Answer:
It will not be very helpful to use this point because it lies on the x-axis. Which doesn't show what area to shade.
Step-by-step explanation:
Which number is equal to 10^-3?
-1,000
-30
0.001
0.003
Work Shown:
10^(-3) = 1/( 10^3 ) = 1/1000 = 0.001
The rule used here is x^(-k) = 1/( x^k )
Answer:
C. O.001
Step-by-step explanation:
10^-3 = (1)/(10^3)
move the negative exponent to the denominator
(1)/(1000)
simplify 10^3 in the denominator
(1)/(1000) = 0.001
Jameel drew circle A and found that the measure of the is 58°. He knows that he can use this measure to determine the measure of many of the other angles shown in the circle. Enter the measure of ∠ADB.
The measure of many of the other angles shown in the circle is: measure of ∠ADB=29°.
Measure of angle ADBGiven:
∠CAD=58°
Hence:
∠BAD=180°-58°
∠BAD=122°
Since ∠ABD is isosceles, thus:
∠ADB-∠ABD
180°-122°=58°
2∠ADB=58°/2
∠ADB=29°
Therefore the measure of many of the other angles shown in the circle is: measure of ∠ADB=29°.
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An ant needs to travel along a 20cm × 20cm cube to get from point A to point B. What is the shortest path he can take, and how long will it be (in cm)?
Each edge of the cube is 20cm. If it stayed on the edges it would need to walk on 3 edges for a total distance of 3 x 20 = 60 cm.
If it walked diagonally across the front face and then one edge it would travel:
Diagonal = sqrt(20^2 + 20^2) = 28.28
Total distance waling a diagonal and then an edge = 28.28 + 20 = 48.28 cm
The shortest distance would be diagonally across the front face then the edge to point B and the distance would be 48.28 cm.
1) UN MOVIL A SE MUEVE DESDE UN PUNTO CON VELOCIDAD CONSTANTE DE 20m/s EN EL MISMO INSTANTE A UNA DISTANCIA DE 1200m, OTRO MOVIL B SALE Y PERSIGUE AL MOVIL A CON VELOCIDAD CONSTANTE DE 40m/s.¿ EN QUE TIEMPO Y A QUE DISTANCIA B ALCANZA a
Answer:
El móvil B necesita 60 segundos para alcanzar al móvil A y le alcanza una distancia de 2400 metros con respecto al punto de referencia.
Step-by-step explanation:
Supóngase que cada movil viaja en el mismo plano y que el móvil B se localiza inicialmente en la posición [tex]x = 0\,m[/tex], mientras que el móvil A se encuentra en la posición [tex]x = 1200\,m[/tex]. Ambos móviles viajan a rapidez constante. Si el móvil B alcanza al móvil A después de cierto tiempo, el sistema de ecuaciones cinemáticas es el siguiente:
Móvil A
[tex]x_{A} = 1200\,m+\left(20\,\frac{m}{s} \right)\cdot t[/tex]
Móvil B
[tex]x_{B} = \left(40\,\frac{m}{s} \right)\cdot t[/tex]
Donde:
[tex]x_{A}[/tex], [tex]x_{B}[/tex] - Posiciones finales de cada móvil, medidas en metros.
[tex]t[/tex] - Tiempo, medido en segundos.
Si [tex]x_{A} = x_{B}[/tex], el tiempo requerido por el móvil B para alcanzar al móvil A es:
[tex]1200\,m+\left(20\,\frac{m}{s} \right)\cdot t = \left(40\,\frac{m}{s} \right)t[/tex]
[tex]1200\,m = \left(20\,\frac{m}{s} \right)\cdot t[/tex]
[tex]t = \frac{1200\,m}{20\,\frac{m}{s} }[/tex]
[tex]t = 60\,s[/tex]
El móvil B necesita 60 segundos para alcanzar al móvil A.
Ahora, la distancia se obtiene por sustitución directa en cualquiera de las ecuaciones cinemáticas:
[tex]x_{B} = \left(40\,\frac{m}{s} \right)\cdot (60\,s)[/tex]
[tex]x_{B} = 2400\,m[/tex]
El móvil B alcanza al móvil A a una distancia de 2400 metros con respecto al punto de referencia.
Describe the relationship between quartiles and percentiles. ▼ are special cases of ▼ ▼ Upper Q 2 Upper Q 3 Upper Q 1 is the 25th percentile, ▼ Upper Q 2 Upper Q 1 Upper Q 3 is the 50th percentile, and ▼ Upper Q 2 Upper Q 3 Upper Q 1 is the 75th percentile.
Answer:
Q1 is the 25th percentile
Step-by-step explanation:
Quartiles are known to be one-fourth of an entity, that is, 1/4th with the whole evaluating to 1. The numerator cannot exceed four, as the division compares an item in an entity to the whole of the entity or sample.
Percentiles represents a whole entity as a 100 with the symbol "%" which denote its use.
The first quartile is 25th percentile, the second is the 50th percentile, the third is the 75th percentile while the fourth quartile which is 4/4 is the 100th percentile mark.
ANSWER QUICKLY PLZZZZZZ
ANSWER QUESTION C
Answer:
[tex] \boxed{12}[/tex]Step-by-step explanation:
E is 5 more than d
f is 7 less than d
a) e = d + 5
b) f = d - 7
c) plug the values of e and f
[tex] = d + 5 - (d - 7)[/tex]
When there is a ( - ) in front of an expression in parentheses, change the sign of each term in the expression
[tex] = d + 5 - d + 7[/tex]
Since, two opposites add up to zero , remove them from the expression
[tex] = 5 + 7[/tex]
Add the numbers
[tex] = 12[/tex]
Hope I helped!
Best regards!
Ken has 86 feet of fencing , to make a vegetable garden . Which design below will give ken the largest garden ?
Answer:it’s the top right box
Step-by-step explanation: what I did was I added 24+24 and 19+19 which gives you 86ft
Answer:It is left side 21ft and top 22ft Step-by-step explanation:
Suppose that F(x) = x? and g(x) = -3x? Which statement best compares the
graph of G(x) with the graph of F(x)?
Answer:
flipped over the x-axis and stretched verticallyStep-by-step explanation:
Multiplying y by a value greater than 1 results in a vertical stretch. When the sign of it is negative there is a reflection over the x-axis. The appropriate choice is shown below.
__
The second attachment shows how the graph is flipped and stretched.
6.3 covert to fractional form like a fraction and get a like and brainiest !
<1 and <2 are vertical angles. If m<1 = (5x+12) and m<2 = (23x + 17) find m<2
Answer:
m∠2 = 10 11/18°
Step-by-step explanation:
Vertical angles are equal to one another.
[tex]5x+12=23x+17\\\\12=18x+17\\\\-5=18x\\\\-\frac{5}{18}=x[/tex]
Now substitute the value for the variable to find m∠2.
[tex]23(-\frac{5}{18})+17\\\\-\frac{115}{18}+17\\\\\frac{191}{18}=10\frac{11}{18}[/tex]
Avanced Algebra PLS ANSWER THIS CORRECTLY
Use the function f(x) to answer the questions:
f(x) = 2x^2 − 3x − 5
Part A: What are the x-intercepts of the graph of f(x)? Show your work. (2 points)
Part B: Is the vertex of the graph of f(x) going to be a maximum or a minimum? What are the coordinates of the vertex? Justify your answers and show your work. (3 points)
Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph. (5 points)
Answer:
Below
Step-by-step explanation:
Part A: -1 and 2.5
Part B: The vertex is a minimum
Part C: tbh, I'm not quite sure about this part but just use parts A and B to answer :)
(you can also use the website desmos. com/calculator as a graphing calculator)
Write the last 4 digits of a telephone number (each digit MUST be different--ex. 5237). List all the 4-digit numbers you can make using those 4 digits.
Answer:
5040
Step-by-step explanation:
All the possible Numbers that can be placed in the last for places =0,1,2,3,4,5,6,7,8,9
If all the digits have be different , then
= 10 x 9 x 8 x 7
= 90 x 56
= 5040 are total no. of 4-digit numbers can be made using those 4 digits.
define space in detail.
Answer:
space is the capacity that an object or shape weigh
What is the additive identity of -17?
Answer:
The additive identity is 0. The sum of any number with the additive identity is the number itself.
I HOPE ITS RIGHT IF NOT THEN SORRYHAVE A GREAT DAY :)
EFGH is an isosceles trapezoid and EFGI is a parallelogram. If m∠IEF = 36°, then m∠HGI = ° (Blank 1).
The base angles of an isosceles trapezoid are equal; For EFGI to be a parallelogram, the measure of [tex]\angle HGI[/tex] is: 108 degrees
Given that:
[tex]\angle IEF = 36^o[/tex]
IEF and GHI are the base angles of the trapezoid.
So:
[tex]\angle GHI = \angle IEF = 36^o[/tex]
Also:
[tex]\triangle GHI[/tex] is an isosceles triangle.
This means that:
[tex]\angle GHI = \angle HIG = 36^o[/tex] --- base angles of an isosceles triangle
So:
[tex]\angle GHI + \angle HIG + \angle HGI = 180[/tex] --- sum of angles in a triangle
Substitute known values
[tex]36 + 36+ \angle HGI = 180[/tex]
[tex]72 + \angle HGI = 180[/tex]
Collect like terms
[tex]\angle HGI = 180-72[/tex]
[tex]\angle HGI = 108[/tex]
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What is the area of a triangle whose vertices are (4,0), (2,
3), (8,-6)?(using distance formula)
a) 2 sq. units b) 0 sq. units c) 1 sq. units d) 4 sq. units
Answer:
The correct option is;
b) 0 sq, units
Step-by-step explanation:
The vertices of the triangle are;
(4, 0), (2, 3), (8, -6)
The distance formula fr finding the length of a segment is given as follows;
[tex]l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}[/tex]
Where, (x₁, y₁) and (x₂, y₂) are the coordinates of the end points of the line
For the points (4, 0) and (2, 3) , we have;
√((3 - 0)² + (2 -4)²) = √13
Distance from (4, 0) to (2, 3) = √13
For the points (4, 0) and (8, -6) , we have;
√((-6 - 0)² + (8 -4)²) = √13 =
Distance from (4, 0) to (8, -6) = 2·√13
For the points (2, 3) and (8, -6) , we have;
√((-6 - 3)² + (8 -2)²) = 3·√13 =
Distance from (2, 3) to (8, -6) = 3·√13
Therefore, the perimeter of the triangle = 6·√13
The semi perimeter s = 3·√13
The area of the triangle, [tex]A = \sqrt{s\cdot \left (s-a \right )\cdot \left (s-b \right ) \cdot \left ( s-c \right )}[/tex]
Where;
a, b, and c are the length of the sides of the triangle;
[tex]A = \sqrt{3\cdot \sqrt{3} \cdot \left (3\cdot \sqrt{3} -\sqrt{3} \right )\cdot \left (3\cdot \sqrt{3} -2 \cdot \sqrt{3} \right ) \cdot \left ( 3\cdot \sqrt{3} -3\cdot \sqrt{3} \right )} = 0[/tex]
Therefore, the area = 0 sq, units.
Find the values of θ in the range 0≤θ≤360° which satisfy: 2 sin^2 θ - sinθ -1= 0
Answer:
Step-by-step explanation:
Solving trig equations are just like solving "regular" equations. Let's get to it. First and foremost we are going to make a "u" substitution. You'll use that all the time in calculus, if you choose to go that route. Let
[tex]sin^2 \theta=u^2[/tex] and sinθ = u. Making the substitution, the equation becomes:
[tex]2u^2-u-1=0[/tex]
That looks like something that can be factored, right? If you throw it into the quadratic formula you get the factors:
(u - 1)(2u + 1) = 0
By the Zero Product Property, either u - 1 = 0 or 2u + 1 = 0, so we will solve those, but not until after we back-substitute!
Putting sinθ back in for u:
sinθ - 1 = 0 so
sinθ = 1 and in the other equation:
2sinθ + 1 = 0 so
2sinθ = -1 and
[tex]sin\theta=-\frac{1}{2}[/tex]
Get out the unit circle and look to where the sinθ has a value of 1. There's only one place in your interval, and it's at 90 degrees.
Now look to where the sinθ has a value of -1/2. There are 2 places within your interval, and those are at 210° and 330°. Now you're done!
Help I don’t know the answer
Answer:
(D) 6
Step-by-step explanation:
We can substitute the values of a (7) and b (-4) into the equation to find it's result.
[tex]\frac{|2a| -b}{3} \\\\\\\frac{|2\cdot7|-(-4)}{3}\\\\\frac{|14|+4}{3}\\\\\frac{14+4}{3}\\\\\frac{18}{3}\\\\ 6[/tex]
So 6 is the value of this expression when a is 7 and b is -4.
Hope this helped!
Find the value of x in this equation. 180-5x=140180−5x=140
Answer: 8
Step-by-step explanation:
Which of the two functions below has the largest maximum y-value?
f(x) = -x4- 2
g(x) = -3x3 + 2
Answer:
g(x)=-3x^{3}+2
Step-by-step explanation:
g(x) has a range that of (-infinity, +infinity), whereas f(x) has a range of (-infinity, -2].
Answer:
Step-by-step explanation:
● f(x) = -x^4 -2
● g(x) = -3x^3 + 2
Derivate both functions:
● f'(x) = -4x^3
● g'(x) = -9x^2
Solve the equations f'(x) =0 and g'(x) =0
● f'(x) = 0
● -4x^3 = 0
● x^3 = 0
● x =0
● g'(x) = 0
● -9x^2 = 0
● x^2 =0
● x = 0
So both functions f and g reach their maximum at 0.
● f(0) = 0^4-2 = -2
● g(0) = -3×0^3 +2 = 2
So g(0)>f(0)
So g has the largest maximum value.
hey i suck at math can someone help me with this question
we can subtract the trapezium (white part) formed after from the trapezium (including white and grey) to get area of striped part
area of trapezium is [tex]\frac H2(a+b)[/tex] where $a$ and $b$ are parallel sides.
for bigger trapezium, $h=4$ parallel sides are $5$ and $5$
hence area is $\frac{4(5+5)}{2}=20$
similarily area of white trapezium, $\frac{4(3+3)}{2}=12$
and area of striped part is $20-12=8$
The Cube root of 66 is between which two integers?
Answer:
4 and 5
Step-by-step explanation:
cube root of 66 is 4.041240021
Your mother has left you in charge of the annual family yard sale. Before she leaves you to your entrepreneurial abilities, she explains that she has made the job easy for you: everything costs either $1.50 or $3.50. She asks you to keep track of how many of each type of item is sold, and you make a list, but it gets lost sometime throughout the day. Just before she’s supposed to get home, you realize that all you know is that there were 150 items to start with (your mom counted) and you have 41 items left. Also, you know that you made $227.50. Write a system of equations that you could solve to figure out how many of each type of item you sold.
A) x + y = 109
(1.5)x + 227.50 = (3.5)y
B) x + y = 109
(3.5)x + 227.50 = (1.5)y
C) x + y = 41
(1.5)x + 227.50 = (3.5)y
D) x + y = 109
(1.5)x + (3.5)y = 227.50
E) x + y = 150
(1.5)x + (3.5)y = 227.50
F) x + y = $3.50
(1.5)x + (3.5)y = 227.50
Answer:
[tex]D)\ x + y = 109\\(1.5)x + (3.5)y = 227.50[/tex]
Step-by-step explanation:
Let the items sold with price $1.5 = [tex]x[/tex]
Let the items sold with price $3.5 = [tex]y[/tex]
Initially, total number of items = 150
Items left at the end of the day = 41
So, number of items sold throughout the day = Total number of items - Number of items left
Number of Items sold = 150 - 41 = 109
So, the first equation can be written as:
[tex]\bold{x+y = 109} ....... (1)[/tex]
Now, let us calculate the sales done by each item.
Sales from item with price $1.5 = Number of items sold [tex]\times[/tex] price of each item
= (1.5)[tex]x[/tex]
Sales from item with price $3.5 = Number of items sold [tex]\times[/tex] price of each item
= (3.5)[tex]y[/tex]
Total sales = [tex]\bold{(1.5)x+(3.5)y = 227.50} ....... (2)[/tex]
So, the correct answer is:
[tex]D)\ x + y = 109\\(1.5)x + (3.5)y = 227.50[/tex]
A cylindrical tank whose diameter is 1.4 metres and height 80 cm is initially empty. Water whose volume is 492.8 litres is poured into the tank. Determine the fraction of the tank filled with water. (4 marks
Answer:
7/40 is the fraction filled with water
Step-by-step explanation:
Here we start by calculating the volume of the cylindrical tank.
Mathematically, that would be;
V = π * r^2 * h
From the question
r = 80 cm = 80/100 = 0.8 meters
h = 1.4 meters
π = 22/7
Plugging these values into the volume equation, we have;
V = 22/7 * 0.8 * 0.8 * 1.4 = 2.816 m^3
But mathematically;
1 m^3 = 1000 liters
So 2.816 m^3 = 2.816 * 1000 = 2816 liters
So the fraction filled with water will be;
492.8/2816 = 0.175 = 175/1000 = 7/40
subtract c from 7, then divide b by the result
Answer:
[tex]\frac{7-c}{b}[/tex]
Answer:
[tex]\frac{7 -c}{b}[/tex]
Step-by-step explanation:
Subtract c from 7 : 7 - c
Then the result is divide by b : [tex]\frac{7 -c}{b}[/tex]
If a is an arbitrary nonzero constant, what happens to a/b as b approaches 0
It depends on how b approaches 0
If b is positive and gets closer to zero, then we say b is approaching 0 from the right, or from the positive side. Let's say a = 1. The equation a/b turns into 1/b. Looking at a table of values, 1/b will steadily increase without bound as positive b values get closer to 0.
On the other side, if b is negative and gets closer to zero, then 1/b will be negative and those negative values will decrease without bound. So 1/b approaches negative infinity if we approach 0 on the left (or negative) side.
The graph of y = 1/x shows this. See the diagram below. Note the vertical asymptote at x = 0. The portion to the right of it has the curve go upward to positive infinity as x approaches 0. The curve to the left goes down to negative infinity as x approaches 0.
Plot the image of quadrilateral ABCD under a reflection across the x-axis.
Answer:
The points for this will be:
A: (1, -4)
B: (-4, -2)
C: (-5, 4)
D: (-2, 1)
Step-by-step explanation:
If we reflect a shape over the x-axis, all of it’s points y values will be negated.
So, (1, 4) becomes (1, -4)
(-4, 2) becomes (-4, -2)
(-5, -4) becomes (-5, 4)
and (-2, -1) becomes (-2, 1)
Hope this helped!
New coordinates of the quadrilateral are A' is (1, -4), B' is (-4, -2), C' is (-5, 4) and D' is (-2, 1)
What is Graph?Graph is a mathematical representation of a network and it describes the relationship between lines and points.
The coordinates of quadrilateral ABCD are A is (1, 4), B is (-4, 2), C is (-5, -4) and D is (-2, -1)
After reflecting across the x-axis , the x-coordinates of the vertices will remain the same, but the signs of their y-coordinates will change.
Therefore, the new coordinates of the vertices will be:
A' is (1, -4)
B' is (-4, -2)
C' is (-5, 4)
D' is (-2, 1)
Hence, new coordinates of the quadrilateral are A' is (1, -4), B' is (-4, -2), C' is (-5, 4) and D' is (-2, 1)
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Choose all answers that apply
A -x + (-x) = 0
B x - (-x) = 0
C none of the above
Answer:
c
Step-by-step explanation:
none of the above
C none of the above
because x-(-x)=x+x=2xand
-x+(-x)= -x-x=-2x
so answer is 'C' none of the above
PLEASE help me with this question! No nonsense answers please. This is really urgent.
Answer:
32
Step-by-step explanation:
This is because you would want the feet and the radium kinda meeting up in a way and would need to make sure you can fill it in with th e drive way as it will be on a horizontal base so you would need X2 of the driveway to make it into a standing up horizontal base
Hope this helps
If this seems incorrect please comment with the answer that it should be and I shall change my answer thanks you :)
r/3 + 5 < 8
please help
Answer:
r<9
Step-by-step explanation:
r/3 + 5 < 8
Subtract 5 from each side
r/3 + 5-5 < 8-5
r/3 < 3
Multiply each side by 3
r/3 *3 <3*3
r<9