What is the approximate pressure of a storage cylinder of recovered r-410a that does not contain any non-condensable impurities and is stored in a room where the temperature is 80°f?

Potential energy is stored energy. For example, if a bowling ball is on top of a giant hill, we say it has potential energy because it has the potential to do work which is to roll down the hill.

Kinetic energy is the energy of movement so once that ball rolls down that hill, that potential energy is converted to kinetic energy.

Hey there!

Potential energy and kinetic energy are the two main groups of energy when it comes to all of that. Potential energy is stored energy. Kinetic energy is the energy that is released.

For example, potential energy is when you hold a ball higher than the ground,  and kinetic energy is when you release the ball.

Hope this helps! Have a great day! :)

Answer:

There will  be a huge problem of holding the wire strands together, and the power losses will also be amplified.

Explanation:

The force per unit length on two current carrying conductors, lying parallel to each other is proportional to the product of the current through the conductors, and inversely proportional to their distance apart. This force is attractive if the current flows through these conductors in the same direction, and is repulsive if it flows in the opposite direction.

For the strand of wire that make up a high voltage wire bundle, there will be a force of attraction pulling the wires closer to each other, and they will experience the maximum pulling force possible, since they lie next to each other. This force helps to hold these wires in a high tension wire strand together, limiting the area, and reducing "skin effect."

In the case that this wires in the wire strand acts in opposite of the known behavior, the wires will repel and push each other apart. This pushing apart will increase power loss due "skin effect" which is increased by an increase in exposed surface area of the wire strands. This will pose a big problem for high tension transmission.

Answer:

hlo

Explanation:

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i can do anything

Answer:

The meaning of grit in psychology is a positive, non-cognitive trait based on an individual's perseverance of effort combined with the passion for a particular long-term goal or end state.

After 1 hour, 80 g decays to 40 g.

After another hour (total 2 hours), 40 g decays to 20 g.

After another hour (total 3), 20 g decays to 10 g.

After one more hour (total 4), 10 g decays to (D) 5 g.

Answer:

C. sound energy

Explanation:

hope this helps

Answer:

A. 112 J

Explanation:

KE = ½mv² = ½(0.14)40² = 112 J

Answer:

For vegetarians beans

Explanation:

Because it's plant protein and very proteinious

Answer:

The formula for speed is speed=distance

time

Explanation:

to work out what the units are for speed,you need to know the units for distance and time.In this example,distance is in metres(m) and time is in seconds (s) , so the units for speed is metre per second (m/s).

We know

[tex]\boxed{\sf F_c=\dfrac{mv^2}{r}}[/tex]

[tex]\\ \sf\longmapsto F_c=\dfrac{20(10)^2}{4}[/tex]

[tex]\\ \sf\longmapsto F_c=\dfrac{20(100)}{4}[/tex]

[tex]\\ \sf\longmapsto F_c=\dfrac{2000}{4}[/tex]

[tex]\\ \sf\longmapsto F_c=500N[/tex]

The centripetal force on the truck can be determined from the mass, velocity and the radius of the circular path. The centripetal force acting on the truck is 500 N. Hence, option A is correct.

Centripetal force is a type force acting on an object traveling through a circular path. The centripetal force is the rotational analogue of the linear force.

The centripetal force acting on an object is related to the mass, velocity and radius of the circular path is given by:

Fc =  mv ²/r

Given that, mass of truck = 20 Kg

radius of circle = 4 m

velocity = 10 m/s

Then, centripetal force Fc = 20 kg ×  10² m/s / 4 m = 500 N

Therefore, the centripetal force on the truck is 500 N.

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Answer:

66.7 cm

Explanation:

The focal length is half the radius of curvature, or f = 40 cm.

The image is real, so i = +100 cm.

The distance to the object is therefore:

1/o + 1/f = 1/i

1/o + 1/40 = 1/100

o = -66.7 cm

The object is 66.7 cm left of the mirror.

The work done by the force on the block is:

[tex]W=135.41*3=406.23 \: J[/tex]

The direction of motion here is in the y-direction, so we need to find the component of the force in this direction.

Using trigonometric functions:

[tex]F_{y}=Fsin(37)[/tex]

This component is in the positive y-direction.

Now, there is a friction force between the block and the wall, so we need to find the friction force.

[tex]F_{f}=\mu N[/tex]

Where:

Let's use the first Newton's Law to get F.

F(y) is upward (+) and F(f) and the weight is downward (-).

[tex]F_{y}-F_{f}-W=0[/tex]

[tex]F_{y}-F_{f}=mg[/tex]

Factoring F in the left side:

[tex]F(sin(37)-\mu cos(37))=mg[/tex]    

[tex]F=\frac{mg}{sin(37)-\mu cos(37)}[/tex]  

[tex]F=\frac{5*9.81g}{sin(37)-(0.3*cos(37))}[/tex]  

[tex]F=135.41\: N[/tex]    

Therefore, the work done will be:

[tex]W=Fd[/tex]  

[tex]W=135.41*3=406.23 \: J[/tex]  

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Answer:

0.632456 m/s

Explanation:

Answer:

(B) Parachutes

Explanation:

Air resistance works to slow down trains and airplanes, so it isn't desirable.  Air resistance also causes pendulums to slow and stop.

Parachutes need air resistance to slow a person's fall.  So air resistance is desirable here.

Answer:

B i answered it it it

Explanation:

Answer:

[tex]{ \bf{mechanical \: adv = \frac{load}{effort} }}[/tex]

Answer:

the final statements the correct one is. The second

The iron piece exerts a force of 1 N on the magnet in the opposite direction

Explanation:

In this exercise they give us the force exerted by a magnet on an iron bar and ask us the force that the iron bar exerts on the magnet. We can see that these are action and reaction forces, which by Newton's third law must be of equal magnitude and opposite direction, each applied to one of the bodies.

the final statements the correct one is. The second

The iron piece exerts a force of 1 N on the magnet in the opposite direction

Explanation:

It is given that,

The distance covered by a body along the x-axis is given by :

[tex]x=2t^3+5t^2+t[/tex]

t is in seconds and x is meters

Speed of the body is given by :

[tex]v=\dfrac{dx}{dt}\\\\v=\dfrac{d(2t^3+5t^2+t)}{dt}\\\\v=6t^2+10t+1[/tex]

At t = 0,

[tex]v=6(0)^2+10(0)+1=1\ m/s[/tex]

At t = 2 s,

[tex]v=6(2)^2+10(2)+1=45\ m/s[/tex]

So, the average speed in a time interval from t= 0s and t=2s is 45 m/s.

Answer:

Standard weight: We calculate the standard weight as follows: G = L * mweight, where L is the length of the beam calculated as the difference between the extreme points of the beam body along the direction of the beam axis, taking into account all features except holes.

Explanation:

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Answer:

The velocity of the stone is 2.57 m/s.

Explanation:

Given that

Height = 0.337 m

We need to calculate the velocity of the stone

Using equation of motion

[tex]v^2-u^2=2gh[/tex]

Where, v = velocity of stone

u = initial velocity

g = acceleration due to gravity

h = height

Put the value into the formula

[tex]v^2-0=2\times9.8\times 0.337[/tex]

[tex]v=\sqrt{2\times9.8\times0.337}[/tex]

[tex]v=2.57\ m/s[/tex]

Hence, The velocity of the stone is 2.57 m/s.

Let consider the whole system to be at equilibrium where the net force is zero. The forces [tex]F_A[/tex] and [tex]F_B[/tex] are acting in the upward direction while the weight (w) of the crate is acting in the downward direction.

The force at equilibrium in the y-direction is computed as:

[tex]\sum F_y = ma_y[/tex]

[tex]F_A +F_B= mg[/tex]

[tex]\mathbf{F_A = mg -F_B}[/tex]  ---- (1)

Recall that the weight w = mg

where;

w = 200 × 9.8

w = 1960 N

The torque about the bottom end is also zero. i.e.

[tex]\sum \tau=0[/tex]

∴

[tex]F_B L_Z - wL_w = 0[/tex] --- (2)

[tex]F_B L_Z= wL_w[/tex]

[tex]F_B = \omega (\dfrac{L_w}{L_z})[/tex]

[tex]F_B =1960\times (\dfrac{0.375\times cos 45^0}{1.25\times cos 45^0})[/tex]

[tex]F_B =1960\times (0.3)[/tex]

[tex]\mathsf{F_B = 588 \ N}[/tex]

Replacing the value for the force of B into equation (1); we have:

[tex]F_A = mg - F_B[/tex]

[tex]F_A = 1960 - 588[/tex]

[tex]\mathsf{F_A = 1372 N}[/tex]

Thus, we can conclude that the magnitude of these forces i.e force B and force A are 588 N and 1372 N respectively.

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Answer: A) an upward force balances the downward force of gravity on the skydiver

Explanation: I got it correct on my test on edge

The statement best applies Newton’s laws of motion to explain the skydiver’s motion an upward force balances the downward force of gravity on the skydiver. Thus, option A is correct.

The statement that best applies Newton’s laws of motion to explain the skydiver’s motion is that an upward force balances the downward force of gravity on the skydiver. Newton's 3rd law often applies to skydiving.

When gravity is not acting upon the skydivers they would continue moving in the direction the vehicle they jumped from was moving. If no air resistance takes place, then the skydivers would still accelerating at 9.8 m/s until they hit the ground.

The skydiver after leaving the aircraft will accelerates downwards due to the force of gravity usually as there is no air resistance acting in the upwards direction, and there is a resultant force acting downwards, the skydiver will accelerates towards the ground.

Therefore, The statement best applies Newton’s laws of motion to explain the skydiver’s motion an upward force balances the downward force of gravity on the skydiver. Thus, option A is correct.

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Answer:

λ = 2.5m

Explanation:

Given the following :

Speed of sound (v) = 10m/s

If 5 oscillations pass through a point in 0.5seconds;

Time taken (period) for 1 oscillation is :

Number of oscillations / total time taken

5 / 0.5 = 0.25 seconds

Wavelength, period and Velocity are related by the formula:

v = λ / T

λ = v * T

λ = 10 * 0.25

λ = 2.5 m

Answer:

190v I believe

hope this helped a little and if it did pls mark brainiest :)

Answer:

True

Explanation:

Thats is true since it cannot be a vector because speed only gives a magnitude, not a direction as well.

Answer:

Abiogenesis in evolutionary science, not sure about creation science

Explanation:

Answer:

first part the skater goes down a constant slope ramp, initially he has Newton's second law

pply Newton's third law, the normal is the reaction to the support of the body on the surface

the ramp shoots off.  axis becomes zero and therefore with Newton's first law its speed

Explanation:

It is the description of this movement let's write Newton's laws.

* The first law that a body goes at constant speed or zero if the sum of the external forces is zero

* the second law is F = m a

* The third law states that the forces act in pairs of equal magnitude and opposite direction, one applied to each body.

Let's apply these laws to our case

In the first part the skater goes down a constant slope ramp, initially he has Newton's second law when he accelerates from the initial velocity of zero to a terminal velocity.

The expression for this is

             Wₓ - fr = ma

             W sin θ - μ W cos θ = m a

             W = mg

             g (sin θ - μ cos) = a

the value of the coefficient of kinetic friction depends on the condition of the surface, dry, wet or muddy

This is Newton's second law

On the Y axis, which is perpendicular to the ramp we have

            N- [tex]W_{y}[/tex] = 0

If we apply Newton's third law, the normal is the reaction to the support of the body on the surface, note that it can be different from the weight.

In the second part when he is on the ramp.

In the ramp the skater enters with a speed v, suppose that the ramp has an incline so that the skater can jump, in this case the angle is positive with respect to the axis x

In this case the analysis is similar to the previous one

Newton's second law gives the acceleration of the skater, who when he reaches the end of the ramp shoots off.

 At this point the force in the x (horizontal) axis becomes zero and therefore with Newton's first law its speed this axis remains constant and the force in the y axis is the force of gravity and has an acceleration that changes if velocity according to Newton's second law

Answer:look at explanations

Explanation:

Answer:

6s , 60mls

Explanation:

hope this helps love

Answer:

0m/s

Explanation:

When the object strikes the ground, it then becomes in uniform motion and when an object is in uniform motion, the velocity is 0

Thiết bị không phải nguồn điện:

Đáp án D

Answer:

Explanation:

Given that:

For a first order instrument with a sensitivity of .4 mV/K

constant c  = 25 ms = 25 × 10⁻³ s

The initial temperature [tex]T_1[/tex] = 273 K

The final temperature [tex]T_2[/tex] = 473 K

The initial volume = 0.4 mV/K × 273 K = 109.2 V

The final volume =  0.4 mV/K × 473 K =  189.2 V

the instrument’s response as a function of time for a sudden temperature increase can be computed as follows:

Let consider y to be the function of time i.e y(t).

So;

y(t) = 109.2  + (189.2 - 109.2)( 1 - [tex]\mathbf{e^{-t/c}}[/tex])mV

y(t) = (109.2 +  80 ( 1 - [tex]\mathbf{e^{t/25\times 10^{-3}}}[/tex])) mV

Plot the response y(t) as a function of time.

The plot of y(t) as a function of time can be seen in the diagram  attached below.

What are the units for y(t)?

The unit for y(t) is mV.

Find the 90% rise time for y(t90) and the error fraction,

The 90% rise time for y(t90) is as follows:

Initially 90% of 189.2 mV = 0.9 ×  189.2 mV

=  170.28 mV

170.28 mV = (109.2 +  80 ( 1 - [tex]\mathbf{e^{t/25\times 10^{-3}}}[/tex])) mV

170.28 mV - 109.2 mV = 80 ( 1 - [tex]\mathbf{e^{t/25\times 10^{-3}}}[/tex])) mV

61.08 mV =  80 ( 1 - [tex]\mathbf{e^{t/25\times 10^{-3}}}[/tex])) mV

0.7635  mV = ( 1 - [tex]\mathbf{e^{t/25\times 10^{-3}}}[/tex])) mV

t = 1.44 × 25  × 10⁻³ s

t = 0.036 s

t = 36 ms

The error fraction = [tex]\dfrac{189.2-170.28 }{189.2}[/tex]

The error fraction = 0.1

The error fraction = 10%

Answer:

lever: Principle of the Lever

lever: Principle of the LeverIt has been found by experiment that two equal forces acting in opposite directions, i.e., clockwise and counterclockwise, and applied to a uniform lever at equal distances from the fulcrum counteract each other and establish a state of equilibrium, or balance, in the lever.