Answer:
-5b^4 - b^3
Step-by-step explanation:
-b^3 (3b + 1) – 2b^4
Distribute
-3b^4 - b^3 -2b^4
Combine like terms
-5b^4 - b^3
The proper choice of toothbrush is important in dental care. On 14 patients, measures of Gingivitis were taken at the beginning of the experiment. After this, each was given an experimental toothbrush to be used for the next 45 days. Afterwards, dental exam measures were given again of these same individuals. The mean of the differences in scores was 5.5 with a sample standard deviation of 11.6. The mean score before the experiment was 56.4 with a sample standard deviation of 6.4 The mean score after the experiment was 60.6 with a sample standard deviation of 4.3 Let alpha = 0.05
What is the p value from the test of the previous hypothesis?
Answer:
The p-value of the test is 0.049.
Step-by-step explanation:
The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.
In this case a paired t-test is used to determine whether the experimental toothbrush was effective or not.
The hypothesis for the test can be defined as follows:
H₀: The experimental toothbrush was not effective, i.e. d = 0.
Hₐ: The experimental toothbrush was effective, i.e. d < 0.
The information provided is:
[tex]\bar d=5.5\\S_{d}=11.6\\n=14[/tex]
Compute the test statistic value as follows:
[tex]t=\frac{\bar d}{S_{d}/\sqrt{n}}[/tex]
[tex]=\frac{5.5}{11.6/\sqrt{14}}\\\\=1.7740617\\\\\approx 1.774[/tex]
The test statistic value is 1.774.
Decision rule:
If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
Compute the p-value of the test as follows:
[tex]p-value=P(t_{n-1}<1.774)[/tex]
[tex]=P(t_{13}<1.774)\\=0.049[/tex]
*Use a t-table.
The p-value of the test is 0.049.
p-value= 0.049 > α = 0.05
The null hypothesis will be rejected.
Thus, it can be concluded that experimental toothbrush was effective.
What is 3/12 in reduced form.
━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━
To simplify a number, you have to find the greatest common factor (of the numerator and the denominator) and divide each number by the greatest common factor.
The greatest common factor of 3 and 12 is 3.
Now divide each 3 and 12 by 3.
3 ÷ 3 = 1
12 ÷ 3 = 4
Now the numerator is 1 and the denominator is 4.
3/12 in reduced form is 1/4.
━━━━━━━━━━━━━━━ ♡ ━━━━━━━━━━━━━━━
Answer:
3/12 in reduced form is 1/4
Step-by-step explanation:
find GCF for 3 and 12 which is 3 . step 2 divide numerator and denominator by GCd which is 3 and rewrite the fraction = (3/3) / (12/3) which equals 1/4. Thus 1/4 is the simplified fraction for 3/12 your welcome
5(6x+2)+4(5x+5)+4=50x+34
Answer:
0=0
Step-by-step explanation:
50x+34=50x+34
50x=50x
50x - 50x = 50x - 50x
0=0
Answer:
5(6x + 2)+4(5x+5)+4=50+34
multiply it then collect like terms
30x+15x+10+15+15+4=50+34
45x +54=50+34
so the 54 will cross over to the other side making it to be -54
45x=50+34-54
45x=30
the u divide both sides by 45
x= 45÷30
x=0.67
17. x^2 + 2x + 1
O A. This polynomial could be factored by finding the GCF, then by grouping or using the perfect squares method.
O B. This polynomial could be factored by using the difference of squares method, perfect squares method, or grouping.
C. This polynomial could be factored only by using the perfect squares method.
O D. This polynomial could be factored only by using the difference of squares method.
E. This polynomial could be factored by using grouping or the perfect squares methods.
O F. This polynomial cannot be factored by any of the methods used in this lesson.
Answer:
E. This polynomial could be factored by using grouping or the perfect squares methods.
Step-by-step explanation:
x^2 + 2x + 1
There is no greatest common factor
This is a perfect square
a^2 + 2ab+ b^2 = ( x+1)^2
We can factor this by grouping
x^2 + 2x + 1
(x^2 +x) + (x+1)
x( x+1) + x+1
Factor out x+1
( x+1) ( x+1)
This is not the difference of squares since there is no subtraction
Explain the order of operations you would use to evaluate (284) • 5-6+42. Then evaluate it.
Answer:
1456
Step-by-step explanation:
If there are parentheses what is inside comes first, then multiplication or division, last is addition and subtraction. If you have multiple division or multiplication you go in order left to right. Once it's down to addition and subtraction you also go left to right.
First we multiply 284 * 5 = 1420
Now we go in order.
1420 - 6 + 42
1414 + 42
1414 + 42 = 1456
Tell which angles are congruent to the given angle measure.
Answer:
2, 5, & 6
Step-by-step explanation:
2, because it’s the opposite angle.
5, because it’s parallel.
6, because it’s opposite to 5.
2, 5, & 6 all equal 100°.
1, 3, 4, & 7 all equal 80°.
The angles formed that are congruent to angle measure of 100 degrees when transversal t intersects parallel lines m and n are:
<2, <5, and <6.Angle measuring 100 degrees is the given angle measure formed at the point of intersection between line m and transversal t.
Thus, angles that are congruent to 100 degrees will be equal in measure to 100 degrees.
The following are angles congruent to 100 degrees.
<2 is congruent to 100 degrees (vertically opposite angles are congruent).
<5 is congruent to 100 degrees (corresponding angles are congruent).
<6 is congruent to 100 degrees (alternate exterior angles are congruent).
Therefore, the angles formed that are congruent to angle measure of 100 degrees when transversal t intersects parallel lines m and n are:
<2, <5, and <6.Learn more here:
https://brainly.com/question/15937977
Snow White is sewing stockings for the animals that visit her in the forest. When she looks around, she sees 38 legs. She knows that there are ten total animals: mice, deer, and birds. She also knows there are twice as many deer as mice. How many of each animal are there?
Answer:
B=1 M=6 D=3
Step-by-step explanation:
the equations are 4M+4D+2B=38
M+D+B=10
2D=M
step two: 4M+4D+2B=38 (multiply 2nd equation by -4)
-4M-4D-4B=-40
4M AND 4D cancels out and your left with -2B=-2 B=1
then you take the first equation and subsitute the third equation for M
step three: M+D+1 =10 (SUBSITUTE B WITH 1)
M+D=9
STEP FOUR: take the last equation (M+D=9) and subsitute 2D=M
2D+D=9
3D=9
D=3
subsitute D=3 into 2D=M so you get 2(3)=M M=6
DOUBLE CHECK USE THE SECOND EQUATION
M+D+B=1-
6+3+1=10
The required number of mice, deers, and birds are 3, 6, and 1 respectively.
What is arithmetic?In mathematics, it deals with numbers of operations according to the statements.
Here,
Let the number of mice be x and the number of birds is y
Number of Deers = 2x
There are a total of 10 animals,
mice + deer + bird = 10
x + 2x + y = 10
3x + y = 10
y = 10 - 3x - - - - - - -(1)
Legs of mouse = 4
Legs of deers = 4
Legs of birds = 2
Total number of legs = 38
4x + 4 * 2x + 2y = 38
4x + 8x + 2y =38
12x + 2y = 38 - - - - - - - (2)
Solving equations 1 and 2
12x + 2(10 -3x ) = 38
12x + 20 - 6x = 38
6x = 18
x = 3
Put x in equation 1
y = 10 - 3 * 3
y = 1
Now,
Mice= x = 3
Deers = 2x = 2 *3 = 6
Bird = y = 1
Thus, the required number of mice, deers, and birds are 3, 6, and 1 respectively.
Learn more about arithmetic here:
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#SPJ2
let f (x) =- 3x and g (x) = 2x - 1 Find the following f (x) + g (x) Pleas show steps
Answer:
See below.
Step-by-step explanation:
So we have the two functions:
[tex]f(x)=-3x\text{ and } g(x)=2x-1[/tex]
And we want to find f(x) + g(x).
So, substitute:
[tex]f(x)+g(x)\\=(-3x)+(2x-1)[/tex]
Combine like terms:
[tex]=(-3x+2x)+(-1)[/tex]
Simplify:
[tex]=-x-1[/tex]
So:
[tex]f(x)+g(x)=-x-1[/tex]
find the volume of the shaded figure by subtracting the smaller volume from the larger
Answer:
a. [tex] 9a^3 - 9ab^2 [/tex]
b. [tex] 9a(a^2 - b^2) [/tex]
Step-by-step explanation:
a.
[tex] Volume = l*w*h [/tex]
[tex] Volume_{smaller} = l*w*h [/tex]
Where, [tex] l = 9a, w = b, h = b [/tex]
[tex] Volume_{smaller} = 9a*b*b = 9ab^2 [/tex]
[tex] Volume_{larger} = l*w*h [/tex]
Where, [tex] l = 9a, w = a, h = a [/tex]
[tex] Volume_{smaller} = 9a*a*a = 9a^3 [/tex]
Volume of the shaded figure = [tex] 9a^3 - 9ab^2 [/tex]
b. [tex] 9a^3 - 9ab^2 [/tex] expressed in factored form:
Look for the term that is common to 9a³ and 9ab², then take outside the parenthesis.
[tex] 9a^3 - 9ab^2 = 9a(a^2 - b^2) [/tex]
Let Y be a random variable. In a population, mu Subscript Upper Y Baseline equals 65μY=65 and sigma Subscript Upper Y Superscript 2 Baseline equals 49σ2Y=49. Use the central limit theorem to answer the following questions. (Note: any intermediate results should be rounded to four decimal places)
In a random sample of size n = 69, find Pr(Y <68) =
In a random sample of size n = 124, find Pr (68< Y <69)=
In a random sample of size n = 196, find Pr (Y >66)=
Answer:
a. [tex]\mathbf{P(\overline x < 68) = 0.9998}[/tex]
b. [tex]\mathbf{P(68 < \overline x < 69 ) =0}[/tex]
c. [tex]\mathbf{P ( \overline x > 66 ) =0.02275}[/tex]
Step-by-step explanation:
Given that ;
Let Y be a random variable In a population, where:
mean [tex]\mu_y[/tex] = 65
[tex]\sigma^2_y[/tex] = 49
standard deviation σ = [tex]\sqrt{49}[/tex] = 7
The objective is to determine the following :
In a random sample of size n = 69, find Pr(Y <68) =
Using the Central limit theorem
[tex]P(\overline x < 68) = \begin {pmatrix} \dfrac{\overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}} < \dfrac{68 - \mu }{\dfrac{\sigma}{\sqrt{n}}} } \end {pmatrix}[/tex]
[tex]P(\overline x < 68) = \begin {pmatrix}Z < \dfrac{68 - 65 }{\dfrac{7}{\sqrt{69}}} } \end {pmatrix}[/tex]
[tex]P(\overline x < 68) = \begin {pmatrix}Z < \dfrac{3 }{\dfrac{7}{8.3066}} } \end {pmatrix}[/tex]
[tex]P(\overline x < 68) = (Z < 3.5599 )[/tex]
From the z tables:
[tex]\mathbf{P(\overline x < 68) = 0.9998}[/tex]
In a random sample of size n = 124, find Pr (68< Y <69)=
[tex]P(68 < \overline x < 69 ) = P \begin {pmatrix} \dfrac{68- \mu}{\dfrac{\sigma}{\sqrt{n}}} < \dfrac{\overline x - \mu}{\dfrac{\sigma}{\sqrt{n}}} < \dfrac{ 69 - \mu}{\dfrac{\sigma}{\sqrt{n}}} \end {pmatrix}[/tex]
[tex]P(68 < \overline x < 69 ) = P \begin {pmatrix} \dfrac{68- 65}{\dfrac{7}{\sqrt{124}}} < Z < \dfrac{ 69 - 65}{\dfrac{7}{\sqrt{124}}} \end {pmatrix}[/tex]
[tex]P(68 < \overline x < 69 ) = P \begin {pmatrix} \dfrac{3}{\dfrac{7}{11.1355}} < Z < \dfrac{ 4}{\dfrac{7}{11.1355}} \end {pmatrix}[/tex]
[tex]P(68 < \overline x < 69 ) = P \begin {pmatrix} 4.7724 < Z < 6.3631 \end {pmatrix}[/tex]
[tex]P(68 < \overline x < 69 ) = P( Z < 6.3631 ) - P ( Z < 4.7724 )[/tex]
From z tables
[tex]P(68 < \overline x < 69 ) = 0.9999 - 0.9999[/tex]
[tex]\mathbf{P(68 < \overline x < 69 ) =0}[/tex]
In a random sample of size n = 196, find Pr (Y >66)=
[tex]P ( \overline x > 66 ) = P ( \dfrac{\overline x -\mu }{\dfrac{\sigma}{\sqrt{n}}} > \dfrac{66 -\mu }{\dfrac{\sigma}{\sqrt{n}}})[/tex]
[tex]P ( \overline x > 66 ) = P ( Z> \dfrac{66 - 65 }{\dfrac{7}{\sqrt{196}}})[/tex]
[tex]P ( \overline x > 66 ) = P ( Z> \dfrac{1 }{\dfrac{7}{14}})[/tex]
[tex]P ( \overline x > 66 ) = P ( Z> \dfrac{14 }{7})[/tex]
[tex]P ( \overline x > 66 ) = P ( Z>2)[/tex]
[tex]P ( \overline x > 66 ) = 1 - P ( Z<2)[/tex]
from z tables
[tex]P ( \overline x > 66 ) = 1 - 0.9773[/tex]
[tex]\mathbf{P ( \overline x > 66 ) =0.02275}[/tex]
The following rational equation has denominators that contain variables. for this equation, A. write the value or values of the variable that makes the denominator zero. These are the restrictions on the variable. B.
keeping the restrictions in mind, solve the equation.
3/x+4 + 2/x-4 = 16/(x+4)(x-4)
A. what is/ Are The value our values of the variable that make(s) the denominators zero?
x=
Answer:
A. -4 and 4
B. No solution.
Step-by-step explanation:
The given equation is
[tex]\dfrac{3}{x+4}+\dfrac{2}{x-4}=\dfrac{16}{(x+4)(x-4)}[/tex]
A.
Equate the denominators equal to 0 to find the restrictions on the variable.
[tex]x+4=0\Rightarrow x=-4[/tex]
[tex]x-4=0\Rightarrow x=4[/tex]
Therefore, [tex]x\neq -4,4[/tex].
B.
We have,
[tex]\dfrac{3}{x+4}+\dfrac{2}{x-4}=\dfrac{16}{(x+4)(x-4)}[/tex]
[tex]\dfrac{3(x-4)+2(x+4)}{(x+4)(x-4)}=\dfrac{16}{(x+4)(x-4)}[/tex]
Multiply both sides by (x-4)(x+4).
[tex]3x-12+2x+8=16[/tex]
[tex]5x-4=16[/tex]
Add 4 on both sides.
[tex]5x=16+4[/tex]
[tex]5x=20[/tex]
Divide both sides by 5.
[tex]x=4[/tex]
Here the solution is x=4 but it is the restricted value.
Therefore, the given equation has no solution.
For the given rational equation, we have that:
A. The values of the variable that make(s) the denominators zero are x = -4 and x = 4.B. The equation has no solution.Rational Equation:The rational equation given in this problem is:
[tex]\frac{3}{x + 4} + \frac{2}{x - 4} = \frac{16}{(x + 4)(x - 4)}[/tex]
Then, applying the least common factor:
[tex]\frac{3(x - 4) + 2(x + 4)}{(x + 4)(x - 4)} = \frac{16}{(x + 4)(x - 4)}[/tex]
[tex]\frac{5x - 4}{(x + 4)(x - 4)} - \frac{16}{(x + 4)(x - 4)} = 0[/tex]
[tex]\frac{5x - 20}{(x + 4)(x - 4)} = 0[/tex]
Item a:
The denominator cannot be zero, hence:
[tex](x + 4)(x - 4) \neq 0[/tex]
[tex]x \neq -4[/tex]
[tex]x \neq 4[/tex]
The values of the variable that make(s) the denominators zero are x = -4 and x = 4.
Item b:
[tex]5x - 20 = 0[/tex]
[tex]5x = 20[/tex]
[tex]x = \frac{20}{5}[/tex]
[tex]x = 4[/tex]
However, x = 4 makes the denominator zero, hence the equation has no solution.
You can learn more about rational functions at https://brainly.com/question/13136492
Name the 5 ways/methods/techniques we can use to find a limit.
Answer:
you have four techniques to choose from: plugging in the x value, factoring, rationalizing the numerator, and finding the lowest common denominator.
hope that helps : )
Plz Help!!!!!!!!!
15. Men need to intake between 2200 and 2800 calories daily. Women need 600 fewer calories than this. Write and solve an inequality to discover how many calories women should be taking in per day.
A. 2200 x < 2800
B. 2200 > x < 2800
C. 600 < x < 1200
D. 1600 < x < 2800
E. 1600 < x < 2200
F. 2800 < x < 3200
Answer:
A
Step-by-step explanation:
The difference between the length and the
width of a rectangle is 5 centimeters. What is
the length (the longer side) of the rectangle, if
its perimeter is equal to 106 centimeters?
Lines L and M are parallel.
L
3/4
2/5
1/6
38° 7
-M
Find : m_3
belongs in the green box. [?]
?
o
Entor
Step-by-step explanation:
Hey, there!
Let's simply solve it.
As there is given that L and M are parallel. Use all the condition or properties of parallel lines.
Here use:
vertically opposite angle. coointerior angles sum is 180°.Now,
angle 6= 38° { Vertically opposite angle}.
angle 6 + angle 5 = 180° { as sum of coointerior angles are equal to 180°}
38°+angle 5 = 180°
or, angke 5 = 180°-38°
Therefore, angle 5 = 142°
Now, angle 3 = angle 5 { Vertically opposite angle}
Therefore, the measure of angle 3 is 142°.
[tex]hope \: it \: helps...[/tex]
Answer: 142
Step-by-step explanation:
Can someone show me how to get the answer to this step by step? It's Combining Like Terms. [tex]-9x^{2}[/tex] - 7 + [tex]4x[/tex] + [tex]10x^{2}[/tex] - 14x
Answer:
x² - 10x - 7
Step-by-step explanation:
See steps below:
- 9x² - 7 + 4x + 10x² - 14x = (-9x² + 10x²) + (4x - 14x) - 7 = ⇒ like terms combined in parenthesisx² - 10x - 7 ⇒ simplifiedThe Perimeter of a rectangle is 12 meters if the length of the rectangle is 5 meters what is the width
Answer:
1 meter wide
Step-by-step explanation:
5+5=10
2/2=1
Answer:
1
Step-by-step explanation:
Bell metal which is a form of bronze is used for casting bells. It is an alloy of copper and tin. To make bell metal requires 17 parts of copper to every 3 parts of tin. (6) (i) Express this requirement as a ratio (ii) Express the amount of tin required as a percentage of the total (iii) If the total amount of tin in a particular casting is 150 kg, find the amount of copper
Answer:
you need 17 parts copper and 3 parts tin in order to make brass
1. ratio of copper with respect to brass: 17:20
ratio of tin with respect to brass: 3:20
ratio of tin with respect to copper: 3:17
2. percentage of tin required in brass: fraction of tin in brass X 100
3/20 X 100 = 15%
3. if we used 150 kg tin in the alloy, then 150 kg is 15 % of the alloy
(from last answer)
150/x X 100 = 15%
x = 1000 kg
if the total brass formed is 1000 kg, and 150 kg of it is tin,
copper used = 1000 - 150 = 850 kg copper
Use Stokes' Theorem to evaluate
∫
C
F � dr
where F(x, y, z) = x2yi + 1/3x3j + xyk and C is the curve of intersection of the hyperbolic paraboloid z = y2 ? x2
and the cylinder x2 + y2 = 1 oriented counterclockwise as viewed from above.
Find parametric equations for C,Let x and y be in terms of t where
0 ? t ? 2?
Answer:
[tex]\int_C F . dr = \pi[/tex]
[tex]C : x = cost , y = sin t, z = sin^2 t - cos^2 t , 0 \leq t \leq 2 \pi[/tex]
Step-by-step explanation:
Given that:
[tex]F(x,y,z) = x^2yi + \dfrac{1}{3}x^3j +xyk[/tex]
Here C is the curve of intersection of the hyperbolic parabolic [tex]z = y^2 - x^2[/tex] and the cylinder [tex]x^2 +y^2 =1[/tex]
Using Stokes' Theorem
[tex]\int_C F . dr =\int \int \limits_s \ curl \ F. \ds[/tex]
From above ;
S = the region under the surface [tex]z = y^2 -x^2[/tex] and above the circle [tex]x^2+y^2 =1[/tex]
Suppose, we consider [tex]f(x,y,z) =z-y^2+x^2[/tex]
therefore, S will be the level curve of f(x,y,z) = 0
Recall that:
[tex]\bigtriangledown f (x,y,z)[/tex] is always normal to the surface S at the point (x,y,z).
∴
This implies that the unit vector [tex]n = \dfrac{\bigtriangledown f}{|| \bigtriangledown ||}[/tex]
So [tex]\bigtriangledown f = <2x, -2y,1 >[/tex]
Also, [tex]|| \bigtriangledown f ||= \sqrt{4x^2+4y^2+1}[/tex]
Similarly ;
[tex]curl \ F = \begin {vmatrix} \begin{array} {ccc}{\dfrac{\partial }{\partial x} }&{\dfrac{\partial }{\partial y} }& {\dfrac{\partial }{\partial z} }\\ \\ x^2y& \dfrac{1}{3}x^3&xy \end {array} \end{vmatrix}[/tex]
[tex]curl \ F = \langle x ,-y,0 \rangle[/tex]
Then:
[tex]\int \int_s curl \ F .ds = \int \int_s curl \ F .nds[/tex]
[tex]\int \int_s curl \ F .ds = \iint_D curl \ F \dfrac{\bigtriangledown f}{ || \bigtriangledown f||} \sqrt{ (\dfrac{\partial z}{\partial x }^2) + \dfrac{\partial z}{\partial x }^2)+1 } \ dA[/tex]
[tex]\int \int_s curl \ F .ds = \iint_D \dfrac{\langle x,-y,0 \rangle * \langle 2x,-2y,1 \rangle }{\sqrt{4x^2 +4y^2 +1 }} \times \sqrt{4x^2 +4y^2 +1 }\ dA[/tex]
[tex]\int \int_s curl \ F .ds = \iint_D (2x^2 + 2y^2) \ dA[/tex]
[tex]\int \int_s curl \ F .ds = 2 \iint_D (x^2 + y^2) \ dA[/tex]
[tex]\int \int_s curl \ F .ds = 2 \int \limits ^{2 \pi} _{0} \int \limits ^1_0r^2.r \ dr \ d\theta[/tex]
converting the integral to polar coordinates
This implies that:
[tex]\int \int_s curl \ F .ds = 2 \int \limits ^{2 \pi} _{0} \int \limits ^1_0r^2.r \ dr \ d\theta[/tex]
⇒ [tex]\int_C F . dr = 2(\theta) ^{2 \pi} _{0} \begin {pmatrix} \dfrac{r^4}{4}^ \end {pmatrix}^1_0[/tex]
[tex]\int_C F . dr = 2(2 \pi) (\dfrac{1}{4})[/tex]
[tex]\int_C F . dr =(4 \pi) (\dfrac{1}{4})[/tex]
[tex]\int_C F . dr = \pi[/tex]
Therefore, the value of [tex]\int_C F . dr = \pi[/tex]
The parametric equations for the curve of intersection of the hyperbolic paraboloid can be expressed as the equations of the plane and cylinder in parametric form . i.e
[tex]z = y^2 - x^2 \ such \ that:\ x=x , y=y , z = y^2 - x^2[/tex]
[tex]x^2 +y^2 =1 \ such \ that \ : x = cos \ t , y= sin \ t, z = z, 0 \leq t \leq 2 \pi[/tex]
Set them equal now,
the Parametric equation of [tex]C : x = cost , y = sin t, z = sin^2 t - cos^2 t , 0 \leq t \leq 2 \pi[/tex]
Problem PageQuestion A circle has a radius of . Find the radian measure of the central angle that intercepts an arc of length . Do not round any intermediate computations, and round your answer to the nearest tenth
Answer:
0.1π radStep-by-step explanation:
The question is incomplete. Here is the complete question.
A circle has a radius of 19m . Find the radian measure of the central angle θ that intercepts an arc of length 5m. Do not round any intermediate computations, and round your answer to the nearest tenth.
The formula for calculating the length of an arc [tex]L = \frac{\theta}{360} * 2 \pi r[/tex]
θ is the central angle
r is the radius of the circle = 19m
L is the length of an arc = 5m
Substitute the given values into the formula and get the central angle θ
5 = θ/360 * 2(22/7)*19
5 = θ/2π * 119.4285714
θ/2π = 5/119.4285714
θ/2π = 0.041866
θ = 2π*0.041866
θ = 0.083732π
θ = 0.1π rad (to the nearest tenth)
Hence the radian measure of the central angle that intercepts an arc of length to the nearest tenth is 0.1π rad
I WILL GIVE THE BRAINIEST
Which of the following could be a rational number?
A. the product of two irrational numbers.
B. the sum of two irrational numbers.
C. the product of a rational number and an irrational number.
D.the sum of a rational number and an irrational number
Answer:
A.
Step-by-step explanation:
the product of two irrational numbers
Answer:
the answer is A
Step-by-step explanation:
A. the product of two irrational numbers.
Write an equation that represents the perimeter of the rectangle. The length of a rectangle is 4 feet less than twice its width, while the perimeter is 15.
Answer:
Equation: 7.5 = ((2b-4) + b)length = 3.6667 ftwidth = 3.8333 ftStep-by-step explanation:
perimeter = 2(length+width)
then:
15 = 2(a+b)
a = 2b - 4
a = length
b = width
solve:
15/2 = (a+b)
7.5 = ((2b-4) + b) ⇒ Equation that represents the perimeter of the
rectangle)
7.5 = 3b -4
7.5+4 = 3b
11.5 = 3b
b = 11.5/3
b = 3.8333
a = 2b - 4
a = 2*3.8333 - 4
a = 3.6667
Check:
15 = 2(3.8333 + 3.6667)
15 = 2*7.5
Which equation correctly shows the multiplication of the means and extremes in the proportion 7.2∕9.6 = 21.6∕28.8?
Which equation correctly shows the multiplication of the means and extremes in the proportion 7.2 ∕ 9.6 = 21.6 ∕ 28.8?
a. 7.2 ⋅ 9.6 = 21.6 ⋅ 28.8
b. 9.6 ⋅ 21.6 = 28.8 ⋅ 7.2
c. 7.2 ⋅ 21.6 = 28.8 ⋅ 9.6
d. 7.2 ⋅ 28.8 = 21.6 ⋅ 28.8
Answer:
b. 9.6 ⋅ 21.6 = 28.8 ⋅ 7.2
Step-by-step explanation:
When a proportion say a/b = c/d is given, the outer terms are called the extremes while the inner/middle terms are called the means.
In the case of a / b = c / d,
the outer terms are a and d
the inner terms are b and c
Often times, we find the cross products of the proportion to test whether the two ratios in the proportion are equal. To do that, we find the product of the extremes and equate it to the product of the means.
In the case of a / b = c / d,
the cross products are a x d and b x c
So if a x d = b x c, then a/b = c/d is a true proportion.
Now to the question;
Given proportion: 7.2 / 9.6 = 21.6 / 28.8
Extremes = 7.2 and 28.8
Means = 9.6 and 21.6
The correct multiplication of the means and extremes is therefore
9.6 x 21.6 = 7.2 x 28.8
or
9.6 · 21.6 = 7.2 · 28.8
Write the equivalent ratio
11:4= __:16
Answer:
the missing value is 44
Step-by-step explanation:
let the missing value be x
we can solve this by expressing both ratios as rational expressions
11:4 = x:16
[tex]\frac{11}{4} = \frac{x}{16}[/tex] (cross multiply the denominators to eliminate them)
(11)(16) = (4)(x)
4x = 176
x = 176 / 4
x = 44
hence the ration is
11:4 = 44 : 16
A polygon is shown:
The area of polygon MNOPQR = Area of a rectangle that is 9 square units + Area of a rectangle that is ___ square units. (Input whole numbers only, such as 8.)
Answer:
10 square units
Step-by-step explanation:
Surface area of this figure
Answer:
23
Step-by-step explanation:
you add 10m(h) plus 8m(w) plus 15m(l)
Answer:
523.1m²
Step-by-step explanation:
Triangle: 1/2bh=1/2(4)(10)=20x2=40 each
Bottom Rectangle: 15x8=120
Side Rectangles: Since the side is a hypotenuse of a right triangle, it’s the square root of 10²+4²=√116=10.77. 10.77x15=161.55
So the total surface area would be 40+40+120+161.55+161.55=523.1m²
Evaluate.
(-4)=
(-7) = 0
Please help ASAP!!
(-4)³ = (-4)(-4)(-4) = 16(-4) = - 64
(-7)² = (-7)(-7) = 49
(-)×(-) = +
(-)×(+) = -
A triangle has vertices at F (8, 3), G (3, 5), and H (1, 7). What are the coordinates of each vertex if the triangle is rotated 180° about the origin counterclockwise?
Question 1 options:
F ¢(8, 3), G¢(-3, 5), H ¢(-1, -7)
F ¢(8, -3), G ¢(3, -5), H ¢(1, -7)
F ¢(-8, 3), G¢(-3, 5), H ¢(-1, 7)
F ¢(-8, -3), G ¢(-3, -5), H ¢(-1, -7)
Answer: F (-8, -3), G (-3, -5) and H (-1, -7)
Step-by-step explanation:
A rotation of 180° around the origin is equivalent to a reflection over the x-axis, and then another reflection over the y-axis.
Then, if we have a point (x, y) and we do a rotation of 180°, the point will transform into (-x, -y)
Then if at the start the vertices of the triangle are:
F (8, 3), G (3, 5), and H (1, 7).
After a rotation of 180°, the vertices will be:
F (-8, -3), G (-3, -5) and H (-1, -7)
The correct option is the last one.
The distributive property of multiplication justifies which of the following statements? A 3x + 4(y – z) = 3x + 4(y) + 4(-z) B 3(x)+ 3(y) + 3(z) = 27(xyz) C 8 + (-8) = 0 D (a + b) + c = (c + a) + b
Answer:
The distributive property is used when we have to multiplicate a parenthesis:
[tex]a*(b+c) = ab+ac[/tex]
So the corrects andwer is A) 3x + 4(y-z) = 3x + 4y - 4z, because:
[tex]3x + 4(y-z) = 3x + 4*y + 4*(-z) = 3x + 4y - 4z[/tex]
B is incorrect, as [tex]3x + 3y + 3z 27\neq xyz[/tex]
C is correct, as a number plus his opposite is always 0.
D is correct, but that's the associate property as it's correct that for any three numbers of an associative set, there's another operation with verifies the equality.
NED THIS AND HOW U GOT THE ANSWER find the measure of the angle greater than BFX using the figure below
Answer: 140°
Step-by-step explanation:
If you look at ∠BXF, you can see that F is at the base of the inner semi circle. Going left, you can see that it stops at 140. Now, we know that m∠BXF is 140°.
Answer:
m∠BXF = 140°
Step-by-step explanation:
The symbol "<" is "greater than." The symbol "∠" is "angle." When used as "m∠", it refers to "the measure of angle ...".
Here, you're asked for the measure of angle BXF.
You can see that it is an obtuse angle, so will have a measure greater than 90°. The protractor has two scales: one measuring angles counterclockwise, and the other measuring angles clockwise. Ray XF is aligned with the 0 on the inner (counterclockwise) scale, so the angle measure is found where ray XB crosses that scale.
Ray XB crosses the inner scale of the protractor at 140, so ...
m∠BXF = 140°.