Hey there!
3 ÷ 10 is 0.3
So, 0.3 ÷ 6 = x
x = 0.05
Hope this helps! Have a wonderful day!
Answer: 0.05 or [tex]\frac{1}{20}[/tex]
Step-by-step explanation:
We can solve this in 2 ways :
1st Method :
In the first method, we will keep 3/10 as a fraction
[tex]\frac{3}{10}[/tex] ÷ 6
= [tex]\frac{3}{10}[/tex] × [tex]\frac{1}{6}[/tex]
Since 3 and 6 is divisible, we can cancel them
Answer: [tex]\frac{1}{20}[/tex] or 0.05
2nd Method :
3 ÷ 10 =0.3
0.3 ÷ 6
=0.05
Please help
A) y< 2x+4
B) y< 1/2x+3
C)y> 1/2x+3
D) y> 2x+3
Answer:
B
Step-by-step explanation:
if it is shaded under than it is <
the slope is 1/2x so that is the answer
3. Solve 2log4y - log4 (5y - 12) = 1/2
Answer:
y = 4 or y = 6
Step-by-step explanation:
2log4y - log4 (5y - 12) = 1/2
2log_4(y) - log_4(5y-12) = log_4(2) apply law of logarithms
log_4(y^2) + log_4(1/(5y-12)) = log_4(/2) apply law of logarithms
log_4(y^2/(5y-12)) = log_4(2) remove logarithm
y^2/(5y-12) = 2 cross multiply
y^2 = 10y-24 rearrange and factor
y^2 - 10y + 24 = 0
(y-4)(y-6) = 0
y= 4 or y=6
Let a1, a2, . . . , a2019 be a sequence of real numbers. For every five indices i, j, k, `, and m from 1 through 2019, at least two of the numbers ai , aj , ak, a` , and am have the same absolute value. What is the greatest possible number of distinct real numbers in the given sequence
There are at most 4 distinct absolute values of elements taken from this sequence. (If there were at least 5 distinct absolute values, then you could pick [tex]a_i,a_j,a_k,a_\ell,a_m[/tex] each with different absolute values, but that would contradict the given statement "for every five indices ... at least two of ... have the same absolute value".)
The pigeonhole principle then says that 2 of any 5 numbers taken from this sequence have the same absolute value. Both |x| = x and |-x| = x, so there can be at most 8 distinct numbers in the sequence.
cuantos son 4 elevado a 4???
Answer:Answer and Explanation:
When a number is said to be 'to the fourth power,' that just means that you need to multiply the number by itself four times. For example, 7 to the...
Step-by-step explanation:
Can someone please help me with these 7 questions please?
The solution to each of the question takes different approach, as the questions are taken from different concepts; however, a common operation among all questions, is factorization.
[tex](1)\ (-xy)^3(xz)[/tex]
Expand
[tex](-xy)^3(xz) = (-x)^3* y^3*(xz)[/tex]
[tex](-xy)^3(xz) = -x^3* y^3*xz[/tex]
Rewrite as:
[tex](-xy)^3(xz) = -x^3*x* y^3*z[/tex]
Apply law of indices
[tex](-xy)^3(xz) = -x^4y^3z[/tex]
[tex](2)\ (\frac{1}{3}mn^{-4})^2[/tex]
Expand
[tex](\frac{1}{3}mn^{-4})^2 =(\frac{1}{3})^2m^2n^{-4*2}[/tex]
[tex](\frac{1}{3}mn^{-4})^2 =\frac{1}{9}m^2n^{-8[/tex]
[tex](3)\ (\frac{1}{5x^4})^{-2}[/tex]
Apply negative power rule of indices
[tex](\frac{1}{5x^4})^{-2}= (5x^4)^2[/tex]
Expand
[tex](\frac{1}{5x^4})^{-2}= 5^2x^{4*2}[/tex]
[tex](\frac{1}{5x^4})^{-2}= 25x^{8[/tex]
[tex](4)\ -x(2x^2 - 4x) - 6x^2[/tex]
Expand
[tex]-x(2x^2 - 4x) - 6x^2 = -2x^3 + 4x^2 - 6x^2[/tex]
Evaluate like terms
[tex]-x(2x^2 - 4x) - 6x^2 = -2x^3 -2x^2[/tex]
Factor out x^2
[tex]-x(2x^2 - 4x) - 6x^2 = (-2x-2)x^2[/tex]
Factor out -2
[tex]-x(2x^2 - 4x) - 6x^2 = -2(x+1)x^2[/tex]
[tex](5)\ \sqrt{\frac{4y}{3y^2}}[/tex]
Divide by y
[tex]\sqrt{\frac{4y}{3y^2}} = \sqrt{\frac{4}{3y}}[/tex]
Split
[tex]\sqrt{\frac{4y}{3y^2}} = \frac{\sqrt{4}}{\sqrt{3y}}[/tex]
[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2}{\sqrt{3y}}[/tex]
Rationalize
[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2}{\sqrt{3y}} * \frac{\sqrt{3y}}{\sqrt{3y}}[/tex]
[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2\sqrt{3y}}{3y}[/tex]
[tex](6)\ \frac{8}{3 + \sqrt 3}[/tex]
Rationalize
[tex]\frac{8}{3 + \sqrt 3} = \frac{3 - \sqrt 3}{3 - \sqrt 3}[/tex]
[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{(3 + \sqrt 3)(3 - \sqrt 3)}[/tex]
Apply difference of two squares to the denominator
[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{3^2 - (\sqrt 3)^2}[/tex]
[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{9 - 3}[/tex]
[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{6}[/tex]
Simplify
[tex]\frac{8}{3 + \sqrt 3} = \frac{4(3 - \sqrt 3)}{3}[/tex]
[tex](7)\ \sqrt{40} - \sqrt{10} + \sqrt{90}[/tex]
Expand
[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =\sqrt{4*10} - \sqrt{10} + \sqrt{9*10}[/tex]
Split
[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =\sqrt{4}*\sqrt{10} - \sqrt{10} + \sqrt{9}*\sqrt{10}[/tex]
Evaluate all roots
[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =2*\sqrt{10} - \sqrt{10} + 3*\sqrt{10}[/tex]
[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =2\sqrt{10} - \sqrt{10} + 3\sqrt{10}[/tex]
[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =4\sqrt{10}[/tex]
[tex](8)\ \frac{r^2 + r - 6}{r^2 + 4r -12}[/tex]
Expand
[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r^2 + 3r-2r - 6}{r^2 + 6r-2r -12}[/tex]
Factorize each
[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r(r + 3)-2(r + 3)}{r(r + 6)-2(r +6)}[/tex]
Factor out (r+3) in the numerator and (r + 6) in the denominator
[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{(r -2)(r + 3)}{(r - 2)(r +6)}[/tex]
Cancel out r - 2
[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r + 3}{r +6}[/tex]
[tex](9)\ \frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14}[/tex]
Cancel out x
[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x^2 - 5x - 14}[/tex]
Expand the numerator of the 2nd fraction
[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x^2 - 7x+2x - 14}[/tex]
Factorize
[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x(x - 7)+2(x - 7)}[/tex]
Factor out x - 7
[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{(x + 2)(x - 7)}[/tex]
Factor out 4 from 4x + 8
[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4(x + 2)}{x} \cdot \frac{1}{(x + 2)(x - 7)}[/tex]
Cancel out x + 2
[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4}{x} \cdot \frac{1}{(x - 7)}[/tex]
[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4}{x(x - 7)}[/tex]
[tex](10)\ (3x^3 + 15x^2 -21x) \div 3x[/tex]
Factorize
[tex](3x^3 + 15x^2 -21x) \div 3x = 3x(x^2 + 5x -7) \div 3x[/tex]
Cancel out 3x
[tex](3x^3 + 15x^2 -21x) \div 3x = x^2 + 5x -7[/tex]
[tex](11)\ \frac{m}{6m + 6} - \frac{1}{m+1}[/tex]
Take LCM
[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m(m + 1) - 1(6m + 6)}{(6m + 6)(m + 1)}[/tex]
Expand
[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m^2 + m- 6m - 6}{(6m + 6)(m + 1)}[/tex]
[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m^2 - 5m - 6}{(6m + 6)(m + 1)}[/tex]
[tex](12)\ \frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}}[/tex]
Rewrite as:
[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} \div \frac{2}{y^2 - 9}[/tex]
Express as multiplication
[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{y^2 - 9}{2}[/tex]
Express y^2 - 9 as y^2 - 3^2
[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{y^2 - 3^2}{2}[/tex]
Express as difference of two squares
[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{(y - 3)(y+3)}{2}[/tex]
[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{1} * \frac{(y+3)}{2}[/tex]
[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{y+3}{2}[/tex]
Read more at:
https://brainly.com/question/4372544
Find the coordinates of U' after a reflection across parallel lines; first across the line x=-2 and then across the line x=-1 write your answer in form (a,b)
Answer:
U in the line x=-2: (-4,0)
U in the line x=-1: (-2-0)
Step-by-step explanation:
...............
In the function f(x) = 4(x2 − 6x + ____) + 20, what number belongs in the blank to complete the square?
Answer:
9
Step-by-step explanation:
6x=2*x*(a number), (a number)^2=the number we need. A number=3, the number is 3^2=9
Question 5 10 pts Which function represents the inverse of f(x) = (x + 6)2 - 5? of 1(1) = V1 + 5 - 6 of '(x) = (x + 5)2 - 6 of '(x) = V1 – 6 + 5 Of '(x) = (x + 6 – 5
Answer:
f(x)^-1(x) =sqrt(x+5) -6
Step-by-step explanation:
f(x) = (x + 6)^2 - 5
y = (x + 6)^2 - 5
Exchange x and y and solve for y
x = (y + 6)^2 - 5
Add 5 to each side
x+5 = (y + 6)^2 - 5+5
x+5 = (y + 6)^2
Take the square root of each side
sqrt(x+5 )= sqrt( (y + 6)^2 )
sqrt(x+5 )=(y + 6)
Subtract 6 from each side
sqrt(x+5 ) -6=y + 6-6
sqrt(x+5) -6 = y
Vertices name in triangle A B C
Answer:
The answer is B.
I think I answered the wrong answer.
Find the formula for the 4th of the following A.P.S a)3,7,11........ b)12,7,2.......
Answer:
A = 15
B = -3
Step-by-step explanation:
3 ,7,11..... You add 4 each time so 11+4 is 15
12,7,2.... You take 5 each time so 2-5 is -3
Rory records the percentage of battery life remaining on his phone throughout a day. The battery life decreases as Rory uses the phone, but will increase or stay at 100% while charging. The graph represents the percentage of battery life remaining after a certain number of hours.
A graph titled Phone Battery Life. The horizontal axis shows Elapsed Time (hours) numbered 2 to 20, and the horizontal axis shows Battery Life (%) numbered 10 to 120. A line begins at 100% in 0 hours, to 20% in 8 hours, to 100% from 10 to 12 hours, to 60% in 16 hours, to 100% from 17 to 20 hours.
At which times could Rory's phone have been plugged into the charger? Select three options.
Answer:
9 hours
11 hours
19 hours
Step-by-step explanation:
The graph represents the percentage of battery life remaining after a certain number of hours is attached below.
At which times could Rory's phone have been plugged into the charger? Select three options.
6 hours
9 hours
11 hours
14 hours
19 hours
Answer: From the graph, the line segment with negative slope (that is decreasing value) shows that the phone is not plugged but being used while the line segment with positive slope (increasing value) or stays at 100% shows that the phone is plugged to the charger.
As shown, from 0 to 8 hours their is a decreasing value, the phone is not plugged. From 8 to 10 hours their is an increasing value therefore the phone is plugged also from 10 to 12 hours the phone is plugged since it is constant. From 12 to 16 hours it is not plugged. From 16 to 18 hours it is plugged and from 18 to 20 hours it is plugged.
From the options it is plugged at 9 hours, 11 hours and 19 hours
Answer:
B - 9 HOURS
C - 11 HOURS
E - 19 BHOURS
Step-by-step explanation:
i took the test
a broker gets rs 20000 as commission from sale of a piece of land which costs rs 8000000. Find the rate of commission.
Answer:
0.25%
Step-by-step explanation:
Rate of commission
= (commission*100)/cost of land
=( 20000*100)/8000000
= 2000000/8000000
=2/8
= 0.25%
Which statement is true regarding the traits of scatterplots?
A) The strength of a correlation is independent of whether the correlation of a scatterplot is positive or negative. A scatterplot with positive correlation can have either weak correlation or strong correlation.
B) The slope of a line is independent of whether the correlation of a scatterplot has positive or negative correlation. A scatterplot with a negative slope can have either positive correlation or negative correlation.
C) The nonlinear association of a scatterplot depends on whether it has a weak or strong correlation. A scatterplot with nonlinear association will have a strong correlation.
D) The nonlinear association of a scatterplot depends on whether it has a positive or negative correlation. A scatterplot with nonlinear correlation will have a negative correlation.
Answer:
The strength of a correlation is independent of whether the correlation of a scatterplot is positive or negative. A scatterplot with positive correlation can have either a weak correlation or strong correlation.
Step-by-step explanation:
Answer:
The answer to your question would be A.) The strength of a correlation is independent of whether the correlation of a scatterplot is positive or negative. A scatterplot with positive correlation can have either weak correlation or strong correlation.
Step-by-step explanation:
I got it right on edge 2020
PLEASE HELP, WILL GIVE BRAINLIEST The number of views on an interesting video after it's uploaded is represented by the following table: Time (days) Views 000 101010 444 452452452 888 889889889 121212 133013301330 161616 177017701770 202020 221122112211 Which model for V(t)V(t)V, left parenthesis, t, right parenthesis, the number of views ttt days after it's uploaded, best fits the data?
Answer:
Option C
Step-by-step explanation:
Options A, B, C, and D all satisfy the base case of V(0) = 10; however, they also all fail the next step case of V(4) = 452.
A at t = 4, results in 163047.361
B at t = 4, results in 1770
C at t = 4, results in 450 (close but not 452)
D at t = 4, results in 41740124.42
Note that at option C, we had the closet value 450 which is only 2 from 452 whereas the next closet was 1218 away.
Choose option C as the curve of best fit.
Cheers.
Answer:
c
Step-by-step explanation:
1. Solve the equation: - 2x + 8 = 3x + 14
-2x + 8 = 3x + 14
-2x - 3x = 14 - 8
-5x = 6 / : (-5)
x = -1,2
Answer: x = -6/5
Step-by-step explanation:
Given equation
-2x + 8 = 3x + 14
Subtract 3x on both sides
-2x + 8 - 3x = 3x + 14 - 3x
-5x + 8 = 14
Subtract 8 on both sides
-5x + 8 - 8 = 14 - 8
-5x = 6
Divide -5 on both sides
-5x / -5 = 6 / -5
[tex]\boxed{x = -\frac{6}{5} }[/tex]
Hope this helps!! :)
Please let me know if you have any questions
Find the value of x.
76
Katie brought 5/6 pounds of candy to a slumber party tori brought 1/3 pound of candy how much candy did the girls have altogether
Answer:
1 [tex]\frac{1}{6}[/tex] pounds of candy
Step-by-step explanation:
Add together the fractions by creating a common denominator of 6:
[tex]\frac{5}{6} + \frac{1}{3}[/tex]
[tex]\frac{5}{6} + \frac{2}{6}[/tex]
= [tex]\frac{7}{6}[/tex]
Simplify into a mixed fraction:
= 1 [tex]\frac{1}{6}[/tex]
So, the girls had 1 [tex]\frac{1}{6}[/tex] pounds of candy
If the measure of angle 4 is (11 x) degrees and angle 3 is (4 x) degrees, what is the measure of angle 3 in degrees?
Answer:
is it 2
Step-by-step explanation:
Use the distributive property to clear parentheses
Answer:
18z + 24
Step-by-step explanation:
The distributive property is the multiplication of the number outside the parenthesis with the numbers inside.
All you need to do to solve this is to multiply 6 with 3z, and 6 with 4.
6 × 3 = 18 =
18z
6 × 4 = 24
Put them together:
18z + 24
Another way to do this:
6 times a number increased by 11 is equal to 17. What is the number?
Let the no be x
ATQ
[tex]\\ \sf\longmapsto 6x+11=17[/tex]
[tex]\\ \sf\longmapsto 6x=17-11[/tex]
[tex]\\ \sf\longmapsto 6x=6[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{6}{6}[/tex]
[tex]\\ \sf\longmapsto x=1[/tex]
Answer:
1
Step-by-step explanation:
let the number be x
and solve it
how do I do this and what is the answer?
Answer:
4
plug in -1 for all the x's
3 + 2 + 7 = 12 (remeber that -1 *-1 = + 1 and that -2*-1 = + 2
-2+ 5 = + 3
12/3 = 4
Step-by-step explanation:
look at picture and solve
Answer:
79°
Step-by-step explanation:
PQO is straight angle with measure of 180°
the given angles' sum makes 101° and we need 79 to complete it to 180° therefore the angle STQ = 79°
square root of 3x^4 times square root of 5x^2 times square root of 10.
Multiply and remove all perfect squares from inside the square roots. Assume x is positive.
Answer:
[tex]5x^3\sqrt{6}[/tex]
Step-by-step explanation:
We need to simplify
[tex]\sqrt{3x^4}\times\sqrt{5x^2}\times\sqrt{10}[/tex]
Right away we can take out the perfect squares. Remember a perfect square is the result of multiplying any value by itself.
[tex]= x^2\sqrt{3}\times x\sqrt{5}\times\sqrt{10} \\= x^3\sqrt{3\times 5 \times 10}\\= x^3\sqrt{3 \times 5 \times 5 \times 2 }\\= 5x^3\sqrt{6}[/tex]
The square root of 3x⁴ times square root of 5x² times square root of 10, the product of all the term is, 5x³ [tex]\sqrt{6}[/tex]
What is square root?In mathematics, square roots is a concept in which, if we multiply square roots of any number by itself then it will give us an original number.
if 'a' is square root of 'b' then it will represent as, a = √b.
Given that,
three terms,
[tex]\sqrt3{x^{4} }[/tex]
[tex]\sqrt{5x^{2} }[/tex]
[tex]\sqrt{10}[/tex]
by multiplying all the three terms,
⇒ [tex]\sqrt3{x^{4} }[/tex] × [tex]\sqrt{5x^{2} }[/tex] × [tex]\sqrt10} }[/tex]
⇒ √(3x⁴×5x²10)
⇒ √ 150x⁶
⇒ 5x³ [tex]\sqrt{6}[/tex]
Hence, the product is 5x³ [tex]\sqrt{6}[/tex]
To know more about square root check:
https://brainly.com/question/29286039
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Find the difference between8/15 and −2/3. Show all calculations in your final answer.
Answer:
6/5
Step-by-step explanation:
8/15 - (-2/3)
8/15 + 2/3
24 + 30/45
54/45 = 6/5
Thus, the difference between 8/15 and -2/3 is 6/5
Start by changing the minus a negative to plus a positive.
So we have 8/15 + 2/3.
To add these two fractions together, we need a common denominator.
The common denominator is simply the
least common multiple for the two denominators.
You should find that the least common multiple is 15.
Since 8/15 already has 15 as its denominator, leave it.
To get a denominator of 15 in 2/3, we multiply top
and bottom of 2/3 by 5 to get 10/15.
So we have 8/15 + 10/5.
This simplifies to 18/15.
Now reduce to get 6/5.
if l=5 and b=3 find the value of 2 (l+b)
Answer:
16
Step-by-step explanation:
2 (l+b)
Let l=5 and b=3
2 (5+3)
Parentheses first
2(8)
Multiply
16
Answer:
16
Step-by-step explanation:
Plug in:
2 (l + b)
2 (5 + 3)
2 (8)
16
Hope this helped.
A number if that number and the number b sum to 40.
Answer:
40-b
Step-by-step explanation:
x is the unknown number
x+b = 40
We want to find x
Subtract b from each side
x+b-b = 40 -b
x = 40-b
The unknown number is 40-b
Answer:
[tex]\huge \boxed{40-b}[/tex]
Step-by-step explanation:
[tex]\sf Let \ x \ be \ that \ number.[/tex]
[tex]x+b=40[/tex]
[tex]\sf Solve \ for \ x.[/tex]
[tex]\sf Subtract \ b \ from \ both \ sides.[/tex]
[tex]x+b-b=40-b[/tex]
[tex]\sf Simplify \ the \ equation.[/tex]
[tex]x=40-b[/tex]
Simplify the expression. (6x – 5) + (4x2 – 3x + 4)
[tex](6x - 5) + (4x^2- 3x + 4)=\\6x-5+4x^2-3x+4=\\4x^2+3x-1[/tex]
PLEASE HELP
Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified exact value in terms of π (no approximations). The figures below are based on semicircles or quarter circles and problems b), c), and d) are involving portions of a square.
Answer:
perimeter is 4 sqrt(29) + 4pi cm
area is 40 + 8pi cm^2
Step-by-step explanation:
We have a semicircle and a triangle
First the semicircle with diameter 8
A = 1/2 pi r^2 for a semicircle
r = d/2 = 8/2 =4
A = 1/2 pi ( 4)^2
=1/2 pi *16
= 8pi
Now the triangle with base 8 and height 10
A = 1/2 bh
=1/2 8*10
= 40
Add the areas together
A = 40 + 8pi cm^2
Now the perimeter
We have 1/2 of the circumference
1/2 C =1/2 pi *d
= 1/2 pi 8
= 4pi
Now we need to find the length of the hypotenuse of the right triangles
using the pythagorean theorem
a^2+b^2 = c^2
The base is 4 ( 1/2 of the diameter) and the height is 10
4^2 + 10 ^2 = c^2
16 + 100 = c^2
116 = c^2
sqrt(116) = c
2 sqrt(29) = c
Each hypotenuse is the same so we have
hypotenuse + hypotenuse + 1/2 circumference
2 sqrt(29) + 2 sqrt(29) + 4 pi
4 sqrt(29) + 4pi cm
Step-by-step explanation:
First we need to deal with the half circle. The radius of this circle is 4, because the diameter is 8. The formula for the circumference of a circle is 2piR.
2pi4 so the perimeter for the half circle would be 8pi/2.
The area of that half circle would be piR^2 so 16pi/2.
Now moving on the triangle part, we need to find the hypotenuse side of AC. We will use the pythagoram theorem. 4^2+10^2=C^2
16+100=C^2
116=C^2
C=sqrt(116)
making the perimeter of this triangle 2×sqrt(116)
The area of this triangle is 8×10=80, than divided by 2 which is equal to 40.
We than just need to add up the perimeters and areas for both the half circle and triangle.
The area would be equal to 8pi+40
The perimeter would be equal to 4pi+4(sqrt(29))
Find the missing angle. Round your answer to the nearest tenth. PLS HURRY.
Answer:
x = 24.4°
Hope this helps... Have a good day!!
Assignment: Counting Investigation Dakota and Karen noticed that there were a bunch of combinations available in their school cafeteria. Think about a meal at your school, or maybe a favorite restaurant. How many combinations of choices do you have? Create a tree diagram listing the possible combinations, and count the results. 1. For what will you find the number of combinations? ______________________________________________________________________________________________________________________ 2. List at least three categories to consider. ______________________________________________________________________________________________________________________ 3. List the choices within each category. ____________________________________________________________________________________________________________________________________________________________________________________________________________________________________________ 4. Assign each choice a symbol. Ex. juice = (diamond shape) ____________________________________________________________________________________________________________________________________________________________________________________________________________________________________________ 5. Create a tree diagram to determine the number of combinations available. 6. List all possible combinations and count the total number of possibilities. ____________________________________________________________________________________________________________________________________________________________________________________________________________________________________________ ____________________________________________________________________________________________________________________________________________________________________________________________________________________________________________ ____________________________________________________________________________________________________________________________________________________________________________________________________________________________________________ ____________________________________________________________________________________________________________________________________________________________________________________________________________________________________________
Hi there! Hopefully this helps!
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Q1: (For what)"Will you find the number of combinations?"
Answer: (I unfortunately don't understand this very well so I'm giving it my best, and take this with a grain of salt.) I will be able to find combinations using a school cafeteria!
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Q2: "List at least three categories to consider."
My choices:
Answer: Fruits, Vegetables, Protein.
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Q3: "List the choices within each category."
Answer:
Fruits: Apples, Bananas, and Grapes.
Vegetables: Cauliflower, Carrot, and Corn.
Protein: Green beans, Salmon, and Almonds.
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Q4: "Assign each choice a symbol. Ex. juice = (diamond shape)"
Answer:
Fruits: Apples, Bananas, and Grapes.
Vegetables: Cauliflower✨, Carrot, and Corn.
Protein: Green beans, Salmon, and Almonds.
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Q5: "Create a tree diagram to determine the number of combinations available."
(I'm not very familiar with a tree diagram so here is my interpretation at the bottom.)
(You can rewrite this and do it your way if you want).
Q6: "List all possible combinations and count the total number of possibilities."
There are 27 combinations possible!
All of my possible combinations:
Apples, Cauliflower, Green beans.Apples, Cauliflower, SalmonApples, Cauliflower, Almonds.Bananas, Cauliflower, Green Beans.Bananas, Cauliflower, Salmon.Bananas, Cauliflower, Almonds.Grapes, Cauliflower, Green bean.Grapes, Cauliflower, Salmon.Grapes, Cauliflower, Almonds.Apples, Carrot, Green beans.Apples, Carrot, Salmon.Apples, Carrot, Almonds.Bananas, Carrot, Green beans.Bananas, Carrot, Salmon.Bananas, Carrot, Almonds.Grapes, Carrot, Green beans.Grapes, Carrot, Salmon.Grapes, Carrot, Almonds.Apples, Corn, Green beans.Apples, Corn, Salmon.Apples, Corn, Almonds.Bananas, Corn, Green beans,Bananas, Corn, Salmon.Bananas, Corn, Almonds.Grapes, Corn, Green Beans.Grapes, Corn, Salmon.Grapes, Corn, Almonds.The last image below is for Qestion 5.