what are the like terms of the expression.
3x+8x+y+x+8

Answers

Answer 1

Answer:

the like terms are:

3x+8x+x+y+8

12x+y+8

Answer 2

Answer:

The like terms are

3x, 8x, x

Step-by-step explanation:

3x+8x+y+x+8

The like terms are

3x, 8x, x

They are the terms that are in terms of the first power of x


Related Questions

56 x 10^-4)
Group of answer choices

2.37 x 10^-16

4.21 x 10^15

2.4 x 10^-16

4.2 x 10^15

Answers

9514 1404 393

Answer:

  (d)  4.2×10^15

Step-by-step explanation:

Your calculator will tell you the quotient is about ...

  4.21348...×10^15

The least precise number in the division is 1.5, which has 2 significant digits. Therefore, the result should be rounded to 2 significant digits:

  4.2×10^15

?
6.2
Divided by 1/2

Answers

Answer:

The answer is 3.1

[tex]6.2 \div \frac{1}{2} = 3.1[/tex]

If we were to convert it into a **FRACTION** the answer would be : 31/10.

And that i an improper fraction, but as a **MIXED NUMBER** : [tex]3 \frac{1}{10}[/tex]

All answers would be : 3.1 , 31/10 and 3 1/10

Answer:

0.5167

Step-by-step explanation:

6.2/12 first rewrite 6.2 as an improper fraction or 36/5 then multiply by 1/12 to get the solution of 0.5167.

An oblique cone has a radius of 5 units and a height of 9 units. What is the approximate volume of the oblique cone? Use π ≈ 3.14 and round to the nearest tenth. 117.8 cubic units 141.3 cubic units 235.5 cubic units 282.6 cubic units

Answers

Answer:

235.6 units^3

Step-by-step explanation:

The formula for the volume of the oblique cone is the same as for the volume of a right circular cone:  V = (1/3)(base area)(height).

Here that comes to        V = (1/3)(π)(5 units)^2*(9 units), or

V = 75π units^3, or approximately 235.6 units^3

Answer:

235.5 cubic units

Step-by-step explanation:


[tex] {4}^{3} [/tex]
evaluate this expression ​

Answers

Answer:

64

Step-by-step explanation:

Answer:

64

Step-by-step explanation:

4^3

= 4 * 4 * 4

= 16 * 4

= 64

An economist is interested in studying the spending habits of consumers in a particular region. The population standard deviation is known to be $1,000. A random sample of 50 individuals resulted in an average expense of $15,000. What is the width of the 99% confidence interval for the mean of expense? a. 364.28 b. 728.55 c. 329.00 d. 657.99

Answers

Answer:

The  width is  [tex]w = \$ 729.7[/tex]

Step-by-step explanation:

From the question we are told that

   The population standard deviation is  [tex]\sigma = \% 1,000[/tex]

    The  sample size is  [tex]n = 50[/tex]

    The sample mean  is  [tex]\= x = \$ 15,000[/tex]

Given that the confidence level is  99% then the level of significance is mathematically represented as  

               [tex]\alpha = 100 - 99[/tex]

=>            [tex]\alpha = 1\%[/tex]

=>             [tex]\alpha = 0.01[/tex]

Next we obtain the critical value of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table, the value is

             [tex]Z_{\frac{\alpha }{2} } = Z_{\frac{0.01 }{2} } = 2.58[/tex]

Generally margin of error is mathematically represented as

             [tex]E = Z_{\frac{\alpha }{2} * \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

              [tex]E = 2.58 * \frac{1000 }{\sqrt{50} }[/tex]

              [tex]E = 2.58 * \frac{1000 }{\sqrt{50} }[/tex]

               [tex]E = 364.9[/tex]

The width of the 99% confidence interval is mathematically evaluated as

         [tex]w = 2 * E[/tex]

substituting values

          [tex]w = 2 * 364.9[/tex]

          [tex]w = \$ 729.7[/tex]

The following 3 points are on a parabola defining the edge of a ski.
(-4, 1), (-2, 0.94), (0,1)

The general form for the equation of a parabola is:
Ax^2 + Bx + C= y

Required:
a. Use the x- and y-values of 1 of the points to build a linear equation with 3 variables: A, B, and C.
b. Record your equation here. Repeat this process with 1 of the other 2 points to build a 2nd linear equation.
c. Record your equation here. Repeat this process with the other point to build a 3rd equation.
d. Record your equation here. Build a matrix equation that represents this system of equations.
e. Record your matrix equation here. Use a graphing calculator or other graphing utility to find the inverse of the coefficient matrix.
f. Record your result here. Use the inverse matrix to solve the system of equations. Record the equation of the parabola here.

Answers

a. The linear equation for the first point (-4,1) is 16A-4B+C=1

b. The linear equation for the second point (-2, 0.94) is 4A-2B+C=0.94

c. The linear equation for the third point (0,1) is 0A+0B+C=1

d. The matrix equation looks like this:

[tex]\left[\begin{array}{ccc}16&-4&1\\4&-2&1\\0&0&1\end{array}\right]*\left[\begin{array}{c}A\\B\\C\end{array}\right]=\left[\begin{array}{c}1\\0.94\\1\end{array}\right][/tex]

e. The inverse of the coefficient matrix looks like this:

[tex]A^{-1}=\left[\begin{array}{ccc}\frac{1}{8}&-\frac{1}{4}&\frac{1}{8}\\\frac{1}{4}&-1&\frac{3}{4}\\0&0&1\end{array}\right][/tex]

f. The equation of the parabola is: [tex]\frac{3}{200}x^{2}+\frac{3}{50}x+1=y[/tex]

a. In order to build a linear equation from the given points, we need to substitute them into the general form of the equation.

Let's take the first point (-4,1). When substituting it into the general form of the quadratic equation we end up with:

[tex](-4)^{2}A+(-4)B+C=1[/tex]

which yields:

[tex]16A-4B+C=1[/tex]

b. Let's take the second point (-2,0.94). When substituting it into the general form of the quadratic equation we end up with:

[tex](-2)^{2}A+(-2)B+C=0.94[/tex]

which yields:

[tex]4A-2B+C=0.94[/tex]

c. Let's take the third point (0,1). When substituting it into the general form of the quadratic equation we end up with:

[tex](0)^{2}A+(0)B+C=1[/tex]

which yields:

[tex]0A+0B+C=1[/tex]

d. A matrix equation consists on three matrices. The first matrix contains the coefficients (this is the numbers on the left side of the linear equations). Make sure to write them in the right order, this is, the numbers next to the A's should go on the first column, the numbers next to the B's should go on the second column and the numbers next to the C's should go on the third column.

The equations are the following:

16A-4B+C=1

4A-2B+C=0.94

0A+0B+C=1

So the coefficient matrix looks like this:

[tex]\left[\begin{array}{ccc}16&-4&1\\4&-2&1\\0&0&1\end{array}\right][/tex]

Next we have the matrix that has the variables, in this case our variables are the letters A, B and C. So the matrix looks like this:

[tex]\left[\begin{array}{c}A\\B\\C\end{array}\right][/tex]

and finally the matrix with the answers to the equations, in this case 1, 0.94 and 1:

[tex]\left[\begin{array}{c}1\\0.94\\1\end{array}\right][/tex]

so if we put it all together we end up with the following matrix equation:

[tex]\left[\begin{array}{ccc}16&-4&1\\4&-2&1\\0&0&1\end{array}\right]*\left[\begin{array}{c}A\\B\\C\end{array}\right]=\left[\begin{array}{c}1\\0.94\\1\end{array}\right][/tex]

e. When inputing the coefficient matrix in our graphing calculator we end up with the following inverse matrix:

[tex]A^{-1}=\left[\begin{array}{ccc}\frac{1}{8}&-\frac{1}{4}&\frac{1}{8}\\\frac{1}{4}&-1&\frac{3}{4}\\0&0&1\end{array}\right][/tex]

Inputing matrices and calculating their inverses depends on the model of a calculator you are using. You can refer to the user's manual on how to do that.

f. Our matrix equation has the following general form:

AX=B

where:

A=Coefficient matrix

X=Variables matrix

B= Answers matrix

In order to solve this type of equations, we can make use of the inverse of the coefficient matrix to end up with an equation that looks like this:

[tex]X=A^{-1}B[/tex]

Be careful with the order in which you are doing the multiplication, if A and B change places, then the multiplication will not work and you will not get the answer you need. So when solving this equation we get:

[tex]\left[\begin{array}{c}A\\B\\C\end{array}\right]=\left[\begin{array}{ccc}\frac{1}{8}&-\frac{1}{4}&\frac{1}{8}\\\frac{1}{4}&-1&\frac{3}{4}\\0&0&1\end{array}\right]*\left[\begin{array}{c}1\\\frac{47}{50}\\1\end{array}\right][/tex]

(Notice that I changed 0.94 for the fraction 47/50 you can get this number by dividing 94/100 and simplifying the fraction)

So, in order to do the multiplication, we need to multiply each row of the coefficient matrix by the answer matrix and add the results. Like this:

[tex]\frac{1}{8}*1+(-\frac{1}{4})(\frac{47}{50})+\frac{1}{8}*1[/tex]

[tex]\frac{1}{8}-\frac{47}{200}+\frac{1}{8}=\frac{3}{200}[/tex]

So the first number for the answer matrix is [tex]\frac{3}{200}[/tex]

[tex]\frac{1}{4}*1+(-1)(\frac{47}{50})+\frac{3}{4}*1[/tex]

[tex]\frac{1}{4}-\frac{47}{50}+\frac{3}{4}=\frac{3}{50}[/tex]

So the second number for the answer matrix is [tex]\frac{3}{50}[/tex]

[tex]0*1+0(\frac{47}{50})+1*1[/tex]

[tex]0+0+1=1[/tex]

So the third number for the answer matrix is 1

In the end, the matrix equation has the following answer.

[tex]\left[\begin{array}{c}A\\B\\C\end{array}\right]=\left[\begin{array}{c}\frac{3}{200}\\\frac{3}{50}\\1\end{array}\right][/tex]

which means that:

[tex]A=\frac{3}{200}[/tex]

[tex]B=\frac{3}{50}[/tex]

and C=1

so, when substituting these answers in the general form of the equation of the parabola we get:

[tex]Ax^{2}+Bx+C=y[/tex]

[tex]\frac{3}{200}x^{2}+\frac{3}{50}x+1=y[/tex]

For further information, you can go to the following link:

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if f(x)=3x-3 and g(x)=-x2+4,then f(2)-g(-2)=

Answers

Answer:

3

Step-by-step explanation:

f(x)=3x-3

g(x)=-x^2+4,

f(2) = 3(2) -3 = 6-3 =3

g(-2) = -(-2)^2+4 = -4+4 = 0

f(2)-g(-2)= = 3-0 = 3

Ayudaaaaaaaa plorafacvor

Answers

4/24,7/5,5/3,3/5 espero hallude

A survey of undergraduates revealed the follwoing information: WOMEN MENsample mean weight 124.7 183.3sample standard deviation of weight 23.32 25.41sample proportion Roman Catholic 0.40 0.32Sample mean GPA 3.34 3.24Sample standard deviation of GPA 0.35 0.44Sample size 20 25Assume the populations are normally distributed. Suppose you want to determine whether the proportion of SCU women who are Roman Catholic is greater than the proportion of SCU men that are Roman Catholic.a. What are the null and alternative hypothesis to run this test?b. What is the calculated value of the test statistic?c. What is the p-value of the calculated test statistic?d. What is the conclusion of the hypothesis test, at 5% the significance level?

Answers

Answer:

the answers are below:

Step-by-step explanation:

a. null hypothesis:

H0: Pw - Pm = 0 (so Pw = Pm)

alternate hypothesis:

H1: Pw - Pm > 0 (so Pw > Pm)

where Pw is the proportion of women

Pm is the proportion of men

b.) proportion of women = o.40

proportion of men =  0.32

sample size of women = 20

sample size of men = 25

[tex]z = 0.4 - 0.32/ \sqrt{((0.4 *0.6)/20) * (0.32 * 0.68)/25)}[/tex]

[tex]z = 0.56[/tex]

c.) p value =

p(z>0.56)

= 0.7123

= 1 - 0.7123

= o.2877 which can be approximated to be 0.288

d. alpha value was set at 0.05

the p value is greater than alpha.

therefore it is not statistically significant.

we conclude that the proportion of roman catholic women is not greater than men.

C-Spec, Inc., is attempting to determine whether an existing machine is capable of milling an engine part that has a key specification of 4 ± .003 inches. After a trial run on this machine, C-Spec has determined that the machine has a sample mean of 4.001 inches with a standard deviation of .002 inch. Calculate the Cpk for this machine.

Answers

Answer:

0.3333

Step-by-step explanation:

Given the following :

Sample mean(m) = 4.001 inch

Standard deviation(sd) = 0.002 inch

Key specification : = 4 ± .003 inches

Upper specification LIMIT ( USL) : (4 + 0.003) = 4.003 inches

Lower specification limit (LSL) : (4 - 0.003) = 3.997 inches

Cpk is found using the relation:

min[(USL - mean) / (3 * sd), (mean-LSL) / (3*sd)]

min[(4.003 - 4.001)/(3*0.002), (4.001 - 3.997)/(3*0.002)]

min[(0.002 / 0.006), (0.004 / 0.006)]

min[(0.33333, 0.66667)

Therefore Cpk = 0.3333

Because 0.33333<0.66667

Topic: Linear functions and their inverses Carlos and Clarita have a pet sitting business. When they were trying to decide how many each of dogs and cats they could fit into their yard, they made a table based on the following information. Cat pens require 6 ft2 of space, while dog runs require 24 ft2 . Carlos and Clarita have up to 360 ft2 available in the storage shed for pens and runs, while still leaving enough room to move around the cages. They made a table of all of the combinations of cats and dogs they could use to fill the space. They quickly realized that they could fit in 4 cats in the same space as one dog. cats 0 4 8 12 16 20 24 28 32 36 40 44 48 52 56 60 dogs 15 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 8. Use the information in the table to write 5 ordered pairs that have cats as the input value and dogs as the output value. 9. Write an explicit equation that shows how many dogs they can accommodate based on how many cats they have. (The number of dogs "d" will be a function of the number of cats "c" or 10. Use the information in the table to write 5 ordered pairs that have dogs as the input value and cats as the output value. 11. Write an explicit equation that shows how many cats they can accommodate based on how many dogs they have. (The number of cats "c" will be a function of the number of dogs "d" or c = g(d).) Base your answers in #12 and #13 on the table at the top of the page. 12. Look back at problem 8 and problem 10. Describe how the ordered pairs are different.

Answers

Last sentences is the answer

Which statements about the dilation are true? Check all that apply. Triangle X prime Y prime Z prime. Point X prime is 2 units from the center of dilation C and point Z prime is 3 units from the center of dilation. Triangle X Y Z. Point X is 5 units from point C and point Z is 7.5 units from point C. The center of dilation is point C. It is a reduction. It is an enlargement. The scale factor is 2.5. The scale factor is Two-fifths.

Answers

Pls give brainliest.

Answer:

I only know two right answers.

A: The center of dilation is point C.

C: It is an enlargement.

E: The scale factor is 2/5.

Step-by-step explanation:

These two answers are correct because When you look in the center you see a C.

You tell if it is a reduction because the pre image is small but the image is big.

The center of dilation is point C.

It is an enlargement.

The scale factor is 2/5

The correct options are D, F, H.

What is dilation?

Resizing an item uses a transformation called dilation. Dilation is used to enlarge or shorten the structures. The result of this transformation is an image with the same shape as the original. However, there is a variation in the shape's size. The initial form should be stretched or contracted during a dilatation.

Given:

The transformation of the figure is dilation.

The figure is given in the attached image.

From the diagram:

The center of dilation is point C.

It is an enlargement.

The scale factor is 2/5

Therefore, all the correct statements are given above.

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A project has an initial cost of $40,000, expected net cash inflows of $10,000 per year for 8 years, and a cost of capital of 14%. What is the project's NPV? (Hint: Begin by constructing a time line.) Do not round intermediate calculations. Round your answer to the nearest cent.

Answers

Answer:

50k

Step-by-step explanation:

Find the final amount in each of these retirement accounts, in which the rate
of return on the account and the regular contribution change over time,
(a) $400 per month invested at 4%, compounded monthly, for 10 years, then
$600 per month invested at 6%, compounded monthly, for 10 years
(b) $1,000 per quarter invested at 4.42%, compounded quarterly, for 10 years,
then $1,500 per quarter invested at 7.4%, compounded quarterly, for 15
years

Answers

Answer:

Compound Interest: The future value (FV) of an investment of present value (PV) dollars earning interest at an annual rate of r compounded m times per year for a period of t years is:

FV = PV(1 + r/m)mt

or

FV = PV(1 + i)n

where i = r/m is the interest per compounding period and n = mt is the number of compounding periods.

One may solve for the present value PV to obtain:

PV = FV/(1 + r/m)mt

Numerical Example: For 4-year investment of $20,000 earning 8.5% per year, with interest re-invested each month, the future value is

FV = PV(1 + r/m)mt = 20,000(1 + 0.085/12)(12)(4) = $28,065.30

Notice that the interest earned is $28,065.30 - $20,000 = $8,065.30 -- considerably more than the corresponding simple interest.

Effective Interest Rate: If money is invested at an annual rate r, compounded m times per year, the effective interest rate is:

reff = (1 + r/m)m - 1.

This is the interest rate that would give the same yield if compounded only once per year. In this context r is also called the nominal rate, and is often denoted as rnom.

Numerical Example: A CD paying 9.8% compounded monthly has a nominal rate of rnom = 0.098, and an effective rate of:

r eff =(1 + rnom /m)m = (1 + 0.098/12)12 - 1 = 0.1025.

Thus, we get an effective interest rate of 10.25%, since the compounding makes the CD paying 9.8% compounded monthly really pay 10.25% interest over the course of the year.

Mortgage Payments Components: Let where P = principal, r = interest rate per period, n = number of periods, k = number of payments, R = monthly payment, and D = debt balance after K payments, then

R = P × r / [1 - (1 + r)-n]

and

D = P × (1 + r)k - R × [(1 + r)k - 1)/r]

Accelerating Mortgage Payments Components: Suppose one decides to pay more than the monthly payment, the question is how many months will it take until the mortgage is paid off? The answer is, the rounded-up, where:

n = log[x / (x – P × r)] / log (1 + r)

where Log is the logarithm in any base, say 10, or e.

Future Value (FV) of an Annuity Components: Ler where R = payment, r = rate of interest, and n = number of payments, then

FV = [ R(1 + r)n - 1 ] / r

Future Value for an Increasing Annuity: It is an increasing annuity is an investment that is earning interest, and into which regular payments of a fixed amount are made. Suppose one makes a payment of R at the end of each compounding period into an investment with a present value of PV, paying interest at an annual rate of r compounded m times per year, then the future value after t years will be

FV = PV(1 + i)n + [ R ( (1 + i)n - 1 ) ] / i

where i = r/m is the interest paid each period and n = m × t is the total number of periods.

Numerical Example: You deposit $100 per month into an account that now contains $5,000 and earns 5% interest per year compounded monthly. After 10 years, the amount of money in the account is:

FV = PV(1 + i)n + [ R(1 + i)n - 1 ] / i =

5,000(1+0.05/12)120 + [100(1+0.05/12)120 - 1 ] / (0.05/12)

What is the value of x to the nearest tenth?

Answers

Step-by-step explanation:

Hello!!!

Let's workout with this figure.

BC is a chord, O is the centre and OA is the perpendicular bisector.

AB = 1/2 of BC (according to circle's theorem)

so, A B = 1/2 × 25.6

Therefore, the measure of AB is 12.8.

now, let's have a small work with triangle AOB.

as it is a Right angled triangle, taking angle B as refrence angle we get,

p=x

b=12.8

h= OB = 16 (it is also a radius.)

now,

by Pythagoras relation we get,

[tex]p = \sqrt{ {h}^{2} - {b}^{2} } [/tex]

or, x = root 16^2- 12.8 ^2

by simplification, we get;

the measure of x is 9.6.

Therefore, the value of x is 9.6.

Hope it helps...

Joe drove 315 miles on 15 gallons of gas. What is his mileage in miles/gallon?
miles/gallon

Answers

Answer:

21 miles/gallon

Step-by-step explanation:

To find his mileage in miles/gallon, divide the number of miles by the number of gallons.

315/15

= 21

= 21 miles/gallon

Answer:

21 miles / gallon

Step-by-step explanation:

Take the miles and divide by the gallons

315 miles / 15 gallons

21 miles / gallon

In a simple regression analysis with age as the only explanatory variable, the effects of other factors, such as faminc, are

Answers

Answer:

In the error term.

Step-by-step explanation:

A simple linear regression is a regression that has only one explanatory variable. It tries to establish the existing relationship between the variable of interest (dependent variable) and the explanatory variable (independent variable).

Since age is the only explanatory variable, other variables such as faminc would be in the error term. The error term exists because the explanatory variable is never able to on its own to predict the dependent variable perfectly.

PLZ HELPPPPPP.
A store sells books for $12 each. In the proportional relationship between x, the number of books purchased, and y, the cost per books in dollars" to "y, the total cost of the books in dollars, the constant of proportionality is 12. Which equation shows the relationship between x and y?
A. y=12/x
B. y=12x
C. y=12+x
D. y=12−x

Answers

Answer:

B. y=12x

Step-by-step explanation:

x = # of books bought

so then y=12x

How many solutions does 2−9x=−6x+5−3x have?

Answers

Answer:

There are no values of  x  that make the equation true.

No solution

Step-by-step

hope it help

Hi

2-9x = -6x+5-3x

-9x+6x+3x = 5-2

  0x = 3

as  0 ≠ 3 , there is no answer possible to your equation.

Please answer fast! :)

Answers

Answer:

D

Step-by-step explanation:

The fastest way to solve this probelm would be to plug in each x value into these equations untill it outputs the correct two y values.

When you plug 3 into equation D the entire right side it will become.

y-1=0

y=1, which is true.

When you plug 6 into that equation.

y-1=5

y=6 which is also true.

im sorry but the thing is i cant translate these words but the answer is D

plz help me plz
(2.5a^ + 5.2b^) (6.2a^ + 2.6b^)​

Answers

Answer:

Sorry my HANDWRITING is not good . :(

5. During a national debate on changes to health care, a cable news service performs an opinion poll of 500 small business owners. It shows that 65% of small-business owners do not approve of health care changes. Develop a 95% confidence interval for the proportion opposing health care changes. Use 4 decimal places.

Answers

Answer:

The 95% confidence interval for the proportion opposing health care changes is (0.6082, 0.6918).

Step-by-step explanation:

The (1 - α)% confidence interval for the population proportion is:

[tex]CI=\hat p\pm z_{\alpha/2}\cdot\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

The information provided is:

[tex]\hat p=0.65\\n=500\\\text{Confidence level}=95\%[/tex]

The critical value of z for 95% confidence level is:

[tex]z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96[/tex]

*Use a z-table.

Compute the 95% confidence interval for the proportion opposing health care changes as follows:

[tex]CI=\hat p\pm z_{\alpha/2}\cdot\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

     [tex]=0.65\pm 1.96\sqrt{\frac{0.65(1-0.65)}{500}}\\\\=0.65\pm 0.04181\\\\=(0.60819, 0.69181)\\\\\approx (0.6082, 0.6918)[/tex]

Thus, the 95% confidence interval for the proportion opposing health care changes is (0.6082, 0.6918).

Evaluate the expression you got in part f for d = 5.

Answers

Answer:

2(8-d)

2(8-5)   (substituting d=5)

2(3)

=6

Step-by-step explanation:

The required expression is f = 6 for d =5 in the for the expression f = 2 (8 -d).

What is an algebraic expression?

An algebraic expression is consists of variables, numbers with various mathematical operations,

The expression,

f = 2 (8 - d)              (1)

To evaluate the expression for d = 5

Substitute the value of d = 5 in equation (1),

f = 2 (8 - 5)

f = 2 x 3

f = 6

The required expression is f=6.

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Example 2.20
Solution
After 7% discount, Faizal get RM1,930 from a bank. He then promised to pay the bank RM2,000
after x days. Determine the value of x.
Kaspersk
Th​

Answers

The period of days (value of x) for which Faizal promised to pay the bank RM 2,000 after getting 7% discounted present value of RM 1,930 is 180 days.

The value of x is the period of days (number of days) that the loan from the bank will last before Faizal, who received RM 1,930 discounted at 7%, would repay the bank the principal and interest of RM 2,000.

This implies that Faizal is paying an interest of RM 70 (RM 2,000 - RM 1,930), since he borrowed RM 1,930 and will repay RM 2,000.

Data and Calculations:

Present value of loan received = RM 1,930

Discount rate per year = 7%

Future value of the loan to be repaid to the bank = RM 2,000

Interest expense for one year based on 7% = RM 140 (RM 2,000 x 7%)

Interest expense for 180 days or 6 months = RM 70 (RM 2,000 - RM 1,930) or (RM 2,000 x 7%) x 180/360

Interest expense that equals RM 70 will be half of a year or 180 days (RM 140 * 180/360)

Thus, the period of days (x) that will lapse for Faizal to repay the bank is 180 days or half of a year (6 months).

Learn more about time period of a loan here: https://brainly.com/question/19118285

If “n” is a positive integer divisible by 3 and n is less than or equal to 44, then what is the highest possible value of n?

Answers

Answer:

Step-by-step explanation:

positive integer divisible by 3 includes

3,6,9,12,15,18,21,24,27,30,33,36,39,42,45...

less than highest possible value is 42

Question 1 of 10
Is (0,0) a solution to this system?
A. No. (0,0) does not satisfy either inequality.
B. No. (0,0) satisfies y< x2 + 2x + 1 but does not satisfy yz x2 + x - 4.
C. No. (0,0) satisfies ya x2 + x - 4 but does not satisfy y< x2 + 2x + 1.
O
D. Yes. (0,0) satisfies both inequalities.

Answers

Answer:

D

Step-by-step explanation:

0=> 0+0-4, 0=>-4 TRUE

0<0+0+1, 0<1 TRUE

Which expression represents the perimeter of the rectangle above? . 6x + 3. 10x + 6. 8x² + 6x. 12x + 6

Answers

There is no any image of rectangle

PLEASE HELP ASAP WILL GIVE BRAINLIEST

Answers

It would be D
Rational functions are fractions where numerator and denominator are polynomials.

Yo help me real quick?

Answers

Answer:

1,2 and 6

Step-by-step explanation:

pie symbol

2/3

0.333333....

An old campfire is uncovered during an archaeological dig. Its charcoal is found to contain less than 1/1000 the normal amount of ^{14}\text{C} ​14 ​​ C. Estimate the minimum age of the charcoal, noting that

Answers

An old campfire is uncovered during an archaeological dig. Its charcoal is found to contain less than 1/1000 the normal amount of [tex]^{14}\text{C}[/tex] ​. Estimate the minimum age of the charcoal, noting that  [tex]2^{10} = 1024[/tex]

Answer:

57300 years

Step-by-step explanation:

Using the relation of an half-life time in relation to fraction which can be  expressed as:

[tex]\dfrac{N}{N_o} = (\dfrac{1}{2})^{\frac{t}{t_{1/2}}[/tex]

here;

N represents the present atom

[tex]N_o[/tex] represents the  initial atom

t represents the time

[tex]t_{1/2}[/tex] represents the half - life

Given that:

Its charcoal is found to contain less than 1/1000 the normal amount of [tex]^{14}\text{C}[/tex] ​.

Then ;

[tex]\dfrac{N}{N_o} = \dfrac{1}{1000}[/tex]

However; we are to  estimate the minimum age of the charcoal, noting that  [tex]2^{10} = 1024[/tex]

so noting that [tex]2^{10} = 1024[/tex], then:

[tex]\dfrac{1}{1000}> \dfrac{1}{1024}[/tex]

[tex]\dfrac{1}{1000}> \dfrac{1}{2^{10}}[/tex]

[tex]\dfrac{1}{1000}> (\dfrac{1}{2})^{10}[/tex]

If

[tex]\dfrac{N}{N_o} = \dfrac{1}{1000}[/tex]

Then

[tex]\dfrac{N}{N_o} > (\dfrac{1}{2})^{10}[/tex]

Therefore, the estimate of the minimum time needed is 10 half-life time.

For [tex]^{14}\text{C}[/tex] , the normal half-life time = 5730 years

As such , the estimate of the minimum age of the charcoal =  5730 years × 10

= 57300 years

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