Which equation represents the line that is perpendicular to and passes through (-8,-2)?

x = -2

x = -8

y = -6

y = -8

Answer:

The numbers 1 to 12 must be placed in the circles of the star shown on the right. The sums of the numbers in each row, and the sum of the numbers in the six outer circles of the star, must be equal to 26. Arrange the numbers accordingly.

The solution of the system of equation of the matrix is as follows:

x = - 8

y = 3

3x + 10y = 6

x + 3y = 1

multiply equation(ii) by 3

3x + 10y = 6

3x + 9y = 3

Therefore,

y = 3

Hence,

x + 3y = 1

x + 3(3) = 1

x + 9 = 1

x = 1 - 9

x = -8

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Answer:

800

Step-by-step explanation:

zero percent is just no percent...

800 - (0% × 800) =

800 - (0 ÷ 100 × 800) =

800 - (0 × 800) =

800 - 0 =

800

lol

The 0% of 800 is 800

Percentage is a fraction or a ratio in which the value of whole is always 100. For example, if Sam scored 30% marks in his math test, it means that he scored 30 marks out of 100. It is written as 30/100 in the fraction form and 30:100 in terms of ratio.

Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".

Calculating percentage means to find the share of a whole, in terms of 100. There are two ways to find a percentage:

Given:

800 - (0% × 800)

=800 - (0 ÷ 100 × 800)

=800 - (0 × 800)

=800 - 0 =800

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The inequalities that match the given expressions are

x ≤ 95

x > 100

5x ≤ 100

20 ≤ x ≤100

respectively

From the question, we are to match the statements with the corresponding inequalities

x ≤ 100 -5

x ≤ 95

x > 100

5x ≤ 100

x ≤ 100

and

x ≥ 1/5 × 100

x ≥ 20 ≡ 20 ≤ x

∴ 20 ≤ x ≤100

Hence, the inequalities that match the given expressions are

x ≤ 95

x > 100

5x ≤ 100

20 ≤ x ≤100

respectively

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Applying the law of sines, when the first lighting was made, the distance from the ship to the lighthouse was: 3.2 miles.

The law of sines is expressed by the equation, sin A/a = sin B/b = sin C/c.

Using the information we are provided with, the diagram that shows the ship and other information is drawn and shown in the image attached below, where:

m∠CAB = 65 + 30 = 95°

m∠BCA = 50 - 30 = 20°

m∠B = 180 - 95 - 20 = 65°

c =  the distance from the ship to the lighthouse

Considering triangle ABC, use the Law of Sines to find c:

sin B/b = sin C/c

B = 65°

b = 8.5 miles

C = 20°

Plug in the values

sin 65/8.5 = sin 20/c

Cross multiply

c(sin 65) = (8.5 × sin 200)

Divide both sides by sin 65

c(sin 65)/sin 65 = (8.5 × sin 200)/sin 65

c = (8.5 × sin 200)/sin 65

c ≈ 3.2 miles

Thus, when the first lighting was made, the distance from the ship to the lighthouse was: 3.2 miles.

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Answer: 4

Step-by-step explanation:

[tex]1102_{3}=2+0(3)+1(9)+1(27)=38\\\\212_{n}=2+1(n)+2(n^2)=2n^2 + n+2\\\\\implies 2n^2 + n+2=38\\\\2n^2 + n-36=0\\\\(n-4)(2n+9)=0\\\\n=-\frac{9}{2}, 4[/tex]

However, as the base must be positive, n=4.

Answer:Joey is 18 hope that helped you

Answer:

Vertex (2 , -25)

Axis of symmetry: x = 2

Step-by-step explanation:

 The vertex is the highest point if the parabola open downwards and the lowest point if the parabola opens upward.

 f(x) = (x - 2)² - 25

The given quadratic function  is in vertex form.

 f(x)  = a(x - h)² + k

Here,  (h , k) is the vertex of the parabola.

 h = 2  ; k = -25

[tex]\sf \boxed{\bf Vertex (2 , -25)}[/tex]

 The axis of symmetry is the vertical line that divides the parabola into two equal halves and it passes through the vertex of the parabola.

Axis of symmetry: x = h

  [tex]\sf \boxed{\bf x = 2}[/tex]

Answer:

1000

Step-by-step explanation:

cancel by 3

Answer:

[tex]\sf \dfrac{8}{21}[/tex]

Step-by-step explanation:

Given expression:

[tex]\sf \dfrac{6x}{-7} \cdot \dfrac{4}{-9x}[/tex]

When multiplying fractions, simply multiply the numerators and multiply the denominators:

[tex]\implies \sf \dfrac{6x}{-7} \cdot \dfrac{4}{-9x} = \dfrac{6x \cdot 4}{-7 \cdot -9x} =\dfrac{24x}{63x}[/tex]

Cancel the common factor x:

[tex]\implies \sf \dfrac{24 \diagup\!\!\!\!x}{63 \diagup\!\!\!\!x}=\dfrac{24}{63}[/tex]

Rewrite 24 as 3 · 8 and rewrite 63 as 3 · 21:

[tex]\implies \sf \dfrac{24}{63}=\dfrac{3 \cdot 8}{3 \cdot 21}[/tex]

Cancel the common factor 3:

[tex]\implies \sf \dfrac{\diagup\!\!\!\!\!3 \cdot 8}{\diagup\!\!\!\!\!3 \cdot 21}=\dfrac{8}{21}[/tex]

Answer: A

Step-by-step explanation:

There are vertical asymptotes at [tex]x=-2, 1[/tex], so the denominator should have factors of (x+2) and (x-1).

This eliminates everything except for A.

Answer:

  A.  Function f has exactly two complex solutions.

Step-by-step explanation:

The function will have real solutions where the graph crosses the x-axis. It will always have a total number of solutions equal to its degree. The ones that are not real are complex.

The graph has its vertex above the x-axis and extends upward from there. It never crosses the x-axis, so there are no real solutions. That means both solutions are complex.

Answer:

all real values of x where x < -1

Step-by-step explanation:

See attached graph.

The length if the upper portion of the stand is 33. 56 inches

The formula for the finding the length is given thus;

Total height = length of upper portion + length of base

Where

Length of base = 257/16

Total height = 591/2

Length of upper portion = total height - length of base

= 118/2 - 407/16

= 59 - 25. 44

= 33. 56 inches

Thus, the length if the upper portion of the stand is 33. 56 inches

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The way to convert counts into relative frequencies in a Two Way Relative Frequency Table is to divide the count by the total number of items

This refers to the depiction of the number of times in which an event occurs in the form of a table.

Hence, when a two-way frequency table is used, it shows the visual representation of the possible relationship between different sets of data.

Please note that your question is incomplete as you did not provide the frequency table needed and also the trends and generalizations to find, so a general overview was given.

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Answer:

The relative frequency table shows a trend that a majority of people prefer coffee over tea: the ratio in the total row for coffee is 0.65 and just 0.35 for tea. Similarly, more people are night owls than early birds: the total column for night owl is 0.6, but the early bird column is only 0.4.

The list of data points used to generate the histogram is

   x            Frequency

15-20              0

20-25             4

25-30              6

30-35              3

35-40              4

40-45              0

45-50              3

From the question, we are to write the list of data points used to generate the given histogram

The list of data points used to generate the histogram is

   x            Frequency

15-20              0

20-25             4

25-30              6

30-35              3

35-40              4

40-45              0

45-50              3

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Answer:

x = 3, -5

Step-by-step explanation:

I just know

Answer:

x= -5

x=3

Step-by-step explanation:

You are factoring here. The standard form of an equation is Ax² + Bx + C.

The 2 factors must multiple together to be C, but add together to be B. The easiest way to do this is to factor C.

C is -15. Factoring this, we find the only factors of 15 that will add together to be 2 are 5 & -3.

Therefore, the factors are (x+5) and (x-3). If you set each of these factor pairs to 0 and solve, the answers are:

x+5=0

x = -5

x-3 = 0

x=3

A. (1,4)

EXPALINATION :

IF WE WRITE THE VALUE x = -1 AND y = 4

THEN, y= -8x - 4

4= -8×-1-4

4= 8-4

AND SECOND EQUATION IS : y = x+5

y = -1 +5

y = 4

hence, solved and explained

thank you And mark me brainlist if you understand And hopes so

Answer:

[tex]f(x) = \frac{1}{2}x + 5[/tex]

Step-by-step explanation:

So you can generally express a linear function use the slope-intercept form as such: [tex]y=mx+b[/tex] where m=slope, and b=y-intercept.

The y-intercept is defined as the value of f(0), since when the line crosses the y-axis, the x-value is 0, and as provided in the table that value is 5, so we have the function rule: [tex]f(x) = mx+5[/tex]

The slope is defined as how much y-changes, as x increases by 1. We can generally use the formula: [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex] and this can be found using any two points, since the slope is constant.

We can use the two points (0, 5) and (2, 6) and plug it into the equation, to find the rise/run

[tex]\frac{6-5}{2-0} = \frac{1}{2}[/tex]

So plugging this into the slope-intercept form you get the function

[tex]f(x) = \frac{1}{2}x + 5[/tex]

Answer:

  (c)  y = 3^x

Step-by-step explanation:

A function is described as exponential if the independent variable is found in the exponent.

  y = x^(1/2) . . . a square root function, not exponential

  y = 2x^3 . . . . a cubic (polynomial) function, not exponential

  y = 3^x . . . . . an exponential function

The total amount he will pay for 20 years of coverage is $61,980. Option D

To find the total amount, we use the expression

First, we multiply the value per $1,000.00 by the number of thousands of face value coverage. This gives an estimate of the annual premium for  life insurance policy.

Nikos's premium per year = [tex]\frac{300000}{1000} * 10. 33[/tex]

Niko's premium per year = [tex]300 * 10. 33[/tex]

Niko's premium per year = $3, 099

To find the total amount, we need to multiply by the number of years

=  $3,099 x 20

= $61,980

Thus, the total amount he will pay for 20 years of coverage is $61,980. Option D

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The area of the kite exists 48 sq. ft.

The area of a kite exists half the outcome of the lengths of its diagonals. The formula to define the area of a kite exists:

Area = ½ × p × q.

Given that a kite contain diagonals of lengths 12 ft and 8 ft.

We know that the area of a kite having diagonals of length 'p' units and 'q' units exists

Area of kite = ½ (p × q)

Here, p = 12 ft and q = 8 ft.

Area of kite = ½ (p × q)

= (12 × 8)/2

= 96/2 = 48

Therefore, the area of the kite will be 48 sq. ft.

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Answer:

  1.14200738982×10^26

Step-by-step explanation:

Substitution can make this integral much easier to evaluate.

Let u = 7x² -x. Then du = (14x -1)dx. The limits on x become different limits for u:

  for x = 1: u = 7(1²) -1 = 6

  for x = 3: u = 7(3²) -3 = 60

  [tex]\displaystyle\int_1^3{(14x-1)e^{(7x^2-x)}}\,dx=\int_6^{60}{e^u}\,du=\left.e^u\right|^{60}_6\\\\=e^{60}-e^6\approx e^{60}\approx\boxed{1.14200738982\times10^{26}}[/tex]

Answer:

There are many different answers to this question but here is one that I thought of.

g(x)=x^2

f(x)=x/(x+4)

f(g(x))=F(x): plug in x^2 into each of the x in f(x) and and answer should equal F(x)

Step-by-step explanation:

since the function F(x) had 2 x^2 in it, I thought that g(x) could easily be x^2 that way u can subsitute the x in f(x) later to x^2 and get the right answer.

The non response bias can happen  if the chosen sample is too small for a study.

This is the term that is used to refer to the type of bias that happens in a research study because the some of the study participants could not participate in the study.

This type of bias is a very serious matter of concern while carrying out research.

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The relative minimum point in the graph is (-6, 2)

To do this, we simply locate a point that at a lower level, when compared to its neighboring points

Using the above highlight, there is only one relative minimum point in the graph

And the point is located at (-6,2)

Hence, the relative minimum point in the graph is (-6, 2)

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Let A, B, and W denote the sets of students apply to Addis Ababa Uni (A), Bahir Dar Uni (B), or Wachemo Uni (W). Let U denote the universal set of all students in the class.

We're given the cardinalities of several sets:

• total number of students: [tex]n(U) = 60[/tex]

• A applicants: [tex]n(A) = 30[/tex]

• B applicants: [tex]n(B) = 25[/tex]

• W applicants: [tex]n(W) = 24[/tex]

• A and B applicants: [tex]n(A\cap B) = 11[/tex]

• A and W applicants: [tex]n(A \cap W) = 6[/tex]

• B and W applicants: [tex]n(B\cap W) = 9[/tex]

• non-applicants: [tex]n(U \setminus (A\cup B\cup W)) = 4[/tex]

The last cardinality tells us [tex]n(A\cup B\cup W) = 60-4 = 56[/tex] students applied anywhere at all.

We want to find [tex]n(A\cap B\cap W)[/tex], the number of students that applied to each of the three universities.

By the inclusion/exclusion principle,

[tex]n(A\cup B\cup W) = n(A) + n(B) + n(W) \\\\~~~~~~~~~~~~~~~~~~~~~~~~ - n(A\cap B) - n(A\cap W) - n(B\cap W)\\ \\~~~~~~~~~~~~~~~~~~~~~~~~ + n(A\cap B\cap W)[/tex]

That is, we count up all the students in the sets A, B, and W, then subtract the number of students in each pairwise intersection to not double-count, then add back the number of students in the intersection of all three sets since it was removed in the previous step.

Now solve.

[tex]56 = 30 + 25 + 24 - 11 - 6 - 9 + n(A\cap B\cap W)[/tex]

[tex]\implies n(A\cap B\cap W) = \boxed{3}[/tex]