What is the exact distance from (−1, 4) to (6, −2)? square root of 80. units square root of 82. units square root of 85. units square root of 89. units

Answers

Answer 1

Answer:

[tex]\sqrt{85}[/tex].

Step-by-step explanation:

[tex]x[/tex]-coordinates:

First point: [tex]-1[/tex].Second point: [tex]6[/tex].Difference: [tex]|-1 - 6| = |-7| = 7[/tex].

[tex]y[/tex]-coordinates:

First point: [tex]4[/tex].Second point: [tex]-2[/tex].Difference: [tex]|4 - (-2)| = |6| = 6[/tex].

Refer to the diagram attached. Consider these two points as the two end points of the hypotenuse of a right triangle. The lengths of the two legs are equal to:

the difference between the two [tex]x[/tex]-coordinates, [tex]7[/tex], and the difference between the two [tex]y[/tex]-coordinates, [tex]6[/tex].

Apply Pythagorean Theorem to find the length of the hypotenuse (which is equal to the distance between the two points in question.)

[tex]\begin{aligned}\text{Hypotenuse} &= \sqrt{(\text{First Leg})^2 + (\text{Second Leg})^2} \\ &= \sqrt{7^2 + 6^2} \\ &= \sqrt{85}\end{aligned}[/tex].

What Is The Exact Distance From (1, 4) To (6, 2)? Square Root Of 80. Units Square Root Of 82. Units Square
Answer 2

Answer:

C

Step-by-step explanation:


Related Questions


A hot air balloon descends 200 feet per
minute from an altitude of 1000 feet. Write a expression

Answers

Answer:
y=90x+2,000
Step-by-step explanation:
90 is the rate of change because the hot air balloon descends 90 feet per minute.
And 2,000 is the starting point because the hot air balloon started the descent at 2,000 feet.

Given that the sum of squares for error is 60 and the sum of squares for regression is 140, then the coefficient of determination is:

Answers

Answer:

0.7

Step-by-step explanation:

The coefficient of determination which is also known as the R² value is expressed as shown;

[tex]R^{2} = \frac{sum\ of \ squares \ of \ regression}{sum\ of \ squares \ of total}[/tex]

Sum of square of total (SST)= sum of square of error (SSE )+ sum of square of regression (SSR)

Given SSE = 60 and SSR = 140

SST = 60 + 140

SST = 200

Since R² = SSR/SST

R² = 140/200

R² = 0.7

Hence, the coefficient of determination is 0.7. Note that the coefficient of determination always lies between 0 and 1.

The coefficient of determination of the dataset is 0.7

The given parameters are:

[tex]SSE = 60[/tex] --- sum of squared error

[tex]SSR = 140[/tex] --- sum of squared regression

Start by calculating the sum of squared total (SST)

This is calculated using

[tex]SST =SSE + SSR[/tex]

So, we have:

[tex]SST =60 +140[/tex]

[tex]SST =200[/tex]

The coefficient of determination (R^2) is then calculated using

[tex]R^2 = \frac{SSR}{SST}[/tex]

So, we have:

[tex]R^2 = \frac{140}{200}[/tex]

Divide

[tex]R^2 = 0.7[/tex]

Hence, the coefficient of determination is 0.7

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Help please!! Simplify the following expression
*4 + 3x3 - 2x - 5x2 - X+ x2 + x +1+7x4
O A. 8x4 +5x2 + 4x2 + 0x+1
B. 8x4 +5x + 4x2 +1
C. 8x4 + x2 - 4x + 0x
D. 8x4 + x2 - 4x2 +1

Answers

━━━━━━━☆☆━━━━━━━

▹ Answer

D. 8x⁴ + x³ - 4x² + 1

▹ Step-by-Step Explanation

Remove the opposites:

x⁴ + 3x³ - 2x³ - 5x² + x² + 1 + 7x²

Collect like terms:

8x⁴ + 3x³ - 2x³ - 5x² + x² + 1

8x⁴ + x³ - 5x² + x² + 1

8x⁴ + x³ - 4x² + 1

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

A detective knows what time of day it is based on the angle at which the sun is hitting a man. Suppose a detective is looking at a photograph of a 6-foot tall man with a shadow that is 3.5 feet. Find the angle at which the sun is hitting the ground.

Answers

Answer:

The angle [tex]\theta[/tex] at which the sun is hitting the ground is:

[tex]\theta\approx 59.74^o[/tex]

Step-by-step explanation:

You can use right angle trigonometry to solve this, since the man (6 ft tall) and the shadow on the ground (3.5 ft long) form a right angle triangle as shown on the attached image.

The use the tangent function to find the angle that the sun's rays make with the ground:

[tex]tan(\theta)=\frac{opposite}{adjacent} \\tan(\theta)=\frac{6}{3.5} \\\theta=arctan(\frac{6}{3.5})\\\theta\approx 59.74^o[/tex]

Complete the table of values for y=-x^2+2x+1
X -3, -2, -1,0,1,2,3,4,5
Y -14,7, ,1, -2 -14

Answers

Answer:

  see the attachment

Step-by-step explanation:

When you have a number of function evaluations to do, it is convenient to let a graphing calculator or spreadsheet do them. That avoids the tedium and the mistakes in arithmetic.

Here's your completed table.

find the range of the inequality 2e-3< 3e-1​

Answers

Answer:

[tex]x = { - 1, 0,1 ,2 ...}[/tex]

Step-by-step explanation:

[tex]2e - 3 < 3e - 1 = 2e - 3e < - 1 + 3 = - 1e < 2 = e > - 2[/tex]

Hope this helps ;) ❤❤❤

I
Ifm DGF = 72, what equation can you use to find mZEGF?

Answers

Answer:

see explanation

Step-by-step explanation:

∠ DGE + ∠ EGF = ∠ DGF , that is

∠ EGF = ∠ DGF - ∠ DGE

∠ EGF = 72° - ∠ DGE

1. Write a survey question for which you would expect to collect numerical
data.
2. Write a survey question for which you would expect to collect categorical
data.

Answers

Answer:

How many siblings do you have?

I hope this helps you out :)

25. After a horizontal reflection across the y-axis, f(x) is: options: f(–x) f(x – 1) –f(–x) –f(x)

Answers

Answer:

A,  f(–x)

Step-by-step explanation:

Reflection about the y-axis is defined as:

f(x) = - f(-x)

So the correct answer is

A,  f(–x)

Consider the following. (Assume that the coins are distinguishable and that what is observed are the faces or numbers that face up.) Three coins are tossed; the result is at most one head. Which of the following sets of elements are included in the sample space
HHTHTTTTHTTTTHTHHHTHHHTH
List the elements of the given event. (Select all that apply.)
HHT
HTT
TTH
TTT
THT
HHH
THH
HTH
List the elements of the given event. (select all that apply)
HTT
TTH
HTH
THH
THT
HHH
TTT
HHT

Answers

Answer:

Even set = {HTT, THT, TTH, TTT}

Step-by-step explanation:

We are given that three coins are tossed; the result is at most one head.

And we have to find the sets of elements that are included in the sample space.

Firstly, as we know that when three coins are tossed, the total number of cases formed is 8.

Let Head on the coin be represented by 'H' and the Tail on the coin be represented by 'T'.

So, the sample space so formed is;

S = {HHH, HTH, HHT, THH, THT, TTH, HTT, TTT}

Now, our event is at most one head. So, the sample space for the favorable event is given by;

Even set = {HTT, THT, TTH, TTT}

In this, three cases are of head occurring only once and one case is of head not appearing in three tosses of a coin.

Which box holds more popcorn?

Answers

Answer:

Amanda's popcorn container holds more popcorn

Step-by-step explanation:

First we'll have to find the volume.

The Volume helps us determine which is bigger.

Step 1

We'll find Amanda's popcorn container

10cm*10cm*13.5cm=1350cm

Step 2

We'll find Mary's popcorn container

8cm*8cm*20cm=320cm

Step 3

Since Amanda's popcorn container has 1350cm (volume) and Mary's popcorn container has 320cm (volume) we'll have this. 1350cm>320cm. We can determine the Amanda's popcorn container has holds more,

Final Answer

Amanda's popcorn container holds more popcorn

Multiply the following complex numbers:
(7+2i)(2+3i)

Please don’t guess

Answers

Answer:

14 + 25l + 6l^2

Step-by-step explanation:

(7 + 2i) (2 + 3i)

=> 14 + 4l + 21l + 6l^2

=> 14 + 25l + 6l^2

This is the correct answer

14+ 25|+ 6|^2 is the correct answer

Describe and correct the error in determining the formula for the sequence below

Answers

Answer:An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. For instance, the sequence 5, 7, 9, 11, 13, 15.. . is an arithmetic progression with a common difference of 2.

Step-by-step explanation:

If xy = 1 what is the arithmetic mean of x and y in terms of y? Please show work as detailed as possible

Answers

Answer:

(1+y^2) /2y

Step-by-step explanation:

arithmetic mean is the average of x and y

(x+y)/2

Using the equation

xy = 1

and solving for x

x = 1/y

Replacing x in the first equation

(1/y + y) /2

Multiply by y/y

(1/y + y) /2 * y/y

(1/y + y)*y /2y

(1+y^2) /2y

The sum of two polynomials is 10a^2b^2-8a^2b+6ab^2-4ab+2 if one addend is -5a^2b^2+12a^2b-5 what is the other addend

Answers

Answer:

The other addend is [tex]15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7[/tex].

Step-by-step explanation:

The other addend is determined by subtracting [tex]-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b-5[/tex] from [tex]10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a\cdot b^{2}-4\cdot a \cdot b + 2[/tex]:

[tex]x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b + 2 - (-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b -5)[/tex]

[tex]x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +2 +5\cdot a^{2}\cdot b^{2}-12\cdot a^{2}\cdot b+5[/tex]

[tex]x = (10\cdot a^{2}\cdot b^{2}+5\cdot a^{2}\cdot b^{2})-(8\cdot a^{2}\cdot b+12\cdot a^{2}\cdot b)+6\cdot a \cdot b^{2}-4\cdot a \cdot b +7[/tex]

[tex]x = 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7[/tex]

The other addend is [tex]15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7[/tex].

Answer:

A

Step-by-step explanation:

Which regular polygon has a rotation of 240 degree to carry the polygon onto itself?

Equilateral triangle

Octagon

Rectangle

Pentagon

Answers

The regular polygon that has a rotation of 240 degrees to carry the polygon onto itself is an B. Octagon.

What is an Octagon?

This refers to an eight-sided polygon that has eight angles and is used in geometry.

Hence, we can see that an octagon, can be rotated to 240 degrees and when this is done, it is able to carry itself which cannot be done by others as other polygons would need 360 degrees to carry themselves.

Read more about polygons here:

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The check_time function checks for the time format of a 12-hour clock, as follows: the hour is between 1 and 12, with no leading zero, followed by a colon, then minutes between 00 and 59, then an optional space, and then AM or PM, in upper or lower case. Fill in the regular expression to do that. How many of the concepts that you just learned can you use here

Answers

Answer:

Following are the correct code to this question:

import re#import package for regular expression

def check_time(text):#defining a method check_time that accepts string value  

   p = r'(1[012]|[1-9]):[0-5][0-9][ ]{0,1}?(am|pm|AM|PM)'#defining string variable p that stores values

   val = re.search(p, text)#defining val variable that check serachs p and text variable values

   return val!= None#use return keyword to return val value

print(check_time("12:45pm"))#defining print method that calls method by input value  

print(check_time("9:59 AM")) #defining print method that calls method by input value

print(check_time("6:60 am")) #defining print method that calls method by input value

print(check_time("five o'clock"))#defining print method that calls method by input value

Output:

True

True

False

False

Step-by-step explanation:

In the above-given program, some data is missing that is code file so, the correct code can be defined as follows:

In the above-given method, that is "check time" it uses 12-hour time format validation, that is tested by coding the regex and  all the value validates in the "val" variables, that can be defined as  follows:  

In the first step, its values should be in  1,2,3, ... 10,11,12   In the second step, it values in Between hour and minutes, and there will be a colon.  In the third step, the minutes variable should take the double-digit, that will be like  00,01 .... 59.  In the last step, one space becomes permitted after an hour: a minute or no space for am or pm value.

A population has a mean and a standard deviation . Find the mean and standard deviation of a sampling distribution of sample means with sample size n. nothing ​(Simplify your​ answer.) nothing ​(Type an integer or decimal rounded to three decimal places as​ needed.)

Answers

Complete Question

A population has a mean mu μ equals = 77 and a standard deviation σ = 14. Find the mean and standard deviation of a sampling distribution of sample means with sample size n equals = 26

Answer:

The mean of sampling distribution of the sample mean ( [tex]\= x[/tex]) is [tex]\mu_{\= x } = 77[/tex]

The standard deviation of sampling distribution of the sample mean ( [tex]\= x[/tex]) is  

    [tex]\sigma _{\= x} = 2.746[/tex]

Step-by-step explanation:

From the question we are told that

    The population mean is  [tex]\mu = 77[/tex]

     The  standard deviation is  [tex]\sigma = 14[/tex]

     The sample size is  [tex]n = 26[/tex]

     

Generally the standard deviation of sampling distribution of the sample mean ( [tex]\= x[/tex]) is  mathematically represented as

           [tex]\sigma _{\= x} = \frac{ \sigma }{ \sqrt{n} }[/tex]

substituting values  

          [tex]\sigma _{\= x} = \frac{ 14}{ \sqrt{26} }[/tex]

          [tex]\sigma _{\= x} = 2.746[/tex]

Generally the mean of sampling distribution of the sample mean ( [tex]\= x[/tex]) is  equivalent to the population mean i.e  

      [tex]\mu_{\= x } = \mu[/tex]

      [tex]\mu_{\= x } = 77[/tex]

Suppose that the Blood Alcohol Content (BAC) of students who drink five beers varies from student to student according to a Normal distribution with mean 0.07 ans standard deviation 0.01.

1. The middle 95% of students who drink five beers have a BAC between

a. 0.06 and 0.08 b. 0.05 and 0.09 c. 0.04 and 0.10 d. 0.03 and 0.11

2. What percent of students who drink five beers have a BAC above 0.08 (the legal limit for driving in most states)?

a. 0.15% b. 0.3% c. 2.5% d. 16% e. 32%

3. What percent of students who drink five beers have a BAC above 0.10 (the legal limit for driving in most states)?

a. 0.15% b. 0.3% c. 2.5% d. 16% e. 32%

Answers

Answer:

1.    b. 0.05 and 0.09

2.   d. 16%

3.    a. 0.15%

Step-by-step explanation:

Given that :

mean = 0.07

standard deviation = 0.01

Confidence interval = 95%

The level of significance ∝= 1 - 0.95 = 0.05

At 0.05 level of significance,

critical value for [tex]z_{\alpha/2} = z_{0.05/2}[/tex]

critical value for [tex]z_{0.025}[/tex]  = 1.96

Confidence interval = [tex]\mathtt{\mu \pm ( {z} \times{\sigma})}[/tex]

Lower limit = [tex]\mathtt{\mu -( {z} \times{\sigma})}[/tex]

Upper Limit = [tex]\mathtt{\mu +( {z} \times{\sigma})}[/tex]

Lower limit = [tex]\mathtt{0.07 - ({1.96} \times {0.01})}[/tex]

Upper limit = [tex]\mathtt{0.07 + ({1.96} \times {0.01})}[/tex]

Lower limit = 0.07 - 0.0196

Upper limit = 0.07 + 0.0196

Lower limit = 0.0504  [tex]\simeq[/tex] 0.05

Upper limit = 0.0896    [tex]\simeq[/tex] 0.09

The confidence interval of 95% is ( 0.05, 0.09)

2. What percent of students who drink five beers have a BAC above 0.08 (the legal limit for driving in most states)?

[tex]P(X> 0.08) = P(\dfrac{0.08 - \mu}{\sigma} > \dfrac{X - \mu}{\sigma} )[/tex]

[tex]P(X > 0.08) = P(z > \dfrac{0.08 - 0.07}{0.01} )[/tex]

[tex]P(X > 0.08) = P(z > \dfrac{0.01}{0.01} )[/tex]

[tex]P(X > 0.08) = P(z > 1 )[/tex]

[tex]P(X> 0.08) = 1- P(z < 1 )[/tex]

P(X > 0.08) = 1 - 0.8413

P(X > 0.08) = 0.1587

P(X > 0.08) [tex]\simeq[/tex] 16%  

3. What percent of students who drink five beers have a BAC above 0.10 (the legal limit for driving in most states)?

[tex]P(X> 0.10) = P(\dfrac{0.10 - \mu}{\sigma} > \dfrac{X - \mu}{\sigma} )[/tex]

[tex]P(X > 0.10) = P(z > \dfrac{0.10 - 0.07}{0.01} )[/tex]

[tex]P(X > 0.10) = P(z > \dfrac{0.03}{0.01} )[/tex]

[tex]P(X > 0.10) = P(z > 3)[/tex]

[tex]P(X> 0.10) = 1- P(z < 3 )[/tex]

P(X > 0.10) = 1 - 0.9987

P(X > 0.08) = 0.0013

P(X > 0.08) [tex]\simeq[/tex] 0.15%  which is the closet value to 0.0013

A vat of milk has spilled on a tile floor. The milk flow can be expressed with the function r(t) = 4t, where t represents time in minutes and r represents how far the milk is spreading.

The spilled milk is creating a circular pattern on the tile. The area of the pattern can be expressed as A(r) = πr2.

Part A: Find the area of the circle of spilled milk as a function of time, or A[r(t)]. Show your work.

Part B: How large is the area of spilled milk after 4 minutes? You may use 3.14 to approximate π in this problem.

Answers

Answer:

For a) $A(r(t))=π(4t)^2.$

For b) 803.84

Step-by-step explanation:

For a) we can do a simple substitution on the variable r. Notice that $A=πr^2$ make $A$ a function of $r.$ Then, $A(r(t))=\pi (r(t))^2=\pi (4t)^2.$

For b) you only need to substitute the value $t=4$ on the expresión $A(r(t)).$

Fifteen chaperones went on a field trip with 225 students. Which fraction represents the number of chaperones to students on the field trip

Answers

Answer:

15/225

Step-by-step explanation:

The number of chaperones for the group of students can be represented with a ratio - 15:225 or 15/225.

Because there are 15 chaperones for the 225 students, you can state what the ratio does - for every 225 students, there are 15 chaperones.

However, 15/225 can be reduced to 1/15, so for every 15 students, there is 1 chaperone.

Help plz! Jim is climbing a mountain that has a base 150 feet above sea level. If he climbs 233 feet then descends into a cave 64 feet, how far above sea level is Jim

Answers

150+233-64=319
Jim is 319 ft above sea level.

Answer:

150+233-64=319

Jim is 319 ft above sea level.

Step-by-step explanation:

On a map 1 cm represents 4.5km. What is the actual distance between two towns which are 4cm apart on the map?

Answers

Answer:

18km

Step-by-step explanation:

1cm:4.5km/4cm then get the answer as 18km

1 cm represents [tex]4.5[/tex] km. To find the actual distance between two towns that are 4 cm apart on the map, we can use the scale ratio.

Since 1 cm represents [tex]4.5[/tex] km, we can calculate the actual distance by multiplying the map distance with the scale ratio. Map distance: 4 cm Scale ratio: 1 cm represents [tex]4.5[/tex] km Actual distance = Map distance × Scale ratio Actual distance[tex]= 4 cm × 4.5[/tex] km/cm Actual distance[tex]= 18 km[/tex]

Therefore, the actual distance between the two towns is18 [tex]18[/tex] km. Using the given scale, 1 cm on the map corresponds to[tex]4.5[/tex]km in reality. As the towns are represented as 4 cm apart on the map, the actual distance between them is [tex]18[/tex]km.

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A normal distribution has a mean of 30 and a variance of 5.Find N such that the probability that the mean of N observations exceeds 30.5 is 1%.​

Answers

Answer:

109

Step-by-step explanation:

Use a chart or calculator to find the z-score corresponding to a probability of 1%.

P(Z > z) = 0.01

P(Z < z) = 0.99

z = 2.33

Now find the sample standard deviation.

z = (x − μ) / s

2.33 = (30.5 − 30) / s

s = 0.215

Now find the sample size.

s = σ / √n

s² = σ² / n

0.215² = 5 / n

n = 109

Evaluate the expresión 6c-d when c=2 and d=10 I need help?

Answers

Answer:

the answer is 18

Step-by-step explanation:

8 is the answer

5.
The width of a rectangle is one foot more than a third of the length. If the
perimeter is 42 feet, what is the width? What is the length?

Answers

Well, the formula for the perimeter of a rectangle is:
2l + 2w.
So, by plugging in our values of the length and width, we can easily find an answer:
length = L
width = 1 + L ( 1/3 )
2 ( L ) + 2 ( L ( 1/3 + 1 ) = 42
2l + 2/3( L ) + 2 = 42
8/3 ( L ) = 40
L = 40 * 3/8
L = 15
Therefore, the length is 15 and the width is 6.

Help with number 50 please. Thanks.

Answers

Answer:

[tex] d = 7 + 3\sqrt{3} [/tex] and

[tex] d = 7 - 3\sqrt{3} [/tex]

Step-by-step explanation:

To solve the equation, [tex] d^2 - 14d - 22 = 0 [/tex], using the quadratic formula,

Recall: quadratic formula = [tex] \frac{-b ± \sqrt{b^2 - 4ac}}{2a} [/tex]

Where,

a = 1

b = -14

c = 22

Plug in your values into the formula and solve:

[tex] \frac{-(-14) ± \sqrt{(-14)^2 - 4(1)(22)}}{2(1)} [/tex]

[tex] \frac{14 ± \sqrt{196 - 88}}{2} [/tex]

[tex] \frac{14 ± \sqrt{108}}{2} [/tex]

[tex] d = \frac{14 + \sqrt{108}}{2} [/tex]

[tex] d = \frac{14 + 6\sqrt{3}}{2} [/tex]

[tex] d = (\frac{2(7 + 3\sqrt{3})}{2} [/tex]

[tex] d = 7 + 3\sqrt{3} [/tex]

And

[tex] d = \frac{14 - \sqrt{108}}{2} [/tex]

[tex] d = \frac{14 - 6\sqrt{3}}{2} [/tex]

[tex] d = (\frac{2(7 - 3\sqrt{3})}{2} [/tex]

[tex] d = 7 - 3\sqrt{3} [/tex]

What is the midpoint between A(-6,1) and B(0,2)?

Answers

Answer:

(-3, 3/2)

Step-by-step explanation:

To find the midpoint between two points you are going to add the X1 and X2, then divide by two. Then you are going to add the Y1 and Y2, and divide by two.

A(-6,1)       B(0,2)

= (-6+0, 1+2)

= (-6, 3)

=(-6/2, 3/2)

=(-3, 3/2)

An unfair coin is flipped. If a head turns up you win $1. The probability of a head is .54 and the probability of a tail is 0.46. What is the expected value of the game

Answers

Answer:

54 cents

Step-by-step explanation:

(.54 * 1)+(.46*0) = .54

Find an equation of the circle whose diameter has endpoints (-6, -1) and (-2,3).

Answers

Step-by-step explanation:

Let find the distance of the diameter. using distance formula.

[tex](3 + 1) {}^{2} + ( - 2 + 6) {}^{2} = \sqrt{8} [/tex]

The diameter is sqr root of 8 units.

A circle equation is

[tex] {x}^{2} + {y}^{2} = {r}^{2} [/tex]

where r is the radius. The radius is half the diameter so

[tex]r = \frac{ \sqrt{8} }{2} = \frac{ \sqrt{8} }{ \sqrt{4} } = \sqrt{2} [/tex]

[tex] {r}^{2} = { \sqrt{2} }^{2} = 2[/tex]

So our radius is 2.

Now we need to find the midpoint or Center of the diameter.

[tex] \frac{ - 6 - 2}{2} = - 4[/tex]

[tex] \frac{3 - 1}{2} = 1[/tex]

So the center of the circle is (-4,1). So our equation of the Circle us

[tex](x + 4) {}^{2} + (y - 1) {}^{2} = ( \sqrt{2} ) {}^{2} [/tex]

Other Questions
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