writie any assay about challenges of teaching mathematics on 21st century​

Answer:

86.28 ft²

Step-by-step explanation:

The figure given consists of a rectangle and a semicircle.

The area of the figure = area of rectangle + area of semicircle

Area of rectangle = [tex] l*w [/tex]

Where,

l = 10 ft

w = 8 ft

[tex] area = l*w = 10*8 = 80 ft^2 [/tex]

Area of semicircle:

Area of semicircle = ½ of area of a circle = ½(πr²)

Where,

π = 3.14

r = ½ of 8 = 4 ft

Area of semi-circle = ½(3.14*4) = 6.28 ft²

Area of the figure = area of rectangle + area of semi-circle = 80 + 6.28 = 86.28 ft² (nearest hundredth)

Answer:

the area of the figrue is 105.12

Step-by-step explanation:

Answer:

x=-3 and x=4

Step-by-step explanation:

Since x=-2 is a zero of the function, we can find the other two factors by dividing f(x) by (x+2) using long division to obtain the other two roots. The quadratic obtained is x^2-x-12. Now factorising this quadratic will result in (x-4)(x+3)=0, x=-3 and 4 are the other rrots

The factorization of the function f(x) = x³ + x² - 14x - 24​ will be (x + 2), (x + 3), and (x - 4).

It is a method for dividing a polynomial into pieces that will be multiplied together. At this moment, the polynomial's value will be zero.

The function is given below.

f(x) = x³ + x² - 14x - 24​

Factorize the function, then we have

f(x) = x³ + x² - 14x - 24​

f(x) = x³ + x² - 14x - 24

f(x) = x³ + 2x² - x² - 2x - 12x - 24

f(x) = x²(x + 2) - x(x + 2) - 12(x + 2)

f(x) = (x + 2)(x² - x - 12)

f(x) =(x + 2)(x² - 4x + 3x - 12)

f(x) = (x + 2)[x(x - 4) + 3(x - 4)]

f(x) = (x + 2)(x + 3)(x - 4)

The factorization of the function f(x) = x³ + x² - 14x - 24​ will be (x + 2), (x + 3), and (x - 4).

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Answer:

243

Step-by-step explanation:

The general term for this arithmetic sequence is:

a(n) = -2 + 5(n - 1).

Then a(50) = -2 + 5(49) =   243

Answer:

100000

Step-by-step explanation:

Answer:

∠ H ≈ 23°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan H = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{FG}{HG}[/tex] = [tex]\frac{5}{12}[/tex] , thus

∠ H = [tex]tan^{-1}[/tex] ( [tex]\frac{5}{12}[/tex] ) ≈ 23° ( to the nearest degree )

9514 1404 393

Answer:

  y was not substituted for every x

Step-by-step explanation:

To find the inverse of ...

  y = f(x)

you need to solve ...

  x = f(y)

Here, f(x) = x^2 +12x, so f(y) = y^2 +12y

This is not the expression we see on the right of ...

  x = y^2 +12x

Apparently y was not properly substituted into f(x).

Answer:

137, 280 feet

Step-by-step explanation:

There are 5,280 feet in a mile.

26 * 5,280 = 137,280

There are 137, 280 feet in 26 miles.

There are 137,280 feet in 26 miles.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

We know that there are 5,280 feet in a mile.

So, the solution would be;

26 x 5,280 = 137,280

Thus, There are 137,280 feet in 26 miles.

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Answer; Down

Step-by-step explanation:The graph of the squaring function has the shape of a parabola that opens up. Its vertex is at (0,0). The graph of F(x) = (1/2)x^2 has the same shape, but is compressed vertically by a factor of (1/2).

Let y be a solution to the given differential equation,

[tex]y' = xy[/tex]

where

[tex]\displaystyle y = \sum_{n=0}^\infty c_n x^n \\\\ y' = \sum_{n=0}^\infty nc_nx^{n-1} = \sum_{n=1}^\infty nc_nx^{n-1} = \sum_{n=0}^\infty (n+1)c_{n+1}x^n[/tex]

Substituting these series into the DE gives

[tex]\displaystyle \sum_{n=0}^\infty (n+1)c_{n+1}x^n = x\sum_{n=0}^\infty c_nx^n \\\\ \sum_{n=0}^\infty (n+1)c_{n+1}x^n = \sum_{n=0}^\infty c_nx^{n+1} \\\\ \sum_{n=0}^\infty (n+1)c_{n+1}x^n = \sum_{n=1}^\infty c_{n-1}x^n \\\\ c_1 + \sum_{n=1}^\infty (n+1)c_{n+1}x^n = \sum_{n=1}^\infty c_{n-1}x^n \\\\ c_1 + \sum_{n=1}^\infty \bigg((n+1)c_{n+1}-c_{n-1}\bigg)x^n = 0[/tex]

Then the coefficients [tex]c_n[/tex] in the series solution are governed by the recurrence,

[tex]\begin{cases}c_0 = c_0 \\ c_1 = 0 \\ (n+1)c_{n+1}-c_{n-1} = 0&\text{for }n\ge1\end{cases}[/tex]

We have

[tex](n+1)c_{n+1}-c_{n-1} = 0 \implies nc_n - c_{n-2} = 0 \implies c_n = \dfrac{c_{n-2}}n[/tex]

so it follows that [tex]c_1=c_3=c_5=\cdots = 0[/tex], while

[tex]c_0 = \dfrac{c_0}1 = \dfrac{c_0}{2^0\times0!} \\\\ c_2 = \dfrac{c_0}2 = \dfrac{c_0}{2^1\times1!}\\\\ c_4 = \dfrac{c_2}4 = \dfrac{c_0}{2\times4} = \dfrac{c_0}{2^2\times2!}\\\\ c_6 = \dfrac{c_4}6 = \dfrac{c_0}{2\times4\times6} = \dfrac{c_0}{2^3\times3!}[/tex]

and so on, with the general n-th coefficient being

[tex]c_n = \begin{cases}0&\text{if }n\text{ is odd} \\ \dfrac{c_0}{2^{n/2}\left(\frac n2\right)!} &\text{if }n\text{ is even}\end{cases}[/tex]

Then the power series solution is

[tex]\displaystyle y(x) = c_0 \sum_{n=0}^\infty \frac{x^n}{2^{n/2}\left(\frac n2\right)!} = c_0 \sum_{n=0}^\infty \frac1{\left(\frac n2\right)!} \left(\frac x{\sqrt2}\right)^n[/tex]

but this doesn't tell the whole story because it doesn't capture the odd-index-is-zero case.

More concisely: let n = 2k for integers k ≥ 0. Then

[tex]\displaystyle y(x) = c_0 \sum_{k=0}^\infty \frac{x^{2k}}{2^k k!} = c_0 \sum_{k=0}^\infty \frac1{k!} \left(\frac{x^2}2\right)^k[/tex]

and as a bonus, it's easier to get an exact solution for this DE,

[tex]y(x) = c_0e^{x^2/2}[/tex]

Answer:

Does the answer help you?

Answer:

-5-9i

Step-by-step explanation:

-1-8i-4-i

-1-4-8i-i

-5-9i

Answer:18.5

Step-by-step explanation:

10+8=18

18*5=90

90/4

22.5-4=18.5

Answer:  3.79 litres

Step-by-step explanation:

1 litre is equivalent to about ‭1.05668821‬ American quarts.

4 quarts would therefore be;

= 4/‭1.05668821‬

= 3.78541178

= 3.79 litres

Answer:

y = 7 sqrt(2)

Step-by-step explanation:

Since this is a triangle, we can use trig functions

sin theta = opp/ hyp

sin 45 = 7/y

y sin 45 = 7

y = 7/ sin 45

y = 7 / (1/sqrt(2) )

y = 7 sqrt(2)

Answer:

the answer is y = 7 sqrt (2)

Step-by-step explanation:

[tex]\sf{}[/tex]

♛┈⛧┈┈•༶♛┈⛧┈┈•༶

Answer:

Dilation changes (x,y) values not the grid or coordinate plane. Basically, dilating a graph or a coordinate grid means the original coordinates you may have had will be changed with the dilation.  For example, a triangle plotted had its original area of 26 dilated to an area of 58.

Answer:

C

Step-by-step explanation:

Since they are pythagorian triplets, ABC is a right angled triangle at the angle between the arc 3 and arc 4. Theta is the angle opposite to 3 and hence tan(theta)=3/4

Answer:

work is shown and pictured

Answer:

a; H0: u= 140 Ha: u ≠ 140 two tailed test.

b. Therefore reject H0 as t= 3 ≠ t≤ t ( ∝/2) (n-1) =2.353 or

3 > t ( ∝/2) (n-1) =2.353    

c. If we check from the table the p- value is 0.6 which lies between 0.1 and 0.05  therefore reject H0.

d. Again reject H0 as 140 < 150.163

e. A type II error has not been committed as H0 is rejected.

Step-by-step explanation:

We formulate the null and alternative hypotheses as

a; H0: u= 140 Ha: u ≠ 140 two tailed test.

For a two tailed test the significance level ∝= 0.1 the critical region is given by

t ≤ t ( ∝/2) (n-1) and t > t ( ∝/2) (n-1)

So the critical region will be

t≤ t ( ∝/2) (n-1) =2.353

where

t= x` - u / s/ √n

Sr. No X X²

1 150 22500

2 150 22500

3 180 32400

4 170 28900

∑ 650 106,300

X`= ∑x/n = 650/4= 162.5

s²= 1/n-1 (x-x`)²= 1/n-1 [ ∑x² -(∑x)²/n ]

= 1/3[106,300 -650²/4] = 225

s= 15

Putting the values in the above equation

t= 162.5- 140/ 15/ √4

t= 3

So calculated value of t= 3

b. Therefore reject H0 as t= 3 ≠ t≤ t ( ∝/2) (n-1) =2.353 or

3 > t ( ∝/2) (n-1) =2.353    

c. If we check from the table the p- value is 0.6 which lies between 0.1 and 0.05  therefore reject H0.

d. a 90% confidence interval based on the calculated values will be

x`± 1.645 (s)/ √n

Putting the values

162.5 ±1.645 ( 15/2)

162.5 ±12.3375

174.84 , 150.163

d. Again reject H0 as 140 < 150.163

e. A type II error has not been committed as H0 is rejected.

Answer:

24

Step-by-step explanation:

24-16=8

The solution to the equation is g = 24.

To solve the equation g - 16 = 8 and find the value of g.

we need to isolate the variable g on one side of the equation.

Starting with the given equation:

g - 16 = 8

To isolate g, we can add 16 to both sides of the equation:

g - 16 + 16 = 8 + 16

g = 24

Therefore, the solution to the equation is g = 24.

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Answer:

True

Step-by-step explanation:

Integers are always whole numbers

negative, 0, positive:: whole numbers

[tex] \begin{array}{l} 2^x = 3^y = 12^z \\ 2^x = 3^y = 2^{2z} \cdot 3^z \\ \Rightarrow 3 = 2^{\frac{x}{y}} \\ \Rightarrow 2^x = 2^{2z} \cdot 2^{\frac{xz}{y}} \\ \Rightarrow x = 2z + \frac{xz}{y} \\ \Rightarrow xy = 2zy + xz \\ \Rightarrow 2zy = xy - xz \\ \text{Dividing both sides by }xyz,\text{ we get:} \\ \dfrac{2}{x} = \dfrac{1}{z} - \dfrac{1}{y} \end{array} [/tex]

Answer:

  x = 1.00995066776

  x = 2.52925492433

Step-by-step explanation:

This sort of equation is best solved using a graphing calculator. For that purpose, I like to rewrite the equation as a function whose zeros we're seeking. Here, that becomes ...

  [tex]f(x)=\log{(x)}-\log{(x-1)}^2-2\log{(x-1)}[/tex]

The attached graph shows zeros at

  x = 1.00995066776 and 2.52925492433

_____

Comment on the equation

Note that we have taken the middle term to be the square of the log, rather than the log of a square. For the latter interpretation, see mberisso's answer at https://brainly.com/question/17210068

Comment on the answer refinement

We have used Newton's method iteration to refine the solutions to this equation. The solution near 1.00995 requires the initial guess be very close for that method to work properly. Fortunately, the 1.01 value shown on the graph is sufficient for the purpose.

Step-by-step explanation:

Px^2+6x+1=x^2+x^2+Qx+1

P=2 and Q=6

Next, 3x^2-5-(x^2-6x+R/2)=2x^2+6x+1

2x^2-5-R/2+6x=x^2+6x+1

-5-R/2=6, R=-22

Answer:

w = [tex]\frac{ku}{d^{2} }[/tex]

Step-by-step explanation:

An equation that expresses the given relationship is ud²=1.

Given that, w varies directly with u and inversely with the square of d.

We need to write an equation that expresses the following relationship.

Direct variation is a linear function defined by an equation of the form y = kx when x is not equal to zero. Inverse variation is a nonlinear function defined by an equation of the form xy = k when x is not equal to zero and k is a nonzero real number constant.

Now, w∝u⇒w=ku

and w∝1/d²⇒w=k/d²

⇒wd²=k

⇒w=wd²u

⇒ud²=1

Therefore, an equation that expresses the given relationship is ud²=1.

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Answer:

a = 4

Step-by-step explanation:

(15)(16)/ a = (3)(4)(5)

15 * 16 = 240

240/ a = (3)(4)(5)

240/a = 60

240/60 = a

a = 4

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Answer:

The volume of this cone is V = 50 (~50.27)

(I'm assuming that 'his' is height?)

Answer: 50

Step-by-step explanation:

Answer:

fourth option

Step-by-step explanation:

Common difference is given by difference of two consecutive term

d = nth term - (n-1)th term

______________________________________

for all the  series lets take second term as nth term

and first term as (n-1)th term

_________________________________________

for first series

n th term = -3 1/2 = -3.5

(n-1)th term = -5

therefore

d= -3.5 -(-5) = -3.5 +5 = 1.5

______________________________________

for second series

n th term = 4 1/2 = 4.5

(n-1)th term = 2 1/2 = 2.5

therefore

d= 4.5 -(2.5) =2

_________________________

for third series

n th term = 3

(n-1)th term =1.5

therefore

d= 3 - 1.5 = 1.5

__________________________________

for fourth series

n th term = -1.5

(n-1)th term = -4

therefore

d= -1.5 -(-4) = -1.5 + 4 = 2.5 = 2 1/2

___________________________________

Thus, based on above solution option four has common difference of 2 1/2

The lub is 0.23[tex]\mathbf{\overline{43}}[/tex], while the glb is 0.2

The given set is presented as follows;

E = {0.2, 0.23, 0.234, 0.2343, 0.23434, 0.234343,...}

The least upper bound, lub, of a set, E, is known as the supremum of the set which is the number B such that all x ∈ E are of the value x  ≤ B, while there all y ∈ E has a x ∈ E such that t < x

Therefore;

The supremum, lub of the given set is 0.23[tex]\overline{43}[/tex]

The greatest lower bound, glb, b, also known as the infimum, is defined as follows;

b is the greatest lower bound if for all x ∈ E then x ≥ b

Given that b < t, then where x ∈ E, there exist a x < t

The glb of the given set is 0.2

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Answer:

Please do it by your shelf because if we measure it and send you may not be able to do by online .So, please do it by by yourself using your scale .