The speed of a pendulum is highest at the mean point because at this point the pendulum has the greatest potential energy. As the pendulum swings back and forth, potential energy is converted to kinetic energy at the mean point, leading to the highest speed.
The pendulum is at its highest point in its swing and has the most potential energy at the mean position. This potential energy is transformed into kinetic energy, the energy of motion, when it starts to swing downward. The kinetic energy increases with potential energy, increasing speed as a result. Because of this, the mean point is where the pendulum swings at its fastest. In addition, air resistance and friction have a greater impact as the pendulum approaches the extremities of its arc, slowing it down. The pendulum's maximum speed is reached at the mean point in part because of this.
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a researcher secretly puts a dab of rouge on a child's nose before placing him in front of a mirror. the child points to the rouge on the mirror's reflected image. from this example we can conclude that the child:
With the child pointing to the rouge on the mirror's reflected image on the rouge test, we can conclude that the child lacks self-recognition.
Self-recognition is defined as a recognition of own self as separate from others, as well as an awareness and realization of own personality, individuality, and experience. With the boy pointing the mirror's reflected image of himself to check on the rouge marking, we can conclude that the boy has not yet reached the identification stage of self-awareness, a stage in which an individual is able to identify himself/herself and has a complete sense of himself/herself.
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A point charge q1=2. 0μC is located on the positive y axis at y=0. 30m, and an identical charge q2 is at the origin. Find the magnitude and direction of the total force that these two charges exert on a third charge q3=4. 0μC that is on the positive x axis at x=0. 40m. A)In the same example, what is the magnitude of the net force on q3 if q1=2. 0μC, as in the example, but q2=−2. 0μC?B)In the same example, what is the direction of the force on q3 if q1=2. 0μC, as in the example, but q2=−2. 0μC?
This copy is written to explain the forces that two charges, q1 and q2, exert on a third charge, q3.
The two charges, q1 and q2, are located on the positive y axis at y=0.30m and the origin, respectively. The third charge, q3, is located on the positive x axis at x=0.40m.
To find the magnitude and direction of the total force that these two charges exert on q3, we must first calculate the electric field produced by each charge at the location of q3.
The magnitude of the net force on q3 is then calculated by multiplying the electric field by the charge of q3. The direction of the force on q3 is determined by the direction of the electric field.
For example, if q1=2.0μC and q2=2.0μC, the magnitude of the net force on q3 is 8.0μC and the direction of the force on q3 is towards q2. However, if q1=2.0μC and q2=-2.0μC, the magnitude of the net force on q3 is 4.0μC, and the direction of the force on q3 is away from q2.
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1. Mr. Bradford walks around a 400 meter track in 5 minutes.
a. What is his speed in m/s?
The 400 m fast and slow walks took an average of 333.3 and 380.3 seconds, respectively (P .001).
How long does it take to walk 400m?It is not known how performance converges on fast and slow-paced 400-meter walking tests, which are frequently used to evaluate physical fitness or function, respectively. The purpose of this study is to find out if age and physical function affect how well people do on the 400-meter walks at fast and slow speeds.Methods : A 400-meter walk was done at a quick and regular rate by the participants (26 men and 38 women, ages 70 to 92). Functional evaluation was performed using the Short Physical Performance Battery. Additional evaluations included BMI and medical history.Results : It took 333.3 and 380.3 seconds to complete the 400-meter walk at the fast and normal paces, respectively (p0.0001), and there was a strong correlation between the two times (r =.88, P.001). Younger participants (age 80) compared to those age 80 and older (56.8 vs. 32.8 seconds, p=0.003), and persons with higher SPPB scores (SPPB >10) compared to lower SPPB scores (SPPB 10) had significant disparities across tests.To Learn more About slow walks refer To:
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Two cars, a and b, are traveling with the same speed of 40. 0 m/s, each having started from rest. Car a has a mass of 1. 2 x 103 kg , and car b has a mass of 2 x 103 kg. Compared to the work required to bring car a up to speed, how much additional work is required to bring car b up to speed?.
The work done on an object can change the kinetic energy. The additional work required to bring the car B up to the speed of 40m/sec is 640 KJ.
The work done on an object will change kinetic energy. The relation between the work done and kinetic energy is W=KEi-KEf
If the initial velocity is zero, then the work done is equal to the kinetic energy. Thus W=KEf, W=1/2×m×v², where m is the mass of the object and v is the final velocity of the object. The speed of car A and car B is 40m/sec.
The mass of car A is 1200 kg and the mass of car B is 2000kg. The work done by car A to get a speed of 40m/sec is, W(A)=1/2×1200×40×40 =960 KJ. The work done by car B to get a speed of 40m/sec is, W(B)=1/2×2000×40×40 = 1600 KJ.
The additional work required to bring car B up to speed is Wn=W(B)-W(A), Wn=1600-960 =640 KJ.
Hence the additional work that is required to bring the car B up to the speed is 640KJ.
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A 5.0-kg block and a 4.0-kg block are connected by a 0.6 kg rod, as shown in the figure. The links between the blocks and the rod are denoted by A and B. A vertical upward force of magnitude F of magnitude 150 N is applied to the upper block. What magnitude force does each of the links A and B exert?
To determine the magnitude of the force exerted by each of the links A and B, we can use the principle of conservation of energy.
The force applied to the upper block creates a gravitational potential energy (mgh) which will be converted into kinetic energy (1/2mv^2) of the blocks when they start moving.
The initial potential energy of the system is:
Ui = m1gh1 + m2gh2 + m3gh3
The final kinetic energy of the system is:
Uf = (1/2)m1v1^2 + (1/2)m2v2^2
Since the net force on the system is zero and there is no external force acting on it,
Ui = Uf
Where:
m1= 5.0 kg (mass of upper block)
m2= 4.0 kg (mass of lower block)
m3= 0.6 kg (mass of rod)
g = 9.8 m/s^2 (acceleration due to gravity)
v1 = velocity of upper block
v2 = velocity of lower block
The force exerted by link A is the force exerted on the upper block by link A and the force exerted by link B is the force exerted on the lower block by link B.
F(A) = m1a = m1g = 5.0 kg * 9.8 m/s^2 = 49 N
F(B) = m2a = m2g = 4.0 kg * 9.8 m/s^2 = 39.2 N
So the force exerted by link A is 49 N, and the force exerted by link B is 39.2 N.
two small metal cubes with masses 2.0 g and 4.0 g are tied together by a 5.0-cm-long massless string and are at rest on a frictionless surface. each is charged to 2.0 mc. a. what is the energy of this system? b. what is the tension in the string? c. the string is cut. what is the speed of each cube when they are far apart?
a.) To find the energy of this system, we need to calculate the potential energy of the two cubes due to their charges. The potential energy of a charged object is given by the formula:
U = (1/2)QV
Where:
U = potential energy
Q = charge of the object (in Coulombs)
V = voltage (in Volts)
The masses of the cubes are given in grams, so we need to convert them to Coulombs:
2.0 g = 2.0 x 10^-3 kg x (1 Coulomb/1.6 x 10^-19 Coulombs) = 1.25 x 10^-16 Coulombs
4.0 g = 4.0 x 10^-3 kg x (1 Coulomb/1.6 x 10^-19 Coulombs) = 2.5 x 10^-16 Coulombs
The cubes are charged to 2.0 mc, which is equal to 2.0 x 10^-6 Coulombs.
Now we can use the formula above to find the potential energy of each cube:
U1 = (1/2)QV = (1/2)(1.25 x 10^-16 Coulombs)(2.0 x 10^-6 Coulombs) = 0.000015625 J
U2 = (1/2)QV = (1/2)(2.5 x 10^-16 Coulombs)(2.0 x 10^-6 Coulombs) = 0.00003125 J
The total energy of the system is the sum of the potential energies of the two cubes:
E = U1 + U2 = 0.000015625 J + 0.00003125 J = 0.000046875 J
b.) To find the tension in the string, we need to consider the forces acting on the two cubes. The cubes are at rest, so the net force on each cube must be zero. Therefore, the tension in the string must be equal to the weight of the two cubes. The weight of an object is given by the formula:
F = m*g
Where:
F = force (weight)
m = mass of the object
g = acceleration due to gravity (9.8 m/s^2)
The mass of the two cubes is 2.0 g + 4.0 g = 6.0 g. So the weight of the two cubes is:
F = m*g = (6.0 x 10^-3 kg)(9.8 m/s^2) = 0.0588 N
The tension in the string is the same as the weight of the two cubes, which is 0.0588 N.
c.) When the string is cut, the two cubes will move apart due to the repulsion of their charges. The speed of each cube can be found using the conservation of energy principle. The initial energy of the system is the potential energy of the two cubes:
Ei = U = 0.000046875 J
The final energy of the system is the kinetic energy of the two cubes:
Ef = (1/2)mv^2
Where:
m = mass of the cube
v = velocity of the cube
The total final energy of the system is the sum of the kinetic energies of the two cubes:
Ef = (1/2)m1v1^2 + (1/2)m2v2^2
Since the total energy of the system is conserved, we can say:
Ei = Ef
0.000046875 J = (1/2)(2.0 x 10^-3 kg)v1^2 + (1/2)(4.0 x 10^-3 kg)v2^2
To find the speed of each cube, we can solve for v1 and v2 individually by isolating them on one side of the equation:
v1 = ((2*(0.000046875 J)) / (2.0 x 10^-3 kg))^0.5
v2 = ((2*(0.000046875 J)) / (4.0 x 10^-3 kg))^0.5
v1 = 0.019 m/s
v2 = 0.013 m/s
So the speed of the first cube is 0.019 m/s and the speed of the second cube is 0.013 m/s (rounded to the nearest whole number).
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18. all of the following are units of power except (a) watts (b) joules per second (c) electron volts per second (d) newton meters per second (e) kilogram meters per second
joule is not the unit of power.
In physics, power measures the rate of transfer of electrical energy through a circuit per unit of time. It is denoted by P and is measured using the SI unit of power (watts or 1 joule/second). Electrical energy is usually supplied by batteries and produced by generators. Power refers to the rate per unit of time at which electrical energy is transferred through a circuit. When we talk about units of power, it is joules per second or joules per unit of time. A watt is a unit of electrical power equivalent to 1 ampere under 1 volt of pressure.
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for every action there is an equal and opposite reaction
Newton's 3rd Law of Motion states that:
for every action (force) in nature there is an equal and opposite reaction.
write a differential equation that is a mathematical model of the situation described. the time rate of change of the velocity v of a coasting motorboat is proportional to the square of v.
The time rate of change of the velocity v of a coasting motorboat is proportional to the square of v.
write a differential equation that is a mathematical model of the situation described?
A differential equation is an equation involving an unknown function y=f(x) and one or more of its derivatives. A solution to a differential equation is a function y=f(x) that satisfies the differential equation when f and its derivatives are substituted into the equation.A differential equation is an equation which contains one or more terms and the derivatives of one variable (i.e., dependent variable) with respect to the other variable (i.e., independent variable) dy/dx = f(x) Here “x” is an independent variable and “y” is a dependent variable. For example, dy/dx = 5x.Ordinary Differential Equation. Partial Differential Equation. Linear Differential Equation.Numerical methods for ordinary differential equations are methods used to find numerical approximations to the solutions of ordinary differential equations (ODEs). Their use is also known as "numerical integration", although this term can also refer to the computation of integrals.To learn more about differential equation refers to:
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a 1,400 kg car moving at 5.3 m/s is initially traveling north. after completing a 90o right-hand turn in 4.6 s, the inattentive operator drives into a tree, which stops the car in 350 ms. calculate the magnitude of the impulse delivered to the car (a) during the turn and (b) during the collision. calculate the average force acting on the car (c) during the turn and (d) during the collision.
a. The impulse acting on the car is 7.4×10³ N⋅s
b. The new impulse acting on the car is −7.4×10³ N⋅s.
c. The average force is 2.3×10³ N.
d. the new average force is 2.1×10⁴ N.
Let the initial and final momentum of the car be pi =mνi and pf =m νf, respectively. The impulse on it equals the change in its momentum, J =Δ p = pf − pi =m(νf − νi ). The average force over the duration Δt is given by Favg = J /Δt.
(a) The initial momentum of the car is pi =m νi =(1400kg)(5.3m/s)j^ =(7400 kg⋅m/s) j^ and the final momentum after making the turn is pf =(7400 kg⋅m/s) i^.
Thus, the impulse is, J = pf − pI =(7.4×10³ N⋅s)( i^ − j^ ) .
(b) The initial momentum of the car after the turn is pi' =(7400 kg⋅m/s) i^ and the final momentum after colliding with a tree is p f′ =0.
The impulse acting on it is J′ = pf′ − pi′ =(−7.4×10³ N⋅s) i^.
(c) the average force on the car during the turn is Favg = ΔtxΔ p = ΔtxJ = 4.6s(7400⋅m/s)( i^ − j^ ) =(1600N)( i^ − j^ ) and its magnitude is Favg=(1600N) 2 =2.3×10³ N .
(d) The average force during the collision with the tree is Favg′ = ΔtxJ' = 350×10 −3 s(−7400 kg⋅m/s) i^ =(−2.1×10⁴ N) i^ and its magnitude is F avg′
=2.1×10⁴ N.
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your vfr flight will be conducted above 10,000 msl in class e airspace. what is the minimum flight visibility?
The minimum flight visibility for a VFR flight conducted above 10,000 feet MSL in Class E airspace is 5 statute miles.
The minimum flight visibility requirement for Visual Flight Rules (VFR) flights is set by the Federal Aviation Administration (FAA) in the United States. The minimum visibility requirement depends on the type of airspace in which the flight is conducted and the altitude of the flight.
For a VFR flight conducted above 10,000 feet Mean Sea Level (MSL) in Class E airspace, the minimum flight visibility requirement is 5 statute miles. This means that the pilot must be able to see and avoid other aircraft and obstacles, and must be able to maintain visual reference to the surface. This minimum flight visibility requirement is in place to ensure a safe and efficient flight, and to minimize the risk of collisions and other accidents.
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How much of 11. 2 g of iodine-135 (half-life: 6. 6 h) would remain after 19. 8 hours?
The remaining quantity is 1.4 g.
We know that half life of a first order reaction is given by:
t(1/2) = ln 2 / k
where , t(1/2) = half life = 6.6 hours
k = reaction constant
Putting these values in above equation we get : k = ln 2 / t(1/2) = ln2 / 6.6
Also rate of a reaction is given by:
k =[tex]\frac{1}{t} ln\frac{A_{o} }{A}[/tex]
where,
k = rate of reaction = ln2/ 6.6
t = time = 19.8 hours
A = final quantity
[tex]A_{o}[/tex] = initial quantity = 11.2 g
Putting these values in above equation we get: A = 1.4 g
So the remaining quantity is 1.4 g.
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a 17.5kg dodo bird is on a cliff that is 25 meters tall. what is the potential energy of the dodo bird
The potential energy of the 17.5 kg dodo bird on 25 meters is 4287.5 Joule.
What is potential energy?Potential energy is a form of stored energy that is dependent on the relationship between different system components.
When a spring is compressed or stretched, its potential energy increases. If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy.
The potential energy of the 17.5 kg dodo bird is = mass × acceleration due to gravity × height
= 17.5 kg × 9.8 m/s² × 25 meter
= 4287.5 Joule.
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Use the equation where p = pressure and v = volume. What happens to the pressure as the volume approaches 0? explain your reasoning.
As the volume approaches 0, the pressure approaches infinity. This is because the equation states that pressure is inversely proportional to volume. As the volume decreases, the pressure increases due to the inverse relationship.
What happens to the pressure as the volume approaches 0?The pressure of the system will approach infinity as the volume gets closer to zero. This is because pressure and volume have an inverse relationship, which means that as the volume drops, the pressure must rise to keep the same amount of energy. This is due to the fact that the same amount of energy can be contained in a particular volume, thus as the volume shrinks, the pressure must rise to keep the same amount of energy. PV = nRT, where P is pressure, V is volume, n is number of moles of gas, R is gas constant, and T is temperature, is what is referred to as the ideal gas law. In order for the pressure to remain constant when the volume decreases to zero, it should satisfy the equation.
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what happens to a sound wave when the frequency of the wave is changed?
When the frequency of a sound wave is changed, the wavelength and the velocity of the wave will also change.
This is because the frequency, wavelength, and velocity of a sound wave are all related by the equation:
v = fλ
Where v is the velocity of the wave, f is the frequency of the wave, and λ is the wavelength of the wave. If the frequency of a wave is increased, the wavelength will decrease and the velocity will remain the same. Conversely, if the frequency of a wave is decreased, the wavelength will increase and the velocity will remain the same.
Additionally, the pitch of the sound also changes with the frequency, higher frequency sound has a higher pitch and lower frequency sound has a lower pitch. In summary, a change in the frequency of a sound wave will result in a corresponding change in its wavelength and pitch.
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What is torque on a body when the force is applied in the direction of the radius vector?
The torque on a body when the force is applied in the direction of the radius vector is calculated to be zero.
The twist to an object around a specified axis is called torque. It is a vector product of position vector and force. Another name for it is the turning effect.
Mathematically, Torque τ bar = r bar × F bar
where, r bar is the position vector
F bar is the force on the particle
Given that, the direction of force is along the direction of radius.
This means that the angle between radius and torque is 0°.
"τ = r × F = r F sin θ"
As sinθ = sin0° = 0
τ = r F sinθ = 0
Thus, the required torque on a body when the force is applied in the direction of the radius vector is zero.
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Class 2 cables shall have a minimum voltage rating of ? .
a. 150 V 725.179(G)
b. 250 V 725.179(G)
c. 350 V 725.179(G)
d. 450 V 725.179(G)
"Class 2 cables shall have a minimum voltage rating of 150 volts."
The voltage is a measure of the difference in electric potential between two points in a circuit. It is measured in volts and is one of the basic parameters of electrical engineering. Voltage can be generated in a variety of ways, including through generators, batteries, and power supplies. When two points with different potentials are connected, current can flow from the higher potential point to the lower potential point.
Voltage is also used to measure the potential difference between two points in a circuit, as well as to calculate the power in the circuit. In addition, voltage is used to control the flow of current in a circuit, by either increasing or decreasing the potential difference between the two points.
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a super ball is a toy ball made of hard synthetic rubber called zectron. this material has a high coefficient of restitution so that if it is dropped from a certain height onto a hard fixed surface, it rebounds to a substantial portion of its original height. if the super ball has 7 cm diameter and the density of zectron is about 1.5 mg/m3, determine the weight of the super ball on the surface of the earth in u.s. customary units.
The weight of the super ball is 0.00224 oz.
To determine the weight of the super ball in U.S. customary units, we first need to calculate its volume. We can use the formula for the volume of a sphere: V = 4/3 * pi * r^3, where r is the radius of the sphere (half the diameter). In this case, the radius is 3.5 cm.
So, V = 4/3 * pi * [tex](3.5 cm)^3[/tex]= 4/3 * pi * 42.875 [tex]cm^3[/tex]
Next, we can use the density of section (1.5[tex]mg/m^3[/tex]) and the volume of the sphere to calculate the weight of the super ball.
Weight = Density * Volume
The weight of the super ball will be approximately:
Weight = 1.5 [tex]mg/m^3[/tex] * 42.875 [tex]cm^3[/tex] = 63.8125 mg
Converting to ounces:
63.8125 mg = 0.00224 oz
Therefore, The weight of the super ball is 0.00224 oz.
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The half life of phosphorus-33 is 25 days. After 50
days, What is the original sample size if 10 g
remain?
The half-life of a first-order reaction is a constant that is related to the rate constant for the reaction: t1/2 = 0.693/k.
What is phosphorus-33?It is used in life-science laboratories in applications in which lower energy beta emissions are advantageous such as DNA sequencing. P can be used to label nucleotides. It is less energetic than 32P, giving a better resolution.
Phosphorus 33 is an artificial radioactive element. It is produced with a low yield by the neutron bombardment of phosphorus 31 (stable). The phosphorus 33 has a radioactive period of 25.3 days.
Phosphorus-33 atom is the radioactive isotope of phosphorus with relative atomic mass 32.971725, half-life of 25.34 days and nuclear spin (1)/2.
Phosphorus was discovered by the German merchant Hennig Brand in 1669.
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You slide a 0. 12 kg coffee mug 0. 15 m across a table. The force you exert is horizontal and of magnitude 0. 10 N. The coefficient of kinetic friction between the mug and the table is 0. 5. How much work is done on the mug?
-0.00882 J work is done on the mug. This can be solved by using the concept work formula's are used.
What is kinetic friction?As a force that occurs between moving surfaces, kinetic friction is described. An opposing force to the direction of a body's movement is felt by a body traveling over a surface. According to how much kinetic friction there is between the two materials, the force's strength will vary. The frictional force at this point is referred to as dynamic friction or kinetic friction. In other words, dynamic friction is the force that opposes a body as it moves across the surface of another body.
The force that prevents one solid item from moving across another is known as friction. The four basic forms of friction are fluid friction, rolling friction, sliding friction, and static friction.
Given that,
0.12 kg coffee mug 0.15 m across a table
force exert is horizontal and of magnitude 0.10 N
kinetic friction between the mug and the table is 0.5
As we know,
W(external) = F × d
W(external) = 0.10 N × 0.15 m
W(external) = 0.015 J
Thus, W (friction) = -m(u) × m × g × d
here, m(u) is the co-efficient of kinetic friction
W(friction) = - 0.05 × 0.12 × 9.8 × 0.15
W(friction) = -0.00882 J
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Under what condition does the addition of two simple harmonic motions produce a resultant, which is also simple harmonic?
Answer:
Explanation:
The addition of two simple harmonic motions will produce a result that is also simple harmonic if the two simple harmonic motions have the same frequency and phase.
When two simple harmonic movements attain their maximum or lowest values at the same moment, they are said to be in phase. If the amplitudes of two simple harmonic movements have the same frequency and are in phase, the amplitude of the resulting motion may be calculated. This indicates that the combined system's motion will still oscillate at the same frequency as the separate movements and will be sinusoidal in form, as is the distinguishing feature of simple harmonic motion. As a result, adding two simple harmonic movements with the same frequency and phase results in a consequent motion that is likewise simple harmonic.
a concave mirror has a focal point of 1.5 meters. if we stand 3 meters in front of it, where is the image?
If we stand 3 meters in front of it, then the image is 3m away from the lens.
define focal point ?
The focal point of a mirror is a point located on the principal axis where the light rays that are reflected from the mirror converge to form an image, or from where light rays appear to originate. The distance from the mirror to the focal point is known as the focal length, and it is a characteristic property of the mirror that depends on its shape and material. In a concave mirror, the focal point is located on the side of the mirror opposite the object being reflected, and the light rays are directed towards it, resulting in the formation of an image.
The image formed by a concave mirror is behind the mirror. In this case, since the focal point of the mirror is 1.5 meters, the image will be located 1.5 meters behind the mirror. So, if you are standing 3 meters in front of the mirror, the image will be located 1.5 meters behind the mirror, at a distance of 4.5 meters from you.
Given,
The focal point of 1.5 meters
Object length = 3 meters
Using lens equation
1/x + 1/y = 1/f
Here, x = distance of object = 3 meters
f = focal point = 1.5 meters
y = distance of image
i.e.
1/3 + 1/y = 1/1.5
1/y = 1/1.5 - 1/3
1/y = 2/3 - 1/3
1/y = (2 - 1)/3
1/y = 1/3
y = 3m
Thus, If we stand 3 meters in front of it, then the image is 3m away from the lens.
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What does high kinetic energy mean?
having a high kinetic energy level mean An object's kinetic energy increases with its speed An item has more kinetic energy the more mass it possesses
The energy an item has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. Kinetic energy, which may be seen in the movement of an item or subatomic particle, is the energy of motion. Kinetic energy is present in every particle and moving object. Examples of kinetic energy in action include a person walking, a baseball flying through the air, a piece of food falling from a table, and a charged particle in an electric field.
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a ? is a special test instrument (dc voltmeter) that detects the presence or absence of a high or low signal.
An example of a test tool that can be used to determine whether a high or low signal is present or absent is a dc voltmeter.
Describe a test instrument.
Any tool used to measure and assess a system or product to make sure it is operating correctly and conforming to specifications is referred to as a test instrument. To ensure that products are of the highest quality and comply with all safety regulations, test instruments are frequently used in research, development, and manufacturing.It operates by detecting the voltage difference in a circuit between two points. Depending on the signal level, the instrument will indicate a "high" or "low" signal when the distance between the two points is within a predetermined range.To learn more about Signal here
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A capacitor is connected to a battery. The force of attraction between the plates when the separation between them is halved:
A . remains the same
B . becomes eight times
C . becomes four times
D . becomes two times
A capacitor is connected to a battery. When the separation between the plates of the capacitor is halved, the force of attraction between then will become four times.
We know that the parallel plate capacitor's capacitance is determined by
C = ∈₀[tex]\frac{A}{d}[/tex]
and that the distance between the two plates is denoted by d. So, when the distance between objects is cut in half, the capacitance doubles. We can express that mathematically as,
C' = ∈₀[tex]\frac{A}{\frac{d}{2} }[/tex]
or, C' = 2∈₀ [tex]\frac{A}{d}[/tex]
or, C' = C
Here, the potential remains constant.
Now, charge is equal to the product of capacitance and potential, i.e.,
Q = C × V
The charge will double as the capacitance does, and vice versa.
The following equation describes the connection between the d and the potential difference between the two plates:
E = [tex]\frac{V}{d}[/tex]
The value of the electric field doubles because the separation has decreased by half.
From Coulomb's law, we have
Force of attraction, F = QE
Now that charge and the electric field have both increased by two, the force of attraction will be
F' = Q'E'
or, F' = 2Q × 2E
or, F' = 4QE
or, F' = 4F
Hence, the force of attraction will become four times.
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A styrofoam cup holding 125 g of water at 100 C cools to room temperature 20 C. What is the change in entropy of the room?
A styrofoam cup holding 125 g of water at 100 C cools to room temperature 20 C. 0.14266 KJ/K is the change in entropy of the room
What is the change in entropy?
Entropy A thermodynamic system's state of the disorder can change when heat or enthalpy is converted into work, which is referred to as change. An extremely disordered system has more entropy than a more orderly one. Entropy is a state function, so regardless of the path taken, the change in entropy of a system only depends on the initial and final states. Therefore, the nature of the processes—whether they are reversible or irreversible—does not affect the change in entropy.Entropy changes that are positive (+) indicate more chaos. The entropy of the cosmos is increasing. The entropy of the cosmos increases whenever there is any spontaneous change. Entropy change for the system and its surroundings must be added together and must be positive (+) for a spontaneous process.Given that,
m = 125 g = 0.125 kg
T = 100°C = 373 K
Tsurrounding = 20°C = 293 K
Heat release from cup to the surrounding.
Q = m × c × (T - Tsurrounding)
Q = 0.125 × 4.18 × 80
Q = 41.8 kJ
Entropy change of the room(surrounding),
ΔS = Q/Tsurrounding
ΔS = 41.8/293
ΔS = 0.14266 KJ/K
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In a 'keep-fit' exercise, a student of mass 45 kg steps 40 times on and off a box of height 0.50 m.
a) Calculate the weight of the student.
Weight of a body is the force with which the earth pulls on it. So W = mg = 45 * 9.8 newtons.
How can you calculate weight?Weight is a gauge of how strongly gravity is dragging something down. It relies on the mass of the item and the acceleration brought on by gravity, which on Earth is 9.8 m/s2. F = m 9.8 m/s2 is the formula for computing weight, where m is the object's mass in kilogrammes and N is the object's weight in Newtons (N).Body Mass Index (BMI) is calculated by dividing a person's weight in kilogrammes (or pounds) by their height in metres squared (or feet). High body fatness may be indicated by a high BMI. BMI does not make a body fat or health diagnosis for a person, but it does screen for weight categories that may cause health issues.Learn more about Weight refer to ;
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What is the formula and SI unit of torque?
The formula of Torque(T) is force(F) × Radius(R) of rotation. Its SI unit is Newton-meter.
Torque is the measure of force which is responsible for the rotation of an object about its own axis. As force causes an object to accelerate in linear direction, similarly torque causes an object to acquire angular acceleration. It is a vector quantity. Torque is also defined as the cross product of force vector and distance vector(distance from the axis). The formula of Torque is as follows:
T = F × R
Where F is the force, R is the radius of rotation. Its SI unit will be Newton-meter.
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a wire of length l is made of an insulating material. this wire holds a net charge of q that is distributed uniformly along the length of the wire. what is the linear charge density, , of this charged wire?
When a wire of length l is made of an insulating material. this wire holds a net charge of Q which is distributed uniformly along the length of the wire. Lambda =Q/L is the linear charge density of this charged wire,
What do you mean by insulating material.?Insulating substance definitions. A substance Which generally lessens or stops the transmission of electricity, sound, or heat. Insulant and insulation are the synonyms for each other. varieties: lagging. used to wrap around boilers or pipes, or it was placed in attics to stop heat loss.
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A circuit in mike’s home is almost at maximum current. if it is a 120 v circuit with about 1/3 of an amp available to safely use, which bulb would be the maximum wattage mike could use?a. an illustration of a light bulb labeled 100 w. b. an illustration of a light bulb labeled 60 w. c. an illustration of a light bulb labeled 40 w.
The maximum wattage that can be used is 40 W. So, the correct answer is C.
The maximum wattage Mike could use is determined by the power formula: P = IV
Where: P = power (watts), I = current (amps), V = voltage (volts)
Given that the circuit is 120 V with 1/3 of an amp available to safely use we can use the formula to calculate the power P = 120 x (1/3) = 40 W
Therefore, Mike can use a bulb with a maximum wattage of 40 W. So the correct answer is C an illustration of a light bulb labelled 40 W.
It's always important to make sure that the electrical devices used in the circuit are not exceeding the capacity of the circuit to avoid overloading and potential fire hazards.
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Answer:
the 3rd image (40W)
Explanation:
EDGE 2023