Step-by-step explanation:
2 cups of water used with 4 packs
therefore for 12 we use x cups of water
2:4
X :12
therefore 6'cups of water?
A graph is shown below: A graph is shown. The values on the x axis are 0, 2, 4, 6, 8, and 10. The values on the y axis are 0, 4, 8, 12, 16, and 20. Points are shown on ordered pairs 0, 16 and 2, 12 and 4, 8 and 6, 4 and 8, 0. These points are connected by a line. What is the equation of the line in slope-intercept form?
Answer:
Graph is image, and equation is from the work result below:
Step-by-step explanation:
Take two points find the slope and y-intercept:
Slope = -2
Y-intercept = (0,16)
Equation =
y = − 2 x + 16
check work for one point (to make sure equation works):
(2,12)
y = -2x + 16
12 = -2(2) + 16
12 = -4 + 16
12 = 12
The equation is correct: y = − 2 x + 16
Image below are the points given:
How would A = L + O be rewritten to solve for O?
Answer:
A - L = O
Step-by-step explanation:
A = L + O
Subtract L from each side
A-L = L + O - L
A - L = O
The way that the given formula A = L + O can be rewritten to solve for O is; O = A - L
How to change subject of formula?We are given the formula to find A as;
A = L + O
Now, to make O the subject of the formula, let us use subtraction property of equality to subtract L from both sides to get;
A - L = L + O - L
O = A - L
Thus, the way the formula can be rewritten to solve for O is;
O = A - L
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help help help help help help
Answer:
75 yards long and 90 yards wide.
Step-by-step explanation:
Let's first find the perimeter of the main rectangle:
100x2 + 65x2 =
330
_________________________________________
Next we need to find two numbers that match:
75 and 90
75x2 + 90x2 =
330
_________________________________________
75x90 is 6750 (More Area)
100x60 is 6500 (Less Area)
While walking in the country, you count 39 heads and 116 feet in a field of cows and chickens. How many of each animal are there?
Answer: 58
Step-by-step explanation:
its 58 because chickens have two feet each so divide 2 % 166 and its 58
because each chicken has 2 legs count the 2 legs up to 116 then u get ur answer
802.4 divided 1.7
Thankkkk u
The answer to this equation is 472.
Answer:
472
Step-by-step explanation:
First we make both numbers into wholes by moving the decimal point one place behind.Then divide normally.
8024 ÷ 17 = 472
I hope this helps :)
Alonso brings $21 to the market to buy eggs and avocados. He gets eggs that cost $2.50. Then, he notices
that the store only sells avocados in bags of 3 for $5. He wants to buy as many avocados as he can with his
remaining money.
Let B represent the number of bags of avocados that Alonso buys.
1) Which inequality describes this scenario?
Answer:
Step-by-step explanation:
The money Alonso has is $21 which he wants to use to buy eggs and Avocados. The eggs he bought costs $2.50. Therefore the money remaining after the egg is bought is $18.50 (21 - 2.50)
Each bag of avocado cost $5, therefore the number of bags that can be bought with $18.50 is:
Bags of Avocado = $18.50 / $5 = 3.7 = 3 (to the previous whole number).
This means that the maximum number of bags of Avocado that can be bought is 3 bags. It can be represented by the inequality:
Bags ≤ 3
Answer:
2.50 + 5B ≤ 21;
Step-by-step explanation:
Cost of eggs = $2.50
Cost of avocado = $5 (bag of 3)
Total budgeted amount = $21
Bags of avocado = B
Therefore :
(Cost of eggs + cost of avocado) ≤ total budgeted amount
($2.50 + $5(B)) ≤ 21
2.50 + 5B ≤ 21
5B ≤ 21 - 2.50
5B ≤ 18.50
B ≤ 18.50 / 5
B ≤ 3.7
Therefore the maximum number of bags can purchase is 3(whole number without exceeding $21)
Sammy the Sailor swears entirely too much. The following probability distribution shows the number of times Sammy swears per day and the corresponding probabilities:
# of swear words: 2 5 9 14 20
Probability: 0.01 0.09 0.30 0.40 0.20
In an effort to reduce his amount of swearing, Sammy places $1.00 in a jar every time he swears. Further, if at the end of the day he swears more than 10 times, he places an extra $2.00 in the jar per swear word over 10. If Sammy swears less than 5 times, he takes out $0.50 for each of his swear words.
A B C D E F G
1 # of swear word Probability
2 Cost per swear word $1.00 2 0.01
3 Extra cost per swear
word over 10 $2.00 5 0.09
4 Refund per swear word
less than 5 $0.50 9 0.3
5 14 0.4
6 20 0.2
7
8
9 # Regular Extra cost Refund Total
swear swear if over 10 if under money
words word swear 5 swear in the jar
cost words words for the
day
10
Based off the partial simulation spreadsheet above, answer the following questions:
A) What formula should go into cell C10 to calculate the Regular Swear word cost?
B3*B4 SUMPRODUCT(B2:B4, B10) B4*B10 SUM(B2:B4) B2*B10 B3*B2 B3*B10
B) What formula should go into cell D10 to calculate the Extra Swear word cost?
=IF(B10>10,(B10-10)*B3,0) =IF(B10>10,(10-B10)*B3,0) =(B10-10)*B3 =IF(B10>10,0,(B10-10)*B3) SUMPRODUCT(B10,B3) B10*B3
C) What formula should go into cell E10 to calculate the Refund amount?
B10*B4 =IF(B10>5,(B10-5)*B4,0) =IF(B10<5,0,B10*B4) =IF(B10<5,B10*B4,0) SUMPRODUCT(B10:B4) =IF(B10<5,(B10-5)*B4,0)
D) What formula should go into cell F10 to calculate the total money in the jar?
Full question attached:
Answer and explanation:
A) B2*B10: cell B2 and B10 have the values regular swear costs and number of swears respectively and we need to multiply these two values to get our answer
B) =IF(B10>10,(B10-10)*B3,0): Sam is supposed to pay an extra $2 for swear words over 10 and so we check if his swear words are above 10 and if they are we find out how many they are by subtracting 10 from them and then we multiply the value gotten by the cost for extra swear words($2)
C) =IF(B10<5,B10*B4,0): here we check if swear words are less than 5 and if they are we multiply number of swears words less than by 5 by the cost ($0.50)
D) F10=C10+D10+E10: to calculate total money in jar(F10), we simply add up regular cost(C10), extra cost(D10) and refund(E10)
If 1/2 of a loaf of brown bread costs R6,how much will 2 halves cost
Answer:
wdym R6
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
6*2
Let f(x)=x+8 and g(x)= x2-6x-7 find f(g2)
Answer:
-7.
Step-by-step explanation:
g(x) = x^2 - 6x - 7
g(2) = 2^2 - 6(2) - 7
= 4 - 12 - 7
= -8 - 7
= -15
f(x) = x + 8
f(-15) = (-15) + 8
= 8 - 15
= -7
Hope this helps!
Kaliska is jumping rope. The vertical height of the center of her rope off the ground R(t)R(t)R, left parenthesis, t, right parenthesis (in \text{cm}cmstart text, c, m, end text) as a function of time ttt (in seconds) can be modeled by a sinusoidal expression of the form a\cdot\cos(b\cdot t)+da⋅cos(b⋅t)+da, dot, cosine, left parenthesis, b, dot, t, right parenthesis, plus, d. At t=0t=0t, equals, 0, when she starts jumping, her rope is 0\text{ cm}0 cm0, start text, space, c, m, end text off the ground, which is the minimum. After \dfrac{\pi}{12} 12 π start fraction, pi, divided by, 12, end fraction seconds, it reaches a height of 60\text{ cm}60 cm60, start text, space, c, m, end text from the ground, which is half of its maximum height
Answer:
Step-by-step explanation:
Which graph best represents the equation –x + 2y = 4?
Answer:
C
Step-by-step explanation:
Convert the equation into slope intercept form : y=mx+b
2y=x+4
y=1/2x + 2
The m is the slope and the b is the y intercept
In this equation, the slope is 1/2 and the y intercept is 2
The only graph with y intercept 2 is C
Find the value of m.
L
R
A
3m +21 U
6m
O A. 14
ОВ. 7
Answer:
B
Step-by-step explanation:
Since LR=LA, RU=RA. 3m+21=6m, 3m=21, m=7
if Israel spends the most time on social media with an average of 11.1 and peru spends a total time of 8.3 how much more time does israel spend on social media than peru
Answer:
israel spends 2.8 more (units) than peru.
Step-by-step explanation:
11.1 - 8.3 = 2.8, so israel spends 2.8 (units), more on social media.
Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth.
3.6
5
9.4
13
Answer:
≈ 3.6
Step-by-step explanation:
Calculate the distance d using the distance formula
d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = (P(5, 1) and (x₂, y₂ ) = Q(3, 4)
d = [tex]\sqrt{(3-5)^2+(4-1)^2}[/tex]
= [tex]\sqrt{(-2)^2+3^2}[/tex]
= [tex]\sqrt{4+9}[/tex]
= [tex]\sqrt{13}[/tex] ≈ 3.6 ( to the nearest tenth )
Answer:
3.6
Step-by-step explanation:
Look above bru
Find the fourth roots of 16(cos 200° + i sin 200°).
Answer:
See below.
Step-by-step explanation:
To find roots of an equation, we use this formula:
[tex]z^{\frac{1}{n}}=r^{\frac{1}{n}}(cos(\frac{\theta}{n}+\frac{2k\pi}{n} )+\mathfrak{i}(sin(\frac{\theta}{n}+\frac{2k\pi}{n})),[/tex] where k = 0, 1, 2, 3... (n = root; equal to n - 1; dependent on the amount of roots needed - 0 is included).
In this case, n = 4.
Therefore, we adjust the polar equation we are given and modify it to be solved for the roots.
Part 2: Solving for root #1
To solve for root #1, make k = 0 and substitute all values into the equation. On the second step, convert the measure in degrees to the measure in radians by multiplying the degrees measurement by [tex]\frac{\pi}{180}[/tex] and simplify.
[tex]z^{\frac{1}{4}}=16^{\frac{1}{4}}(cos(\frac{200}{4}+\frac{2(0)\pi}{4}))+\mathfrak{i}(sin(\frac{200}{4}+\frac{2(0)\pi}{4}))[/tex]
[tex]z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{\pi}{4}))[/tex]
[tex]z^{\frac{1}{4}} = 2(sin(\frac{5\pi}{18}+\frac{\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{\pi}{4}))[/tex]
Root #1:
[tex]\large\boxed{z^\frac{1}{4}=2(cos(\frac{19\pi}{36}))+\mathfrack{i}(sin(\frac{19\pi}{38}))}[/tex]
Part 3: Solving for root #2
To solve for root #2, follow the same simplifying steps above but change k to k = 1.
[tex]z^{\frac{1}{4}}=16^{\frac{1}{4}}(cos(\frac{200}{4}+\frac{2(1)\pi}{4}))+\mathfrak{i}(sin(\frac{200}{4}+\frac{2(1)\pi}{4}))[/tex]
[tex]z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{2\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{2\pi}{4}))\\[/tex]
[tex]z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{\pi}{2}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{\pi}{2}))\\[/tex]
Root #2:
[tex]\large\boxed{z^{\frac{1}{4}}=2(cos(\frac{7\pi}{9}))+\mathfrak{i}(sin(\frac{7\pi}{9}))}[/tex]
Part 4: Solving for root #3
To solve for root #3, follow the same simplifying steps above but change k to k = 2.
[tex]z^{\frac{1}{4}}=16^{\frac{1}{4}}(cos(\frac{200}{4}+\frac{2(2)\pi}{4}))+\mathfrak{i}(sin(\frac{200}{4}+\frac{2(2)\pi}{4}))[/tex]
[tex]z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{4\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{4\pi}{4}))\\[/tex]
[tex]z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\pi))+\mathfrak{i}(sin(\frac{5\pi}{18}+\pi))\\[/tex]
Root #3:
[tex]\large\boxed{z^{\frac{1}{4}}=2(cos(\frac{23\pi}{18}))+\mathfrak{i}(sin(\frac{23\pi}{18}))}[/tex]
Part 4: Solving for root #4
To solve for root #4, follow the same simplifying steps above but change k to k = 3.
[tex]z^{\frac{1}{4}}=16^{\frac{1}{4}}(cos(\frac{200}{4}+\frac{2(3)\pi}{4}))+\mathfrak{i}(sin(\frac{200}{4}+\frac{2(3)\pi}{4}))[/tex]
[tex]z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{6\pi}{4}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{6\pi}{4}))\\[/tex]
[tex]z^{\frac{1}{4}}=2(cos(\frac{5\pi}{18}+\frac{3\pi}{2}))+\mathfrak{i}(sin(\frac{5\pi}{18}+\frac{3\pi}{2}))\\[/tex]
Root #4:
[tex]\large\boxed{z^{\frac{1}{4}}=2(cos(\frac{16\pi}{9}))+\mathfrak{i}(sin(\frac{16\pi}{19}))}[/tex]
The fourth roots of 16(cos 200° + i(sin 200°) are listed above.
At a baby shower, 15 guests are in attendance and 4 of them are randomly selected to receive a door prize. If all 4 prizes are identical, in how many ways can the prizes be awarded?
Answer:
1365
Step-by-step explanation:
We figure out combinations using this formula: n!
r!(n-r)!
n=15
r=4
So n!= 15x14x13x12x11x0x9x8x7x6x5x4x3x2x1
r! = 4x3x2x1 times 15-4!, which is 11! = 11x10x9x8x7x6x5x4x3x2x1
Put this together and you have 15x14x13x12/4x3x2x1=
There are 1365 different ways to award the 4 door prizes to 4 guests from a group of 15 guests.
What are the Combinations?Combinations are the procedures used in mathematics to pick k things from n different items without replacement.
The following formula computes the combinations of k items from n:
(n, k) = n! / k!×(n-k)!
The number of ways to award the 4 door prizes to 4 guests out of a group of 15 guests is a combinatorial problem that can be calculated using the formula.
Here, n = 15 (the total number of guests) and k = 4 (the number of prizes to be awarded).
So, the number of ways to award the prizes is:
C(15, 4) = 15! / (4! (15 - 4)!)
= 15! / (4! 11!)
= 15 x 14 x 13 x 12 / (4 x 3 x 2 x 1)
= 1365.
Therefore, there are 1365 different ways to award the 4 door prizes to 4 guests from a group of 15 guests.
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The acute angle of the right angle triangle are in the ratio of 4:5
Answer:
Since the triangle is a right angled triangle, one of the angles is 90°. In the right angled triangle, the acute angles are in the ratio 4:5. Let the measures of the acute angles of the triangle in degrees be 4k and 5k, where k is a constant.
Step-by-step explanation:
hope it helps.
Answer:
40and50
Step-by-step explanation:
let the acute angles be 4x and 5x then,
4x+5x+90=180 [sum of all angles of a right angled triangle]
or,9x=180-90
or,x=90/9
x=10
4x=4×10=40
5x=5×10=50
Find the measure of a.
A. 60
B. 57
C. 40
D. 80
Answer:
Option (C)
Step-by-step explanation:
Since angle 'a' is the inscribed angle of the given triangle
Therefore, angle measure of the intercepted arc will be equal to the double of the inscribed angle.
x = 2a ⇒ a = [tex]\frac{x}{2}[/tex]
By the tangent-chord theorem,
"Angle between a chord and tangent measure the half of the angle measure of intercepted minor arc"
[tex]\frac{x}{2}[/tex] = 40°
Therefore, a = [tex]\frac{x}{2}[/tex] = 40°
Option (C) will be the answer.
Solve for
x. Round to the nearest tenth of a degree, if necessary.
Answer:
[tex]\displaystyle x \approx 30.8[/tex]
Step-by-step explanation:
Note that the figure is a right triangle, and that we are given the length of the side adjacent to x and the hypotenuse of the triangle.
Therefore, we can use the cosine ratio. Recall that:
[tex]\displaystyle \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}}[/tex]
The adjacent side is 8.5 and the hypotenuse is 9.9. Therefore:
[tex]\displaystyle \cos x = \frac{8.5}{9.9}[/tex]
We can take the inverse cosine of both sides:
[tex]\displaystyle x = \cos^{-1} \frac{8.5}{9.9}[/tex]
Use a calculator. Hence:
[tex]\displaystyle x \approx 30.8[/tex]
A computer parts company wants to make a rectangular memory board that has a perimeter of 14 cm and a diagonal of length 5 cm. What are the dimensions of the board?
Answer:
A computer parts company wants to make a rectangular memory board that has a perimeter of 28 centimeters and a diagonal length of 10 centimeters. Find the dimensions of the board. Consider the length to be the longer side.: Call the two sides L & W: the perimeter 2L + 2W = 28 Simplify, divide by 2 L + W = 14 L = (14-W); use this form for substitution
Step-by-step explanation:
==========================================================
Explanation:
x = width
y = length
both x and y are positive real numbers, and the units of which are in cm.
The perimeter of any rectangle is found by saying
P = 2*(length+width)
P = 2*(x+y)
Plugging in P = 14 leads us to
P = 2*(x+y)
14 = 2*(x+y)
14/2 = x+y
7 = x+y
Solve for one of the variables. Let's say we solve for y. That should get us y = 7-x which we'll use a bit later.
--------------
Notice how the diagonal forms two identical right triangles. The legs of which are x and y as defined earlier. The hypotenuse is 5, which is the diagonal length.
Use the pythagorean theorem to help solve for x
a^2 + b^2 = c^2
x^2 + y^2 = 5^2
x^2 + (7-x)^2 = 25 ... plug in y = 7-x
x^2 + 49 - 14x + x^2 = 25 ... use FOIL rule
2x^2-14x+49 = 25
2x^2-14x+49-25 = 0
2x^2-14x+24 = 0
2(x^2-7x+12) = 0
x^2-7x+12 = 0
(x-3)(x-4) = 0
x-3 = 0 or x-4 = 0
x = 3 or x = 4
If x = 3, then y = 7-x = 7-3 = 4
If x = 4, then y = 7-x = 7-4 = 3
We have this symmetry going on. If x is one of 3 or 4, then y is the other of those values. Because x = 3 and y = 4, or vice versa, this means we have a 3-4-5 right triangle (well to be fair we have two identical copies of such a triangle to form the rectangle).
Therefore, the dimensions of the rectangular board is 3 cm by 4 cm. The order doesn't matter so you could easily say "4 cm by 3 cm" to mean the same thing.
--------------
Check:
P = perimeter
P = 2*(length+width)
P = 2*(x+y)
P = 2*(3+4)
P = 2*7
P = 14
That helps confirm the answer.
Jim is designing a seesaw for a children's park. The seesaw should make an angle of 30° with the ground, and the maximum height to which it should rise is 2 meters, as shown below:
A seesaw is shown with one end on the ground and the other in the air. The seesaw makes an angle of 30 degrees with the ground. The height of the seesaw from the ground, at the other end, is labeled 2 meters.
What is the maximum length of the seesaw?
3 meters
3.5 meter
4 meters
4.5 meters
You are giving the angle and opposite leg.
Using the law of sines:
Sin(angle) = opposite leg / hypotenuse
Sin(30) = 2/ hypotenuse
Hypotenuse = 2/sin(30)
Hypotenuse = 4 meters
The maximum length of the seesaw is : (C). 4 meters
Meaning of Maximum lengthMaximum length can be defined as the total distance between two point in consideration.
Maximum length can also be said to be the total sum of all the length along a distance.
In the case above, the hypotenuse side is the maximum length.
In conclusion, The maximum length of the seesaw is : 4 meters
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When trying to find the best deals for items, you should what?
Answer:
Try to find the unit rate for bulk items that you have for these and then compare all of the prices together.
Ever since Renata moved to her new home, she's been keeping track of the height of the tree outside her window. H represents the height of the tree (in centimeters), t years since Renata moved in. H = 210 + 33t How fast does the tree grow? ANSWER centimeters per year.
Answer:
The tree grows 33cm per year
Step-by-step explanation:
Here in this question, we are interested in knowing how fast the growth of the tree is.
This is easily obtainable from the equation for the height of the tree.
Mathematically, the equation is given as;
H = 210 + 33t
Interpreting this, we can have 210 as the original height of the tree when Renata moved in, while the term 33 represents the growth per year.
So we can say the tree adds a height of 33 cm each year and this translates to the yearly growth of the tree
What is the slope of the line joining (5.9) and (-2, 9)?
0-1
0-
00
O No slope
Answer:
0
Step-by-step explanation:
The slope of the line is m=(9-9)/(-2-5)=0/-7=0
. Tachycardia means ...................heart rate a) fast b) slow c) irregular d) arrhythmic
Hi,
Answer:
Tachycardia is a fast heart rate
2. The volume of a cube is 8 cm", find the length of one of its sides
Answer:
Step-by-step explanation:
The question has an error. Volume is expressed in cubic units. You probably mean cm³ .
Volume = 8 cm³
Length of each edge = ∛8 = 2 cm
Answer:
2cm
Step-by-step explanation:
Volume of cube=a^3 cubic units
8=a^3
a=cuberoot of 8
which is 2
不
Which line is horizontal?
O y=2
O y = 2x
O y = -2x
o y=x
Answer:
y=2
Step-by-step explanation:
A horizontal line has a slope of zero so the x term is zero
y = mx+b
y = b
y must equal a constant
If f(x)=ax+b and f(2)=1 and f(-3)=11, what is the value of A?
Answer:
a = -2
Step-by-step explanation:
f(x)=ax+b
f(2)=1
f(-3)=11
f(2) = 1 means 2a+b =1
f(-3)=11 means -3a + b = 11
Subtracting the two equations
-(-3a +b =11) becomes 3a -b = -11 so we can add
2a+b =1
3a - b = -11
----------------------
5a = -10
Divide by 5
5a/5 = -10/5
a=-2
Find f(3) given f(x) = -3x3 + 2x2 + 24
Answer:
-39
Step-by-step explanation:
Randy is walking home from school. According to the diagram above, what is his total distance from school to home? Show your work and include units. If he had a jet pack, would you use distance or displacement? Why?
Answer:
if he needs to walk, we can see that between the street and his house he must walk 4 times a distance of 0.5km, so this is a total of 4¨*0.5km = 2km.
Now he has a jet-pack, he can ignore the buildings and just travel in the shorter path, so we can draw a triangle rectangle, in such a way that the hypotenuse of this triangle is the distance between the home and the school.
One of the cathetus is the vertical distance, in this case, is 1km, and the other one is the horizontal distance, also 1km.
So the actual distance is given by the Pythagorean's theorem:
A^2 + B^2 = H^2
Where A and B are the cathetus, and H is the hypotenuse, then:
H^2 = 1km^2 + 1km^2
H = (√2)km = 1.41km.
Now, in the case that he has a jet-pack, he can actually go to the school using this hypotenuse line as his path, so in this case the distance and the displacement would be the same.
Distance: "how much ground an object has covered"
Displacement: "Difference between the final position and the initial position"
When he walks, the distance is 2km, but the displacement is 1.41km
When he uses the jet-pack, both the distance and the displacement are 1.41km
Answer and Step-by-step explanation:
The first thing is we can see in the image, when he walks, that between the house and his school he has to walk four times a distance of 0.5 km. The result of this is a total of 4¨*0.5 km = 2 km. The second thing is that he must walk 2 kilometers. On the other hand, if he has a jetpack, he can simply take the shorter path by ignoring all the buildings. This idea is where we can draw a triangular rectangle on the map in a way so that the hypotenuse of the triangle is the distance between the school and the home. As for the Catheti, it is a vertical distance which in this case is two blocks of 0.5 km. The result is that these catheti have a length of 2*0.5 km = 1 km. The other is the distance of the horizontal line, which is 1 km. The absolute distance of this path is given by Pythagorean's theorem, which is A^2 + B^2 = H^2. Here, A and B are the cathetus, and H is the hypotenuse, then, H^2 = 1 km^2 + 1 km^2. As well, H = (√2)km = 1.41 km. Currently, in the situation where he has a jetpack, he can literally fly to the school utilizing this hypotenuse line for the path he would need to follow. For this specific situation, the displacement, and the distance would be the exact same. The reason for this is that the definitions of displacement and distance are displacement is the difference between the final position and the initial position and distance is how much area an item has covered. Also, when he walks, the distance is 2 km and the displacement is 1.41 km. Also, when he utilizes the jet pack, the distance is equal to the displacement. Both of these are 1.41 km.