and is in group 38 Rock she can put them into groups of 10 rocks or as single rocks what are the different ways Ann can group the rocks?


and is grouping 38 rocks she can put them into groups of 10 rocks or has single rocks what are the different ways and can group The Rocks ​

Answers

Answer 1

Answer:

She can put the rocks into groups of 19.

That would give her 2 groups.

Step-by-step explanation:

Answer 2
She can put 19 rocks in a group

Related Questions

Identify the decimals labeled with the letters A, B, and C on the scale below. Letter A represents the decimal Letter B represents the decimal Letter C represents the decimal

Answers

[tex]10[/tex] divisions between $15.59$ and $15.6$ so each division is $\frac{15.60-15.59}{10}=0.001$

A is 5 division from $15.59$, so, A is $15.59+5\times 0.001=15.595$

similarly, C is 4 division behind $15.59$ so it is $15.590-4\times0.001=15.586$

and B is $15.601$

Emma rents a car from a company that rents cars by the hour. She has to pay an initial fee of $75, and then they charge her $9 per hour. Write an equation for the total cost if Emma rents the car for ℎ hours. If Emma has budgeted $250 for the rental cars, how many hours can she rent the car? Assume the car cannot be rented for part of an hour.

Answers

Y = 9h + 75. She can rent the car for 19 hours. The math for determining the amount of hours she can rent the car is 250 minus 75 is 175. 175 divided by 9 is 19.44. Assuming she can’t rent for part of an hour, it would be 19.

A circular water fountain in the town square has a 112-foot circumference. How far is the center of the fountain from the outer edge? Round to the nearest whole number.

Answers

Answer:

18 feet

Step-by-step explanation:

The distance of the center of the fountain from the enter edge is equal to the radius of the circular fountain.

Use the circumference formula, c = 2[tex]\pi[/tex]r, to find the radius.

c = 2[tex]\pi[/tex]r

112 = 2[tex]\pi[/tex]r

18 = r

So, to the nearest whole number, the distance between the center of the fountain and outer edge is 18 feet.

Solve the following equation using the square root property.
9x2 + 10 = 5

Answers

Answer: -5/81

Solving Steps:

9x^2+10=5
Simplify- 81x+10=5
Subtract 10 from both sides- 81x +10 -10= 5 -10
Simplify- 81x= -5
Divide both sides by 81- 81x/81= -5/81
Simplify- X= -5/81

Please help me to find out the answer

Answers

Answer:

8.204786801 in

Step-by-step explanation:

cos (79°) = BE/BG= adjacent/hypotenuse

cos ( 79°) = BE/43 in

BE = cos (79°) × 43 in= 8.204786801 in

Help ASAP Marly has to get some cavities filled at the dentist. The dentist charges a fee of $35 plus $43 per cavity. If Marly ends up having a bill of $164 and c represents the number of cavities, which of the following equations could be used to find how many cavities Marly had filled?
35 = 164 + 43c
164 = 35 - 43c
164 = 35c + 43
35 + 43c = 164

Answers

Answer:

the answer is d i believe.

Answer:

The answer is D I took the test the other person is right!

Step-by-step explanation:

A 100.0 m long polymer cable of uniform circular cross section and of diameter 0.4cm has a mass of 1885.0 gm. What is the mass density, of the polymer in kg/m3?

Answers

The answer is option b.15

Don't forget put heart ♥️

The mass density in kg/m3 will be -  15 x [tex]10^{-2}[/tex] Kg/m3.

We have a 100.0 m long polymer cable of uniform circular cross section and of diameter 0.4cm has a mass of 1885.0 gm.

We have to determine its mass density in kg/m3.

What is Mass density ?

The amount of mass per unit volume present in the body is called its mass density.

According to question, we have -

Length of polymer cable = 100.0 m

diameter of polymer cable = 0.4 cm = 0.004 m

Therefore, its radius = 0.002 m

The mass density of the wire will be -

[tex]\rho =\frac{m}{\pi r^{2} l}[/tex]

[tex]\rho[/tex] = [tex]\frac{1885}{3.14 \times0.002 \times 0.002 \times 100 }[/tex]

[tex]\rho = \frac{1885}{0.001256}[/tex] = 1500796.1 g/m3

1 Kg = 1000g

1g = 1/1000kg

1500796.1g = 1500.7 Kg = 15 x [tex]10^{-2}[/tex] Kg

Therefore, mass density = 15 x [tex]10^{-2}[/tex] Kg/m3

Hence, the mass density in kg/m3 will be -  15 x [tex]10^{-2}[/tex] Kg/m3.

To solve more questions on mass density, visit the link below -

https://brainly.com/question/4893600

#SPJ2

group the like term together​

Answers

Answer:

Step-by-step explanation:

[tex]xy^{2}[/tex],   [tex]5y^{2}x[/tex],   [tex]\frac{-3}{5}[/tex][tex]xy^{2}[/tex]

[tex]-3x^{2}y[/tex],   [tex]\frac{2}{3}[/tex][tex]yx^{2}[/tex]

Hope this helps

plz mark it as brainliest!!!!!

Which proportion would you use to solve the following problem?

A map has a scale of 1 cm : 5 km. Determine how far apart two cities are if they are 4 cm apart on the map.
A.
B.
C.
D.

Answers

Answer:

20 km

Step-by-step explanation:

We can use ratios to solve

1 cm          4 cm

--------  = ------------

5 km          x km

Using cross products

1 * x = 4 * 5

x = 20

20 km

Answer:

1/5 = 4/x

Step-by-step explanation:

Each cm on the map represents 5 km. If it shows 4 cm apart of the map, you can use the proportion 1 cm : 5 km = 4 cm : x km.

g The intersection of events A and B is the event that occurs when: a. either A or B occurs but not both b. neither A nor B occur c. both A and B occur d. All of these choices are true. a. b. c. d.

Answers

Answer:

c. both A and B

Step-by-step explanation:

Given that there are two events A and B.

To find:

Intersection of the two sets represents which of the following events:

a. either A or B occurs but not both

b. neither A nor B occur

c. both A and B occur

d. All of these choices are true. a. b. c. d

Solution:

First of all, let us learn about the concept of intersection.

Intersection of two events means the common part in the two events.

Explanation using set theory:

Let set P contains the outcomes of roll of a dice.

P = {1, 2, 3, 4, 5, 6}

And set Q contains the set of even numbers less than 10.

Q = {2, 4, 6, 8}

Common elements are {2, 4, 6}

So, intersection of P and Q:

[tex]P \cap Q[/tex] = {2, 4, 6}

Explanation using Venn diagram:

Please refer to the image attached in the answer area.

The shaded region is the intersection of the two sets P and Q.

When we apply the above concept in events, we can clearly say from the above explanation that the intersection of two events A and B is the event that occurs when both A and B occur.

So, correct answer is:

c. both A and B

Answer:

C.

Step-by-step explanation:

Please help on my hw

Answers

Answer:

x^2 - 7x - 30 = 0

Step-by-step explanation:

since solutions are 10 and -3

a factorised quad eqn can be formed:

(x-10)(x+3)=0

expand the eqn

x^2-7x-30 = 0 is the answer

Find the surface area of the figure round your answer to the nearest tenth if necessary

Answers

Answer:

.kpokojj8nvchrfhuthuvu9jeuvh

Step-by-step explanation:

j8tguhrhfgzhedh8ugh8euweuhujdhhruehf hhcufe7fhd fu y in my as 08ygrt8hthts8hewhrs8h8h8

Write and equation for each situation and solve. Your car gets 25 miles per gallon in the city if you travel 300 miles how many gallons of gas will you use?

Answers

if. 25 miles : 1 gallon

300 miles. : ?

if more less divides

300/25×1

=12 gallons of gas will be used

Help please, I don't understand :(

Answers

Answer:

38 = JKL

Step-by-step explanation:

JKM = JKL + LKN + NKM

Substituting what we know

104 = JKL + LKN +33

KN  bisects LKM so NKM =  LKN

33 =  LKN

104 = JKL + 33 +33

104 = JKL + 33 +33

Combine like terms

104 = JKL +66

104 - 66 = JKL

38 = JKL

Answer:  ∡JKL=38°

Step-by-step explanation:

KN bidects ∡LKM => ∠KLN=∡NKM=33°

=> ∡LKM=∠KLN+∡NKM=33°+33°=66°

=>∡JKL= ∡JKM-∡LKM= 104°-66°=38°

∡JKL=38°

49, 34, and 48 students are selected from the Sophomore, Junior, and Senior classes with 496, 348, and 481 students respectively. Group of answer choices

Answers

Answer:

Stratified Random sampling.

Step-by-step explanation:

As per the scenario, It is stratified random sampling as it divides students into strata which represent Sophomores, Juniors, and Seniors.

Simple random samples of the given sizes of the proportional to the size of the stratum which is to be taken from every stratum that is to be about 10 percent of students from every class that is selected here.

Hence, according to the given situation, the correct answer is a random stratified sampling.

IQ scores have a mean of 100 and a standard deviation of 15. What percentile corresponds to an IQ score of 115? Explain the steps you took to find the percentile.

Answers

Answer:

The percentile that corresponds to an IQ score of 115 is 34.13 %

Step-by-step explanation:

Here, we want to find the percentile that corresponds to an IQ score of 115.

To calculate this percentile, we start with making observations. From the question, we are told that the mean score is 100 while the standard deviation is 15.

Now we want to find the percentile for a score if 115. For a score of 115, we can see that the difference between this score and the mean is 15 which is exactly equal to the standard deviation.

What this means is that the score is within +1 SD of the mean.

For a score of within +1 SD of the mean, the percentile is 34.13%

A score at the mean is the 50th percentile, a score which is 1 SD above or below the mean has a percentile value of 34.13%

Please, I will like you to check the attachment to see how percentiles are valued given the number of standard deviations a particular value is from the mean.

A company has 8 mechanics and 6 electricians. If an employee is selected at random, what is the probability that they are an electrician

Answers

Answer:

[tex]Probability = \frac{3}{7}[/tex]

Step-by-step explanation:

Given

Electrician = 6

Mechanic = 8

Required

Determine the probability of selecting an electrician

First, we need the total number of employees;

[tex]Total = n(Electrician) + n(Mechanic)[/tex]

[tex]Total = 6 + 8[/tex]

[tex]Total = 14[/tex]

Next, is to determine the required probability using the following formula;

[tex]Probability = \frac{n(Electrician)}{Total}[/tex]

[tex]Probability = \frac{6}{14}[/tex]

Divide numerator and denominator by 2

[tex]Probability = \frac{3}{7}[/tex]

Hence, the probability of selecting an electrician is 3/7

Find the output, hhh, when the input, ttt, is 353535.
h = 50 - \dfrac{t}{5}h=50−
5
t

h, equals, 50, minus, start fraction, t, divided by, 5, end fraction
h=

Answers

9514 1404 393

Answer:

  43

Step-by-step explanation:

Put the value where t is and do the arithmetic.

  h = 50 -t/5

  h = 50 -35/5 = 50 -7 = 43

The output, h, is 43 when the input is 35.

Answer:

43

Step-by-step explanation:

The answer is 43 on Khan :)

2. Find the value of the expression 21 – 2a if a = 3.
O A. 15
O B. 57
O C. 27
O D. 16

Answers

Answer:

A

Step-by-step explanation:

we just substitute the value of "a" given in the above expression we get

21-2(3)

21-6=15

Answer:

a. 15

Explanation:

Step 1 - Input the value of 'a' in the expression.

21 - 2a

21 - 2(3)

Step 2 - Multiply two and three

21 - 2(3)

21 - 6

Step 3 - Subtract six from twenty one

21 - 6

15

Therefore, the value of the expression 21 - 2a if a = 3 is a. 15.

Find the P​-value in a test of the claim that the mean IQ score of acupuncturists is equal to​ 100, given that the test statistic is z2.00.

Answers

Answer:

P-value = 0.0455

Step-by-step explanation:

In this question, we are concerned with calculating the P- value in a test.

Mathematically we know that;

P-value = 2 * P(Z > |z|)

Please check attachment for complete solution and by step explanation

Four friends go to the movies. How many different ways can they sit in a row?

Answers

Answer:

120 ways

..................

Answer:

24

Step-by-step explanation:

4  friends

1st seat: 4 different people could sit here

Now there are 3 friends left

2nd seat: 3 different people could sit here

Now there are 2 friends left

3rd seat: 2 different people could sit here

Now there are 1 friends left

4th seat: 1 different people could sit here

4*3*2*1

24 ways

A test of abstract reasoning is given to a random sample of students before and after they completed a formal logic course. The results are given below. Construct a 95% confidence interval for the mean difference between the before and after scores. Is there evidence to suggest the logic course improves abstract reasoning? You may assume that the differences for the dependent samples are normally distributed . Before 74, 83, 75, 88, 84, 63, 93, 84, 91, 77 After 73, 77, 70, 77, 74, 67, 95, 83, 84, 75
Note : define d = before - after, then đ = 3.7 and s = 4.95
Please sketch the rejection region and show computation for the test statistic

Answers

Answer:

1. confidence interval = (0.163, 7.237)

1. confidence interval = (0.163, 7.237)2. t = 2.366

1. confidence interval = (0.163, 7.237)2. t = 2.3663. critical value of one tailed test = 1.833

Step-by-step explanation:

before after    dt(before - after)   d²

74         73          1                            1

83         77           6                          36

75         70          5                          25

88         77           11                         121

84         74           10                         100

63         67           -4                         16

93          95         -2                           4

84         83           1                            1

91           84          7                           49

77           75          2                          4

∑dt = 37    

d* = 37/10

since sample space = 10

d* = 3.7

s.d from the question = 4.95

df = 10 - 1 = 9

critical value at 0.05 significance

t(0.025 at df of 9) = ±2.262

marginal error computation:

= (2.262) × (4.945/√10)

= 2.262 × 1.5637

= 3.5370

confidence interval CI = d* + marginal error

= 3.7 ±3.5730

= (0.163, 7.237)

The logic course give an improvement on abstract reasoning. The confidence interval shows that the result is significant.

H₀: Цd = 0

H₁: Цd > 0

∝ = 0.05

t = (3.7 - 0)/(4.945/√10)

t = 3.7/1.564

t = 2.366

for a right tailed test at 0.05 significance, and df of 9, the critical value is 1.833

please refer to the attachment to see the rejection region.

A refrigerator magnet uses five eights of an inch of magnetic tape how many refrigerator magnets can you make with 10 inches of magnetic tape

Answers

ANSWER: You can make 16 refrigerator magnets.

If you divide 10 by 5/8, you multiply by the reciprocal of 5/8 which is 8/5. You have 8/5 x 10. Cross simplify and you have 16.

Given the two functions, which statement is true?
fx = 3^4, g(x) = 3^x + 5

Answers

Answer:

third option

Step-by-step explanation:

Given f(x) then f(x) + c represents a vertical translation of f(x)

• If c > 0 then shift up by c units

• If c < 0 then shift down by c units

Given

g(x) = [tex]3^{x}[/tex] + 5 ← this represents a shift up of 5 units

Thus g(x) is the graph of f(x) translated up by 5 units

Answer:

[tex]\boxed{\sf{Option \: 3}}[/tex]

Step-by-step explanation:

g(x) is translated up 5 units compared to f(x). In a vertical translation, when the graph is moved 5 units up, 5 is added to the function. When the graph is moved 5 units down, 5 is subtracted from the function. The graphs are shifted  in the direction of the y-axis.

A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 2 large boxes and 12 small boxes has a total weight of 223 kilograms. A delivery of 5 large boxes and 3 small boxes has a total weight of 139 kilograms. How much does each type of box weigh?

Answers

Answer:

A large box weighs 18.5 kilograms and a small box weighs 15.5 kilograms

Step-by-step explanation:

Create a system of equations where l is the weight of one large box and s is the weight of one small box.

2l + 12s = 223

5l + 3s = 139

Solve by elimination by multiplying the bottom equation by -4:

2l + 12s = 223

-20l - 12s = -556

Add these together and solve for l:

-18l = -333

l = 18.5

So, a large box weighs 18.5 kilograms. Plug in 18.5 as l into one of the equations, and solve for s:

5l + 3s = 139

5(18.5) + 3s = 139

92.5 + 3s = 139

3s = 46.5

s = 15.5

A large box weighs 18.5 kilograms and a small box weighs 15.5 kilograms.

9514 1404 393

Answer:

large: 18.5 kgsmall: 15.5 kg

Step-by-step explanation:

Two equations for the total weight can be written in general form as ...

  2L +12S -223 = 0

  5L +3S -139 = 0

These can be solved using the "cross multiplication method" by computing three differences:

  d1 = (2)(3) -(5)(12) = 6 -60 = -54

  d2 = (12)(-139) -(3)(-223) = -1668 +669 = -999

  d3 = (-223)(5) -(-139)(2) = -1115 +278 = -837

Then the weighs of the boxes are ...

  1/d1 = L/d2 = S/d3

  L = d2/d1 = -999/-54 = 18.5

  S = d3/d1 = -837/-54 = 15.5

The large box weighs 18.5 kg; the small box weighs 15.5 kg.

_____

Additional comment

If the coefficients are written in two rows of four numbers, with the first repeated at the end, the pattern of differences can be seen to be (ad -cb) for [a, b] in the first row and [c, d] in the second row of a pair of adjacent columns. This method of solution is fully equivalent to solution using Cramer's Rule for a system of equations represented by a matrix equation.

An apple orchard has an average yield of 32 bushels of apple per acre. For each unit increase in tree density, yield decreases by 2 bushels per tree. How many trees per acre should be planted to maximize yield

Answers

An apple orchard has an average yield of 32 bushels of apples per tree if tree density is 26 trees per acre. For each unit increase in tree density, the yield decreases by 2 bushels per tree. How many trees per acre should be planted to maximize the yield?

Answer:

Step-by-step explanation:

From the given information:

Let assume that  26+x trees per acre  are planted

then the  yield per acre will be (26+x)(32-2x)

However;

As x = 0 (i.e. planting 26 per acre), we have;

= (26+0) (32 - 2 (0))

= 26 × 32

= 832

As x = 1 (i.e planting 19 per acre), we have:

= (26+1) (32-2(1)

= 27 × 30

= 810

As x = 2 (i.e. planting 20 per acre), we have:

= (26 +2 ) ( 32 - 2(2)

= 28 × 28

= 784

The series continues in a downward direction for the yield per acre.

Thus,  for maximum plant 19 per acre, it can achieved by method of calculus given that the differentiation of the maximum point of x = 1

Finally, due to integer solution, it is not advisable to use calculus as such other methods should be applied.

Find the surface area of the figure. ft

Answers

Answer:

486

Step-by-step explanation:

Hello!

To find the surface area of a cube we use the equation

[tex]S = 6a^{2}[/tex]

S is the surface area

a is the side length

Put what we know into the equation

[tex]S = 6*9^{2}[/tex]

Solve

S = 6 * 81

S = 486

Hope this Helps!

Answer:486[tex]ft^{2}[/tex]

Step-by-step explanation:

surface area= 6[tex]l^{2}[/tex]

l=9

sa=6 ([tex]9^{2}[/tex])= 6 x 81=486[tex]ft^{2}[/tex]

If y varies directly with x and y = -11.7 when x = -3, find the value of y when x = 7.

Answers

Answer:

y = 27.3

Step-by-step explanation:

To find the value of y when x = 7 we must first find the relationship between them.

The statement

y varies directly with x is written as

y = kx

where k is the constant of proportionality

From the question

when y = - 11.7

x = - 3

We have

- 11.7 = -3k

Divide both sides by - 3

k = 3.9

So the formula for the variation is

y = 3.9k

When x = 7

y = 3.9(7)

y = 27.3

Hope this helps you

Answer: 27.3

Step-by-step explanation:

Joint Variation

You missed your payment due date and now have $300 on your card that has a 24% APR. You are able to pay $100 in one month and then every month after that. How many months will it take you to pay this credit card off?

Answers

It would take you 4 months to pay the credit card off.

Need help please! what is the total length of a 20 mm steel coiled like a spring with a 16 turns and an outer diameter of 600 mm. pitch is 300 mm. Show your solution please coz i don't really know how to do it! thanks

Answers

Answer:

L = 29,550 mm

Step-by-step explanation:

i think i've done this before.. but anyway Lets make it simple and easy.

Let A = 600mm

Let B = 300mm

Let C = 16 as number turns

Let d = 20mm

L = sqrt ((3.14 * (600 - 20))² + 300³)    * 16

L = 29,550 mm

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Prepare the journal entries to reflect expiration of the insurance and correctly report the balance of the Supplies account and the Supplies Expense account as of December 31, 2017.