A jet plane is launched from a catapult on an aircraft carrier. In 2.0 s it reaches a speed of 42 m/s at the end of the catapult. Assuming the acceleration is constant, how far did it travel during those 2.0 s?

Answers

Answer 1

First find Acceleration

Initial velocity=u=0m/sFinal velocity=v=42m/sTime=t=2sDistance=sAcceleration=a

[tex]\boxed{\sf Acceleration=\dfrac{v-u}{t}}[/tex]

[tex]\\ \sf\longmapsto Acceleration=\dfrac{42-0}{2}[/tex]

[tex]\\ \sf\longmapsto Acceleration=\dfrac{42}{2}[/tex]

[tex]\\ \sf\longmapsto Acceleration=21m/s^2[/tex]

Using second equation of kinematics

[tex]\boxed{\sf s=ut+\dfrac{1}{2}at^2}[/tex]

[tex]\\ \sf\longmapsto s=0(2)+\dfrac{1}{2}(21)(2)^2[/tex]

[tex]\\ \sf\longmapsto s=21(2)[/tex]

[tex]\\ \sf\longmapsto s=42m[/tex]


Related Questions

When light travels from air into water, Group of answer choices its wavelength changes, but its velocity and frequency does not change its velocity remains constant, but its frequency and wavelength changes its velocity, wavelength and frequency all change its velocity and wavelength changes, but its frequency does not change

Answers

Answer:

its velocity, wavelength and frequency all change

Explanation:

Whenever a wave crosses the boundary between two media of different densities, its velocity, frequency and wavelength changes. This appears as a bending of the wave as it crosses the boundary from one medium to another.

Refraction is a fundamental property of waves. Hence when light is travelling from air into water, it wavelength, speed and frequency all changes at the interface between the two media.

The law of conservation of momentum states that the total momentum of interacting objects does not change . This means the total momentum a collision or explosion is equal to the total momentum a collision or explosion.what is momentum

Answers

Answer:

The momentum of an object is equal to the product of its mass and its velocity.

Explanation:

Consider an object of mass [tex]m[/tex] travelling at a velocity [tex]\vec{v}[/tex]. The momentum [tex]\vec{p}[/tex] of this object would be:

[tex]\vec{p} = m \cdot \vec{v}[/tex].

For the law of conservation of momentum, consider two objects: object [tex]\rm a[/tex] and object [tex]\rm b[/tex]. Assume that these two objects collided with each other.

Let [tex]m_{\rm a}[/tex] and [tex]m_{\rm b}[/tex] denote the mass of the two objects. Let [tex]\vec{v}_{\rm a}(\text{initial})[/tex] and [tex]\vec{v}_{\rm b}(\text{initial})[/tex] denote the velocity of the two object right before the interaction. Let [tex]\vec{v}_{\rm a}(\text{final})[/tex] and [tex]\vec{v}_{\rm b}(\text{final})[/tex] denote the velocity of the two objects right after the interaction. The momentum of the two objects right before the collision would be [tex]m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial})[/tex] and [tex]m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial})[/tex], respectively. The momentum of the two objects right after the collision would be [tex]m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final})[/tex] and [tex]m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final})[/tex], respectively.

The sum of the momentum of the two objects would be:

[tex]m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial})[/tex] right before the collision, and[tex]m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final})[/tex] right after the collision.

Assume that the system of these two objects is isolated. By the law of conservation of momentum, the sum of the momentum of these two objects should be the same before and after the collision. That is:

[tex]m_{\rm a}\cdot \vec{v}_{\rm a}(\text{initial}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{initial}) = m_{\rm a}\cdot \vec{v}_{\rm a}(\text{final}) + m_{\rm b}\cdot \vec{v}_{\rm b}(\text{final})[/tex].

The mass of an object is 4kg and it has a density of 5gcm^-3. what is the volume ​

Answers

Answer:

density =   mass/ volume

5=4000/ volume

volume=4000/5

volume=800 cm^-3

Help uhh i need to know this answer

Answers

Answer:

Explanation:

2. 330.63 ft because v*t=d and 3.09*107=330.63

3. 4.2 because 10/2.4=4.1666

4. 130 miles because 2 hours times 65mph= 130

5. 62.3 seconds because 480000/7700=62.33766233

8. 60 meters, because 0.5 *120 (because 2 minutes converted to seconds is 120) is equal to 60.

IMPORTANT 3 QUESTIONS!

Answers

Answer:

7. 20,000,000 mL.

8. 8,000 m.

9. 120,000 secs.

10. 4

Explanation:

7. Determination of the volume in millilitres (mL)

Volume in litre (L) = 20,000 L

Volume in millilitres (mL) =..?

The volume in mL can be obtained as follow:

1 L = 1,000 mL

Therefore,

20,000 L = 20,000 x 1,000 = 20,000,000 mL.

Therefore, 20,000 L is equivalent to 20,000,000 mL.

8. Determination of the distance in metre (m)

Distance in mile = 5 mile

Distance in metre =?

First, we shall convert from mile to kilometre.

This can be done as follow:

1 mile = 1.6 km

Therefore,

5 mile = 5 x 1.6 = 8 km

Finally, we shall convert 8 km to metre (m).

This is illustrated below:

1 km = 1,000 m

Therefore,

8 km = 8 x 1,000 = 8,000 m

Therefore, 5 miles is equivalent to 8,000 m.

9. Determination of the time in seconds.

Time = 400 minutes for 5 days.

First, we shall convert 400 mins to hour.

This is illustrated below:

60 minutes = 1 hour

Therefore,

400 mins = 400/60 = 20/3 hours

The time (hours) is 20/3 hours in 1 day.

Therefore, the time (hours) in 5 days will be = 20/3 x 5 = 100/3 hours.

Next, we shall convert 100/3 hours to minutes.

This is illustrated below:

1 hour = 60 minutes

Therefore,

100/3 hours = 100/3 x 60 = 2000 mins

Finally, we shall convert 2000 mins to seconds.

This is illustrated below:

1 mins = 60 secs

2000 mins = 2000 x 60 = 120,000 secs.

Therefore, the time is 120,000 secs.

10. Determination of the number of significant figures.

To obtain the significant figures of a number, we simply count all the numbers available.

Therefore, the number of significant figures for 9876 is 4.

A screen is separated from a double-slit source by a distance L. When light of wavelength 563 nm is incident on the double slit, the separation distance between adjacent bright fringes on the screen is 0.0290 mm. When instead, 500 nm light is used, what is the separation distance (in mm) between adjacent bright fringes

Answers

Answer:

β 2 = 0.02575 mm

Explanation:

given data

wavelength = 563 nm

separation distance between adjacent bright fringes =  0.0290 mm

wavelength = 500 nm

solution

we get here separation distance between adjacent bright fringes that is express as

β = [tex]\frac{\lambda D }{d}[/tex]    ..................................1

here D is distance from plane of slit to screen

and d is slit sepation that is constant

so

[tex]\frac{\beta 1}{\beta 2} = \frac{\lambda 1}{\lambda 2}[/tex]  

β 2 = [tex]\frac{500}{563} \times 0.0290[/tex]  

β 2 = 0.02575 mm

Write any three importance of Measurement.

Stay Safe,Stay Healthy and Stay Happy ​

Please answer me this question fast, PLEASE

Answers

Explanation:

The three importance of measurement are as follows :-

measurement is used to compare the items when barter system takes place .measurement helps in weighing the foods , groceries etc .Measurement are important in laboratory when there experiments is being taken for different purposes .

Hope it is helpful to you

✌️✌️✌️✌️✌️✌️✌️

A model rocket blasts off from the ground, rising straight upward with a constant acceleration that has a magnitude of 76.8 m/s2 for 1.99 seconds, at which point its fuel abruptly runs out. Air resistance has no effect on its flight. What maximum altitude (above the ground) will the rocket reach?

Answers

Answer:

Explanation:

Take note that when the fuel of the rocket is consumed, the acceleration would be zero. However, at this phase the rocket would still be moving up until all the forces of gravity would dominate and change the direction of the rocket. Hence, there will be a need to calculate two distances, one from the ground until the point where the fuel is consumed and from that point to the point where the gravity would change the direction.

Given:

a = 76.8 m/s^2

t = 1.99 s

Solution:

d = vi (t) + 0.5 (a) (t^2)

d = (0) (1.99) + 0.5 (76.8) (1.99)^2

d = 0+38.4×3.9601

d = 152.068m

vf = vi + at

vf = 0 + 76.8 (1.99)

vf = 152.83 m/s (velocity when the fuel is consumed completely)

Then, we calculate the time it takes until it reaches the maximum height.

vf = vi + at

0 = 152.83+(-9.8) (t)

0 = 152.83 + (-9.8) (t)

-152.83 = -9.8t

t = 152.83/9.8 s

t = 15.59s

Then, the second distance

d= vi (t) + 0.5 (a) (t^2)

d = 152.83 (15.59) + 0.5 (-9.8) (15.59^2)

d = 2382.6197- 1190.93

d = 1191.68m

Then, we determine the maximum altitude:

d1 + d2 = 152.068 m + 1191.68m = 1343.748m


The velocities of light in air and glass are 3.0 x 10^8ms and 2.0×10^8ms respectively. If the angle of refraction is 30°, the sine of the angle of incidence is?
Pls help​

Answers

Answer:

0.75

Explanation:

[tex]refractive \: index \: = \frac{3.0 \times {10}^{2} }{2.0 \times {10}^{2} } [/tex]

= 1.5

[tex]refractive \: index = \frac{ \sin(angle \: of \: incidence) }{ \sin(angle \: of \: refraction) } [/tex]

[tex]1.5 = \ \frac{ \sin(i) }{ \sin(30) } [/tex]

1.5 × ½ = sin(i)

[tex] \sin(i) = 0.75[/tex]

What evidence supported the inflation theory? (the big bang theory one pls)

Answers

Answer:

The comic microwave background

Explanation:

The cosmic microwave background is said to be part of the remnant of the Big Bang that happened which resulted in the formation of the universe. This is because the universe was thought to be a very hot place which resulted in the expansion of it.

The heat was said to have resulted in the cooling of gases present and the remnant of the heat is what formed the radiation called the cosmic wave background.

Every time Dylan takes his dog Frisbee for a walk, the dog always pulls hard on the leash. This nearly pulls Dylan's arm out of its socket and Frisbee almost chokes himself! Explain these effects in terms of Newton's third law.

Answers

Answer:

See explanation below for Newton's third law of "action generates reaction" for this example

Explanation:

From Newton's third law: "For every action there is an equal and opposite reaction."

Frisbee is pulling on the leash with force F which is felt by Dylan as a tension force in the leash trying to pull his arm out of its socket, and Frisbee feels an equal and opposite tension force from the leash chocking him.

Monochromatic light of wavelength 649 nm is incident on a narrow slit. On a screen 2.25 m away, the distance between the second diffraction minimum and the central maximum is 1.99 cm. (a) Calculate the angle of diffraction θ of the second minimum. (b) Find the width of the slit.

Answers

Answer:

a)0.51°

b)1.47×10^-4m

Explanation:

a)for a single slit experiment, the minima that has an angle of θ towards the centre needs to satisfy the expression below.

bsin(θ)= mλ.........................(*)

Where b= width of the slit

The distance on the screen from Central angle can be expressed as

Sin(θ)= y/d............. (**)

d and y is the horizontal distance between slit and screen

If we input eqn(**) into equation (*) we have

y= mλd/b................(z)

In order to find angle (θ) we have

(θ)= sin-(1.99×10^-2)/2.25

= 0.51°

Therefore, angle of diffraction θ of the second minimum is 0.51°

b)to find the width of the sloth using eqn(z) by substitute the values, we have

b= (2)(649×10^-9)(2.25)/1.99×10^-2

b= 1.47×10^-4m

Therefore, the width of the slit is 1.47×10^-4m

Velocity may be positive,negative or zero.Explain this statement with diagram.​

Answers

Answer:

/

Explanation:

The Doppler effect a. can be applied only to sound waves. b. is the basic explanation for the blue shift of light in our Universe. c. occurs when the frequency of sound waves received is lower if the wave source is moving toward you than if it's moving away. d. occurs when the pitch of a sound gets lower if the source is receding.

Answers

Answer:

a. can be applied only to sound waves.

c. occurs when the frequency of sound waves received is lower if the wave source is moving toward you than if it's moving away

d. occurs when the pitch of a sound gets lower if the source is receding.

Explanation:

[tex].[/tex]

Write a formula by showing the relation among density mass and volume.​

Answers

Lets do

[tex]\boxed{\sf P=\dfrac{m}{v}}[/tex]

[tex]\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}[/tex]

[tex]\\ \sf\longmapsto Mass=Density\times volume[/tex]

[tex]\\ \sf\longmapsto Volume=\dfrac{Mass}{Density}[/tex]

SI unit of density is kg/m^3SI unit of mass is kgSI unit of Volume is m^3

Which of the following is a true statement about mass and weight? Mass is a measure of how much matter an object has, while weight is a measure of how much space the object takes up. Mass will not change based on location, while weight will change based on gravitational pull. Mass is a measure of a gravitational pull on an object, while weight is a measure of how much matter is an object has. Mass is proportional to the force of gravity, while weight is proportional to the amount of mass.

Answers

Answer:

Mass will not change based on location, while weight will change based on gravitational pull.

Explanation:

The formula for weight is mass*gravitational pull, hence weight changes based on gravitational pull

Mass will not change based on location, while weight will change based on gravitational pull. This is a true statement about mass and weight.

What are mass and weight?

The most fundamental characteristic of matter is mass, which is one of the fundamental quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilograms is the SI unit of mass (kg). A body's mass remains constant at all times.

The amount of weight t indicates how much gravity is pulling on a body. The weight formula is provided by: w = mg

Weight being a force The SI unit of weight is the Newton, which is also the same as the SI unit of force (N). When we look at how weight is expressed, we can see that it depends on both mass and the acceleration caused by gravity; while the mass may not change from one location to another, the acceleration caused by gravity does.

Learn more about mass here:

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why do objects in equilibrium have a net force of 0?

Answers

Answer:

Because there is no net force acting o an object in equilibrium.

Explanation:

When object is in equilibrium (either at rest or moving with constant velocity, the net force acting o it is zero.A vector can only have zero magnitude fall of its components are zero this means that all forces acting on the object are balanced.

What is the cat's displacement t=0.5s to 1.5s,

Answers

Answer:

3.75m

Explanation:

area under graph

5+2.5=7.5

7.5/2=3.75

3.75x0.5=1.875

1.875x2=3.75m

Is there a way for us to control motion

Answers

Answer:

They are:

1) change position

2) distract yourself

3) Get fresh air

4) Face the direction you are going.

5) Drink water.

6) Play music.

7) Put your eyes on horizon.  

Explanation:

Hope it helps.

The energy change in an endothermic reaction is: A. Internal B. External C. Negative D. Positive

Answers

Answer:

Positive

Explanation:

In an endothermic reaction, the products are at a higher energy than the reactants. This means that the enthalpy change of the reaction (∆H) is positive

If, on a particular day, atmospheric pressure is 730 mm
of mercury, what is this
a) in pascals
b) in atmospheres
c) in millibars?

Answers

Answer:

b) in atmostphere

Explanation:

I made lots of research and it should be b.

a. On a particular day, atmospheric pressure is 730 mm of mercury In pascals 97392.2896252, b. On a particular day, atmospheric pressure is 730 mm of mercury in atmospheres 0.960526316 atm, c. on a particular day, atmospheric pressure is 730 mm of mercury in millibars 973.70355547 mb.

a) To convert atmospheric pressure from mm of mercury to pascals, we can use the conversion factor: 1 mm Hg = 133.322387415 pascals.

Pressure in pascals = 730 mm Hg * 133.322387415 = 97392.2896252 pascals.

b) To convert atmospheric pressure from mm of mercury to atmospheres, we can use the conversion factor: 1 atm = 760 mm Hg.

Pressure in atmospheres = 730 mm Hg / 760 = 0.960526316 atm.

c) Atmospheric pressure is often expressed in millibars (mb), where 1 atmosphere is approximately equal to 1013.25 millibars.

Pressure in millibars = 0.960526316 atm * 1013.25 mb/atm = 973.70355547 mb.

Atmospheric pressure is the force exerted by the weight of air molecules in the Earth's atmosphere. It can be measured in various units, including millimeters of mercury, pascals, atmospheres, and millibars.

Converting between these units involves using conversion factors based on established relationships between them.

In this case, the provided pressure of 730 mm Hg was converted to pascals, atmospheres, and millibars using the appropriate conversion factors.

Conversions help express pressure measurements in units that are more suitable for different contexts or calculations.

Know more about atmospheric pressure:

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An observer is standing next to the tracks, watching a train approach. The train travels at 30 m/s and blows its whistle at 8,000 Hz as it approaches and then passes by the observer without slowing down. Assuming the speed of sound is 340 m/s, how much of a frequency change did the observer hear?

Answers

7351.35Hz

f0= v-Vo/v-Vs × FSA

= 340-0 /340+30 ×8000

= 340/370× 8000

= 7351.35hz

briefly explain what EMF of a cell cell is​

Answers

Answer:

The emf of a cell is the sum of the electric potential differences (PDs) produced by a separation of charges (electrons or ions) that can occur at each phase boundary (or interface) in the cell. The magnitude of each PD depends on the chemical nature of the two contacting phases.

Explanation:

pls mark brainliest

3. What two characteristics do you need to include when defining a force? (a) speed and direction (b) strength and direction (c) acceleration and time (d) distance and direction
4. When a bug traveling west hits the windshield of a car that is traveling east, what can be said about the collision? (a) The bug feels a stronger force than the car. (b) The car and the bug feel the same size force. (c) The car accelerates more than the bug. (d) The bug does not accelerate due to the force.
5. What is the reaction force to the force on a baseball from a bat? (a) The force of the bat on the ball (b) The force of the ball on the ground (c) The force of the bat on the players hand (d) The force of gravity on the

Answers

Answer:

2

yes

Explanation:

been submitted to the Theme 20 participants will be there was a lot of fun and I will be there at Home

Which statement correctly compares the number of protons and electrons in atoms of rubidium (Rb) and calcium (Ca)?

(1 point)

Rubidium has fewer protons and fewer electrons than calcium.
Rubidium has fewer protons and more electrons than calcium.
Rubidium has more protons and fewer electrons than calcium.
Rubidium has more protons and more electrons than calcium.

Answers

Answer

#1. number of valence electrons

#2. oxygen

#3. Rubidium has more protons and more electrons than calcium.

#4. 20

#5. helium (he)

Explanation:

Answer:

Rubidium has more protons and more electrons than calcium.

Explanation:

for connexus honors chemistry unit 3 lesson 3 quick check :)

What is the goal of the scientific method

Answers

Answer:

Regardless of how the steps are documented, the goal of scientific method is to gather data that will validate or invalidate a cause and effect relationship.

Hope this helped!!!

A 4.00-m long rod is hinged at one end. The rod is initially held in the horizontal position, and then released as the free end is allowed to fall. What is the angular acceleration as it is released

Answers

Answer:

The angular acceleration α = 14.7 rad/s²

Explanation:

The torque on the rod τ = Iα where I = moment of inertia of rod = mL²/12 where m =mass of rod  and L = length of rod = 4.00 m. α = angular acceleration of rod

Also, τ = Wr where W = weight of rod = mg and r = center of mass of rod = L/2.

So Iα = Wr

Substituting the value of the variables, we have

mL²α/12 = mgL/2

Simplifying by dividing through by mL, we have

mL²α/12mL = mgL/2mL

Lα/12 = g/2

multiplying both sides by 12, we have

Lα/12 × 12 = g/2 × 12

αL = 6g

α = 6g/L

α = 6 × 9.8 m/s² ÷ 4.00 m

α = 58.8 m/s² ÷ 4.00 m

α = 14.7 rad/s²

So, the angular acceleration α = 14.7 rad/s²

1. Si tengo medio kilo de fruta y te doy un cuarto y tú me das tres cuartos de kilo, ¿cuánto tengo? 2. Si en una carrera te queda por recorrer la mitad de la mitad de 1 km, ¿cuánto te falta? 3. ¿Qué pesa mas, un kilo y medio de hierro o tres medios kilos de paja? porfavor es urgente.

Answers

Answer:

1. Tienes 1 kg de fruta.

2. Queda por recorrer 1/4 km.

3. Ambos pesan lo mismo.

Explanation:

1. Tienes 1/2 kg y cuando te doy 1/4 te queda:

[tex] m = \frac{1}{2} - \frac{1}{4} = \frac{1}{4} [/tex]

Ahora cuando te doy 3/4 kg te queda en total:

[tex] m_{T} = \frac{1}{4} + \frac{3}{4} = 1 kg [/tex]

Por lo tanto, tienes 1 kg de fruta al final.

2. Si falta por recorrer la mitad de la mitad, tenemos:

[tex] d = \frac{1/2}{2} = \frac{1}{4} [/tex]

Entonces, queda por recorrer 1/4 km.

3. El peso (P) del hierro es:

[tex] P = m*g [/tex]    

[tex] P = (1 + 1/2)kg*9.81 m/s^{2} = 14.72 N [/tex]

Y el peso de la paja es:

[tex] P = 3/2 kg*9.81 m/s^{2} = 14.72 N [/tex]

Por lo tanto, ambos pesan lo mismo.

Espero que te sea de utilidad!

A girl walks 55 m downhill in 3.2 s. What is her average velocity?

Answers

Answer:

V = 17.2

Explanation:

Speed = distance(m) / time(s)

= 55m / 3.2s

=17.2 m/s

what is the scientific notation for 1,500,000​

Answers

Answer:

[tex]1.5 * 10^6[/tex]

Explanation:

Given

Digit: 1,500,000

Required

Represent using scientific notation

We start by expressing the given digit as a product of 1.5 and a multiple of 10

[tex]Digit = 1.5 * 1,000,000[/tex]

1,000,000 can be represented as 10⁶

So; the digit becomes

[tex]Digit = 1.5 * 10^6[/tex]

Hence, the scientific notation of 1,500,000 is 1.5 * 10⁶

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