Answer:
2/3×3/5=2/3. 3/4×1/6=1/8
2/3-1/8=11/40
Answer:
[tex] \boxed{ \frac{11}{40} }[/tex]Step-by-step explanation:
[tex]( \frac{2}{3} \times \frac{3}{5} ) - ( \frac{3}{4} \times \frac{1}{6} )[/tex]
Reduce the numbers with Greatest common factor 3
⇒[tex] \mathsf{(2 \times \frac{1}{5} ) - ( \frac{1}{4} \times \frac{1}{2} )}[/tex]
Calculate the product
⇒[tex] \mathsf{( \frac{2}{5} )- ( \frac{1}{4} \times \frac{1}{2}) }[/tex]
Subtract the fractions
⇒[tex] \mathsf{ \frac{2 \times 8 - 1 \times 5}{40} }[/tex]
⇒[tex] \mathsf{ \frac{16 - 5}{40} }[/tex]
⇒[tex] \mathsf{ \frac{11}{40} }[/tex]
Hope I helped!
Best regards!
If triangle ABC has the following measurements, what is the measure of angle B? a=5 b=7 c=10
Answer: about 40.54°
Step by step explanation:
7^2 = 5^2 + 10^2 - 2(5)(10)cos(B)
cos(B) = (7^2 - 5^2 - 10^2) / (-2(5)(10) )
B = cos-1 [ (7^2 - 5^2 - 10^2) / (-2(5)(10) ] = cos-1 (.76) = about 40.54°
A person of height 2m observes the angle of elevations of the top of a Pole 62m height which is in front of him and finds it to be 45. find the distance between the person end the pole .
For the function F defined by F(x) = x^2 – 2x + 4, find F(| – 4|).
| - 4 | = 4
Thus :
f ( | - 4 | ) = f ( 4 )
f ( 4 ) = ( 4 )^2 - 2(4) + 4
f ( 4 ) = 16 - 8 + 4
f ( 4 ) = 16 + 4 - 8
f ( 4 ) = 20 - 8
f ( 4 ) = 12
Four friends go to the movies. How many different ways can they sit in a row?
Answer:
120 ways
..................
Answer:
24
Step-by-step explanation:
4 friends
1st seat: 4 different people could sit here
Now there are 3 friends left
2nd seat: 3 different people could sit here
Now there are 2 friends left
3rd seat: 2 different people could sit here
Now there are 1 friends left
4th seat: 1 different people could sit here
4*3*2*1
24 ways
1.Write 32 1/2 in radical form
Answer:
√32
Step-by-step explanation:
An agriculture company is testing a new product that is designed to make plants grow taller. This can be thought of as a hypothesis test with the following hypotheses. H0: The product does not change the height of the plant. Ha: The product makes the plant grow taller. Is the following an example of a type I or type II error? The sample suggests that the product makes the plant grow taller, but it actually does not change the height of the plant.
Answer:
hi
Step-by-step explanation:
hji
49, 34, and 48 students are selected from the Sophomore, Junior, and Senior classes with 496, 348, and 481 students respectively. Group of answer choices
Answer:
Stratified Random sampling.
Step-by-step explanation:
As per the scenario, It is stratified random sampling as it divides students into strata which represent Sophomores, Juniors, and Seniors.
Simple random samples of the given sizes of the proportional to the size of the stratum which is to be taken from every stratum that is to be about 10 percent of students from every class that is selected here.
Hence, according to the given situation, the correct answer is a random stratified sampling.
What is the simplified form of square root 400 x to the power 100
Step-by-step explanation:
[tex]thank \: you[/tex]
Answer:
20x⁵⁰
Step-by-step explanation:
With the equation √400x¹⁰⁰
we need to take the square root away separately
√400 = √20*20 = 20
Then with x¹⁰⁰
√x¹⁰⁰ = √x⁵⁰*x⁵⁰ = x⁵⁰
So √400x¹⁰⁰ = 20x⁵⁰
hope this helps
Help ASAP Marly has to get some cavities filled at the dentist. The dentist charges a fee of $35 plus $43 per cavity. If Marly ends up having a bill of $164 and c represents the number of cavities, which of the following equations could be used to find how many cavities Marly had filled?
35 = 164 + 43c
164 = 35 - 43c
164 = 35c + 43
35 + 43c = 164
Answer:
the answer is d i believe.
Answer:
The answer is D I took the test the other person is right!
Step-by-step explanation:
Kelly bought a cup of coffee and drank 58 of it. Write an addition equation to represent how much coffee is remaining.
Answer:
[tex]L + \frac{5}{8} = 1[/tex]
Step-by-step explanation:
Given
A cup of coffee
Kelly drank 5/8 of the coffee
Required
Determine how much is left
Start by representing the amount of coffee left with L
Because the amount of coffee Kelly drank is in fraction (5/8), the total cup of coffee will equate to 1;
Hence, the addition equation as requested in the question to represent the scenario is
[tex]L + \frac{5}{8} = 1[/tex]
If a=2b=2c find the value of each.
Answer:
b=a/2
c=a/2
b=c
a=2b and a=2c
Find the P-value in a test of the claim that the mean IQ score of acupuncturists is equal to 100, given that the test statistic is z2.00.
Answer:
P-value = 0.0455
Step-by-step explanation:
In this question, we are concerned with calculating the P- value in a test.
Mathematically we know that;
P-value = 2 * P(Z > |z|)
Please check attachment for complete solution and by step explanation
bon
Question 21
O pts
The recipe for a s'more is as follows:
1 graham cracker
chocolate bar
2 marshmallows
If you have 10 graham crackers, 7 marshmallows, and 5 chocolate bars, how many
complete s'mores can you make using this recipe?
Question 22
O pts
Answer:
3 s'mores
Step-by-step explanation:
If we center our attention on how many marshmallows you need per s'more which is 2 and you only have 7 you can only make 3 with one marshmallow remaining.
Which of the following expression is equal to X^2+9
Answer:
(x + 3i) * (x - 3i) = x^2 + 3xi - 3xi - 9(i^2) = x^2 + 9
Step-by-step explanation:
I will mark as brainliest:)
Answer:
Cube C
Step-by-step explanation:
[tex]{ \sf{because \: it \: is \: identical}}[/tex]
Suppose you do not know the population mean fee charged to H&R Block customers last year. Instead, suppose you take a sample of size n-8 and find a sample mean of 350. Assume that the distribution for fees is normally distributed with a sample standard deviation of $100.
i. Before conducting the survey, suppose you believed based on your previous observations, your best guess for population standard deviation of fee charged to H&R Block is $50. With this assumption in mind, What should your sample size n approximately be if you want:
Margin-of-Error of to be 2 % and confidence level to be 95 %?
Margin-of-Error of to be 4% and confidence level to be 95%?
Margin-of-Error of to be 4 % and confidence level to be 99%?
ii. 90% confidence interval for the population mean of fees H&R Block.
a. Calculate the margin of error (MOE) of x using a 10% significance level.
b. Calculate the 90 % confidence interval.
c. Suppose an analyst belief that the population mean fee is equal to $185. Using a 90% confidence level. can we conclude the analyst is right? Why or why not?
Answer:
i [tex]\to[/tex] a
[tex]n = 96040000[/tex]
i [tex]\to[/tex] b
[tex]n_1 =24010000[/tex]
i [tex]\to[/tex] c
[tex]n_2 =41602500[/tex]
ii[tex]\to[/tex]a
[tex]E = 58.16[/tex]
ii[tex]\to[/tex]b
[tex]291.84 < \mu < 408.16[/tex]\
ii[tex]\to[/tex]c
There is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval
Step-by-step explanation:
From the question we are told that
The sample size is [tex]n = 8[/tex]
The sample mean is [tex]\= x = \$ 350[/tex]
The sample standard deviation is [tex]\$ 100[/tex]
Considering question i
i [tex]\to[/tex] a
At [tex]E = 0.02[/tex]
given that the confidence level is 95% = 0.95
the level of significance would be [tex]\alpha =1-0.95 = 0.05[/tex]
The critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table is
[tex]Z_{\frac{ \alpha }{2} } = 1.96[/tex]
So the sample size is mathematically evaluated as
[tex]n = [ \frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ]^2[/tex]
=> [tex]n =[ \frac{ 1.96 * 100}{ 0.02} ]^2[/tex]
=> [tex]n = 96040000[/tex]
i [tex]\to[/tex] b
At [tex]E_1 = 0.04[/tex] and confidence level = 95% => [tex]\alpha_1 = 0.05[/tex] => [tex]Z_{\frac{\alpha_1 }{2} } = 1.96[/tex]
[tex]n_1 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_1} ]^2[/tex]
=> [tex]n_1 =[ \frac{ 1.96 * 100}{ 0.04} ]^2[/tex]
=> [tex]n_1 =24010000[/tex]
i [tex]\to[/tex] c
At [tex]E_2 = 0.04[/tex] confidence level = 99% => [tex]\alpha_2 = 0.01[/tex]
The critical value of [tex]\frac{\alpha_2 }{2}[/tex] from the normal distribution table is
[tex]Z_{\frac{ \alpha_2 }{2} } = 2.58[/tex]
=> [tex]n_2 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_2} ]^2[/tex]
=> [tex]n_2 =[ \frac{ 2.58 * 100}{ 0.04} ]^2[/tex]
=> [tex]n_2 =41602500[/tex]
Considering ii
Given that the level of significance is [tex]\alpha = 0.10[/tex]
Then the critical value of [tex]\frac{\alpha }{2}[/tex] from the normal distribution table is
[tex]Z_{\frac{\alpha }{2} } = 1.645[/tex]
Generally the margin of error is mathematically represented as
[tex]E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }[/tex]
substituting values
[tex]E = 1.645 * \frac{100 }{\sqrt{8} }[/tex]
[tex]E = 58.16[/tex]
Generally the 90% confidence interval is mathematically evaluated as
[tex]\= x - E < \mu < \= x + E[/tex]
=> [tex]350 - 58.16 < \mu < 350 + 58.16[/tex]
=> [tex]291.84 < \mu < 408.16[/tex]
So the interpretation is that there is 90% confidence that the mean fee charged to H&R Block customers last year is in the interval .So there is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval.
This person did something wrong and I do not know what it is :( Please help this is for points!
Answer:
It is, indeed, a reduction. But, the scale factor of the dilation should be a fraction instead of a whole number, since the shape has shrunk.
Instead of [tex]\frac{KN}{K'N'}[/tex], it should be [tex]\frac{K'N'}{KN}[/tex]. That would make it (4 - 2) / (8 - 4) = 2 / 4 = 1/2.
Hope this helps!
If the average(arithmetic mean) of g and 100 is 75,what is the value of g + 100?
The value of g + 100 is 150.
Given that,
The average of g and 100 is 75.
And we have to determine the value of g + 100.
So that means
The arithmetic mean of g and 100 is 75.
So, mathematically it should be
[tex]\frac{g + 100}{2} = 75\\\\[/tex]
So, g + 100 = 150
Therefore we can conclude that the value of g + 100 is 150
Learn more about the mean here: brainly.com/question/11230531
Find the most general antiderivative of the function. (Use C for the constant of the antiderivative).
f(x) = 6x5 − 7x4 − 9x2
F(x) = ?
Answer:
[tex]x^6 - \frac{7x^5}{5} - 3x^3 + C[/tex]
Given m -1/2 & the point ( 3, -6), which is the point slope form of the equation?
Answer:
[tex]y+6=-\frac{1}{2} (x-3)[/tex]
Step-by-step explanation:
Since point-slope form is [tex]y-y1=m(x-x1)[/tex], you have to plug in the values given to you to create the equation. The "y1" is the "y" coordinate given to us, while the x1 is the x coordinate given to us. So, you have to plug in the x and y coordinates, 3 and -6, into the equation. Since two negatives cancel out to be a positive, y--6= y+6. The "m" stands for the slope, so -1/2 is inserted into the equation, giving us [tex]y+6=-\frac{1}{2} (x-3)[/tex].
Question 9
Explain using complete sentences how you would solve for the
variable a in this equation : p = (3a +4)/ b
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12nt
Daragranh
DET
U
A
e
T2
Answer:
To solve for a, you will need to get that variable alone on one side. First you will multiply each side by variable b. This will give you the equation pb = 3a + 4. Next you subtract 4 from each side. This puts it at pb - 4 = 3a. After that you’ll divide both sides by 3 and get a alone. This gives you (pb - 4)/3 = a or, if you switch it around, a = (pb - 4)/3. This is the simplest form when solving for a in this equation.
Answer:
Hello,
All my sentences will be written in mathematical language.
Step-by-step explanation:
[tex]p=\dfrac{3a+4}{b} \\\\p*b=3a+4 \ :\ \forall\ x,y,z\in\mathbb{R},z\neq 0:x=y\Longleftrightarrow\ x*z=y*z\\\\p*b-4=3a \ :\forall\ x,y,z\in\mathbb{R} :x=y\Longleftrightarrow\ x+z=y+z\\\\\dfrac{p*b-4}{3} =a \ :\forall\ x,y,z\in\mathbb{R},z\neq 0:x=y\Longleftrightarrow\ x*z=y*z\\\\a=\dfrac{p*b-4}{3} \ :\forall\ x,y\in\mathbb{R}:x=y\Longleftrightarrow\ y=x[/tex]
how to write this in number form The difference of 9 and the square of a number
Answer:
9-x^2
Step-by-step explanation:
The difference of means subtracting. the first number is 9 and the second is x^2, so you get 9-x^2
Identify the decimals labeled with the letters A, B, and C on the scale below. Letter A represents the decimal Letter B represents the decimal Letter C represents the decimal
[tex]10[/tex] divisions between $15.59$ and $15.6$ so each division is $\frac{15.60-15.59}{10}=0.001$
A is 5 division from $15.59$, so, A is $15.59+5\times 0.001=15.595$
similarly, C is 4 division behind $15.59$ so it is $15.590-4\times0.001=15.586$
and B is $15.601$
Area And Perimeter! Find the Area and the Perimeter of the Triangle!!! and explain.... ( help hurry!!)
perimeter of triangle: P = l+w+h
9+12+10= 31in.
area of triangle: A=b×h÷2
21 + 21 = 42in^2
please help
-3(-4x+4)=15+3x
Answer:
x=3
Step-by-step explanation:
● -3 (-4x+4) = 15 + 3x
Multiply -3 by (-4x+4) first
● (-3) × (-4x) + (-3)×(4) = 15 + 3x
● 12 x - 12 = 15 +3x
Add 12 to both sides
● 12x - 12 + 12 = 15 + 3x +12
● 12 x = 27 + 3x
Substract 3x from both sides
● 12x -3x = 27 + 3x - 3x
● 9x = 27
Dividr both sides by 9
● 9x/9 = 27/9
● x = 3
simplify 27- 9+(12-5)÷4 with solution
Answer:
It's 28 3/4
Step-by-step explanation:
Answer:
Answer is 19.5
Step-by-step explanation:
27-9+(12-5)÷4
27-9+6÷4 [BOD MAS Rule]
27-9+1.5
28.5-9
19.5
A researcher is interested in finding a 95% confidence interval for the mean number of times per day that college students text. The study included 210 students who averaged 28 texts per day. The standard deviation was 21 texts.A. The sampling distribution follows a_______.1. "F"2. "normal"3. "T"4. "Chi-square" B. With 95% confidence the population mean number of texts per day of is between_______and______texts. A. 1. "24.92"2. "25.79"3. "27.37"4. "25.14"B. 1. "31.19"2. "31.20"3. "29.28"4. "30.86" C. If many groups of 210 randomly selected students are studied, then a different confidence interval would be produced from each group. About_______% of these confidence intervals will contain the true population mean number of texts per day and about______% will not contain the true population mean number of texts per day.A. 1. "5"2. "95"3. "1"4. "99"B. 1. "95"2. "99"3. "5"4. "1"
Answer: A. The sampling follows a normal distribution.
B. Between 25.14 and 30.86
C. About 95% will contain the true mean and about 5% won't
Step-by-step explanation: A. The sampling is normally distributed because:
it has a symmetric bell shape, mean and median are both the same and located at the center of graphic, approximately 68% of the data falls within one standard deviation;95% falls within two standard deviations;99.7% within 3 standard deviations;B. For a 95% confidence interval: α/2 = 0.025
Since n = 210, use z-score = 1.96
To calculate the interval:
mean ± [tex]z.\frac{s}{\sqrt{n} }[/tex]
Replacing for the values given:
28 ± [tex]1.96.\frac{21}{\sqrt{210} }[/tex]
28 ± [tex]1.96*1.45[/tex]
28 ± 2.84
lower limit: 28 - 2.84 = 25.14
upper limit: 28 + 2.84 = 30.86
Confidence Interval is between 25.14 and 30.86.
C. Confidence Interval at a certain percentage is an interval of values that contains the true mean with a percentage of confidence. In the case of number of times per day students text, 95% of the interval will contain the true mean, while 5% will not contain it.
It need the answer to these please
hopefully this answer can help you to answer the next question
help me by using formula how did came by reason
Answer:
angleABC=isosceles triangle
angleB=(180-50)÷2=65
angle B=angleX(alternative angle)
angleB=65degree
A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 2 large boxes and 12 small boxes has a total weight of 223 kilograms. A delivery of 5 large boxes and 3 small boxes has a total weight of 139 kilograms. How much does each type of box weigh?
Answer:
A large box weighs 18.5 kilograms and a small box weighs 15.5 kilograms
Step-by-step explanation:
Create a system of equations where l is the weight of one large box and s is the weight of one small box.
2l + 12s = 223
5l + 3s = 139
Solve by elimination by multiplying the bottom equation by -4:
2l + 12s = 223
-20l - 12s = -556
Add these together and solve for l:
-18l = -333
l = 18.5
So, a large box weighs 18.5 kilograms. Plug in 18.5 as l into one of the equations, and solve for s:
5l + 3s = 139
5(18.5) + 3s = 139
92.5 + 3s = 139
3s = 46.5
s = 15.5
A large box weighs 18.5 kilograms and a small box weighs 15.5 kilograms.
9514 1404 393
Answer:
large: 18.5 kgsmall: 15.5 kgStep-by-step explanation:
Two equations for the total weight can be written in general form as ...
2L +12S -223 = 0
5L +3S -139 = 0
These can be solved using the "cross multiplication method" by computing three differences:
d1 = (2)(3) -(5)(12) = 6 -60 = -54
d2 = (12)(-139) -(3)(-223) = -1668 +669 = -999
d3 = (-223)(5) -(-139)(2) = -1115 +278 = -837
Then the weighs of the boxes are ...
1/d1 = L/d2 = S/d3
L = d2/d1 = -999/-54 = 18.5
S = d3/d1 = -837/-54 = 15.5
The large box weighs 18.5 kg; the small box weighs 15.5 kg.
_____
Additional comment
If the coefficients are written in two rows of four numbers, with the first repeated at the end, the pattern of differences can be seen to be (ad -cb) for [a, b] in the first row and [c, d] in the second row of a pair of adjacent columns. This method of solution is fully equivalent to solution using Cramer's Rule for a system of equations represented by a matrix equation.