What combination of substances will give a buffered solution that has a pH of 5.05? (Assume each pair of substances is dissolved in 5.0 L of water.) (Kb for NH3 = 1.8 ´ 10–5; Kb for C5H5N = 1.7 ´ 10–9) Select one: a. 1.0 mole NH3 and 1.5 mole NH4Cl b. 1.5 mole NH3 and 1.0 mole NH4Cl c. 1.0 mole C5H5N and 1.5 mole C5H5NHCl d. 1.5 mole C5H5N and 1.0 mole C5H5NHCl e. none of these

Answers

Answer 1

Answer:

c. 1.0 mole C5H5N and 1.5 mole C5H5NHCl

Explanation:

We can determine pH of a buffer using H-H equation:

pH = pKa + log [A⁻] / [HA]

Where [A⁻] is concentration of conjugate base and [HA] concentration of weak acid. These concentrations can be computed as moles of each species.

We need to determine pKa of both NH₃ and C₅H₅N buffers, thus:

pKb = -log Kb

NH₃ pKb = -log 1.8x10⁻⁵ = 4.74

C₅H₅N pKb = -log 1.7x10⁻⁹ = 8.77

And pKa = 14 - pKb:

NH₃ pKa = 14 - 4.74 = 9.26

C₅H₅N pKb = 14 - 8.77 = 5.23

A buffer works only under pH's between pKa-1 and pKa + 1. As pKa NH₃ buffer is 9.23 is not possible to produce a buffer with pH 5.05 for this system.

Thus, we only will compute the buffers made with C₅H₅N:

c. 1.0 mole C5H5N (Weak base) and 1.5 mole C5H5NHCl (Conjugate acid)

pH = pKa + log [A⁻] / [HA]

pH = 5.23+ log [1.0 moles] / 1.5 moles]

pH = 5.05

d. 1.5 mole C5H5N and 1.0 mole C5H5NHCl

pH = pKa + log [A⁻] / [HA]

pH = 5.23+ log [1.5 moles] / 1.0 moles]

pH = 5.41

Right solution is:

c. 1.0 mole C5H5N and 1.5 mole C5H5NHCl

Related Questions

How old is a bone if it presently contains 0.3125g of C-14, but it was estimated to have originally contained 80.000g of C-14?

Answers

Half-life of C-14 is 5730 years

The age of the bone is the time taken to decay carbon -14 from a mass of 80 g to 0.3125 g. The decay time is 46209 years. That is the age of the bone.

What is carbon dating?

Carbon -14 isotope is radioactive and undergoes nuclear decay by the emission of charged particles. The age of a fossil sample which contains carbon -14 can be determined using the time of decay.

Half life of C-14 = 5730 years

decay constant k = 0.693 / 5730 = 0.00012 yr⁻¹

Initial amount of C-14 = 80 g

final amount = 0.3125 g

Then the time taken to decay 80 g to 0.3125 g is t = 1/k ln (80/0.312)

t = ln (80/0.312) / (0.00012 yr⁻¹)

 = 46209 years.

Therefore, the age of the bone is 46209 years.

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Cubes are three-dimensional square shapes that have equal sides. What is the density of a cube that has a mass of 12.6 g and a measured side length of 4.1 cm? (Density: D = )

Answers

Answer:

0.1828g/cm³

Explanation:

density= mass÷volume

m= 12.6g

v= 4.1×4.1×4.1 = 68.921cm³

density= 12.6÷68.921 = 0.1828g/cm³

What is conservation area write in 8 points

Answers

Answer:

The Conservation area is the pay way to the special architectural and historic interest  these are special character.

Explanation:

Conservation area is the features of building and use that historical development to contribute to its special character material and style.

Conservation area is that contain process to the application management development process and local residents.Conservation is that the produce demolition of a building structure with the conservation area,contribute to the group in individually.Conservation area that are special protection in the trees to the dangerous tree and some of the fruit trees.Conservation area are often to the protected by their building, planning works, these character area of appearance.Development rights to the conservation area require to the planning and permission to the outside area.Conservation area is classified to the regulation and the restricted area to the department planning.Conservation area  is a composed to the impact of materials and building and the setting of impact.The new development in the conservation area is to the process of the renewal and the managed in the conservation area.

Balance the equation: "Sodium oxide reacts with water to form sodium hydroxide and hydrogen." I can't find the correct coefficients to balance the equation. I have written my unbalanced equation in the file attached.

Answers

Answer:

So, sodium oxide + water = sodium hydroxide + hydrogen is written Na2O+H2O-->NaOH+H.

To balance the equation it should read NaO+H2O-->2NaOH

Explanation:

Na2O+H2O-->2NaOH+0H2.......the 0H2 is dropped because there is no value

The correct balance of equation will be

Na2O + H2O - - > 2NaOH

What is a balanced chemical equation?

A chemical equation where the number of atoms on both the reactant side and the product side of the reaction are equal is called a balanced chemical equation.

In a balanced chemical equation, not only the number of atoms but the charge and the mass is the same on both sides of the equation.

A chemical equation needs to be balanced to validate the law of conservation of mass. The law of conservation of mass states that the 'mass can neither be created nor destroyed in a chemical reaction'.

If the chemical equation is not balanced, it will go against the fundamental law of law of conservation of mass.

Thus, the chemical equations need to be balanced.

Therefore to balanced the given chemical equation, we equate the number of atoms on both the reactant and the product side of the reaction.

It will be written as

Na2O + H2O - - > 2NaOH

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Chromium is dissolved in sulfuric acid according to the following equation: Cr + H2SO4 ⇒ Cr2 (SO4) 3 + H2


a) How many grams of Cr2 (SO4) 3 can be obtained by reacting 165 g of 85.67% H2SO4 of purity?

b) If 485.9 g of Cr2 (SO4) 3 are obtained, what is the yield of the reaction?

Answers

Answer:

[tex]\large \boxed{\text{a)188.4 g; b) 98.67 $\, \%$}}[/tex]

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:                      98.08           392.18

             2Cr + 3H₂SO₄ ⟶ Cr₂(SO₄)₃ + 3H₂

To solve the stoichiometry problem, you must

Use the molar mass of H₂SO₄ to convert  the mass of H₂SO₄ to moles of H₂SO₄ Use the molar ratio to convert moles of H₂SO₄ to moles of Cr₂(SO₄)₃ Use the molar mass of Cr₂(SO₄)₃ to convert moles of Cr₂(SO₄)₃ to mass of Cr₂(SO₄)₃

a) Mass of Cr₂(SO₄)₃

(i) Mass of pure H₂SO₄

[tex]\text{Mass of pure} = \text{165 g impure} \times \dfrac{\text{85.67 g pure} }{\text{100 g impure}} = \text{141.36 g pure}[/tex]

(ii) Moles of H₂SO₄

[tex]\text{Moles of H$_{2}$SO}_{4} = \text{141.36 g H$_{2}$SO}_{4} \times \dfrac{\text{1 mol H$_{2}$SO}_{4}}{\text{98.08 g H$_{2}$SO}_{4}} = \text{1.441 mol H$_{2}$SO}_{4}[/tex]

(iii) Moles of Cr₂(SO₄)₃

The molar ratio is 1 mol Cr₂(SO₄)₃:3 mol H₂SO₄ [tex]\text{Moles of Cr$_{2}$(SO$_{4}$)}_{3} = \text{1.441 mol H$_{2}$SO}_{4} \times \dfrac{\text{1 mol Cr$_{2}$(SO$_{4}$)}_{3}}{\text{3 mol H$_{2}$SO}_{4}} = \text{0.4804 mol Cr$_{2}$(SO$_{4}$)}_{3}[/tex]

(iv) Mass of Cr₂(SO₄)₃ [tex]\text{Mass of Cr$_{2}$(SO$_{4}$)}_{3} = \text{0.4804 mol Cr$_{2}$(SO$_{4}$)}_{3} \times \dfrac{\text{392.18 g Cr$_{2}$(SO$_{4}$)}_{3}}{\text{1 mol Cr$_{2}$(SO$_{4}$)}_{3}} = \textbf{188.4 g Cr$_{2}$(SO$_{4}$)}_{3}\\\text{The mass of Cr$_{2}$(SO$_{4}$)$_{3}$ formed is $\large \boxed{\textbf{188.4 g}}$}[/tex]

b) Percentage yield

It is impossible to get a yield of 485.9 g. I will assume you meant 185.9 g.

[tex]\text{Percentage yield} = \dfrac{\text{Actual yield}}{\text{Theoretical yield}} \times 100 \, \% = \dfrac{\text{185.9 g}}{\text{188.4 g}} \times 100 \, \% = \mathbf{98.67 \, \%}\\\\\text{The percentage yield is $\large \boxed{\mathbf{98.67 \, \%}}$}[/tex]

boron has two naturally occurring isotopes: boron -10 (abundance = 19.8% , mass = 10.013 amu) boron -11 (abundance = 80.2%, mass= 11.009 amu) Calculate th eatomic mass of boron

Answers

Explanation:

eam=%abudance×mass+%abudance×mass

eam=19.8%×10.013/100+80.2%×11.009/100

eam=198.2574/100+882.9218/100

eam=1081.1792/100

eam=10.811792

eam=10.812

A student with a body temperature of 37°C holds a piece of ice that has a
temperature of -8°C.
Which statement best explains what happens?
1. Thermal energy transfers coldness from the student's hand to the ice.
2. Heat transfers coldness from the ice to the student's hand.
3. Heat transfers thermal energy from the student's hand to the ice.
4. Thermal energy transfers heat from the student's hand to the ice.

Answers

Answer:

Thermal energy transfers hear from the students hand to the ice

Explain the reaction that would occur in a galvanic cell between solutions of Al 3+and Pb 2+ . Identify the oxidation and reduction reactions and the location of each reaction. Then, use the standard reduction potential tables to determine the cell potential.

Answers

Answer:

Al ==> Al^3+ + 3e

Pb^2+ + 2e ==> Pb

Oxidation is the loss of electrons. Reduction is the gain of electrons. Which half rxn above lost and which gained?

For the potential of the cell, look up the reductions potentials, change the sign of the Al half cell, add in the potential for the Pb and add them.

Explanation:

Calculate the pressure drop over a 100m length due to friction when a slurry made from 1.0-mm silica particles is pumped through a horizontal 6-cm diameter pipeline (smooth pipe) at 2.5 m/s. The slurry contains 25 per cent silica by volume. The density of silica is 2700 kg/m3, rhow = 1000 kg/m3, μw = 0.001 kg/ms. Use a value of 82 for Ω. Drag coefficient for these particles,CD, may be taken as 0.44 .


For the slurry/Pipe system in question 1, estimate the deposition velocity.

Answers

Answer:

The answer is "2.78".

Explanation:

Given values:

CD= 0.44

Formula:

[tex]\bold{f_r= \frac{v^{2}}{ g(s-1)D}}[/tex]

g=9.8

s= 2.7

D= 0.06

[tex]\to f_r=\frac{2.5^2}{9.8(2.7-1)0.06}\\\\[/tex]

        [tex]=\frac{2.5 \times 2.5}{9.8 \times 1.7 \times 0.06 }\\\\=\frac{6.25}{.9996 }\\\\=6.252501[/tex]

[tex]\phi = \frac{82\times v}{ \sqrt{cD} \times f_r^{-1.5}}\\\\[/tex]

   [tex]= \frac{82 \times 0.25 }{ \sqrt{0.44} \times 6.25^{1.5}}\\\\=2.4285\\[/tex]

[tex]\frac{\bigtriangleup P f_1 s_1}{L} = \frac{\bigtriangleup Pf_w}{L}(1+\phi)\\[/tex]

           [tex]=\frac{2fwSwv^2 (1+2.4285)}{D}\\\\[/tex]

[tex]Re= \frac{D \bar v Sw}{M_w}\\[/tex]

     [tex]=\frac{0.06 \times 2.5 \times 1000 }{0.001}\\\\=\frac{150 }{0.001}\\\\= 150 \times 10^{3}\\\\= 1.50 \times 10^{5}\\\\[/tex]

[tex]fw= 0.00389[/tex]

[tex]\to \frac{\bigtriangleup P f_1 s_1}{L}[/tex]

[tex]\to \frac{2 \times 0.00389 \times 1000 \times2.5^2 \times 3.4265}{0.06}\\\\\to 2.78[/tex]

what is local unit?



. ​

Answers

Answer:

Explanation:

Local unit means a county, city, village, or township.

26. Calculate the mass of hydrogen formed when 25 grams of aluminum reacts with excess hydrochloride acid. 2AI + 6HCl →l Al2Cl6 + 3H2

Answers

Answer:

2.76 gram

Explanation:

2AI + 6HCl → 2AlCl3 + 3H2

get the mol of aluminum => n = m / M = 25 / 27 = 0.925 (mol)get the ratio mol of Hydro => nH2 = 0.925 * 3 / 2 = 1.38 (mol)get weight of hydro mH2 = n x M = 1.38 x 2 = 2.76 (gram)

Answer

Al +2 HCl - AlCl2 + H2

what does porous mean​

Answers

Answer:

porous = allowing liquid or air to pass through slowly

I hope it's helpful

Answer:

It is a rock or or other materials, having minutes interstices through which liquid or air may pass.

The diameter of neutral atoms generally decreases going left to right across one period on the periodic table. What change causes this decrease in diameter of atoms?

Answers

Explanation:

Atomic size gradually decreases from left to right across the periodic table because within a period of elements, all electrons are added to the same shell. However, at the same time, protons are being added to the nucleus, making it more positively charged. The effect of increasing proton number is greater than that of the increasing electron number. Therefore, there is a stronger nuclear attraction. This means that the nucleus attracts the electrons more strongly, pulling the atom's electron shells closer to the nucleus. As a result, the atomic diameter of the atom decreases.

List the metals Mg, Cu, Au, Na and Al in the decreasing order of their reactivity with air.

Answers

Answer:

Na is most reactiveAlcuAu is less reactiveIN HERE

Answer:

Potassium  (K)

Sodium  (Na)    

Calcium  (Ca)

Magnesium (Mg)  

Aluminium  (Al)

Iron  (Fe)  

Lead  (Pb)

Copper  (Cu)  

Silver  (Ag)

Gold  (Au)

what is the mass of 1 mole of chlorine ion ​

Answers

Answer:

35.453 g

Explanation:

one mole of chlorine is 34.453 g

Answer:

One mole of chlorine atoms has a mass of 35.453g. A mole of something means that you have 6.023×1023 units of that something. So if you have a mole of Cl atoms you have 6.023×10  

Hope this helps <3

Need thanks? Comment /hearthelp

How much does 9.8 liters of ammonia (NH3) weigh at standard temperature and pressure (273 K and 100 kPa)?
A. 13.84 grams
B. 7.44 grams
C. 17 grams
D. 12.91 grams
Reset Selection

Answers

B.7.33 gramsssss answer

Can someone tell me the advantages and disadvantages of Ceramics? I need scientific, good and clear points! :)

Answers

Advantage
Good conductor of heat
Extreme hard

Disadvantage
Zero ductility
Brittle in nature

Explain the bonding that occurs between sodium and chlorine. Specifically, what kind of bonding takes
place, what’s the name of the resulting compound, and what properties would you expect this compound to
have with respect to water?

Answers

Answer:

About bonding

Explanation:

A chemical bond is a lasting attraction between atoms, ions or molecules that enables the formation of chemical compounds. The bond may result from the electrostatic force of attraction between oppositely charged ions as in ionic bonds or through the sharing of electrons as in covalent bond.

Answer:

An ionic bond occurs between sodium and chlorine where sodium has one  electron while chlorine has seven electrons. The electron from sodium is lost and transferred to a chlorine atom which results in a sodium ion with a charge of one+ and a chloride ion with a charge of one-. These oppositely charged ions attract each other making a balanced charge to make a compound that is electrically neutral.. Sodium cation (Na+) and chlorine anion (Cl-) are attracted to each another to form sodium chloride (table salt). When dissolved in water, the sodium and chloride ions are strongly attracted to the polar water molecules because of ion-dipole interactions.  

Explanation:

3.490x 10^-3 + 1.100x10^-2

[?]x10^[?]​

Answers

[tex]1.44\times 10^{-2}[/tex]

Explanation:

We need to find the value of [tex]3.49\times 10^{-3}+1.1\times 10^{-2}[/tex].

Here,

The first number is [tex]3.49\times 10^{-3}[/tex]

The second number is [tex]1.1\times 10^{-2}[/tex]

To add these numbers as follows :

[tex]3.49\times 10^{-3}+1.1\times 10^{-2}=0.01449\\\\=1.44\times 10^{-2}[/tex]

So, the value of [tex]3.49\times 10^{-3}+1.1\times 10^{-2}[/tex] is [tex]1.44\times 10^{-2}[/tex]

Plsss help with this ASAP TT

Answers

Answer: lithium- 3 protons, 3 electrons, 3 neutrons

Oxygen- nucleon no. 16, Atomic no. 8, 8 protons, overall charge (-2)

Sorry I don't the others. Hope this helps

The number of ATPs per NADH generated by the electron transport system is higher than the number generated per FADH2 because __________. The number of ATPs per NADH generated by the electron transport system is higher than the number generated per FADH2 because __________. NADH is converted to NAD , which increases the charge gradient for ATP synthesis FADH2 has a higher (more negative) redox potential than NADH does electrons from FADH2 are not oxidized all the way to water FADH2 has a lower (less negative) redox potential than NADH does

Answers

Answer:

FADH2 has a lower (less negative) redox potential than NADH does

Explanation:

Flavin Adenine Dinucleotide (FAD) and Nicotinamide Adenine Dinucleotide (NAD) are redox cofactors that play important functions for mitochondrial activity and cellular redox balance. Both coenzymes exist in two forms: an oxidized and a reduced, which are abbreviated as NAD/FAD and NADH/FADH2, respectively. These reduced forms (NADH and FADH2) are produced in the Krebs cycle during respiration. FADH2 has lower redox potential than NADH because FADH2 is only capable of activating 2 proton pumps, while NADH can activate 3 proton pumps during the electron transport chain, thereby FADH2 generates a minor number of ATP molecules than NADH.

Which statement defines an ore?

Answers

Answer:

The third one

Explanation:

An ore is a naturally occurring solid material from which a metal or valuable mineral can be profitably extracted.

What is 16.30 to the 100th gram

Answers

Answer:

1.65485688 × 10121 grams

Explanation:

Aside from those discrete items, anything like rice or flour can be measured out to make up 100 grams. For example, 1/2 cup (125 ml or about 4 and 1/2 fl. oz) of dry rice weighs very close to 100 grams.


500kg, 42m, 675g, and 10m/s are all examples of what typed of data?b

Answers

500kg, 42m, 675g, and 10m/s are all examples of a: continuous data.

A numerical data can be defined as a data set that is expressed in numbers only or a data set consisting of numbers rather than words. A numerical data is also known as a quantitative data.

Generally, numerical data are classified into two (2) main categories and these are;

Discrete data: a discrete data is a data set in which the number of possible values are either finite or countable. Some examples are; the value of a fair die, number of pen in a box, number of eggs in a crate, etc.Continuous data: a continuous data is a data set that has infinitely many possible values and as such those values cannot be counted, which simply means they are uncountable. Any data (quantity) such as mass, height, volume, weight, density, velocity, length, pressure, temperature, speed, distance, time are generally classified as continuous data.

In conclusion, mass (500 kg), height (42m), mass (675g), and speed (10m/s) are all examples of a: continuous data.

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What are differences between viruses and bacteria?

Answers

Answer:

viruses are computer program that replicate itself and distribute itself to another computer but bacteria is micro organism that contaminate our food and can make us sick

What are the requirements of any hypothesis in science?

Answers

Answer:

A scientific hypothesis must meet 2 requirements:

Explanation:

A scientific hypothesis must be testable, and;

A scientific hypothesis must be falsifiable.

What does empirical fomula means with examples ​

Answers

scienece of the end. kindgoms will do

Suppose you were given a substance and asked
to determine whether or not it was a plasma. Write
the characteristics you would look for to identify
the substance.

Answers

Answer:Particles in plasmas collide more often.

Plasma particles have high kinetic energy (they move quickly).

Plasma particles are far apart.

The ionized particles have no fixed volume

Explanation:

Plasma is the fourth form of matter which has freely moving electrons in it. The substance can be identified as plasma if its particles collide often and are far apart.

What is plasma?

Plasma is a type of matter other than solids, liquids, and gas. They have similar properties to that of gas. Plasma particle collides are often like gases as they move freely in space. Like gases that have no definite shape and volume.

The plasma particles have ionic charges, positive and negative resulting in high kinetic energy. This property allows them to show electromagnetism and electrical conductivity.

The ionized particles are due to the high temperature that allows them to have the property of electrical conductivity and compression.

Therefore, the particles of plasma are ionized and have high kinetic energy.

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In the figure a cyclist moves A to B and then to C.he could also go through the shortest path AC. Depending on this fact solve the following questions: Find the length of AC .Find the displacement and total distance covered.​

Answers

Answer:

hope it helps you see the attachment for further information

what is the correct electron configuration for an element with five electrons in the third energy level

Answers

That would be phosphorus. It’s electron configuration is 1s^2 2s^2 2p^6 3s^2 3p^3

[tex]1s^2 2s^2 2p^6 3s^2 3p^3[/tex] is the correct electron configuration for an element with five electrons in the third energy level.

What are elements?

Elements are the simplest substances which cannot be broken down using chemical methods.

The shell nearest to the nucleus, 1n, can carry two electrons, while the next shell, 2n, can carry eight, and the third shell, 3n, can carry up to eighteen.

The third shell carries 18 electrons; 2 in a 3s orbital; 6 in three 3p orbitals; and 10 in five 3d orbitals. The fourth shell carries  32 electrons; 2 in a 4s orbital; 6 in three 4p orbitals; 10 in five 4d orbitals; and 14 in seven 4f orbitals.

The element would be phosphorus. Its electron configuration is [tex]1s^2 2s^2 2p^6 3s^2 3p^3[/tex]

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In what way does the passage is text structure You are considering buying a perpetuity contract from your insurance company that will pay you $500 annually where the payment will grow by 3% each year. Using a discount rate of 9%, the most you should be willing to pay for this contract is closest to: How is fine art and applied art the same The solubility of solids______ when the temperature is increased.A. increasesB. decreasesC. does not change PLEASE HELP MEEEEEEEEEEEEEEE 3 people can fix a road in 5 hours how long would it take 4 people give your answer in minutes Two of the lights at the local stadium are flickering. They both just flickered at the same time.One of the lights flickers every 7 seconds and the other light flickers every 8 seconds.How many seconds until both lights will flicker at the same time again?seconds Please help its due in 30 minutes will mark braniliest what type of image is formed by a lens if m = -0.87 A. The image is larger than the object and the image is real B. The image is smaller than the object and the object is real C. The image is larger than the object and is virtualD. The image is smaller than the object and is virtual What is the following simplified product? Assume x greater-than-or-equal-to 0 (StartRoot 10 x Superscript 4 Baseline EndRoot minus x StarRoot 5 x squared EndRoot) (2 StartRoot 15 x Superscript 4 Baseline EndRoot + StartRoot 3 x cubed EndRoot) 10 x Superscript 4 Baseline StartRoot 6 EndRoot + x cubed StartRoot 30 x EndRoot minus 10 x Superscript 4 Baseline StartRoot 3 EndRoot + x squared StartRoot 15 x EndRoot 11 x Superscript 4 Baseline StartRoot 6 EndRoot + x cubed StartRoot 30 x EndRoot minus x Superscript 4 Baseline StartRoot 75 EndRoot + x squared StartRoot 15 EndRoot 10 x Superscript 4 Baseline StartRoot 6 EndRoot + x cubed StartRoot 30 x EndRoot minus 10 x Superscript 4 Baseline StartRoot 3 EndRoot minus x squared StartRoot 15 EndRoot 11 x Superscript 4 Baseline StartRoot 6 EndRoot + x cubed StartRoot 30 x EndRoot minus 10 x Superscript 4 Baseline StartRoot 3 EndRoot minus x cubed StartRoot 15 x EndRoot can anyone write a response to this and try to make it sound like a 7th grade typed it pleasee write a c program to display the series: 1,8,27,64,125 find the total surface area of this square based pyramid Exercise 1: Put the verbs in brackets into the present perfect or the present perfect progressive1. I _______just ________my book.( finish) 2. He _______already _____________his lessons. ( prepare) 3. He ___________my sister since he was very young.(love) 4. We ___________________El for 4 years.(learn) 5. I ________________for two hours (wait), but she ________________yet. ( not come)6. This is the first time I _____________________to Paris. ( be)7. I_______________ that film several times because I like it. ( see)8. I __________________that novel written by Hemingway several times before. ( read)9. Up to the present / So far, we _______________almost every lesson in the book. ( write)10. We____________________to New York lately. (travel) 11. I ______________________him recently (not see)12. __________you ever _________________Huong Pagoda? ( visit)13. You look hot- Yes, I _______________________ (run)14. Carol _________________________on the phone for two hours. ( talk)15. Wheres Sarah? Shes outside. She __________the gardening all this morning. ( do)16. My sister _______________for you since yesterday. ( look)17. I ________________ all afternoon (run)18. She __________________ to meet him all day ( hope)19. I ____________ never __________her before ( see)20. _________ he __________ the report since this morning? (type)Exercise 2: Choose the best answer1. We often __________e-mail to keep in touch with our friends. A. use B. is using C. uses D. have used2. Nicola and Peter always ______________the lesson carefully before going to school. A. prepares B. prepared C. have prepared D. prepare3. It ____________now. Lets find somewhere to hide.A. rains B. is raining C rained D. was raining4. ______________their holidays in Canada every year ? A. Do they spend B. Did they spend C. Have they spent D. Are they spending5. I ___________________to Mom right now. Do you want to say anything to her? A. wrote B. am writing C. had written D. writeGVBM: Nguyn Th Ngc Dip6. I ___________in this house since I___________________born. A. lived / was B. have lived / were C. had lived / am D. have lived / was7. I usually ______________to school by bus. A. went B. am going C. go D. have gone8. How long ___________you ____________her ? For five months. A. do / know B. are / knowing C. have / known D. had / known9. Please dont make so much noise. I ______________. A. studying B. study C. am studying D. studied10. George _______me from Italy. A. has just called B. had just called C. has called just D. just had called11. It _________now. It ________raining two hours ago. So it ________for two hours. A. is raining / began / has rained B. is raining / begun / rained C. rains / began / has rained D. is raining / begun / have rained 12. Mike is playing chess. How long _________he ___________? A. did / play B. is / playing C. has / play D. has / been playing13. My sister __________for you since yesterday. A. is looking B. was looking C. has been looking D. looked 14. We ______________Dorothy since last Saturday. A. dont see B. havent seen C. didnt see D. hadnt seen15. Mary _______________her parents since last Christmas / 2011. A. havent visited B. hasnt visited C. doesnt visit D. isnt visit16. This is the first time I _____________________to Paris. A. am B. have been C. am being D. havent been17. I_______________that film several times because I like it. A. have seen B. havent seen C. dont see D. am seeing18. I __________________that novel written by Hemingway several times before. A. read B. am reading C. have read D. have been read19. Up to the present / So far, we _______________almost every lesson in the book. A. write B. have written C. are writing D. hasnt written20. Fred usually ______________to work, but this week he ____________his car. A. walks / is driving B. walks / drives C. has walked / drives D. is walking / drive The end A device driver would ordinarily be written in :__________ a. machine language b. assembly language c. a platform-independent language, such as Java d. an application-oriented language Which events added to Americans fear of attack by the Soviet Union? (choose all that apply) Group of answer choices the 1956 Olympic Games the U-2 incident first test of a Soviet atomic bomb the Sputnik launch inscribed angles. I need answers asap, thank you! Need help with this ASAP , no need for an explanation, just the answer. Angles and are angles in standard position such that:sin = -5/13 and terminates in Quadrant III tan = -8/15 and terminates in Quadrant II Find sin( + ). Summary should be made up of which of the following A. Important details and interesting detailsB. Main idea and important details C. Main idea and writers thoughts and feelingD. Important details and writers opinion