Three is subtracted from a number, and then the difference is divided by eleven. The result is twelve. What is the
number?

Answer:

The equation of the perpendicular line (PR) to line PQ is; y = -0.5x - 1.5

Step-by-step explanation:

The line is perpendicular to line adjoined by points P(-3,0) and Q(0,6)

The slope of line PQ is;

Slope = change in y ÷ change in x = [tex]\frac{6 - 0}{0 -- 3}[/tex] = 2

The product of slopes of two perpendicular lines = -1

Hence the slope of line PR = -1 ÷ slope of line PQ = -1/2

Taking another point (x,y) and point P(-3,0) the equation of line PR is;

Slope = [tex]\frac{y - 0}{x - -3} = -\frac{1}{2}[/tex]

Cross-multiplying gives;

2y = -x - 3 , y = -x/2 - 3/2 , y = -0.5x - 1.5

Answer/Step-by-step explanation:

a. The sides of ∆ABC can be labelled as follows, taking θ as the reference point.

Adjacent = side AB

Opposite = side BC

Hypotenuse = side AC

b. I. "<B is an acute angle" => FALSE. It is a right angle (90°)

II. "The side opposite to <C is BC" => FALSE. The side opposite to <C is AB.

III. The side adjacent to <A is AB => TRUE

IV. The side opposite to <B is not the longest. => FALSE. It is the hypotenuse and the longest side.

c. Cos θ = [tex] \frac{adjacent}{hypotenuse} = \frac{AB}{AC} [/tex]

Tan θ = [tex] \frac{opposite}{adjacent} = \frac{BC}{AB} [/tex]

d. Sin C = [tex] \frac{opp}{hypo} = \frac{AB}{AC} [/tex]

Cos C = [tex] \frac{adjacent}{hypotenuse} = \frac{BC}{AC} [/tex]

Tan C = [tex] \frac{opp}{adjacent} = \frac{AB}{BC} [/tex]

Answer:

Clarissa will take 10 hours by herself

Step-by-step explanation:

Let s = time for shawna

s-5 = time for clarissa

The formula for determining the time is

1/a + 1/b = 1/c  where a and b are the times alone and c is the time together

1/s + 1/(s-5) = 1/6

Multiply each side by 6s(s-5) to clear the fractions

6s(s-5) ( 1/s + 1/(s-5)) = 1/6 *6s(s-5)

Distribute

6(s-5) + 6s = s(s-5)

Distribute

6s -30 +6s = s^2 -5s

Combine like terms

12s -30 = s^2 -5s

Move everything to the right

0 = s^2 -5s -12s +30

0 = s^2 -17s +30

Factor

0 = ( s-15) (s-2)

Using the zero product property

s-15 =0   s-2 =0

s =15     s=2 ( This is not a reasonable answer since it is less than the time together)

s=15

s-5 = 10

Clarissa will take 10 hours by herself

Answer:

-26!!!! :))))

Step-by-step explanation:

Answer:

22, 24, 26, 28, 30

Step-by-step explanation:

If the sum of 5 numbers is 130, that means the average of these numbers is 26.

If it is the average then it is the middle, or the third number. The two numbers before it would then be 22 and 24 by subtracting twos, and the two numbers after it would be 28 and 30 by adding twos.

22, 24, 26, 28, 30

Answer:

22,24,26,28,30

Step-by-step explanation:

I call the unknown number x

I write consecutive numbers in terms of x.

x+ (x+2) + (x+4) + (x+6) + (x+8) = 130

5x + 20 = 130

5x = (130 - 20)

5x = 110

x = 22 = smallest even number

x + 2 = 24 = second even number

x +4 = 26

x + 6 = 28

x + 8 = 30

Answer:

(-5) ^ 11

Step-by-step explanation:

(-5) ^5 / (-5) ^ -6

We know that a^ b / a^ c = a^ ( b-c)

(-5)^ (5 - -6)

(-5) ^ (5+6)

(-5) ^ 11

Answer:

-5

Step-by-step explanation:

Mathaway

Answer:

your answer is

2 X l+b

2 X 6x + 3x

8x + 10...

Answer: (-1, -2)

Step-by-step explanation:

so at first you have (1, 2)

then you were asked to reflect about y=x which is (x, y) = (y, -x)

(1, 2) = (2, -1)

then followed by y=-x which is (x, y) = (-y, -x)

(2, -1) = (-1, -2)

I hope this helps!

Answer:

[tex]\boxed{=2x(x^2+6y^2)}[/tex]

Step-by-step explanation:

Remember:

[tex](a+b)(a-b)=a^2-b^2\\\\a^3+b^3=(a+b)(a^2-ab+b^2)\\\\\\(x+2y)^3+(x-2y)^3\\\\=(x+2y+x-2y)((x+2y)^2-(x+2y)(x-2y)+(x-2y)^2)\\\\=2x(x^2+4xy+4y^2-(x^2-4y^2)+x^2-4xy+4y^2)\\\\=2x(x^2+6y^2)\\[/tex]

Answer:

[tex]\frac{1}{20}[/tex] of a second

Step-by-step explanation:

We can convert each time into fractions.

11.74 is the same thing as [tex]11 \frac{74}{100}[/tex]

and 11.69 is the same thing as [tex]11 \frac{69}{100}[/tex].

We know that 11 - 11 = 0, so we can focus on the fractions for now.

Let's subtract [tex]\frac{69}{100}[/tex] from [tex]\frac{74}{100}[/tex].

[tex]\frac{74}{100} - \frac{69}{100} = \frac{5}{100}[/tex].

We can now simplify [tex]\frac{5}{100}[/tex] by dividing both the numerator and denominator by 5.

[tex]\frac{5\div5}{100\div5} = \frac{1}{20}[/tex].

Hope this helped!

Here Mass is constant

Using Newtons s law

[tex]\\ \sf \longmapsto F=ma[/tex]

[tex]\\ \sf \longmapsto \dfrac{F}{a}=m[/tex]

[tex]\\ \sf \longmapsto \dfrac{F_1}{a_1}=\dfrac{F_2}{a_2}[/tex]

[tex]\\ \sf \longmapsto \dfrac{8}{4}=\dfrac{F_2}{3}[/tex]

[tex]\\ \sf \longmapsto F_2=\dfrac{24}{4}[/tex]

[tex]\\ \sf \longmapsto F_2=6N[/tex]

Answer:

F = 6N

Step-by-step explanation:

Equation

F = ka

F - force

k - constant of proportionality

a - acceleration

Step 1 - find k  

8N=k*4m/s^2

k=2

Step 2 - find F

F=2*3m/s^s

F=6

Answer:

36

Step-by-step explanation:

6^2

This is 6 multiplied by itself 2 times

6*6

36

Answer:

a ≥ -1/3

Step-by-step explanation:

The square root must be greater than or equal to zero

sqrt(1+3a /25) ≥ 0

Square each side

(1+3a)/25≥ 0

Multiply each side by 25

1+3a≥0

Subtract 1

3a ≥ -1

Divide by 3

a ≥ -1/3

Answer:

12,490

+ 3,941

16431

Step-by-step explanation:

Answer:

[tex]\large \boxed{\sf \bf \ \ x^2-6x+45 \ \ }[/tex]

Step-by-step explanation:

Hello, please consider the following.

You need to develop the expression.

[tex]y=(x-3)^2+36\\\\=x^2-2 * 3 * x +3^2+36\\\\=x^2-6x+9+36\\\\=x^2-6x+45[/tex]

Thank you.

Answer:

D

Step-by-step explanation:

Answer:

a. -2

b. s = 2 and y = -5

c. (2.5, -9)

d. -7x - 2

Step-by-step explanation:

a. In the image, I have used rise over run, which is -8/4 or -2.

b. slope formula is mx + b = y, where m is slope and b is the y-intercept. In the equation 2x - 5y = -10, 2 is the slope and -5 is the y-intercept.

c. Plug in all given numbers into an equation and the ones you do not have will be in the points you need it to be. Once you graph the equation you will receive (2.5, -9).

d. y = mx + b

   5 = (-7)(-1) + b

   5 = 7 + b

   -2 = b

y = -7x - 2  

Answer:

perimeter=40m

Step-by-step explanation:

PERIMETER=(AREA ROOT)*4

                   =10*4=40m

Answer:

(0,-3)

Step-by-step explanation:

2x-y = 3

x+2y = -6

Multiply the first equation by 2 so we can eliminate y

2(2x-y =3)

4x -2y = 6

Add this to the second equation

4x -2y = 6

x+2y = -6

-----------------

5x +0y = 0

x = 0

Now find t

x+2y = -6

0+2y = -6

2y =-6

Divide by 2

y = -3

Answer:

Step-by-step explanation:

Let's try to eliminate y.

First we multiply the first equation by 2,

4x - 2y = 6

x + 2y = -6

Then we add them together

5x = 0

x = 0

Now we plug x into the first equation,

4(0) - 2y = 6

-2y = 6

y= -3

Now we plug x into the second equation,

0 + 2y = -6

2y = -6

y = -3

So our answer is,

(0,-3)

Answer/Step-by-step explanation:

A. [tex] 4b + 3b [/tex]

Using b = 2

[tex] 4(2) + 3(2) = 8 + 6 = 14 [/tex]

Using b = 4

[tex] 4(4) + 3(4) = 16 + 12 = 28 [/tex]

Using b = 6

[tex] 4(6) + 3(6) = 24 + 18 = 42 [/tex]

Using b = 8

[tex] 4(8) + 3(8) = 32 + 24 = 56 [/tex]

Using b = 10

[tex] 4(10) + 3(10) = 40 + 30 = 70 [/tex]

Using b = 2

[tex] 4(12) + 3(12) = 48 + 36 = 84 [/tex]

B. [tex] 3(x - 2) [/tex]

Using x = 3

[tex] 3(3 - 2) = 3(1) = 3 [/tex]

Using x = 5

[tex] 3(5 - 2) = 3(3) = 9 [/tex]

Using x = 7

[tex] 3(7 - 2) = 3(5) = 15 [/tex]

Using x = 9

[tex] 3(9 - 2) = 3(7) = 21 [/tex]

Using x = 11

[tex] 3(11 - 2) = 3(9) = 27 [/tex]

Using x = 13

[tex] 3(13 - 2) = 3(11) = 33 [/tex]

C. [tex] 5(4a - 1) [/tex]

Using a = 2

[tex] 5(4(2) - 1) = 5(8 - 1) = 5(7) = 35 [/tex]

Using a = 3

[tex] 5(4(3) - 1) = 5(12 - 1) = 5(11) = 55 [/tex]

Using a = 4

[tex] 5(4(4) - 1) = 5(16 - 1) = 5(15) = 75 [/tex]

Using a = 5

[tex] 5(4(5) - 1) = 5(20 - 1) = 5(19) = 95 [/tex]

Using a = 6

[tex] 5(4(6) - 1) = 5(24 - 1) = 5(23) = 115 [/tex]

Using a = 7

[tex] 5(4(7) - 1) = 5(28 - 1) = 5(27) = 135 [/tex]

D. [tex] 6y - 2y + 4 [/tex]

Using y = 2

[tex] 6(2) - 2(2) + 4 = 12 - 4 + 4 = 12 [/tex]

Using y = 3

[tex] 6(3) - 2(3) + 4 = 18 - 6 + 4 = 18 - 2 = 16 [/tex]

Using y = 5

[tex] 6(5) - 2(5) + 4 = 30 - 10 + 4 = 30 - 6 = 24 [/tex]

Using y = 10

[tex] 6(10) - 2(10) + 4 = 60 - 20 + 4 = 60 - 16 = 44 [/tex]

Using y = 8

[tex] 6(8) - 2(8) + 4 = 48 - 16 + 4 = 48 - 12 = 36 [/tex]

Using y = 6

[tex] 6(6) - 2(6) + 4 = 36 - 12 + 4 = 36 - 8 = 28 [/tex]

The value of the function of the surface area of a sphere when the radius is 11.5 cm is approximately 1661.9 cm²

The process of arriving at the above value is as follows;

The known parameter

The function of the radius representing the surface area of a sphere is, f(r) = A = 4·π·r²

The radius of the basketball, r = 11.5 cm

Required;

To evaluate the function, f(r), for the basketball

Method;

The process of evaluating a function, is to find the value of the function at a given value of the input or independent variable of the function

The input variable is the variable that determines the output value of the function, it is the variable which is the function is about

In the question, the function given is dependent on the radius, r

Therefore;

When r = 11.5 cm (the radius of the basketball), from the function, the surface area of the basketball, A = f(11.5) = 4 × π × (11.5 cm)² ≈ 1661.9 cm²

Therefore;

The evaluation of the function which is the value of the function, f(r) = A,

when the radius, r, is 11.5 cm, which is the surface area of the spherical

basketball, is A ≈ 1661.9 cm²

Learn more about evaluation of functions here;

https://brainly.com/question/11743679

Answer:

AA Postulate

Step-by-step explanation:

The bottom lines are parallel. In this case they are also congruent. Combined with the top angle this makes in AA postulate

Answer:

The length of the bridge is 72 cm

Step-by-step explanation:

In order to find the length of bridge, we have to apply distance formula which is D = S × T where S represents speed and T is time :

[tex]d = s \times t[/tex]

[tex]let \: s = 18,t = 4[/tex]

[tex]d = 18 \times 4[/tex]

[tex]d = 72 \: cm[/tex]

The length of the bridge is 11 cm .

When an object moves in a straight line at a steady speed, we can calculate its speed if we know how far it travels and how long it takes. This equation shows the relationship between speed, distance traveled and time taken:

Speed is distance divided by the time taken.

For example, a car travels 30 kilometers in 2 hours.

Its speed is 30 ÷ 2 = 15km/hr.

Formula used :

Distance  = Speed * Time

Time = Distance / Speed

Speed = Distance / Time

According to the question

Length of train = 61 cm

Speed of train = 18 cm/s

Time taken to cross the bridge = 4 seconds

In this length traveled by train = length of train + Length of bridge

( as time given is to completely cross platform )

Therefore,

length traveled by train = 61 + Length of bridge

formula used

Distance  = Speed * Time

61 + Length of bridge =  18 * 4

61 + Length of bridge = 72

Length of bridge  = 72 - 61

Length of bridge  = 11 cm

Hence, the length of the bridge is 11 cm .

To know more about relationship between distance time and speed  here :

https://brainly.com/question/26754391

# SPJ2

Answer:

12.5

Step-by-step explanation:

2.5 * 5 = 12.5

Answer:

658ft

Step-by-step explanation:

you first have to calculate the angle next to that 28°angle,if you look at the two they form a 90° so to find that angle you have to subtract 90-28=62

the x is the opposite of angle 62 and the 350 si the adjacent so you can use the tan ratio to find the answer

tan62=opposite/adjacent

tan62=y/350

y=tan62×350

=658ft

I hope this helps

6 cm from what im seeing

Answer: 7 cm

Step-by-step explanation:

Answer:

500×4 =2400 I think would help u

Step-by-step explanation:

Total Surface Area of original cylinder

= (2×(22/7)×9)(9+24)

=18×22/7×33

=1,866.8

Total Surface Area of new cylinder

=(2×(22/7)×9/3)(9/3+24/3)

=(2×(22/7)×3)(3+8)

=6×22/7×11

=207.4

Change or Ratio of org. cylinder to new cylinder

=1,866.8/207.4

=9.0009

Answer:

The expression (-root3·a - a)², can be simplified into the form a² × (4 + 2·√3)

Step-by-step explanation:

The given expression can be written as follows;

(-root3·a - a)² = (-√3·a - a)²

Which can be expanded to give;

(-√3·a - a) × (-√3·a - a) = 3·a² + 2·√3·a² +a²

We collect like terms to get;

3·a² + 2·√3·a² +a² =  3·a² +a²+ 2·√3·a² = 4·a² + 2·√3·a²

We factorize out the common coefficients of the terms  to have;

4·a² + 2·√3·a² = a² × (4 + 2·√3)

Which gives the initial expression (-root3·a - a)², to presented in the form a² × (4 + 2·√3).