There will be a total of 4 test scores including the final exam. To get a 70, the 4 tests need to equal 4 x 70 = 280 points , to be 79, they have to equal 4 x 79 = 316 points.
The 3 already done = 61 + 62 + 86 = 209 points.
The final exam needs to be between :
280 -209 = 71
316 -209 = 107. The answer would be between 71 and 100%
help me out please! everyday !
Answer:
V = 904.32 ft^3
Step-by-step explanation:
The volume of a sphere is given by
V = 4/3 pi r^3
The radius is 6 and pi = 3.14
V = 4/3 ( 3.14) (6)^3
V = 904.31999 ft^3
Rounding to the hundredths place
V = 904.32 ft^3
[tex] \large\begin{gathered} {\underline{\boxed{ \rm {\red{Volume \: of \: sphere \: = \: \frac{4}{3} \: \pi \: {r}^{3} }}}}}\end{gathered}[/tex]
r = 6 ft[tex] \bf \large{\purple{ \implies}} \tt \: Volume \: of \: sphere \: = \: \frac{4}{3} \: \times \: 3.14 \: \times \: {6}^{3} \\ [/tex]
[tex]\bf \large{\purple{ \implies}} \tt \: Volume \: of \: sphere \: = \: \frac{4}{3} \: \times \: 3.14 \: \times \:216[/tex]
[tex]\bf \large{\purple{ \implies}} \tt \: Volume \: of \: sphere \: = \: \frac{4}{ \cancel3} \: \times \: 3.14 \: \times \: \cancel{216 \: {ft}^{3} } \: \: \: ^{72 \: {ft}^{3} } [/tex]
[tex]\bf \large{\purple{ \implies}} \tt \: Volume \: of \: sphere \: = \: 4 \: \times \: 3.14 \: \times \: 72 \: {ft}^{3} [/tex]
[tex]\bf \large{\purple{ \implies}} \tt \: Volume \: of \: sphere \: = \: 12.56 \: \times \: 72 \: {ft}^{3} [/tex]
[tex]\bf \large{\purple{ \implies}} \tt \: Volume \: of \: sphere \: = \: 904.32 \: {ft}^{3} [/tex]
An Image point has coordinates B'7,-4). Find the coordinates of its pre-Image If the translation used was (x+4, y+5).
О ВІЗ, Т
OB(3-9)
OB/11-9)
B110
NET QUESTION
ASK FOR HELP
TURNITIN
Answer:
The ans is (3,-9) which means it's the second option
Find x.
A. 21(route)2
B. 7
C.21(route)3/2
D. 21(route)2/2
Answer:
Option (D)
Step-by-step explanation:
By applying Sine rule in the right ΔABD,
Sin(A) = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]
Sin(60)° = [tex]\frac{\text{BD}}{\text{AB}}[/tex]
[tex]\frac{\sqrt{3}}{2}=\frac{\text{BD}}{7\sqrt{3}}[/tex]
BD = [tex]7\sqrt{3}\times \frac{\sqrt{3} }{2}[/tex]
= [tex]\frac{21}{2}[/tex]
Now by applying Cosine rule in the right ΔBDC,
Cos(45)° = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]
[tex]\frac{1}{\sqrt{2}}=\frac{\frac{21}{2}}{x}[/tex]
x = [tex]\frac{21}{2}\times \sqrt{2}[/tex]
x = [tex]\frac{21\sqrt{2}}{2}[/tex]
Therefore, Option (D) is the correct option.
Which equation is represented by the graph?
Answer:
I don't knowledge bro sorry
Is 1.45 times 10 to the -7 power a scientific notation
Answer:
Yes.
It is 1.45 x 10^-7 or 0.000000145
Hope it helps!
Answer:
It is 1.45 x 10^-7 or 0.000000145
Step-by-step explanation:
what are the comparison symbols for 5/6 and 2/5, 4/10 and 7/8, and 3/12 and 1/4
Answer like this: Example
=
<
>
Answer:
5/6 > 2/44/10 < 7/83/12 = 1/4Step-by-step explanation:
The comparison will be the same if you subtract the right side and compare to zero:
a/b ?? c/d . . . . . . . using ?? for the unknown comparison symbol
a/b - c/d ?? 0 . . . . subtract the fraction on the right
(ad -bc)/bd ?? 0 . . . combine the two fractions
ad - bc ?? 0 . . . . . . multiply by bd to make the job easier
__
5/6 and 2/5
5(5) -6(2) = 25 -12 > 0 ⇒ 5/6 > 2/5
4/10 and 7/8
4(8) -10(7) = 48 - 70 < 0 ⇒ 4/10 < 7/8
3/12 and 1/4
3(4) -12(1) = 0 ⇒ 3/12 = 1/4
_____
Of course, you can use your calculator (or your memory) to change each of these to a decimal equivalent. The comparison should be easy at that point.
0.833 > 0.400
0.400 < 0.875
0.250 = 0.250
One more than three times a number is the same as four less than double a number
Answer:
3x + 1 = 2x - 4. x = -5
Step-by-step explanation:
Drag each tile to the correct box.
Match each expression with its greatest common factor.
Answer:
Step-by-step explanation:
Please help with this
Answer:
B) x=80°
Step-by-step explanation:
This is a hexagon, so it has interior angles equaling 720°. (N-2)*180
So the equation would be
78+134+136+132+2x+x=720
480+3x=720
3x=720-480
3x=240
x=80°
Simplify 6m^2-5m-3+3m+4+9m^2
Answer: 15m²-2m+1
Step-by-step explanation:
To simplify, you want to combine like terms.
15m²-2m+1
Answer:
[tex]\huge\boxed{15m^2-2m+1}[/tex]
Step-by-step explanation:
[tex]6m^2-5m-3+3m+4+9m^2\\\\\text{combine like terms}\\\\=(6m^2+9m^2)+(-5m+3m)+(-3+4)\\\\=(6+9)m^2+(-5+3)m+1\\\\=15m^2-2m+1[/tex]
Pedro : 80%
Javier: 90%
Marcos: 75%
1. If during a month Pedro has taken 30 free throws, how many will he have hit?
Si durante un mes Pedro ha lanzado 30 tiros libres, ¿cuántos habrá acertado?
2. If Javier hits 4 free throws in a match, how many has he taken?
Si Javier acerta 4 tiros libres en un partido, ¿cuántos ha lanzado?
Answer:
1. 24
2. 4.444... (or 4 rounded to the nearest whole number)
Step-by-step explanation:
1. 80/100 = x/30
cross-multiply
100 × x = 100x
80 × 30 = 2400
divide
100x/100 = x
2400/100 = 24
answer
x = 24
2. 90/100 = 4/x
cross-multiply
90 × x = 90x
100 × 4 = 400
divide
90x/90 = x
400/90 = 4.444...
answer
x = 4.444...
General solution of equation sin x + sin 5x = sin 2x + sin 4x is
Answer:
x=nπ3, n∈I
Step-by-step explanation:
sin x + sin 5x = sin 2x + sin 4x
⇒⇒ 2 sin 3x cos 2x = 2 sin 3x cos x
⇒⇒ 2 sin 3x(cos 2x - cos x) = 0
⇒ sin 3x=0 ⇒ 3x=nπ ⇒ x=nπ3⇒ sin 3x=0 ⇒ 3x=nπ ⇒ x=nπ3 , n∈I, n∈I
or cos 2x−cos x=0 ⇒ cos 2x=cos xcos 2x-cos x=0 ⇒ cos 2x=cos x
⇒ 2x=2nπ±x ⇒ x=2nπ, 2nπ3⇒ 2x=2nπ±x ⇒ x=2nπ, 2nπ3 , n∈I, n∈I
But solutions obtained by x=2nπx=2nπ , n∈I, n∈I or x=2nπ3x=2nπ3 , n∈I, n∈I are all involved in x=nπ3x=nπ3 , n∈I
1. Convert the following fractions into percent. a. 6 by 7
Answer:
6/7 =
6 ÷ 7 ≈0.857142857142857
Theresa bought 2 pineapples for $6. She be wants to find the constant of proportionality in terms of dollars per pineapple. She modeled this proportional relationship on a number line diagram, as shown.
Part A
Using the diagram, find the constant of proportionality in terms of dollars per pineapple.
Answer:
$3 per pineapple
Step-by-step explanation:
Hey there!
If 2 pineapples are $6,
6 / 2 = 3
So 1 pineapple is $3.
Hope this helps :)
Answer:
3 dollars for 1 pineapple
Step-by-step explanation:
well 2 pinapples is 6 bucks. so 2x=6, and to get x, just divide each side by 2. 6/2=3.
f(t)= 102,000/1+4400e^-t
Answer:
Beginning (t=0) population with flu is 23.
After 4 weeks, population with flu is 1250.
After an infinite amount of weeks, the population witf flu is 102000
Step-by-step explanation:
First question asks you to replace t with 0 because it says beginning.
102000/(1+4400e^-0)=102000/(1+4400)=102000/4401=23.17655 approximately. To nearest whole number this is 23.
After 4 weeks means we replace t with 4:
102000/(1+4400e^-4)
Calculator time:
1250.17142 which to nearest whole number is 1250
If t is super large, then e^-t is super close to 0.
So the limiting number is
102000/(1+4400×0)=102000/1=102000
help pls:Find all the missing elements
Step-by-step explanation:
Using Sine Rule
[tex] \frac{ \sin(a) }{ |a| } = \frac{ \sin(b) }{ |b| } = \frac{ \sin(c) }{ |c| } [/tex]
[tex] \frac{ \sin(42) }{5} = \frac{ \sin(38) }{a} [/tex]
[tex]a = \frac{5( \sin(38))}{ \sin(42) } [/tex]
[tex]a = 4.6[/tex]
[tex] \frac{ \sin(42) }{5} = \frac{ \sin(100) }{b} [/tex]
[tex]b= \frac{5( \sin(100))}{ \sin(42) } [/tex]
[tex]b = 7.4[/tex]
Compare the line passing through the points (–2, –9) and (4, 6) to the line given by the equation y = 25x – 4.
A. They have the same slope.
B. They have the same x-intercept.
C. The two lines are perpendicular.
D. They have the same y-intercept.
Answer:
D. They have the same y-intercep
Step-by-step explanation:
Before the comparison will be efficient, let's determine the equation of the two points and the x intercept .
(–2, –9) and (4, 6)
Gradient= (6--9)/(4--2)
Gradient= (6+9)/(4+2)
Gradient= 15/6
Gradient= 5/2
Choosing (–2, –9)
The equation of the line
(Y+9)= 5/2(x+2)
2(y+9)= 5(x+2)
2y +18 = 5x +10
2y =5x -8
Y= 5/2x -4
Choosing (4, 6)
The equation of line
(Y-6)= 5/2(x-4)
2(y-6) = 5(x-4)
2y -12 = 5x -20
2y = 5x-8
Y= 5/2x -4
From the above solution it's clear that the only thing the both equation have in common to the given equation is -4 which is the y intercept
1. Look at the figure. Which construction is illustrated?
N
IR
H
a line perpendicular to
H3
through point N
a line parallel to
HU
through pointly
The construction illustrated in the figure is that of a line parallel to [tex]\overrightarrow{HJ}[/tex] through point N.
Given: Figure containing illustration of the construction
To find: The construction illustrated in the figure
It can be seen that the figure contains a straight line passing through H and J, a straight line passing through H and N, and a straight line passing through N which seems to be parallel to [tex]\overrightarrow{HJ}[/tex].
The figure also contains arcs made by a compass that measures the angle between [tex]\overrightarrow{HJ}[/tex] and [tex]\overrightarrow{HN}[/tex]. These arcs have been replicated at the point N on the straight line [tex]\overrightarrow{HN}[/tex].
This implies that the straight line through N has been constructed in such a way, so that the angle between that straight line and [tex]\overrightarrow{HN}[/tex] is equal to the angle between [tex]\overrightarrow{HJ}[/tex] and [tex]\overrightarrow{HN}[/tex]. This makes these angles, corresponding angles and [tex]\overrightarrow{HN}[/tex] as the transversal. Thus, the new straight line is constructed parallel to [tex]\overrightarrow{HJ}[/tex].
A strong counterargument that this illustration is not that of a line perpendicular to [tex]\overrightarrow{HJ}[/tex] through point N is that the figure does not contain any straight line perpendicular to [tex]\overrightarrow{HJ}[/tex].
Thus, the construction illustrated in the figure is that of a line parallel to [tex]\overrightarrow{HJ}[/tex] through the point N.
Learn more about construction of parallel lines here:
https://brainly.com/question/12440487
You are planning to attend college next year. The total cost of tuition and textbooks is $10,000. If you go to school, your room and board will cost you $5,000. If you did not go to school, however, you would live at home, and your total room and board would only be $1,000. Additionally, if you did not go to college, you would work a job making $20,000 for the year.
1. In terms of room and board alone, what would be opportunity cost of attending college. Be sure to explain your answer
2. What are the explicit costs of attending school? How much should be included for room and board?
3. What would be the implicit cost of attending college next year?
4. What would be the total opportunity cost of attending college next year?
Opportunity Cost of attending college, in terms of room and board is $4000 . Explicit Cost, Implicit Cost of attending college is $14000, $20000. Total Opportunity Cost of attending college is $34000
1. Opportunity Cost is the cost of next best alternate foregone, as in value of sacrifice made, while choosing an alternative.
Money foregone to attend college, in room & board = room & board cost with college - room & board cost without college = 5000 - 1000 = 40002. Explicit Cost is the actual out of pocket cash expenses outflow, done for choosing an option. Eg : Cash expenditures
In this case, cash expenses for attending college = 140003. Implicit Cost is the implied estimated cost of self supplied factors of production, like value of self labour & self owned land etc.
In this case : Value of self labour, sacrificed for attending college, ie the salary which could have earned by doing job meanwhile = 200004. Total opportunity cost of attending college = Explicit Cost + Implicit Cost = 14000 + 20000 = 34000
To learn more, refer https://brainly.com/question/12121515?referrer=searchResults
Urgent!!! Please simplify
Answer:
The answer is
3x² - 2x³Step-by-step explanation:
First factor (x+1)² out of the expression
That's
[tex] \frac{ ({x + 1})^{2} (6 \cos( \frac{\pi}{3} )) {x}^{2} - {x}^{3} \times 2 \sin( \frac{\pi}{2} ) }{ ({x + 1})^{2} } [/tex]
Reduce the expression by (x + 1)²
We have
[tex]6 \cos( \frac{\pi}{3} ) \times {x}^{2} - {x}^{3} \times 2 \sin( \frac{\pi}{2} ) [/tex]
Using trigonometric values table
[tex] \cos( \frac{\pi}{3} ) = \frac{1}{2} [/tex]
[tex] \sin( \frac{\pi}{2} ) = 1[/tex]
So we have
[tex]6 \times \frac{1}{2} \times {x}^{2} - {x}^{3} \times 2 \times 1[/tex]
Simplify
We have the final answer as
[tex] {3x}^{2} - 2 {x}^{3} [/tex]
Hope this helps you
What is the value of X? HELP
with no further informations, just go by looking at it.
it's 90°, all other options are too far off
A passenger train traveled 180 miles in the same amount of time it took a freight train to travel 120 miles. The rate of the freight train was 15 miles per hour slower than the rate of the passenger train. Find the rate of the passenger train.
Answer:
The passenger train is moving at 45 miles per hour
Step-by-step explanation:
Let the amount of time it took the two trains to travel the distance = t.
Since the two trains traveled the distance at the same time,
Rate of the passenger train =[tex]\frac{180}{t}[/tex]
Rate of the freight train = [tex]\frac{120}{t}[/tex]
Where t is in hours.
From the problem, we can see that the rate of the freight train was 15 miles per hour slower than the rate of the passenger train. Mathematically, we can represent this as
[tex]\frac{120}{t}= \frac{180}{t}-15[/tex]
from the above equation, we can now get our value for t as
[tex]\frac{120-180}{t}=-15\\\frac{-60}{t}=-15\\t=4 hours[/tex]
We have our time of travel for the two trains as 4 hours.
The rate of the passenger train can now be calculated by 180/4 = 45 miles per hour
The table shows the results of a survey in which 10th-grade students were asked how many siblings (brothers and/or sisters) they have. A 2-column table has 4 rows. The first column is labeled Number of siblings with entries 0, 1, 2, 3. The second column is labeled number of students with entries 4, 18, 10, 8. What is the experimental probability that a 10th-grade student chosen at random has at least one, but no more than two, siblings? Round to the nearest whole percent. 65% 70% 75% 80%
Answer:
70%
Step-by-step explanation:
Given
Number of Siblings: || 0 || 1 || 2 || 3
Number of Students: || 4 || 18 || 10 || 8
Required
Determine the probability of a student having at least one but not more than 2 siblings
First, we have to determine the total number of 10th grade students
[tex]Total = 4 + 18 + 10 + 8[/tex]
[tex]Total = 40[/tex]
The probability of a student having at least one but not more than 2 siblings = P(1) + P(2)
Solving for P(1)
P(1) = number of students with 1 sibling / total number of students
From the given parameters, we have that:
Number of students with 1 sibling = 18
So:
[tex]P(1) = \frac{18}{40}[/tex]
Solving for P(2)
P(2) = number of students with 2 siblings / total number of students
From the given parameters, we have that:
Number of students with 2 siblings = 10
So:
[tex]P(2) = \frac{10}{40}[/tex]
[tex]P(1) + P(2) = \frac{18}{40} + \frac{10}{40}[/tex]
Take LCM
[tex]P(1) + P(2) = \frac{18 + 10}{40}[/tex]
[tex]P(1) + P(2) = \frac{28}{40}[/tex]
Divide numerator and denominator by 4
[tex]P(1) + P(2) = \frac{7}{10}[/tex]
[tex]P(1) + P(2) = 0.7[/tex]
Convert to percentage
[tex]P(1) + P(2) = 70\%[/tex]
Hence, the required probability is 70%
Answer:
Step-by-step explanation:
bB
I need help with this math problem please (3x+2)(5x-7)
Answer:
Hey there!
Using the foil method: (3x+2)(5x-7)
15x^2+10x-21x-14
15x^2-11x-14
Let me know if this helps :)
If 2m−6=8m
2
m
-
6
=
8
m
then 3m=
3
m
=
A. 3
B. -1
C. -3
D. -6
E. I don't know.
Answer:
option A
Step-by-step explanation:
please mark this answer as brainlist
Eliminate the parameter for the following set of parametric equations: x= t + 6 y= 3t – 1
Answer:
Solution : Option A
Step-by-step explanation:
What we want to do here is eliminate the parameter t. In order to do that, we can isolate t in our first equation x = t + 6 ----- ( 1 ) and then plug that value for t in the second equation y = 3t - 1. Our solution will be an equation that is not present with t.
( 1 ) x = t + 6, t = x - 6
( 2 ) y = 3( x - 6 ) - 1 ( Distribute the " 3 " in 3( x - 6 ) )
y = 3x - 18 - 1 ( Combine like terms )
y = 3x - 19
As you can see our result will be option a, y = 3x - 19.
How much can 1/2 go into 25
Answer:
50
Step-by-step explanation:
please mark me as brainliest
Answer:
50
Step-by-step explanation:
Hi there!
Determining how much 1/2 can go into 25 is the same as solving for 25÷1/2:
[tex]25\div\frac{1}{2}[/tex]
Dividing by a fraction is the same as multiplying its reciprocal:
[tex]=25\times\frac{2}{1}\\=25\times2\\=50[/tex]
I hope this helps!
Area of a triangle
A/12 = 12/12bh
solve for b
Step-by-step explanation:
I hope this works for ya.
Given the function h(t) = 2t to the power of 2 + 9 evaluate h(5)
9514 1404 393
Answer:
59
Step-by-step explanation:
Put 5 where t is and do the arithmetic.
[tex]h(t)=2t^2+9\\\\h(5)=2\cdot5^2+9=2\cdot25+9\\\\\boxed{h(5)=59}[/tex]
Factorise:
(5 − )(3 − ) − (2 − )(3 − )
Answer:
15- 6 =9
Step-by-step explanation:
- ×- =+ now above the question .we can say that _ 5×_ 3=15 .similarly _ 2×_ 3 = 6 now,
15 _6 =9