. Use the quadratic formula to solve each quadratic real equation. Round
your answers to two decimal places. If there is no real solution, say so.
a) x^2 - 5x + 11 = 0
b) -2x^2 - 7x + 15 = 0
c) 4x^2 - 44x + 121 = 0​

Answers

Answer 1

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

[tex]\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}[/tex], with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

[tex]\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}[/tex]

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}[/tex]

[tex]\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5[/tex]

So B has two solutions of 5 and -1.5.

Now to C!

[tex]\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}[/tex]

[tex]\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}[/tex]

[tex]\frac{44}{8} = 5.5[/tex]

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)


Related Questions

Find the value of X. 40,x

Answers

Answer:

x = 70°

Step-by-step explanation:

x = one of the congruent angles in the triangle

Given angle measure: 40°

x = ? + ? = 180 - 40 = 140

x = 70

Answer:

x = 70°

Step-by-step explanation:

x = one of the congruent angles in the triangle

Given angle measure: 40°

x = ? + ? = 180 - 40 = 140

x = 70

Find from the first principle the derivative of 4x² -2with respect to x. Brailiest will be given please hurry​

Answers

Answer:

8x

Step-by-step explanation:

Using differentiation from first principles

f'(x) = [tex]lim_{h>0}[/tex]  [tex]\frac{f(x+h)-f(x)}{h}[/tex]

      = [tex]lim_{h>0}[/tex] [tex]\frac{4(x+h)^2-2-(4x^2-2)}{h}[/tex]

      = [tex]lim_{h>0}[/tex]  [tex]\frac{4x^2+8hx+4h^2-4x^2+2}{h}[/tex]

      = [tex]lim_{h>0}[/tex] [tex]\frac{8hx+4h^2}{h}[/tex]

      = [tex]lim_{h>0}[/tex] [tex]\frac{4h(2x+h)}{h}[/tex] ← cancel the h on numerator/denominator

      = 4(2x)

      = 8x

Answer:

8x

Step-by-step explanation:

Pls I hope this helps

i'm doing domain and range, and I'm kinda having a hard time with this... can someone help?

Answers

Answer:

Domain : any real number

Range : y ≥0

Step-by-step explanation:

The domain is the values that x can be

X can be any real number

The range is the values the y can be

Y can be zero or any positive value since y = x^2

Domain : any real number

Range : y ≥0

Answer:

[tex]\boxed{\sf Option \ A}[/tex]

Step-by-step explanation:

[tex]y=x^2[/tex]

[tex]\sf The \ domain \ of \ a \ function \ is \ all \ possible \ values \ for \ x.[/tex]

[tex]\sf There \ are \ no \ restrictions \ on \ the \ value \ of \ x.[/tex]

[tex]\sf The \ domain \ is \ all \ real \ numbers.[/tex]

[tex]\sf The \ range \ of \ a \ function \ is \ all \ possible \ values \ for \ y.[/tex]

[tex]\sf When \ a \ number \ is \ squared \ the \ result \ is \ always \ greater \ than \ or \ equal \ to \ 0.[/tex]

[tex]\sf The \ range \ is \ \{y:y\geq 0\}[/tex]

the angles of traingle are in the ratio 3:7:8 find them in degrees as well as in radians​

Answers

30°, 70°, and 80°.
It is an acute-angled triangle.
Explanation:
The ratio of the measures of ∠s in Δ is 3:7:8.
So, let us suppose that the measures are, 3k, 7k, 8k.
Evidently, their sum is
180°.

3k+7k+8k=180
18k=180
k= 10

Hence, the measures are,
30°, 70°, and 80°.
As all the angles are acute, so is the triangle.

There are 1125 students in a school. If a student pays Rs. 300 as fees and
Rs. 100 as bus charge per month, how much money is collected in a month?

Answers

The school would get 450000 per month


Can someone help me on these ones. PLEASE HELP ME !!

Answers

[tex]\huge\blue{ANSWER}:—[/tex]

Plz mark me as brainliest as I have solve all the questions for you

Answer:1 : x is 95/3

4 x is -32/10

7 b is 6

10 x is 20/7

13 x is 9/2

Step-by-step explanation:

What are the roots of the equation x2 + 6x - 4 = 0?
A6+2V13
B.-6+2V13
C.3V13
D.-3V13

Answers

Answer:

The answer is D

Step-by-step explanation:

use the quadratic formula, plug and chug, and voila!

Enter an inequality that represents the graph in the box.

Answers

Answer:

stop cheating

Step-by-step explanation:

get smart

I need help with these 2 questions. PLZZ help!!!

Answers

Answer:

Step-by-step explanation:

if x is the bill and y is the tip ten

x+y>14.50

x<2   and  x≤ 2

when the sign is< then the dot has to be clear , because 2 does not count and x is less than 2 and not equal to 2

when the sign is ≤ the dot on the graph is solid which represent the equal to.


How to do this question plz answer me step by step plzz plz plz plz ​

Answers

Answer: 25.6

First, notice that there is 1 adult and 2 children.

A normal adult ticket costs 24. But it's 1/3 off, so 24 * 1/3 = 8 off. That means with the Railcard, it only costs 24 - 8 = 16.

Next, one child ticket costs 12. But it's 60% = 3/5 off, so 12 * 3/5 = 7.2 off. That means with the Railcard, it only costs 12 - 7.2 = 4.8.

Remember there are 2 children, so we multiply by 2 to get 4.8 * 2 = 9.6 for the children.

Final answer: 1 adult + 2 children = 16 + 9.6 = 25.6.

Hope that helped,

-sirswagger21

Answer:

£25.60

Step-by-step explanation:

Adult tickets cost £24 and ⅓ is off the adult tickets according to the Family Railcard. That is:

24 × ⅓ = £8 is removed from the adult tickets. Therefore:

£24 - £8 = £16

Child tickets cost £12 and 60% is off the child tickets according to the Family Railcard. That is:

12 × 60/100 = £7.20 is removed from the child tickets. Therefore:

£12 - £7.20 = £4.80

To find the total cost of Mr. Brown spent:

1 child = £4.80

2 children = ?

4.80 × 2 = £9.60

1 adult = £16

£16 + £9.60

= £25.60

Mr. Brown spent £25.60 in total.

Insert 2 rational numbers between -1/3 and -1/2

Answers

Answer:

-11/24 and -4/9

Step-by-step explanation:

A rational number is a fraction in the form a/b where both a and b are integers and b is not equal to zero.

Given the numbers -1/3 and -1/2, to place two numbers between them, we have to first find the width between the two numbers.

Width = -1/3 - (-1/2) = -1/3 + 1/2 = 1/2 - 1/3 = 1/6

Since two numbers are to be placed between -1/3 and -1/2, we have to divide the width into 3 which results to 1/6 ÷ 3 = 1/18

The first number placed is -1/3 - 1/18 = -11/24

The second number is -11/24 - 1/18 = -4/9

I really need help Please help me please

Answers

I think the answer is 35.28 square units. Because triangle ABC is 1/2 of triangle XYZ, the height must be halved. So, 3.36/2 is 1.68. Now, you times 42 by 1.68 to get 70.56. Then, divide that by 2 to get 35.28

Question. 7 Let abc be a three-digit number. Then, abc + bca + cab is not divisible by (a) a + b + c (b) 3 (c) 37 (d) 9

Answers

Answer:

D. 9

Step-by-step explanation:

Let

abc=100a+10b+c

bca=100b+10c+a

cab=100c+10a+b

abc + bca + cab=(100a+10b+c) + (100b+10c+a) + (100c+10a+b)

=100a + 10b + c + 100b + 10c + a + 100c + 10a + b

Collect like terms

=100a + a + 10a + 10b + 100b + b + c + 10c + 100c

=111a + 111b + 111 c

Factorise

=111(a+b+c)

abc + bca + cab = 111(a+b+c)

Factors of 111(a+b+c)= 1, 3, 37, 111, and (a+b+c)

abc + bca + cab is divisible by a+b+c because it is a factor of 111(a+b+c)

abc + bca + cab is divisible by 3 because 3 is a factor of 111(a+b+c)

abc + bca + cab is divisible by 37 because 37 is a factor of 111(a+b+c)

abc + bca + cab is not divisible by 9 because 9 is not a factor of 111(a+b+c)

Please answer answer question

Answers

Answer:

c=13.42

Step-by-step explanation:

[tex]A^2+B^2=C^2\\6^2+14^2=C^2\\C^2=144+36\\C^2=180\\\sqrt{c^2}=\sqrt{180} \\c=13.42[/tex]

Categorize the graph as linear increasing, linear decreasing, exponential growth, or exponential decay

Answers

Answer:

D. Exponential growth

Step-by-step explanation:

Hope this helps

Function that is similar to exponential.

Option (A) is correct.

What is exponential decay?

Exponential decay describes the process of reducing an amount by a consistent percentage rate over a period of time. It can be expressed by the formula  [tex]y=a(1-b)^{x}[/tex] wherein y is the final amount, a is the original amount, b is the decay factor, and x is the amount of time that has passed.

We can observe that

First, y increases as x increases

Last it is a function that is similar to exponential.

Function is an exponential decay.

Option (A) is correct.

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A pizza parlor offers 4 different pizza toppings. How many different kinds of 2-topping pizzas are available?

Answers

Answer:

you need to be more specific.

Step-by-step explanation:


WILL GIVE BRAINLIEST!!!

Answers

Answer:

2 x^2 sqrt(13)

Step-by-step explanation:

sqrt( 52x^4)

sqrt( 4*13 * x^2 * x^2)

We know that sqrt(ab) = sqrt(a) sqrt(b)

sqrt( 4)*sqrt(13) *sqrt( x^2) *sqrt( x^2)

2 sqrt(13) x*x

2 x^2 sqrt(13)

52|2

26|2

13|13

1

[tex]\sqrt{52x^4}=\sqrt{2^2\cdot13\cdot(x^2)^2}=2x^2\sqrt{13}[/tex]

Find the coordinates of point X that lies along the directed line segment from Y(-8, 8) to T(-15, -13) and partitions the segment in the ratio of 5:2. A. (-5, -15) B. (-23, -5) C. (-13, -7) D. (-11.5, -2.5)

Answers

Answer:

C. (-13, -7)

Step-by-step explanation:

The location of a point O(x, y) that divides a line AB with location A[tex](x_1,y_1)[/tex] and B[tex](x_2,y_2)[/tex] in the ratio m:n is given by:

[tex]x=\frac{m}{m+n} (x_2-x_1)+x_1\\\\y=\frac{m}{m+n} (y_2-y_1)+y_1[/tex]

Therefore the coordinates of point X That divides line segment from Y(-8, 8) to T(-15, -13) in the ratio 5:2 is:

[tex]x=\frac{5}{5+2} (-15-(-8))+(-8)\\\\x=\frac{5}{7} (-15+8)-8=\frac{5}{7}(-7)-8=-5-8=-13 \\\\\\y=\frac{5}{5+2} (-13-8)+8\\\\y=\frac{5}{7} (-21)+8=5(-3)+8=-15+8=-7[/tex]

Therefore the coordinates of point X is at (-13, -7)

58°
X Х
jsut give a quick

Answers

Answer:

32

Step-by-step explanation:

The sum of the angles of a triangle is 180

58+90+x = 180

148+x = 180

x = 180-148

x=32

Concept

The angle sum property of a triangle:

The total measure of the three angles of a triangle is 180°

Solution

[tex]\large\bf \longrightarrow \: {\underline{\red{x \: + \: 58 \degree \: + \: 90 \degree \: = \: 180 \degree}}}[/tex]

[tex]\large\bf \longrightarrow \: {\underline{\red{x \: + \: 148 \: = \: 180 \degree}}}[/tex]

[tex]\large\bf \longrightarrow \: {\underline{\red{x \: = \: 180 \degree \: - \: 148 \degree}}}[/tex]

[tex]\large\bf \longrightarrow \: {\underline{\red{x \: = \: 32 \degree}}}[/tex]

There are 9 classes of 25 students each, 4 teachers, and two times as many chaperones as teachers.
Each bus holds a total of 45 people.
What is the least number of buses needed for the field trip?

Answers

5 buses is the answer pls mark me brainliest

Least number of bus require for trip = 5 buses

What is Unitary method?

It is a method where we find the value of a single unit from the value of multiple units and the value of multiple units from the value of a single unit.

Steps to Use Unitary Method

First, let us make a note of the information we have. There are 5 ice-creams. 5 ice-creams cost $125.

Step 1: Let’s find the cost of 1 ice cream. In order to do that, divide the total cost of ice-creams by the total number of ice-creams. The cost of 1 ice-cream = Total cost of ice-creams/Total number of ice-creams = 125/5 = 25. Therefore, the cost of 1 ice cream is $25.

Step 2: To find the cost of 3 ice-creams, multiply the cost of 1 ice cream by the number of ice-creams. The cost of 3 ice-creams is cost of 1 ice-cream × number of ice-creams = 25 × 3 = $75. Finally, we have the cost of 3 ice-creams i.e. $75.

Given:

Total number of classes = 9

Number of student in each class = 25

Number of teacher = 4

Number of chaperones = Double of teacher

Bus hold = 45 people

Now,

Total number of student = 9 × 25

                                         = 225

Number of chaperones = 4 × 2

                                         = 8

Total people = 225 + 8 + 4

                     = 237

Least number of bus require for trip = Total people / Bus hold

= 237 / 45

= 5.266

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Determine the value of x is

Answers

Answer:

x = 5

Step-by-step explanation:

The measure of an arc equals the measure of the central angle that intercepts it.

The measure of an arc intercepted by a diameter is 180 deg.

m(arc)EH = 180

m(arc)EF + m(arc)FG + m(arc)GH = m(arc)EH

10x + 8 + 67 + 11x = 180

21x + 75 = 180

21x = 105

x = 5

Describe the effort of translating tringle abc to tringle a'b'c

Answers

Answer:

Each x-coordinate increased by 6 and each y-coordinate decreased by 3.

Step-by-step explanation:

Let us use the coordinates of a and a' as an example

a = (-3, 5) a' = (3, 2)

So -3 is for the x-axis in coordinate a and 3 is for the x axis in coordinate a'

Then -3 + 6 = 3 ( This is the x coordinate for a' )

So 5 is for the y -axis in coordinate a and 2 is for the y axis in coordinate a'

Then 5 - 3 = 2 ( This is the y coordinate for a' )

HOPE THIS HELPED

arrange0.2,¼,30%,10%in ascending and descending order​

Answers

Answer:

Ascending- 10%, 0.2, 1/4, 30%

Descending- 30%, 1/4, 0.2, 10%

Step-by-step explanation:

0.2 = 2/10 = 4/20

1/4 = 5/20

30% = 30/100 = 6/20

10% = 10/100 = 2/20

Ascending

-2/20, 4/20, 5/20, 6/20

- 10%, 0.2, 1/4, 30%

Descending

- 6/20, 5/20, 4/20, 2/20

- 30%, 1/4, 0.2, 10%

Mr. Ellington has a total of 32 students in his class , The ratio of girls to boys is 3:5, how many girls are in Mr . Ellington's class ?

Answers

Add the ratio: 3 + 5 = 8

Divide total students by that:

32/8 = 4

The ratio for girls is 3, multiply the 4 by 3:

4 x 3 = 12

There are 12 girls

Answer:

12

Step-by-step explanation:

If the ratio of girls to boys is 3:5, that means that for every 8 total students, 3 would be girls and 5 would be boys. Therefore 3/8 of the students are girls and 5/8 are boys. If 3/8 are girls, then:

[tex]\frac{3}{8}[/tex] of 32

= [tex]\frac{3}{8} * 32[/tex]

[tex]=\frac{3 * 32}{8} \\= \frac{96}{8} \\= 12[/tex]

There are 12 girls.

Select the two values of x that are roots of this equatio 2x - 5 = - 3x ^ 2

Answers

alright I can help!

so to find the two values of x that are roots of the equation we need to put the variables all on one side so that we can set up the quadratic formula.

3x^2+2x-5=0 (the -3x^2 becomes positive when moved across the equal sign)

now we can set up the quadratic formula. the equation is x= (-b+-(sqrt of b^2 -4ac))/ 2a

so now we just plug in our variables.

x= (-2+-(sqrt of 2^2 -4×3×-5))/ 2×3

x= (-2+-8)/6

now we just seperate the equations so that we have the two roots. and then just solve!

x= (-2-8)/6 -> x= -5/3

x= (-2+8)/6 -> x=1

hope this helps! best wishes and best of luck!!

if AD is the altitude to BC what is the slope of AD

Answers

Answer:

The answer is most likely 1/3

The correct option D. 3.  The slope of AD, where A is (-2, 4), B is (-6, 2), and C is (3, -1), is 1/3 using the slope formula.

Given points :

[tex]A(-2, 4)\\B(-6, 2)\\C(3, -1)[/tex]

To find the slope of AD,  to determine the slope of the line passing through points A and D.

Calculate the slope of the line passing through points A and D using the formula:

slope [tex]= (y_2 - y_1) / (x_2 - x_1).[/tex]

First, let's find the slope of BC using the coordinates of points B and C:

Slope of BC [tex]= (y_2- y_1 / (x_2- x_1)\\[/tex]

Plugging the coordinates of points B and C gives:

[tex]= (-1 - 2) / (3 - (-6))[/tex]

On adding gives:

[tex]= (-3) / (9)[/tex]

On dividing both numerator and denominator by 3

[tex]= -1/3[/tex]

Since A is the altitude to BC, it is perpendicular to BC.

The slope of a line perpendicular to another line is the negative reciprocal of the slope of that line.

Therefore, the slope of AD will be the negative reciprocal of -1/3.

Negative reciprocal of -1/3 = -1 / (-1/3) = 3

Hence, the slope of AD is 3. The option is D. 3

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What is the solution to 7 × p = -56? A. -49 B. -8 C. 8 D. 49

Answers

Answer:

-8

Step-by-step explanation:

Hello!

What we do to one side of the equation we do to the other side

7 * p = -56

Divide both sides by 7

p = -8

The answer is -8

Hope this helps!

Sandy's older sister was given $2,400 and was told to keep the balance of the money after sharing with her siblings. Give Sandy exactly $350. Write Sandy's portion

Answers

Answer:

Sandy's portion = [tex]\mathsf{\dfrac{7}{48}}[/tex]

Step-by-step explanation:

Sandy's older sister was given $2,400

She was told to keep the balance of the money after sharing with her siblings.

She gave  Sandy exactly $350

The objective is to write Sandy's portion.

Sandy's portion will be the ratio of the amount given to Sandy divided by the total amount at her sister disposal.

Let Sandy's older sister be y,

So, y = 2400

Sandy's portion = [tex]\dfrac{350}{2400}[/tex]

Sandy's portion = [tex]\dfrac{35}{240}[/tex]

Sandy's portion = [tex]\mathsf{\dfrac{7}{48}}[/tex]

what is the expression of 28 19/100

Answers

Answer:

the mixed form is 28 [tex]19/100[/tex]

the improper form is ( 28 x 100) = 19 / 100

2819 / 00

PLS HELP IMMEDIATLYRewrite the equation by completing the square. 4 x^{2} +8 x +3 = 0 in (x+_)^2=_

Answers

Answer:

(x + 1)^2 = 1/4

Step-by-step explanation:

Here, we want to rewrite the equation by completing the square.

The equation to rewrite is;

4x^2 + 8x + 3 = 0

4x^2 + 8x = -3

divide through by the coefficient of x^2 which is 4

That will give ;

x^2 + 2x = -3/4

Now divide the coefficient of x by 2, square it and add to both sides of the equation.

We have;

x^2 + 2x + 1^2 = -3/4 + 1^2

x^2 + 2x + 1 = -3/4 + 1

x^2 + 2x + 1 = 1/4

= (x + 1)^2 = 1/4

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What is the probability that a student buys a drink, given that he or she buys popcorn? Express your answer as a percent, rounded to the nearest tenth... best answer wins brainliest!!! Read and choose the correct option.In Chile in the early 1930s, a unified school uniform was made mandatory for all educational institutions, public or private. The uniform consisted of a navy blue sweater and a white blouse for girls. Boys were required to wear grey pants with a white dress shirt and a navy blue blazer. Nowadays, the traditional uniform has been fading from most schools. Today, most private and public schools prefer using a customized uniform which proudly shows their school colors and emblems. There are even a few private schools that have eliminated the use of uniforms.In El Salvador, all students are required to wear a uniform, regardless if the school is public or private. Uniforms usually vary depending on the school.In Mexico, students from all public schools are required to wear uniforms as well as many private school children. They are not all the same color, and many have a school crest on their sweaters or shirts.Source: http://www.k12academics.com/School%20Uniforms/school-uniforms-colombia#.Wn3CRKinHcsBased on the text, which statement is true? Chile, El Salvador, and Mexico share similar uniform symbols. The same uniform colors were used in all schools in Chile. Different uniform colors were used in all schools in Chile. El Salvador and Mexico followed Chile's uniform policy. Steelcase Inc. (SCS) is one of the largest manufacturers of office furniture in the United States. In Grand Rapids, Michigan, it assembles filing cabinets in an Assembly Department. Assume the following information for the Assembly Department: Direct labor per filing cabinet 18 minutes Supervisor salaries $250,000 per month Depreciation $18,500 per month Direct labor rate $28 per hourRequired:Prepare a flexible budget for 70,000, 80,000, and 90,000 filing cabinets for the month ending February 28 in the Assembly Department. the author suggest that the desire to belong is a very powerful-if not most powerful-human emotio do you agree or disagree Solve equation and show all steps what is 3/8x=36 Cantor Corporation acquired a manufacturing facility on four acres of land for a lump-sum price of $9,000,000. The building included used but functional equipment. According to independent appraisals, the fair values were $4,500,000, $3,000,000, and $2,500,000 for the building, land, and equipment, respectively. The initial values of the building, land, and equipment would be: