheet of drywall up a ramp. Assume that W = 1.80 m, L = 3.30 m, θ = 24.0°, and that the lead builder carries a (vertical) weight of 147.0 N (33.0 lb).
1. What is the (vertical) weight carried by the builder at the rear?
2. The builder at the rear gets tired and suggest that the drywall should be held by its narrow side. What is the weight (in N) he must now carry?
Answers
The vertical weight carried by the builder at the rear is 240.89N. The weight he must now carry is 352.26N
1. How to solve for the vertical weightWe have w = 1.8
Then we have L as 3.30
θ = 24.0
FC = 147
We have to find FB
147 (3.3 + 1.8 tan24)/(3.3 - 1.8 tan24)
= 240.896
The vertical weight carried by the builder is 240.896
2. 240.896 + 147
= 387.896
387.896/[1 + (1.8 + 3.3 tan24) /(1.8 - 3.3 tan24)]
= 387.896/10.885
= 35.64
387.896 - 35.64
= 352.26N
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Calculate the de Broglie wavelength of a 0.56 kg ball moving with a constant velocity of 26 m/s (about 60 mi/h)
Answers
The de Broglie wavelength of a 0.56 kg ball moving with a constant velocity of 26 m/s is 4.55×10⁻³⁵ m.
De Broglie wavelength:The wavelength that is incorporated with the moving object and it has the relation with the momentum of that object and mass of that object. It is inversely proportional to the momentum of that moving object.
λ=h/p
Where, λ is the de Broglie wavelength, h is the Plank constant, p is the momentum of the moving object.
Whereas, p=mv, m is the mass of the object and v is the velocity of the moving object.
Therefore, λ=h/(mv)
λ=(6.63×10⁻³⁴)/(0.56×26)
λ=4.55×10⁻³⁵ m.
The de Broglie wavelength associated with the object weight 0.56 kg moving with the velocity of 26 m/s is λ=4.55×10⁻³⁵ m.
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The small spherical planet called "Glob" has a mass of 7.88×1018 kg and a radius of 6.32×104 m. An astronaut on the surface of Glob throws a rock straight up. The rock reaches a maximum height of 1.44×103 m, above the surface of the planet, before it falls back down. Initial speed of the rock = 1.92×101 m/s. (Glob has no atmosphere, so no energy is lost to air friction. G = 6.67×10-11 Nm2/kg2.)
A 36.0 kg satellite is in a circular orbit with a radius of 1.45×105 m around the planet Glob. Calculate the speed of the satellite.
Answers
The orbiting speed of the satellite orbiting around the planet Glob is 60.8m/s.
To find the answer, we need to know about the orbital velocity a satellite.
What's the expression of orbital velocity of a satellite?Mathematically, orbital velocity= √(GM/r)G= gravitational constant= 6.67×10^(-11) Nm²/kg², M = mass of sun , r= radius of orbitWhat's the orbital velocity of the satellite in a circular orbit with a radius of 1.45×10⁵ m around the planet Glob of mass 7.88×10¹⁸ kg?Here, M= 7.88×10¹⁸ kg, r= 1.45×10⁵ mOrbital velocity of the orbiting satellite = √(6.67×10^(-11)×7.88×10¹⁸/1.45×10⁵)= 60.8m/s
Thus, we can conclude that the speed of the satellite orbiting the planet Glob is 60.8m/s.
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A 1100-N crate rests on the floor.
1) How much work is required to move it at constant speed 5.0 m along the floor against a friction force of 310 N .
Express your answer to two significant figures and include the appropriate units.
2)
How much work is required to move it at constant speed 5.0 m vertically.
Express your answer to two significant figures and include the appropriate units.
Answers
(a) The work done in moving the crate along the floor is 7,050 J.
(b) The work done in moving the crate vertically is 0 J.
Work done in moving the crate horizontally
W = Fdcosθ
where;
F is total force to be appliedd is displacement of the crateθ is the horizontal angle = 0W = (1100 + 310) x 5
W = 7,050 J
Work done in moving the crate verticallyW = Fd cos(90)
W = 0
Thus, the work done in moving the crate along the floor is 7,050 J.
the work done in moving the crate vertically is 0 J.
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A 29.0 kg beam is attached to a wall with a hi.nge while its far end is supported by a cable such that the beam is horizontal.
If the angle between the beam and the cable is θ = 57.0° what is the vertical component of the force exerted by the hi.nge on the beam?
Answers
26.10 N is the vertical component of the force.
Rx represents the Horizontal component of force
Ry represents The Vertical component of force
According to the given diagram
Rx - Tcosθ = 0
Rx = Tcosθ
And,
Ry + Tsinθ = mg
Ry = mg - Tsinθ
The horizontal component of force =The Vertical component of force
Rx = Ry
Tcosθ = mg - Tsinθ
T(cosθ + sinθ) = 29 × 9.8 = 284.2 N
T√2 cosθ = 284.2 N
T × √2 ×0.544 = 284.2 N
T × 0.769 = 284.2 N
T = 370 N (app)
So,
Ry = 284.2 - 370 (sin 57°)
= 284.2 - 310.3 = -26.10 N
Hence, 26.10 N is the vertical component of the force exerted.
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A coil 3.55 cm in radius, containing 470 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×10^−2 T/s )t+( 2.85×10^−5 T/s4 )t^4. The coil is connected to a 610 Ω resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil.
a) Find the magnitude of the induced emf in the coil as a function of time.
b) What is the current in the resistor at time t0 = 5.20 s ?
Answers
The current is 1.13* 10^{-4}A
Given that r = radius of the coil = 4 cm = 0.04 m
Area of coil is given as
A = πr²
A = (3.14) (0.04)² = 0.005024 m²
N = Number of turns = 500
R = Resistance = 600 Ω
B = magnetic field = (0.0120)t + (3 x 10⁻⁵) t⁴
Taking derivative at both the side
[tex] \frac{dB}{dt} = (0.120 + (12 \times 10^-5)t^3)[/tex]
Induced current is given as
[tex]i= (\frac{NA}{R} )( \frac{db}{dt} )[/tex]
[tex]i \: = (\frac{NA}{R})(12 \times 10 ^{-5} )t^3[/tex]
substituting the value t = 5
[tex]i = ( \frac{(500)(0.005024)}{600}) (12 \times 10 ^{-5} )5^3[/tex]
[tex]i = 1.13 \times 10 ^{ - 4} A[/tex]
Hence the current is
[tex]1.13 \times 10^-4A[/tex]
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The Electric current is 1.11* 10^{-4}A
Given that the coil's radius is 3.55 cm (0.35 m),
The formula for the coil's area is A = r2 A = (3.14) (0.35)2 = 0.005024 m2.
R = Resistance = 600 N = Number of spins = 500 B = Magnetic field = (0.0120)
t + (3 x 10⁻⁵) t⁴
The number t = 5 is substituted for taking the derivative at both the induced current and the electric current.
The Electric current is therefore 1.11* 10^{-4}A
Electric current - The rate of electron passage in a conductor is known as electric current. The ampere is the electric current's SI unit. Electrons are little particles that are part of a substance's molecular structure. These electrons can be held loosely or securely depending on the situation.
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The mass of Saturn is 5.68 x 1026 kg, and use an orbital radius of 3.00 x 105 km. (G = 6.67 × 10-11 N ∙ m2/kg2). Find the orbital speed of an ice cube in the rings of Saturn.
Answers
The orbital speed of an ice cube in the rings of Saturn is determined as 355,366.5 m/s.
What is orbital speed?
The orbital speed of an astronomical body or object is the speed at which it orbits around the center of mass of the most massive body.
Orbital speed of ice cube in the rings of SaturnThe orbital speed of ice cube in the rings of Saturn is calculated as follows;
v = √GM/r
where;
G is universal gravitation constantM is mass of Saturnr is the distance of the ice cubev = √(6.67 x 10⁻¹¹ x 5.68 x 10²⁶)/(3 x 10⁵)
v = 355,366.5 m/s
Thus, the orbital speed of an ice cube in the rings of Saturn is determined as 355,366.5 m/s.
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A 2.30 mH toroidal solenoid has an average radius of 6.20 cm and a cross-sectional area of 2.80 cm2.
a) How many coils does it have? In calculating the flux, assume that B is uniform across a cross section, neglect the variation of B with distance from the toroidal axis.
b) At what rate must the current through it change so that a potential difference of 2.60 V is developed across its ends?
Answers
(a) The number of turns of the coil is determined as 1,596 turns.
(b) The rate of change of current is determined as 1,130.43 A/s.
Number of turns of the solenoid
L = N²μA/l
where;
L is inductance N is number of turnsA is areal is average length = 2πrN²μA = LI
N² = LI/μA
N² = (2.3 x 10⁻³ x 2π x 0.062)/(4π x 10⁻⁷ x 2.8 x 10⁻⁴)
N² = 2,546,428.6
N = √2,546,428.6
N ≈ 1,596 turns
Rate of current changeL = (emf)/I
I = (emf)/L
I = (2.6)/(2.3 x 10⁻³)
I = 1,130.43 A/s
Thus, the number of turns of the coil is determined as 1,596 turns.
The rate of change of current is determined as 1,130.43 A/s.
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6.
A swimmer bounces straight up from a diving board and falls feet first into a pool. She
starts with a velocity of 4.00 m/s, and her takeoff point is 1.80 m above the pool. (3pt)
a) How long are her feet in the air?
b) What is her highest point above the board?
c) What is her velocity when her feet hit the water?
Answers
a) Her feet are in the air for 0.73+0.41 = 1.14 seconds
b) Her highest height above the board is 0.82 m
c) Her velocity when her feet hit the water is 7.16 m/s
Given,t = Time taken
u = Initial velocity = 4 m/s
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s²
a) Her feet are in the air for 0.73+0.41 = 1.14 seconds
s = ut + [tex]\frac{1}{2}[/tex]at²
2.62 = 0t + [tex]\frac{1}{2}[/tex] ₓ 9.8 ₓ [tex]t^{2}[/tex]
t = 0.73 s
b) Her highest height above the board is 0.82 m
The total height she would fall is 0.82+1.8 = 2.62 m
v = u + at
0 = 4 ₋ 9.8 ₓ t
t = 0.41 s
s = ut +[tex]\frac{1}{2}[/tex] at²
s = 4 ₓ 0.41 ₊ [tex]\frac{1}{2}[/tex] ₓ ₋9.8 ₓ 0.41 [tex]t^{2}[/tex]
c) Her velocity when her feet hit the water is 7.16 m/s
[tex]v = u + at \\v = 0 + 9.8[/tex] ₓ [tex]0.73[/tex]
v = 7.16 m/s
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Select the correct answer.
Using the statistical definition of entropy, what is the entropy of a system where W = 4?
Answers
Using the statistical definition of entropy, The entropy of a system W = 4 is 1.91×10²³.
What is entropy?Entropy is typically referred to as a measurement of a system's randomness or disorder. In 1850, a German physicist named Rudolf Clausius first proposed this idea. Entropy is a thermodynamic property used to characterize a system's behavior in terms of temperature, pressure, entropy, and heat capacity. This thermodynamic explanation took the systems' equilibrium condition into account.
Entropy can be calculated using a mathematical expression.
Entropy = Total change of heat / thermodynamic temperature
S= KblnW
S is the statistical entropy
The value of Boltzmann's constant is 1.38×10⁻²³.
S= 1.38×10⁻²³ ln(4)
S = 1.91×10⁻²³
Using the statistical definition of entropy, The entropy of a system W = 4 is 1.91×10²³.
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Answer: C.
1.91 × 10⁻²³ joules/kelvin
Explanation: edmentum
What is formed when 2 or more elements combine chemically
Answers
Answer:
compound
Explanation:
a substance made from two or more different elements that have been chemically joined. Examples of compounds include water (H2O), which is made from the elements hydrogen and oxygen, and table salt (NaCl), which is made from the elements sodium and chloride.
The Venn diagram compares protons with electrons. Which shared property belongs in the region marked "B”?
Answers
The shared property of electron and proton that belongs in the region marked "B” is the presence of charge on both of them.
What charge is present on proton and electron?We know that proton is positively charge particle while on the other hand, electron is negatively charge particle. Due to opposite charges, these particles attract each other.
So we can conclude that the shared property of electron and proton that belongs in the region marked "B” is the presence of charge on both of them.
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Answer:
electrically charged
Explanation:
got it right
An 87-kg football player traveling 5.2 m/s is stopped in 1.0 s by a tackler.
What is the original kinetic energy of the player?
Express your answer to two significant figures and include the appropriate units.
What average power is required to stop him?
Express your answer to two significant figures and include the appropriate units.
Answers
The original kinetic energy of the player and the average power is required to stop him are 1200 J and 1200 W respectively.
What is Kinetic Energy ?The energy possessed by a body in motion is known as Kinetic Energy. The S. I unit is Joule.
Given that an 87-kg football player traveling 5.2 m/s is stopped in 1.0 s by a tackler. The given parameters are;
Mass m = 87 KgVelocity v = 5.2 m/sTime t = 1 sThe original kinetic energy of the player can be calculated by using the formula K.E = 1/2m[tex]v^{2}[/tex]
Substitute all the parameters into the formula
K.E = 1/2 x 87 x [tex]5.2^{2}[/tex]
K.E = 1176.24
K.E = 1200 J
Power is the rate at which work is done.
Work done = energy
The average power is required to stop him can be calculated by using the formula P = E/t
Substitute all the parameters into the formula
P = 1200/1
P = 1200 W
Therefore, the original kinetic energy of the player and the average power is required to stop him are 1200 J and 1200 W respectively.
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Consider a message signal m(t) with the spectrum shown in the following Figure. The message signal bandwidth W=1KHz, This signal is applied to a product modulator, together with a carrier Accos(2πfc t)wave producing the DSB-SC modulated wave S(t). This modulated wave is next applied to a coherent detector. Assuming perfect synchronism between the carrier waves in the modulator and detector, determine the spectrum of the detector output when: (a) The carrier frequency fc=1.25 KHz. And (b) The carrier frequency fc=0.75 KHz. What is the lowest carrier frequency for which each component of the modulated wave S(t) is uniquely determined by m(t)?
Answers
The lowest carrier frequency for which each component of the modulated wave S(t) is uniquely determined by m(t) is
[tex]-Fc,-Fc+W,-Fc-wW = > -1.5k,-0.5k,-2.5kHz[/tex]"-w,w -1kHz,1kHz" are the frequency components of the detector output in this case.
[tex]-Fc,-Fc+w,-Fc-W = > -0.75k,0.25k,-1.75kHz[/tex]This is further explained below.
What is the lowest carrier frequency for which each component of the modulated wave S(t) is uniquely determined by m(t)?Generally, the equation for the modulated wave containing frequency components is mathematically given as
[tex]Fc,Fc+w,Fc-W = > 1.5k,2.5k,0.5kHz[/tex]
[tex]-Fc,-Fc+W,-Fc-wW = > -1.5k,-0.5k,-2.5kHz[/tex]
"-w,w -1kHz,1kHz" are the frequency components of the detector output in this case.
b)
In conclusion,, then the modulated wave contains frequency components as
[tex]Fc,Fc+W,Fc-W = > 0.75k,1.75k,-0.25kHz[/tex]
[tex]-Fc,-Fc+w,-Fc-W = > -0.75k,0.25k,-1.75kHz[/tex]
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A moonshiner makes the error of filling a glass jar to the brim and capping it tightly. The moonshine expands more than the glass when it warms up, in such a way that the volume increases by 0.6% (that is, ΔV/V0 = 6 ✕ 10-3) relative to the space available. Calculate the force exerted by the moonshine per square centimeter if the bulk modulus is 2.1 ✕ 109 N/m2, assuming the jar does not break.
Answers
The force exerted per square centimeter is 126 N/cm².
What is pressure?Pressure is the force acting per unit area.
Pressure = force/areaBased on the data given:
volume increase, ΔV/V0 = 6 * 10⁻³
Bulk Modulus, B = 2.1 * 10⁹ N/m²
Bulk modulus B of a material is ratio of change in pressure and change in volume as given below:
B = ΔP/ [(ΔV/V)]Solving for ΔP;
ΔP = B * [(ΔV/V)]
ΔP = (2.1 * 10⁹ N/m²) * (6 * 10⁻³)
ΔP = 1.26 * 10⁶ N/m²
Converting to per square centimeter
ΔP = (1.26 * 10⁶ N/m²)/10⁴
ΔP = 126 N/cm²
In conclusion, the force exerted per square centimeter is a measure of the pressure.
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Find the speed of a satellite in a circular orbit around the Earth with a radius 3.57 times the mean radius of the Earth. (Radius of Earth = 6.37×103 km, mass of Earth = 5.98×1024 kg, G = 6.67×10-11 Nm2/kg2.)
Answers
The orbiting velocity of the satellite is 4.2km/s.
To find the answer, we need to know about the orbital velocity of a satellite.
What's the expression of orbital velocity of a satellite?Mathematically, orbital velocity= √(GM/r)r = radius of the orbital, M = mass of earthWhat's the orbital velocity of a satellite orbiting earth with a radius 3.57 times the earth radius?M= 5.98×10²⁴ kg, r= 3.57× 6.37×10³ km = 22.7×10⁶mOrbital velocity= √(6.67×10^(-11)×5.98×10²⁴/22.7×10⁶)=4.2km/s
Thus, we can conclude that the orbiting velocity of the satellite is 4.2km/s.
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What is the approximate uncertainty in the area of a circle of radius 4.3×104cm ?
Answers
The approximate uncertainty in the area of a circle is 5.4%.
Area of the circle
A = πr²
where;
r is radius of the circleA = π(4.3 x 10⁴)²
A = 5.81 x 10⁹ cm²
Let the error in measurement = 1 x 10⁴ cm
Error in Area measurementA = π(1 x 10⁴)² = 3.14 x 10⁸ cm²
Uncertainty in measurement% = (error/actual area) x 100%
% = ( 3.14 x 10⁸) / (5.81 x 10⁹) x 100%
% = 5.4 %
Thus, the approximate uncertainty in the area of a circle is 5.4%.
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The small amount of missing mass that occurs when _____ atoms fuse to form helium
atoms is converted into energy in the form of heat and light.
nitrogen
hydrogen
barium
Ochromium
Answers
hydrogen
Explanation:Atomic fusion occurs when 2 or more atoms combine to create a new element.
Helium
Before figuring out what elements create helium, we need to understand its properties. Helium is the second element on the periodic table. It has 2 protons and usually 2 electrons in the base state.
There are technically ions but base helium will have 2 electrons, especially because it is a noble gas.
Fusion
In most cases, including this one, when 2 atoms fuse together you can add their protons together to find the atomic number of the new element. Since helium only has 2 protons, the elements fused to form helium must both have 1 proton.
The element with 1 proton is hydrogen. So, 2 hydrogen atoms fuse to form helium.
Real World Applications
Fusion can be seen across the universe. One of the most common examples of hydrogen fusing to become helium is in stars. Due to the heat within stars, 2 hydrogen atoms can fuse together to create helium. This process also creates energy in the form of heat and light that the star is made of.
Radiation from the sun hits Earth unequally and is absorbed by different materials in varying amounts. This is called
A. the Coriolis Effect
B. a thermocline
OC. El Nino Southern Oscillation
OD. differential heating
Answers
Radiation from the sun hits earth unequally and is absorbed by different materials in varying amounts. This is called differential heating.
What is differential heating?Differential heating is the property that causes different surfaces to heat up and cool down at different rates. The earth's surface receives different magnitudes of solar radiation and also the earth's surfaces absorb thermal energy in different magnitudes.
The color, shape, texture, surface and presence of constructions can influence the heating or cooling of the earth.
The earth in the equator line is heated more by solar action than that of the poles, since it receives more amount of radiation per unit area.
In general, dry surfaces heat up and cool down faster than wet ones.
Therefore, we can confirm that when radiation from the sun hits earth unequally and is absorbed by different materials in varying amounts is called differential heating.
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Checking the what will reduce the possibility of having to rebuild or replaced the engine?
Answers
Checking the oil will reduce the possibility of having to rebuild or replaced the engine.
what is an engine ?
A device created to transform one or more sources of energy into mechanical energy is known as an engine or motor. Potential energy, heat energy, chemical energy, electric potential, and nuclear energy are all forms of energy that are readily available.
The lubricating function of engine oil is crucial. It shields and stops all the moving parts from rubbing against one another. Metal-on-metal wear would quickly kill your engine without lubrication.
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Figure 21.62 shows a box on whose surfaces the electric field is measured to be horizontal and to the right. On the left face (3 cm by 2 cm) the magnitude of the electric field is 400 V/m, and on the right face the magnitude of the electric field is 1000 V/m. On the other faces only the direction is known (horizontal). Calculate the electric flux on every face of the box, the total flux, and the total amount of charge that is inside the box.
Answers
(a) The electric flux on left face is 0.24 Vm and on the right face is 1 Vm.
(b) The total flux is 1.24 Vm.
(c) The total amount of charge that is inside the box is 1.1 x 10⁻¹¹ C.
Area of the left face
The area of the left face is calculated as follows;
A1 = 0.03 m x 0.02 m = 0.0006 m²
Electric flux on the left faceФ1 = EA1
Ф1 = (400 V/m)( 0.0006 m²) = 0.24 Vm
Let the dimension of the right face = 5 cm by 2 cm
Area of the right faceA2 = 0.05 m x 0.02 m = 0.001 m²
Electric flux on the right faceФ2 = EA2
Ф2 = (1000 V/m)( 0.001 m²) = 1 Vm
Total fluxФ = Ф1 + Ф2
Ф = 0.24 Vm + 1 Vm = 1.24 Vm
Total charge inside the boxФ = Q/ε
Q = εФ
Q = (8.85 x 10⁻¹²)(1.24)
Q = 1.1 x 10⁻¹¹ C
Thus, the electric flux on left face is 0.24 Vm and on the right face is 1 Vm.
The total flux is 1.24 Vm and the total amount of charge that is inside the box is 1.1 x 10⁻¹¹ C.
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A constant force F is applied on a body for a time interval of delta t.This force changes the velocity of the body from V1 to V2.then change in momentum in time interval will be
Answers
The change in momentum in time interval, given the data will be F × Δt
What is momentum?Momentum is defined as the product of mass and velocity. It is expressed as
Momentum = mass × velocity
What is impulse?This is defined as the change in momentum of an object.
Impulse = change in momentum
But
Impulse = force × time
Therefore
Force × time = change in momentum
How to determine the change in momentumInitial velocity = v₁ Finalvelocity = v₂Force = FChange in time = ΔtChange in momentum = ?Force × time = change in momentum
F × Δt = change in momentum
Change in momentum = F × Δt
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A flat, circular, steel loop of radius 75 cm is at rest in a uniform magnetic field, as shown in an edge-on view in the figure (Figure 1). The field is changing with time, according to B(t)=(1.4T)e^−(0.057s^−1)t.
a) Find the emf induced in the loop as a function of time (assume t is in seconds).
b) When is the induced emf equal to 110 of its initial value?
c) Find the direction of the current induced in the loop, as viewed from above the loop.
Answers
The solution to the questions are given as
[tex]t=40.39 \mathrm{sec}[/tex][tex]\varepsilon &=(0.12v)e^{0.057t}[/tex]the direction of induced current will be Counterclock vise.What is the direction of the current induced in the loop, as viewed from above the loop.?Given, $B(t)=(1.4 T) e^{-0.057 t}$
[tex]$\varepsilon m f(\varepsilon)=-\frac{d \phi_{B}}{d t}[/tex]
[tex]\quad$ and, $\phi_{B}=\int B \cdot d A=\int B \cdot d A \cdot \cos \theta$[/tex]
[tex]\begin{aligned}\text { Here, } \theta &=30^{\circ} ; \\A &=\pi r^{2} \\a n \delta, R &=0.75 \mathrm{~m} \\\therefore \varepsilon &=-\frac{d}{d t}(B A \cdot \cos \theta)=-A \cdot \cos \theta \cdot \frac{d}{d t}(B(t)) \\\therefore \varepsilon &=-\pi R^{2} \cdot \cos \theta \cdot \frac{d}{d t}\left(e^{-0.057 t}\right)(1.4 T) \\\therefore \varepsilon &=+\pi(0.75)^{2} \cdot \cos 30 \cdot(0.057)(1.4) \cdot e^{-0.057 t}\left\{\because \frac{d}{d t} e^{-x}=-x \cdot e^{-x} .\right.\end{aligned}[/tex]
[tex]\varepsilon &=(0.12v)e^{0.057t}[/tex]
(b) [tex]Here, $\varepsilon_{0}=0.12 \mathrm{~V} \quad\left(a t_{2} t=0 \mathrm{sec}\right)$[/tex]
[tex]\begin{aligned}&\therefore 1 . \varepsilon_{0}=\varepsilon_{0} \cdot e^{-e .057 t} \\&\therefore e^{0.057 t}=10 \quad \text { (taking log both thesides) } \\&\therefore 0.057 t=\ln (10)=2.303 \\&\therefore t=40.39 \mathrm{sec}\end{aligned}[/tex]
c)
In conclusion, the direction of the induced current will be Counterclockwise.
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Which of the following changes would increase the force between two
charged particles to 9 times the original force?
A. Decreasing the distance between the particles by a factor of 3
B. Decreasing the amount of charge on one of the particles by a
factor of 9
C. Increasing the distance between the particles by a factor of 3
D. Increasing the amount of charge on each particle by a factor of 9
Answers
The answer is A. Decreasing the distance between the particles by a factor of 3.
The Universal Law of Gravitation is :
F = Gm₁m₂ / r² (where 'r' is the distance between them)
Since force is inversely proportional to the square of the distance between them, distance has to be decreased by a factor of 3 to increase the force to 9 times the original force.
The Lunar Module could make a safe landing if its vertical velocity at impact is 2.8 m/s or less. Use conservation of energy to determine h in each case. The acceleration due to gravity at the surface of the Moon is 1.62 m/s2.
Suppose that you want to determine the greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is zero.
Express your answer to two significant figures and include the appropriate units.
Suppose that you want to determine the greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s downward.
Express your answer to two significant figures and include the appropriate units.
Suppose that you want to determine the greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s upward.
Express your answer to two significant figures and include the appropriate units.
Answers
(1) The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is zero is 0.4 m.
(2) The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s downward is 0.25 m.
(3) The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s upward is 0.25 m.
Maximum height
v² = u² - 2gh
where;
v is final velocityu is initial velocitywhen the lander's velocity = 0
0 = u² - 2gh
u² = 2gh
h = u²/2g
h = (2.8²)/(2 x 9.8)
h = 0.4 m
when the velocity of the lander is 1.7 m/s downwardh = (u² - v²)/2g
h = (2.8² - 1.7²)/(2 x 9.8)
h = 0.25 m
when the velocity of the lander is 1.7 m/s upwardh = (u² - v²)/2g
h = (2.8² - 1.7²)/(2 x 9.8)
h = 0.25 m
Thus, the greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is zero is 0.4 m.
The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s downward is 0.25 m.
The greatest height h at which the pilot could shut off the engine if the velocity of the lander relative to the surface at that moment is 1.7 m/s upward is 0.25 m.
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