hich of the following is an oxidation-reduction reaction?
ZnS(s) + 2O2(g) Right arrow. ZnSO4(s)
CaO(s) + H2O(l) Right arrow. Ca(OH)2(s)
6Li2O(s) + P4O10(g) Right arrow. 4Li3PO4(s)
SO2(g) + H2O(l) Right arrow. H2SO3(aq)

The enthalpy of vaporization of Bromine is 15.4 kJ/mol. -7.7 kJ is the energy change when 80.2 g of Br₂ condenses to a liquid at 59.5°C.

The amount of enthalpy or energy that must be added to a liquid substance into gas substance is called Enthalpy of Vaporization. It is also known as Latent heat of vaporization.

To calculate the energy use this expression:

[tex]Q = n \Delta H_{\text{vapo.}[/tex]

where,

Q = Energy change

n = number of moles

[tex]\Delta H_{\text{Vapo.}}[/tex] = Molar enthalpy of vaporization

Now find the number of moles

Number of moles (n) = [tex]\frac{\text{Given Mass}}{\text{Molar mass}}[/tex]

                                   = [tex]\frac{80.2\ g }{159.8\ g/mol}[/tex]

                                   = 0.5 mol

Now put the values in above formula we get

[tex]Q = - n \Delta H_{\text{vapo.}[/tex]         [Negative sign is used because Br₂ condensed here]

   = - (0.5 mol × 15.4 kJ/mol)

   = - 7.7 kJ

Thus from the above conclusion we can say that The enthalpy of vaporization of Bromine is 15.4 kJ/mol. -7.7 kJ is the energy change when 80.2 g of Br₂ condenses to a liquid at 59.5°C.

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Radioactive waste from fusion reactions becomes less hazardous much sooner than waste from fission reactions, nuclear fusion is much safer than fission because it leaves no radioactive waste behind.

Both processes are natural, but they can also be carried out in a lab. While fusion involves the "crushing" of two atoms to form a single atom of a new element, fission involves the splitting of an atomic nucleus.

We can conclude from this information that radioactive waste from fusion reactions becomes less hazardous much sooner than waste from fission reactions, and nuclear fusion is much safer than fission because it produces no radioactive waste.

It takes a lot of energy to combine protons so that nuclear forces can overcome electrostatic repulsion. The energy released during the fission process is much greater than the energy released during other chemical reactions.

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Answer: The radioactive waste from fusion reactions becomes less hazardous much sooner than the waste from fission reactions.

Explanation:

The concentration of acetic acid:

The concentration of the acetic acid before titration is 0.128 M

What is titration?

Titration is a quantitative analytical procedure that works by allowing a known analyte to gradually react with a titrant until an endpoint is reached.

Titration for weak acid and strong base:

Moles of acetic acid =  moles of NaOH

Given:

Concentration of NaOH = 0.1067 M

Volume of NaOH = 30.07 ml = 0.03007 L

Calculation:

So, by using the formula, Concentration = Moles/Volume

Moles of NaOH = concentration x volume = 0.1067 x 0.03007 = 0.0032

Therefore, the moles of acetic acid  = 0.0032 mole

Now, using the formula again for determining the concentration of acetic acid, we get,

Concentration = Moles/Volume

Concentration of acetic acid =  0.0032/0.025 = 0.128M

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Answer:

» Chlorine (Cl) is the oxidizing agent because it gains an electron.

Explanation:

Oxidization is the process of losing electrons during an ionic reaction.

In the reaction above, aqueous chlorine captures the electrons of bromide ion hence becoming oxidized. In this sense, since aqueous chlorine is the one gaining electrons, it oxidizes bromide to bromine

[tex]{ \rm{Cl _{2(aq)}+ 2Br {}^{ - } _{(aq)} \dashrightarrow 2Cl {}^{ - } _{(aq)} + Br _{2( aq)}}}[/tex]

Answer:

c

Explanation:

edge 2022

Answer:

(a) Gas pressure ---------------------> (iii) force per unit area

(b) One mole of substance -------------------> (i) 6.02 x 10²³

(c) One mole of any gas ----------------------> (ii) 22.4 dm³ at STP

(d) Avogadro's number -----------------> (iv) 6.02 x 10²³ particles

Orbits do the proton complete:

A proton exits the cyclotron 1. 0 ms after starting its spiral trajectory in the center of the cyclotron and 1.8 x [tex]10^{4}[/tex] orbits does the proton complete during this 1. 0 ms

Calculation:

(a) The kinetic energy of the proton is given by, K.E. = [tex]\frac{1}{2} m v^{2}[/tex]

v = [tex]\sqrt{\frac{2(K E)}{m}}[/tex]

v = [tex]\sqrt{\frac{2(6.5 \mathrm{MeV})\left(1.6 \times 10^{-19} \mathrm{~J} / \mathrm{eV}\right)}{1.672 \times 10^{-27} \mathrm{~kg}}}[/tex]= 3.5 [tex]\times 10^{7} \mathrm{~m} / \mathrm{s}[/tex]

The radius of the orbit is given by,

r = [tex]\frac{m v}{B q}=\frac{1.672 \times 10^{-27} \mathrm{~kg}\left(3.5 \times 10^{7} \mathrm{~m} / \mathrm{s}\right)}{(1.2 \mathrm{~T})\left(1.6 \times 10^{-19} \mathrm{C}\right)}[/tex] = 0.30 m

Hence, the diameter of the largest orbit just before the proton leaves the orbit is 0.60 m.

(b) The time required to complete one revolution is given by, T=[tex]\frac{2 \pi m}{B q}=\frac{2 \pi\left(1.672 \times 10^{-27} \mathrm{~kg}\right)}{(1.2 \mathrm{~T})\left(1.6 \times 10^{-19} \mathrm{C}\right)}[/tex] =5.48 x [tex]10^{-8}[/tex] s

The number of revolutions made by the proton is given by,

Tn = t

Therefore, n = t/T = [tex]\frac{1 \mathrm{~ms}}{5.48 \times 10^{-8} \mathrm{~s}}[/tex] = 1.8 x [tex]10^{4}[/tex]

Note: your question is incomplete, but most probably your full question was, A medical cyclotron used in the production of medical isotopes

accelerates protons to 6.5 MeV. The magnetic field in the

cyclotron is 1.2 T.

a. What is the diameter of the largest orbit, just before the protons

exit the cyclotron?

b. A proton exits the cyclotron 1.0 ms after starting its spiral

trajectory in the center of the cyclotron. How many orbits

does the proton complete during this 1.0 ms?

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Answer:

Limiting Reagent: NaHCO₃

Amount of NaCl: 69.6 g NaCl

Mass of Excess Reagent: 56.6 g HCl

Explanation:

To find the mass of NaCl, you need to (1) convert mass reactant to moles reactant (via molar mass), then (2) convert moles reactant to moles NaCl (via mole-to-mole ratio from equation coefficients), and then (3) convert moles NaCl to mass NaCl (via molar mass).

Molar Mass (NaHCO₃):

22.990 g/mol + 1.008 g/mol + 12.011 g/mol + 3(15.998 g/mol)

Molar Mass (NaHCO₃): 84.003 g/mol

Molar Mass (HCl): 1.008 g/mol + 35.453 g/mol

Molar Mass (HCl): 36.461 g/mol

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

100 g NaHCO₃            1 mole                  1 mole NaCl             58.443 g
------------------------  x  ------------------  x  ---------------------------  x  ----------------  =
                                   84.003 g            1 mole NaHCO₃            1 mole

=  69.6 g NaCl

100 g HCl            1 mole               1 mole NaCl          58.443 g
----------------  x  ------------------  x  -----------------------  x  ----------------  =
                           36.461 g             1 mole HCl              1 mole

=  160 g NaCl

Since NaHCO₃ results in the smaller amount of product, it is the limiting reagent. In other words, it is used up before the HCl has the chance to completely react. Therefore, the actual amount of NaCl produced is 69.6 grams.

To find the mass of the excess reagent, you need to calculate the amount of HCl actually used in the reaction. Then, you need to subtract that value from the total amount of HCl.

69.6 g NaCl             1 mole                1 mole HCl             36.461 g
---------------------  x  ------------------  x  -----------------------  x  ----------------  =
                                58.443 g            1 mole NaCl             1 mole

=  43.4 g HCl

Amount Given - Amount Reacted = Mass Excess

100 g HCl - 43.4 g HCl = 56.6 g HCl

Board instances involving eligibility or disciplinary issues that are addressed by a board-approved order public records and accessible on the BON's web page.

Board Position Statements are a way to give nurses guidance on topics that are important to the Board and relate to the safety of the public, but they do not have the legal force of law. In the context of the position statement's overall intent, each position statement is intended to offer direction. Board position statements are examined every year to determine their applicability and accuracy in light of current practice, the Nursing Practice Act, and Board regulations. In January 2022, the Board conducted its most recent evaluation.

It is possible to find a concise summary of the substance of the Position Statements, although it does not include all the specifics that are included in each Position Statement.

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The formula of the compound will be  [tex]Mg_2Ga[/tex]

The compound contains magnesium and gallium. The symbol and magnesium and gallium is Mg and Ga respectively.

Magnesium content is 41.1%

Gallium content is 58.9%

First, find the number of moles of each element in the compound by dividing their percentage compositions with their respective molar weights.

Mg = 41.1/24.505 =1.6772

Ga = 58.9/69.723 = 0.8448

Next, divide each number of moles by the smallest number of moles.

Mg = 1.6772/0.8448 = 2

Ga = 0.8448/0.8448 = 1

Thus, the formula of the compound is [tex]Mg_2Ga[/tex]

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The amount of space that matter occupies is called its volume. Solids, liquids, and gases all have volume.

0.723 is the [H ] (molarity) before any base is added.

the balanced equation for the acid-base reaction is

KOH + HClO₄ ---> KClO₄ + H₂O

stoichiometry of KOH to HClO₄ is 1:1

The number of HClO₄ moles - 0.723 M / 1000 mL/L x 25.0 mL = 0.0181 mol

Number of KOH moles - 0.27 M/ 1000 mL/L x 80.0 mL = 0.0216 mol

KOH is a strong acid and HClO₄ is a strong base therefore complete dissociation takes place.

the acid reacts with base in a 1:1 molar ratio, there's excess base remaining.

excess OH⁻ ions - 0.0216 - 0.0181 = 0.0035 mol

concentration is calculated as the number of moles/volume

volume of solution - 25.0 + 80.0 = 105.0 mL

[OH⁻] = 0.0035 mol / 0.105 L = 0.033 M

pOH = -log [OH⁻]

pOH = -log(0.033 M)

pOH = 1.48

pH can be calculated by knowing the pOH

pH + pOH = 14

pH = 14 - 1.48 = 12.52

pH = -log [H₃O⁺]

[H₃O⁺] = antilog(-12.52)

[H₃O⁺]  = 3.0 x 10⁻¹³ M

0.723 is the [H ] (molarity) before any base is added.

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The volume measured using such a cylinder will be reported to the nearest 10th mL.

10 mL graduated cylinders are always read to the nearest two decimal places.

100 mL graduated cylinders are always read to the nearest 1 decimal place. The nearest 1 decimal place is the same thing as the nearest 10th.

Thus, a reading made using a 100mL increment graduated cylinder would be reported to the nearest 10th mL.

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Answer:

answer is B

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Answer:

28.1 moles   (three sig digits)

Explanation:

Using Ideal Gas Law

PV = n RT      looking for 'n'   R = .082057366  L-atm/K-mole

15.0 * 45.0  = n  * .082057366 * 293

n = 28.1 Moles

The number of moles of helium that are in a 45.0-liter tank at 293 K and 15.0 atm is  28.1 Moles.

Moles is the measuring unit that measures the quantity of a substance. Moles is a SI unit.

Helium is the lightest gas, which is used in the tires of an airplane if it is filled in the balloons, the balloon flies in the sky.

Given the volume is 45.0 liter

The pressure is 15.0 atm.

The temperature is 293 K

To calculate the moles, we will use the formula of an ideal gas:

PV = n RT      

R = .082057366 is the gas constant.

We have to calculate the n

Putting the values in the equation

15.0 x 45.0  = n  x .082057366 x 293

n = 28.1 Moles.

Thus, the moles of helium is n = 28.1 Moles.

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Ionization of Gold:

The maximum wavelength of light that will ionize gold is 134.5 x 10 ⁻⁴m  

Calculation:

1 mole requires = 890.1kJ = 8.901×10⁵ J

The energy needed to ionize a single atom = Divide it by Avogadro's number (6.0221409×10²³)

Thus, 1 atom requires = 8.901×10⁵ J / 6.0221409×10²³ J

                                    =  1.478×10⁻¹⁸ J

The Energy of photon = E = hc/λ   where,

h =  Planck constant (6.626070040Ă—10â’34 Js)

λ =  the wavelength

c = the speed of light

Putting the values:

E = 1.478×10⁻¹⁸ J

h =6.63x10⁻³⁴ Js

c = 3 x 10⁸ m/s

λ = ?

λ = hc/E

  = (6.63x10⁻³⁴ x 3 x 10⁸ ) / 1.478×10⁻¹⁸

  = 134.5 x 10 ⁻⁴m  

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If your client receives a letter from SilverScript requesting proof of Creditable Coverage, they can ignore the letter is a false statement

Creditable coverage is known to be a form of an health insurance, that consist of prescription drug and also other kinds of health benefit plan that is known to meets  the minimum amount of qualifications.

Note that  the types of creditable coverage plans are group and individual health plans, student health plans,  and others.

It is not right to ignore any letter sent to you concerning the case above as it may be vital and as such, the statement of If your client receives a letter from SilverScript requesting proof of Creditable Coverage, and the client has already submitted proof of creditable coverage with the enrollment application, they can ignore the letter is a wrong/false statement.

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[tex] \huge \quad\quad \underline{ \tt{{Answer}}}[/tex]

Rusting of iron is the most familiar example of corrosion. It is a process in which an iron reacts with atmospheric oxygen and moisture to form a reddish brown substance iron oxide, which is commonly known as rust.

[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex]\blue{ \star}:[/tex][tex] \sf4fe+ 3O_2+ XH_2O→ 2Fe_2O_3.XH_2O[/tex]

Answer:

Rust is an iron oxide, formed by iron and oxygen reacting in the catalytic presence of water or air moisture. Rusting is an oxidation reaction. This means it involves oxygen reacting with something (in this case, iron in the presence of moisture).

The chemical formula for rusting:

4Fe + 3O2 + 6H2O → 4Fe (OH)3

Hope this helps!

- profparis

Answer:

The answer to your question is True

Explanation:

CH2O is a polar molecule. It has three polar bonds that are arranged asymmetrically, thus allowing their dipole moments to add up and give the molecule an overall dipole moment. CH2O has a central carbon atom that forms two single bonds with the two hydrogen atoms and a double bond with the oxygen atom.

I hope this helps and have a good day!

Answer:

D.) The attraction between the delocalized electrons and the metal's cations

Explanation:

Metallic bonds form between free-floating valence electrons (delocalized electrons) and positively charged metal ions (cations). The negative charge from the electrons and the positive charge from the ions are what form the attraction.

Answer:

nuetral

Explanation:

water has neutral

Insulating materials are composed of atoms with tightly bound outer electrons.

The material that stop the flow of Sound, Heat and Electricity by them are called Insulating Material. Insulator are the materials whose atoms have tightly bound outer electrons because electrons are not free to shared by neighboring atoms.

Examples: Glass, Plastic, Rubber, Air and Wood.

There are mainly three types of Insulating Material:

Thus from the above conclusion we can say that Insulating materials are composed of atoms with tightly bound outer electrons.

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Answer:

Point B

Explanation:

From 0 - 7 on the pH scale, substances are said to be acidic. At 7, the substance is said to be neutral. From 7 - 14, substances are basic.

Lime is a basic substance. Therefore, when it is added to the soil, one should expect that the soil becomes more basic. On the graph, this should be represented by the line increasing in pH. As such, the point at which lime was added was most likely Point B.

Group C : 32.1°C , 31.9°C, 31.8°C makes the most precise measurements of the object's temperature.

Precision :The degree of similarity between study results of the experiment if they were performed today under comparable conditions.

If repeated measurements yield similar results, the measurement is considered precise (or repeated surveys).

It means how closely all the results are related .

Therefore, there should be less difference between the measurements of all the results.

In option (a) , there is a difference of 1° in all the results.

In option (b) , there is a difference of approximately 1.5° in all the results.

In option (c), there is only 0.2° difference in all the results.

In option (d) , there is a difference of 3° in all the results.

Therefore, All the option of group (c) are closely related.

Hence, Group (c) 32.1°C, 31.9°C, 31.8°C makes the most precise

measurements of the object's temperature.

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The equilibrium constant K is 17.78 × 10²⁷ at 255 K for the following reaction under acidic conditions.

4H⁺ (aq) + MnO₂ (s) + 2Fe⁺² (aq) → Mn⁺² (aq) + 2Fe⁺³ (aq) + 2H₂O (l)

The relation between standard electrode potential and equilibrium constant is as follows:

G = -2.303 RT log K

-nFE° = -2.303 RT logK

[tex]\log K = \frac{nFE^{\circ}_{\text{cell}}}{2.303RT}[/tex]

Here,

n = 2

F = 96500

[tex]E^{\circ}_{\text{Cell}} = E^{\circ}_{\text{reduced}} - E^{\circ}_{\text{oxidized}}[/tex]

        = 0.77 V - 1.51 V

        = -0.74 V

R = 8.314 J/K mole

T = 255 K

Now put the values in above formula we get

[tex]\log K = \frac{nFE^{\circ}_{\text{cell}}}{2.303RT}[/tex]  

[tex]\log K = \frac{2 \times 96500 \times (-0.74)}{2.303 \times 8.314\ \text{J/K mole} \times 255\ K}[/tex]  

[tex]\log K = \frac{-142820}{4882.521}[/tex]

log K = 29.25

K = 17.78 × 10²⁷

The equilibrium constant K is 17.78 × 10²⁷ at 255 K for the following reaction under acidic conditions.

4H⁺ (aq) + MnO₂ (s) + 2Fe⁺² (aq) → Mn⁺² (aq) + 2Fe⁺³ (aq) + 2H₂O (l)

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Use the appropriate standard reduction potentials below to determine the equilibrium constant at 255 K for the following reaction under acidic conditions.

4H⁺ (aq) + MnO₂ (s) + 2Fe⁺² (aq) → Mn⁺² (aq) + 2Fe⁺³ (aq) + 2H₂O (l)

The equation that relates equilibrium constants with cell potentials is

[tex]\log K = \frac{nFE^{\circ}_{\text{cell}}}{2.303RT}[/tex]

Use this formula, along with the information in the appendix of your book to solve for K.  

Answer:

lithium

Explanation:

The mass of hydrogen is 1 u, so the mass of element x is 7 u, which is approximately the atomic mass of lithium.

To obtain the desired solution:

450 mL of 85% alcohol solution is needed to obtain the desired solution.  

Calculation:

Let x be the amount of the 85% alcohol required

The volume of the resulting 70% alcohol solution will then be = x + 135 ml

135 mL of the 20% alcohol solution contains the amount of "pure" alcohol is =  0.20×135 mL.

The 85% alcohol solution contains x mL of "pure" alcohol = 0.85× x mL.

The total amount of the "pure" alcohol is the sum

=  0.20×135 + 0.85× x mL.

It should be equal to the amount of the "pure" alcohol in the mixture, which is = 0.70× (x+135) ml.

So, your "pure alcohol" equation is,  

=  0.85× x + 0.20×135 = 0.70× (x+135)

Simplify and solve it for x:

0.85x + 0.20×135 = 0.70x + 0.70×135,

0.85x - 0.70x = 0.70×135 - 0.20×135,

0.15x = 67.5

x = 67.5/0.15

= 450mL.

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Answer:

C. It is hard to recreate the extremely high temperatures and pressures found inside stars.

Explanation:

Nuclear fusion occurs when atomic nuclei are forcefully combined to create a new atomic nuclei or subatomic particles. In nature, this process takes place in our Sun and other stars. Within stars, extremely high temperatures and pressures are achieved and cause nuclear fusion to occur. Humans have not yet been successful in recreating the environment necessary to mimic this process.

Answer:

Lowers the freezing point

Explanation:

Lowers the freezing temp

"Freezing point depression is a colligative property observed in solutions that results from the introduction of solute molecules to a solvent. The freezing points of solutions are all lower than that of the pure solvent and is directly proportional to the molality of the solute."

Answer: The temperature at which the solution freezes is lowered

Explanation:

For a second order reaction, if (A)^-1 is plotted vs. time is straight line with k= slope of the line,Plot the inverse of concentration of a reactnt verus time.

Second order reaction defined as chemical reactions which is the sum of the exponents in the rate of law of the chemical reaction is equal to two.The such reaction is written as the - r=k(A)2 or r= k(A)(B).

Second  order reaction is a type of reaction which is depend on the concentrations of one second order or two first order reactants.Reaction proceeds at rate proportional to the square of the product of the concentration of one reactant, or the product of the concentrations of two reactant.

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Partial Pressure for dinitrogen monoxide gas is 187 kPa

Partial Pressure for sulfur tetrafluoride gas is 33.4 kPa.

To calculate partial pressure first we need to calculate number of moles (n).

Mole (n) = mass/molar mass

Number of moles of dinitrogen monoxide gas= 17.7/44 gram per mole = 0.4023.

n=0.4023

Number of moles of sulfur tetrafluoride= 7.77/108.1 = 0.07188 moles.

Pressure × volume = number of moles × gas constant, R × temperature.

Pressure = n × R × T/ V.

For dinitrogen monoxide gas -

Partial Pressure = 0.4023 × 8.314 × 280.03 / 5 × 10^-3 = 187 kPa.

Partial pressure of dinitrogen monoxide gas = 187kPa.

For sulfur tetrafluoride gas-

Partial Pressure = 0.07188 × 8.314 ( × 280.03 / 5 × 10^-3) = 33.4 kPa.

Partial pressure of sulfur tetrafluoride = 33.4kPa.

So, Partial pressure of dinitrogen monoxide gas = 187kPa.

Partial pressure of sulfur tetrafluoride = 33.4kPa.

Disclaimer = This question is incomplete. Please find the full content below.

Question:

5.00L tank at 7.03°C is filled with 17.7g of dinitrogen monoxide gas and

7.77g of sulfur tetrafluoride gas

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