Sound waves reaching the olfactory mucosa do not elicit olfactory perception due to the ____________ not matching the type of stimulus of the receptor.

Answers

Answer 1

Answer:

Sound waves reaching the olfactory mucosa do not elicit olfactory perception due to the ___MODALITY_________ not matching the type of stimulus of the receptos

Explanation:

Because modality of sensation refers to what is perceived after the stimulus is effected eg the pressure modality is effected when the pressure receptors of the skin are stimulated so in this case sound will not elite olfactory sensation because the modality here is sound rather than smell


Related Questions

how to protect the ozone layer?

Answers

Answer:

[tex]\huge{\purple{\underline{\underline{\bf{\pink{Answer}}}}}}[/tex]

we have to protect ozone layer because it is like blanket for earth . It protects the earth form uv rays that are coming from the sun

we have to take some preventive. measures like

Use ecofriendly things that Doesnot contain (cfc) . It is the major reason for ozone Deplition

Effects of uv rays

Uv rays are very harmful . If it directly comes in contact with human it cause skin cancer , eyes irritation etc.

Hope it helps.

LAGOS PROVINCE 10
TEXT:
TOPIC
SPEAKER
DATE:
s
Sussend
5 Gorg
ve
Cand
care. The pre
density is haragin
cable?
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Answers

Answer:

Explanation:

what?

As astronaut visiting Planet X, you’re assigned to measure the free-fall acceleration. Getting out your meter stick and stopwatch, you time the fall of a heavy ball from several Heights. You data is as follows:
Height (m) Fall Time (s)
0.0 0.00
1.0 0.54
2.0 0.72
3.0 0.91
4.0 1.01
5.0 1.17
a.) Analyze these data to determine the free-fall acceleration on Planet X. Your analysis should involve fitting a straight lie to an appropriate graph. Place the graph here. (Hint Kinematics)
b.) Determine the uncertainty in the free-fall acceleration.

Answers

Answer:

g = (0.13 + - 0.05) m / s²

Explanation:

a) The equations of physics are valid in all inertial systems, therefore the kinematic relationships on this planet are the same as on Earth.

        y = v₀ t - ½ g t²

From the statement it follows that the body is released, so its initial velocity is zero

        y = 1/2 g t²

where we take the downward direction as positive

With this expression to make a linear graph we must graph t² vs y, see attached.  Observe that the controlled variable is the height, so this is the independent variable and must go on the x axis, the values ​​of the slope and point of cut can be obtained from this graph  by lineal regretion

           y ’= m x + b

           y ’= 0.2668 x + 0.00406

If we compare this equation of the line with the equation of free fall

          y ’= t2

          x = y

          m = 0.2668

          b = 0.00406

Since the value of b is very small, we can say that our assumption that the initial velocity is zero is correct.

Now we can compare the expressions of free fall and the equation of the line obtained

             y = ½ g t2

             y ’= m x

to be functionally equivalent

            x = 1 / m y '

now we can see the slope

          1 / m = ½ g

          g = 2 / m

          g = 2 / 0.2668

          g = 7.496 m / s²

b) the uncertainty of the acceleration is

          Δg = dg/dm   Δm

the uncertainty of m is given by the fit of the linear regression of the program Δm = 0.025

          dg / dm = 1 / 2m

           

           Δg = 1 /2m  Δm

           Δg = 1 / (2 0.2668) 0.025

           Δg = 0.047

The result of this exercise with the correct significant figures

          g = (0.13 + - 0.05) m / s²

A 550 lines/mm diffraction grating is illuminated by light of wavelength 500 nm . Part A How many bright fringes are seen on a 3.8-m-wide screen located 2.2 m behind the grating?

Answers

Answer:

7bright fringes

Explanation:

First we know that

Sinစ m,max= Mmax, x lambda/d

To find Mmax

Sin90° = Mmax x lambda/d = 1

So

Mmax= d/ lambda

= lambda= 500nm

d= 1/550mm

So

= 1.8 x10-6/500x 10^-9m

= 3.6

So m is approx 3

So 3 bright fringes above below and the central bright fringe itself making 7bright fringes

The north pole of a bar magnet points towards a thin circular coil of wire containing 40 turns. The magnet is moved away from the coil, so that the ux through one turn inside the coil decreases by ∆Φ = 0.3 T.m2 in a time ∆t = 0.2 s. What is the average EMF induced in the (whole) coil during this time interval? Viewed from the side opposite of the bar magnet (from the right), does the induced current run clockwise or counterclockwise? Explain briey. [2 p.]

Answers

Answer:

60 V

Current will flow anticlockwise from the right side of the magnet.

Explanation:

The number of turns on the coil = 40 turns

The magnetic flux changes by ∆Φ = 0.3 T.m^2

The time changes by ∆t = 0.2 s

The induced emf can be gotten as

E = N∆Φ/∆t

substituting values, we have

E = (40 x 0.3)/0.2 = 60 V

If we move the magnet away from the coil, then from Lenz law, the induced current on the coil will try to oppose the motion of the magnet by attracting the magnet towards the coil. For this to happen, the coil must possess the equivalent of a magnetic south pole. For the equivalent of a magnetic south pole, the current on the coil will flow in the clockwise direction when viewed from the left side of the magnet. This will appear as an anticlockwise direction, when viewed from the right side of the magnet.

1. Explain the difference between accuracy and precision 2. Name a statistical quantity that can be used to indicate an accuracy level. 3. Name a statistical quantity that can be used to indicate a precision level. 4. To what level of accuracy (1 cm, 0.1 cm, 0.01 cm. 0.001 cm) can the ruler used to measure the lengths of the pencil in the above example be read?

Answers

Answer:

Accuracy explains the closeness or nearness of a measured or studied quantity to the actual value while precision explains the ability of a measuring device to get the same measured value when measured repeatedly

2 Accuracy is determined by percentage error while precision is by taking the ratio of standard deviation with the individual measurements

3. The accuracy of the ruler is 0.001 cm because that's the least measurement it can take

You are comparing a reaction that produces a chemical change and one that produces a physical change. What evidence could you use to determine which type of change is occurring?

Answers

Answer:

''

Explanation:

A chemical change results from a chemical reaction, while a physical change is when matter changes forms but not chemical identity. Examples of chemical changes are burning, cooking, rusting, and rotting. Examples of physical changes are boiling, melting, freezing, and shredding. Often, physical changes can be undone, if energy is input.

Answer:

If the reaction is a chemical change, new substances with different properties and identities are formed. This may be indicated by the production of an odor, a change in color or energy, or the formation of a solid.

What replaced copper wires in long distance communicationas they are cheaper and less bulky than copper cables carrying the same information

Answers

Answer:

Optical Fiber

Explanation:

Optical fibers have replaced copper wire in long distance communication as they are cheaper and less bulky than copper cables carrying the same information. Optical Fibers transfer information from one place to another by sending pulses of infrared light signals. Light act as carrier waves.

What approximately is the percent uncertainty for a measurement given as 1.57 m^2?

Answers

Answer:

The value is   [tex]u =  0.64[/tex]%

Explanation:

From the question we are told that

  The measurement is  [tex]A =  1.57 \ m^2[/tex]

The  percent uncertainty is mathematically evaluated as

       [tex]u =  \frac{0.01 * 100}{A}[/tex]

Here 0.01 is uesd due to the fact that the value given is in three decimal places

     [tex]u =  0.64[/tex]%

     

The approximately percent uncertainty for the measurement is 0.64%.

The given parameters:

Area of the measurement, A = 1.57 m²

The uncertainty in the measurement of the area = ±0.01 m²

The approximately percent uncertainty for the measurement is calculated as follows;

[tex]Uncertainty = \frac{0.01}{1.57} \times 100\%\\\\Uncertainty = 0.64 \ \%[/tex]

Thus, the approximately percent uncertainty for the measurement is 0.64%.

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What voltage battery would you need to send 2.5A of current through a light bulb of resistance 3.6 ohm

Answers

Given :

Current flow light bulb = 2.5[tex]\sf{A}[/tex]

Resistance of light bulb = 3.6Ω

To Find :

We have to find voltage of battery[tex].[/tex]

Solution :

➠ As per ohm's law, current flow through a conductor is directly proportional to the applied potential difference.

➝ V ∝ I

V = I × R

Where, R is the resistance of conductor.

⇒ V = I × R

⇒ V = 2.5 × 3.6

V = 9 volt

A light plane must reach a speed of 33 m/s for takeoff. How long a runway is needed if the constant acceleration is 3.0 m/s2

Answers

Answer:

181.5 m

Explanation:

From the question,

Applying the equation of motion,

v² = u²+2as................. Equation 1

Where a = acceleration of the light plane, v = final velocity of the light plane, u = initial velocity of the light plane, s = length of the runway.

make s the subject of formula in equation 1

s = (v²-u²)/2a.............. Equation 2

Given: v = 33 m/s, u = 0 m/s(from rest), a = 3.0 m/s²

Substitute these values into equation 2

s = (33²-0²)/(2×3)

s = 1089/6

s = 181.5 m

A pure copper sphere has a radius of 0.935 in. How many copper atoms does it contain? [The volume of a sphere is (4>3)pr3 and the density of copper is 8.96 g>cm3.]

Answers

Answer:

47.68 x 10²³ or 4.768 x 10²⁴ copper atoms

Explanation:

Given:

Radius of the copper sphere (r) = 0.935 in

First convert the radius from inches to centimeters

1 in = 2.54cm

0.935in =  0.935 x 2.54cm = 2.3749cm

∴ r = 2.3749cm

Calculate the volume of the copper sphere as follows

Volume = [tex]\frac{4}{3}\pi r^{3}[/tex]          [substitute r = 2.3749cm and π = 22 / 7]

Volume = [tex]\frac{4}{3}(\frac{22}{7} ) (2.3749)^{3}[/tex]

Volume = 56.108cm³

From the volume and given density, calculate the mass of the copper sphere

mass = density x volume           [density = 8.96g/cm³]

mass = 8.96 x 56.108 = 502.73g

From known facts

1 mole of copper = 63.5g of copper = 6.022 x 10²³ copper atoms.

Then,

502.73 g of copper = [tex]\frac{502.73 * 6.022*10^{23}}{63.5}[/tex]  = 47.68 x 10²³ copper atoms

Therefore, the sphere contains 47.68 x 10²³ copper atoms

Answer:

=4.8*10^-24atoms

Explanation:

To find volume of a sphere

= 5.61*10^-5m³ x 8.96gx 100³m³

=502.7g

So we use density of copper to convert volume to mass so

1atm of cux( 1mol of cu/6.02Eatm of cu)*(63.54g of cu/1 mole of cu)

So = 1.055*10-22g cu

So

= 502.7/1.055*10-22g cu

=4.8*10^-24atoms

You wish to produce an emf of 41.0 mV using an inductor whose inductance is 13.0 H. You start with a current of 1.50 mA through the inductor and increase the current at a steady rate. What is the current through the inductor at the end of 2.60 s

Answers

Answer:

The current through the inductor at the end of 2.60s is 9.7 mA.

Explanation:

Given;

emf of the inductor, V = 41.0 mV

inductance of the inductor, L = 13 H

initial current in the inductor, I₀ = 1.5 mA

change in time, Δt = 2.6 s

The emf of the inductor is given by;

[tex]V = L\frac{di}{dt} \\\\V = \frac{L(I_1-I_o)}{dt} \\\\L(I_1-I_o) = V*dt\\\\I_1-I_o = \frac{V*dt}{L}\\\\I_1 = \frac{V*dt}{L} + I_o\\\\I_1 = \frac{41*10^{-3}*2.6}{13} +1.5*10^{-3}\\\\I_1 = 8.2*10^{-3} + 1.5*10^{-3}\\\\I_1 = 9.7 *10^{-3} \ A\\\\ I_1 = 9.7 \ mA[/tex]

Therefore, the current through the inductor at the end of 2.60 s is 9.7 mA.

How many electrons flow through a point in a wire in 7.00 s if there is a constant current of I = 4.35 A?

Answers

Answer:

1.90×10²⁰ Electrons

Explanation:

From the question,

Q = It.................... Equation 1

Where Q = charge flowing through the wire, I = current, t = time

Given: I = 4.35 A, t = 7.00 s

Substitute these values into equation 1

Q = 4.35(7.00)

Q = 30.45 C.

But,

1 electron contains 1.6×10⁻¹⁹ C

therefore,

30.45 C = 30.45/1.6×10⁻¹⁹  electrons

= 1.90×10²⁰ Electrons

2. The higher the temperature of water, the faster the egg will cook. What
is the dependent variable? *
A. the stove
B. the egg
C.temperature of water
D. the person stirring

Answers

Answer:

The dependent variable is the cook time of the egg

The higher the temperature of the water, the faster the egg will cook, then the dependent variable is the temperature of the water, therefore the correct answer is the option C

What is thermal energy?

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

Thermal energy can be produced with help of various means such as by burning fossil fuels, with the help of solar energy.

The correct direction for heat flow is from hot to cold because heat always moves naturally from a higher thermal potential to a lower thermal potential unless additional work is provided by an external machine.

Thus, The dependent variable is the water's temperature, and since the egg will cook more quickly at higher water temperatures, option C is the best choice.

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Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 9.0 km/h due east. Runner B is initially 5.0 km east of the flagpole and is running with a constant velocity of 8.0 km/h due west. What will be the distance of the two runners from the flagpole when their paths cross

Answers

Answer:

From the data we know that runner A and runner B are 11 km apart from the start because (6+5) km

So the runner from the east direction has distance as unknown km, rate= 9 k/h ; time= d/r=x/9 hr

So runner towards the west will be

distance = 11-x, rate= 8 k/h, time = d/r = (11-x)/8

So equating east and west time we have

x/9= (11-x)/8

8x=99-9x

17x=99

x=5.92 km

That is the distance covered by runner towards the east and he will meet the runner toward the west at

6-5.92=0.08 km west of the flagpole.

A well with vertical sides and water at the bottom resonates at 5.63 Hz and at no lower frequency. (The air-filled portion of the well acts as a tube with one closed end and one open end.) The air in the well has a density of 1.10 kg/m3 and a bulk modulus of 1.33 × 10^5 Pa. How far down in the well is the water surface?

Answers

Answer:

The  value  is  s =  15.4 \ m

Explanation:

From the question we are told that  

     The  frequency is  [tex]f =  5.63 \  Hz[/tex]

      The  density of air in the well is [tex]\sigma  =  1.33 *10^{5} \  Pa[/tex]

      The  Bulk modulus is  [tex]B =  1.33*10^{ 5} \  Pa[/tex]

Generally the distance of the water surface from the opening is mathematically represented as

      [tex]s =  \frac{1}{4 f }  *  \sqrt{\frac{B}{\rho } }[/tex]

=>    [tex]s =  \frac{1}{ 4 *  (5.63 )} \sqrt{\frac{1.33*10^{5}}{ 1.10} }[/tex]

=>   [tex]s =  15.4 \ m[/tex]

Light of wavelength 500 nm illuminates a round 0.50-mm diameter hole. A screen is placed 6.0 m behind the slit.. Find the width of the central maximum on the screen.
A) 6.0 mm.
B) 12 mm.
C) 260 mm.
D) 7.3 mm.
E) 15 mm.

Answers

Answer:

15mm

Explanation:

We know that for circular holes first dark spot is given by

sin စ = 1.22 λ/D

Also we know that at the same time

tan စ = r/L

So

r = L tanစ = 6 x tan( arcsin(1.22x 500 x10^9/0.50 x 10^ 3))

= 0.0073 m = 7.3 mm

However since the size is twice that so 14.6 mm which is approx 15mm

Water condenses on the side of a glass of ice water because the glass's temperature is below the dew point temperature.A. TrueB. False

Answers

Answer:

A. True

Explanation:

Water exists in the air in its gaseous form. If this gaseous water is cooled sufficiently enough below its dew point, it will condense into liquid water. This is what happens to the body of a glass filled with cold water. The glass's temperature drops the temperature of the air immediately around it, cooling it below dew point temperature. This causes water to condense on the body of the glass.

1. How does the de Broglie wavelength of an electron change if its momentum increases?
a. The de Broglie wavelength of the electron increases.
b. The de Broglie wavelength of the electron decreases.
c. The de Broglie wavelength of the electron is unchanged.
2. How does the de Broglie wavelength of an electron change if its kinetic energy decreases?
a. The de Broglie wavelength of the electron increases.
b. The de Broglie wavelength of the electron decreases.
c. The de Broglie wavelength of the electron is unchanged.

Answers

Answer:

1. The de Broglie wavelength of the electron decreases if its momentum increases.

b. The de Broglie wavelength of the electron decreases is the correct answer

2. The de Broglie wavelength of the electron increases as the kinetic energy decreases.

a. The de Broglie wavelength of the electron increases is the correct option

Explanation:

1. The relationship between de Broglie wavelength, λ and momentum ρ is given by

λ = h/ρ

Where λ is the de Broglie wavelength

h is Planck's constant and

ρ is the momentum

From the formula, the de Broglie wavelength, λ varies inversely with the momentum, ρ. Hence, as the de Broglie wavelength increases the momentum decreases; similarly, as the de Broglie wavelength decreases, the momentum increases.

For question 1, The de Broglie wavelength of the electron decreases if its momentum increases.

b. The de Broglie wavelength of the electron decreases is the correct answer

2. From

λ = h/ρ

ρ = mv

∴ λ = [tex]\frac{h}{mv}[/tex]

Where m is mass

and v i velocity

Recall that Kinetic energy K.E is given by

K.E = [tex]\frac{1}{2}mv^{2}[/tex]

[tex]E_{K} = \frac{1}{2}mv^{2}[/tex]

[tex]E_{K}[/tex] is the kinetic energy

∴ [tex]v = \sqrt{\frac{2E_{K} }{m} }[/tex]

Now we will evaluate [tex]mv[/tex]

[tex]mv = m \sqrt{\frac{2E_{K} }{m} }\\mv = \sqrt{m^{2} }.\sqrt{\frac{2E_{K} }{m} }\\ mv = \sqrt{\frac{2m^{2}E_{K} }{m} } \\mv = \sqrt{{2mE_{K} }[/tex]

∴ λ = [tex]\frac{h}{mv}[/tex] becomes

λ = [tex]\frac{h}{\sqrt{2mE_{K} } }[/tex]

This equation shows the relationship between the de Broglie wavelength and kinetic energy, [tex]E_{K}[/tex]

From the equation, de Broglie wavelength varies inversely with kinetic energy. That is, as the de Broglie wavelength increases the kinetic energy decreases; similarly, as the de Broglie wavelength decreases, the kinetic increases.

For question 2, The de Broglie wavelength of the electron increases as the kinetic energy decreases.

a. The de Broglie wavelength of the electron increases is the correct option

El tubo de entrada que suministra presión de aire para operar un gato hidráulico tiene 2 cm de diámetro. El pistón de salida es de 32 cm de diámetro. ¿Qué presión de aire se tendrá de aire se tendrá que usar para levantar un automóvil de 17,640 N?`

Answers

Answer:

P₁ = 219.3 Pa

Explanation:

This fluid mechanics problem, we can use that the pressure is distributed with the same value throughout the system, which is Pascal's principle.

Let's use the subinidce1 for the small diameter and the subscript 2 for the larger diameter.

              P₁ = P₂

pressure is defined by

             P = F / A

we subtitute

             F₁ / A₁ = F₂ / A₂

             F₁ = F₂ A₁ / A₂

the area in a circle is

             A = π r² = π d² / 4

we substitute

            F₁ = F₂ (d₁ / d₂)²

we calculate

           F₁ = 17640 (2/32)²

           F₁ = 68.9 N

Having the force to be applied we can find the air pressure on the small plunger

          P₁ = F₁ / A₁

          P₁ = F₁ 4 / π d₁²

let's calculate

          P₁ = 68.9 4 / (π 0.02²)

          P₁ = 219.3 Pa

Which number below equals 129000? * *

Answers

Answer:

0.1

Explanation:

A swimmer heads for the opposite bank of a river. Make a sketch showing the swimmer's two velocities and the resultant velocity. (Assume the river flows in the +x direction and the opposite bank is in the +y direction.)

Answers

Answer:

    v = √ (v₁² - vₓ²)

 θ = sin⁻¹ (vₓ / v₁)

Explanation:

This is a speed composition exercise in kinematics, in the adjoint we can see the swimmer with speed v₁ and the river with speed vₓ, the resulting speed is v

To find these values ​​we can use the Pythagorean theorem

           v₁² = v² + vₓ²

           v = √ (v₁² - vₓ²)

the direction the swimmer should take is

           sin θ = vₓ / v₁

           θ = sin⁻¹ (vₓ / v₁)

In experimental design: What are
the two groups?

Answers

Answer:

The correct answer is : a special type of experimental design where subject divides in two groups according their treatment setting.

Explanation:

A two group is a experimental design two groups are the two different groups of subjects divided by the researcher for comparing the data and result to establish relation in variables.

In normal case, one of the two groups one is a group of subjects who get treatment known as experiment or treatment group while other group is known as control group without treatment.

Thus, the correct answer is : a special type of experimental design where subject divides in two groups according their treatment setting.

a particular kind of experimental design in which the subjects are split into two groups based on the treatment environment. A two-group design is an experiment.

The researcher separated the participants into two groups and then compared the data and results to identify any relationships between the variables.

In a typical scenario, one of the two groups is made up of participants in an experiment or treatment group who receive care, while the other group is referred to as the control group who do not receive care.

Therefore, a particular kind of experimental design where subjects are divided into two groups according to their course of therapy.

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A car is traveling at a speed of 80 ft/s when the brakes are suddenly applied, causing a constant deceleration of 10 ft/s2. Determine the time required to stop the car and the distance traveled before stopping.

Answers

Answer:

Time taken = 8 second

Distance traveled = 320 ft

Explanation:

Given:

Initial velocity (u) = 80 ft/s

Acceleration (a) = (-)10 ft/s²

Final velocity (v) = 0 ft/s

Find:

Time taken

Distance traveled

Computation:

v = u + at

0 = 80 + (-10)(t)

t = 8 second

Time taken = 8 second

s = ut + (1/2)(a)(t)²

s = (80)(8) + (1/2)(-10)(8)²

s = 320 ft

Distance traveled = 320 ft

What is the magnitude of the force of a +25 microCoulomb charge exerts on a +2.5 miliCoulomb charge 28 cm away?

Answers

Answer:

7.175 N

Explanation:

From coulomb's law of electrostatics,

F = kQq/r²........................... Equation 1

Where F = magnitude of the force, M = first Charge, q = second Charge, r = distance between the charges and k = coulomb's constant

Given: Q = +25 micro-Coulomb = + 25×10⁻⁶ C, q = +2.5 micro-coulomb = +2.5×10⁻⁶ C, r = 28 cm = 0.28 m.

Constant: k = 9×10⁹ Nm²/C²

Substitute these values into equation 1

F = 9×10⁹(25×10⁻⁶)(2.5×10⁻⁶)/ 0.28²

F = 562.5×10⁻³/0.0784

F = 7.175 N

Some species of whales can dive to depths of 1 kilometer. What is the absolute pressure they 352 experience at this depth

Answers

Answer:

The whales experience pressures of about 9.87Mpa at this depth of 1km into the water.

Explanation:

The absolute pressure can be calculated using the formula: P Abs = P Guage + P Fluid.

This means that once the whales dive under the water, both the pressure from the atmosphere and the pressure from the water is acting on them.

The Guage pressure is 101325 Pa. This can be obtained from standard tables.

The fluid pressure at a depth of 1km (1000 m) can be obtained using the formula: [tex]P = \rho gh[/tex]

Where [tex]\rho[/tex] = density of water = 997 kg/m³

g = acceleration due to gravity = 9.8 m/s2

h = depth of dive = 1000m

[tex]P = 997 \times 9.8 \times 1000 = 9770600 Pa[/tex]

Therefore, Absolute pressure = 101325 Pa + 9770600 Pa = 9871925 Pa

The whales experience pressures of about 9.87Mpa at this depth of 1km

Fluid flows at 2.0 m/s through a pipe of diameter 3.0 cm. What is the volume flow rate of the fluid?

Answers

Answer:

The volume flow rate of the pipe is 1.41 x 10⁻³ m³/s

Explanation:

Given;

velocity of the fluid, v = 2.0 m/s

diameter of the pipe, d = 3.0 cm = 0.03 m

The volume flow rate is given by;

Q = Av

Where;

A is the area of the pipe

v is the velocity of the fluid

circular surface Area of the pipe is given by;

A = ¹/₄ πd²

A = ¹/₄ π(0.03)² = 7.07 x 10⁻⁴ m²

Q = (7.07 x 10⁻⁴)(2)

Q = 1.41 x 10⁻³ m³/s

Therefore, the  volume flow rate of the pipe is 1.41 x 10⁻³ m³/s

The planet Mercury takes 0.24 sidereal years to go around the sun. What is the distance from the center of Mercury to the center of the sun

Answers

Answer:

5.77×10¹⁰ m

Explanation:

From the question,

Applying

Kepler's third law

P² = d³...................... Equation 1

Where P = Planet's period, d = distance between the center of the planet and the sun.

make d the subject of the formula n equation 1

d = [tex]\sqrt[3]{P^{2} }[/tex].................. Equation 2

Given: P = 0.24 sidereal.

Substitute the value of P into equation 2

d = [tex]\sqrt[3]{0.24^{2} }[/tex]

d = 0.386 Au

d = 0.386×1.496×10¹¹

d = 5.77×10¹⁰ m

7: A 2 mA current passes through a 1.4 cm long solenoid producing a magnetic field of .162 G. How many turns are in the solenoid

Answers

Answer:

The number of turns is 64449395

Explanation:

The expression for the solenoid formula is stated below, and it is what we are going to use to solve for the number of turns

B= μ₀nl

where B= magnetic field

           μ₀= permeability , 4π × 10⁻⁷ Henry

           n= number of turns

            l= length of coil

Given data

current I=  2 mA

length L= 1.4 cm to meter we have 0.014

magnetic field B= 0.162 T

From the expression we can make n subject of formula we have

n=B/μ₀l

Substituting we have

n= 0.162/4π × 10⁻⁷*2*10^-3

n= 0.162/8π × 10^⁻10

n= 0.162/2.5136*10^-9          

n= 64449395

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