Classify each substance based on the intermolecular forces present in that substance.
A. Hydrogen bonding, dipole dipole, and dispersion
B. Dipole dipole and dispersion only
C. Dispersion only
1. H2O
2. CH4
3. CO
4. CH2Cl

Answer:

38,050,000,000,000 picoliters.

Explanation:

10-5=5, 7.61 x 5=38.05 (38.05L)

every liter is equal to 1000000000000 picoliters, so you go from there and just multiply 1000000000000 by 38.05.

Answer:

A) It must be negative

Explanation:

A spontaneous reaction in Chemistry is that which is proceeding in a particular direction without the intervention of any external effect. As a spontaneous reaction proceeds (which can be relatively slow), free energy ΔG, which is the available energy for work, is released.

Gibbs free energy, ΔG, is released during a spontaneous process and hence the ΔG is negative because the reactants have more free energy than the products, hence, no energy input is needed for the reaction to proceed forward but rather an energy output. This is what makes a negative ΔG depict a spontaneous reaction.

Answer:

The daughter nuclides of these two decay processes are [tex]^{192}_{78}Pt [/tex] and [tex]^{192}_{76}Os[/tex].

Explanation:

The beta emission is represented by:

A = (Z + 1) + (n - 1) = is invariant

n: neutron

p: proton

[tex]^{A}_{Z}X \rightarrow ^{A}_{Z+1}Y[/tex]

Hence, the daughter nuclide of the beta emission of Ir-192 is:

[tex]^{192}_{77}Ir \rightarrow ^{192}_{78}Pt[/tex]      

Now, electron capture is represented by:

A = (Z - 1) + (n + 1) = is invariant

[tex]^{A}_{Z}X \rightarrow ^{A}_{Z-1}Y[/tex]

Then, the daughter nuclide of the electron capture of Ir-192 is:

[tex]^{192}_{77}Ir \rightarrow ^{192}_{76}Os[/tex]    

Therefore, the daughter nuclides of these two decay processes are [tex]^{192}_{78}Pt [/tex] and [tex]^{192}_{76}Os[/tex].

I hope it helps you!

Answer:

10.64

Explanation:

Let's consider the basic reaction of cyclohexamine, C₆H₁₁NH₂.

C₆H₁₁NH₂(aq) + H₂O(l) ⇄ C₆H₁₁NH₃⁺(aq) + OH⁻     pKb = 3.36

C₆H₁₁NH₃⁺ is its conjugate acid, since it donates H⁺ to form C₆H₁₁NH₂. C₆H₁₁NH₃⁺ acid reaction is as follows:

C₆H₁₁NH₃⁺(aq) + H₂O(l) ⇄ C₆H₁₁NH₂(aq) + H₃O⁺(aq)   pKa

We can find the pKa of C₆H₁₁NH₃⁺ using the following expression.

pKa + pKb = 14.00

pKa = 14.00 - pKb = 14.00 - 3.36 = 10.64

The pKa of conjugate acid of cyclohexamine has been 10.64.

The pKa has been acid dissociation constant, and has been describing the hydrogen ion concentration in the sample.

The pKb has been the base dissociation constant and has been describing the hydroxide ion concentration in the sample.

The sum of pKa and pKb has been found to be 14.

[tex]\rm pKa \;+\;pKb=14[/tex]

The pKb of cyclohexamine has been 3.36. The pKa of conjugate acid in the sample has been given by substituting the values as:

[tex]\rm pKa\;+\;3.36=14\\pKa=14\;-\;3.36\\pKa=10.64[/tex]

The pKa of conjugate acid of cyclohexamine has been 10.64.

For more information about pKa and pKb, refer to the link:

https://brainly.com/question/12639696

Answer:

C

Explanation:

When an apple is cut (or bruised), oxygen is introduced into the injured plant tissue. When oxygen is present in cells, polyphenol oxidase (PPO) enzymes in the chloroplasts rapidly oxidize phenolic compounds naturally present in the apple tissues to o-quinones, colorless precursors to brown-colored secondary products

Answer:

0.306 g/L

Explanation:

D = M/V

D= 3.45 g/11.24 L

D= 0.306 g/L

Answer:

[tex]24540\frac{mg}{m^3}[/tex]

Explanation:

Hello,

In this case, since the 3% by volume is represented as:

[tex]\frac{3L\ CO}{L\ gas}[/tex]

By using the ideal gas equation we compute the density of CO:

[tex]\rho =\frac{MP}{RT} =\frac{28g/mol*1atm}{0.082\frac{atm*L}{mol*K}*298K}= 0.818g/L[/tex]

Then we apply the conversion factors as follows:

[tex]=\frac{3L\ CO}{100L\ gas}*\frac{0.818g\ CO}{1L\ CO} *\frac{1000mg\ CO}{1g\ CO} *\frac{1000L\ gas}{1m^3\ gas} \\\\=24540\frac{mg}{m^3}[/tex]

Regards.

Answer:

No

Explanation:

A white dwarf has a higher surface temperature than a red giant.

Answer:

Explanation:

Lithium, Potassium and Sodium follow each other in that order when it comes to reactivity.

Succinctly put, Lithium is the most reactive. Potassium is more reactive and Sodium is the least reactive.

Also, for Calcium, Strontium and Barium. It is the least reactive in this order.

Strontium, Barium, Calcium

That is, Strontium is more reactive than Barium, which is more reactive than Calcium. Calcium is the least reactive of the 3

Answer:

[OH⁻] = 0.000324619M

pH = 10.51

[CN⁻] = 5.175x10⁻³M

Explanation:

Full question says:

Calculate the OH- concentration and pH of a 5.5×10-3M aqueous solution of sodium cyanide, NaCN. Finally, calculate the CN- concentration.

Ka (HCN) = 4.9×10-10

Sodium cyanide, is in equilibrium with water as follows:

NaCN(aq) + H₂O(l) ⇄ HCN(aq) + OH⁻(aq)

Where Kb (Kb = Kw / Ka = 1x10⁻¹⁴ / 4.9x10⁻¹⁰ = 2.04x10⁻⁵) is:

2.04x10⁻⁵ = [HCN] [OH⁻] / [NaCN]

In equilibrium, ann amount of HCN and OH⁻ is produced = X and the molarity of NaCN is: 5.5x10⁻³M - X

Replacing in Kb expression:

2.04x10⁻⁵ = [X] [X] / [5.5x10⁻³M - X]

1.12x10⁻⁷- 2.04x10⁻⁵X = X²

1.12x10⁻⁷- 2.04x10⁻⁵X - X² = 0

Solving for X:

X = -0.0003 → False solution. There is no negative concentrations

X = 0.000324619

As [OH⁻] = X.

pOH = -log [OH⁻]

pOH = 3.489

pH = 14 -pOH

And as molarity of NaCN = [CN⁻] = 5.5x10⁻³M - X

Answer:

read and green

Explanation:

By convention, the three primary colors in additive mixing are red, green, and blue. In the absence of light of any color, the result is black. If all three primary colors of light are mixed in equal proportions, the result is neutral (gray or white). When the red and green lights mix, the result is yellow.

Answer:

ground tumeric

Explanation:

Mix 1/4 cup water and 1/2 teaspoon of ground tumeric

Answer:

A. 2

B. 3

C. 4

Explanation:

Please see attached photo for explanation.

Answer:

Dew is liquid water droplets that form on grass, spider webs, and other things in the early morning or late evening. ... That means it turns from a liquid into a gas called "water vapor." When evening comes, the warm ground continues to radiate heat into

Answer:

1 mol of electron is exchanged. The mol of electrons that is released by the iron, is gained by the silver.

Explanation:

We need to determine the half reactions:

Ag⁺ → Ag

These is the reduction reaction, where Silver decreases the oxidation state. It gained 1 mol of e⁻

Fe²⁺ → Fe³⁺

In this case, iron increases the oxidation state, from +2 to +3. It has released 1 mol of electrons. This is the oxidation reaction.

The complete redox is:

Ag⁺ + 1e⁻ → Ag

Fe²⁺ → Fe³⁺ + 1e⁻

Ag⁺(aq) + 1e⁻ + Fe²⁺(aq) ⇌ Ag(s) + Fe³⁺(aq) + 1e⁻

The electrons will be cancelled.

In the redox reaction Ag⁺(aq) + Fe²⁺(aq) ⇌ Ag(s) + Fe³⁺(aq),

1 mole of electrons is exchanged.

Let's consider the following balanced redox reaction.

Ag⁺(aq) + Fe²⁺(aq) ⇌ Ag(s) + Fe³⁺(aq).

We can identify both half-reactions.

We can conclude that:

In the redox reaction Ag⁺(aq) + Fe²⁺(aq) ⇌ Ag(s) + Fe³⁺(aq),

1 mole of electrons is exchanged.

Learn more: https://brainly.com/question/2671074

Answer:

The correct answer is a. 0.223 grams, b. 3.36 × 10²¹ and c. 2.79 × 10⁻³ mol.

Explanation:

a. The volume of the solution given is 23.46 ml or 23.46 × 10⁻³ L, the molarity of NaOH is 0.238 M or 0.238 mol/L. Now the number of moles of NaOH will be,  

Number of moles = Molarity × Volume in Liters of solution

= 0.238 mol/L × 23.46 × 10⁻³ L  

= 5.5835 × 10⁻³ mol

Now the mass of NaOH will be,

= Moles × Molecular mass of NaOH

= 5.5835 × 10⁻³ mol × 39.997 g/mol  

= 223.322 × 10⁻³ grams

b) The number of moles in 23.46 ml is 5.5835 × 10⁻³ mol

Now the number of hydroxide ions found will be,  

= No. of moles × NA  

= 5.5835 × 10⁻³ × 6.022 × 10²³

= 3.36 × 10²¹

c) The balanced chemical equation is,

2NaOH + H₂SO₄ ⇒ Na₂SO₄ + 2H₂O

The number of moles of H₂SO₄ neutralized is,  

= Number of moles of NaOH taken/2

= 5.5835 × 10⁻³/2 mol

= 2.7917 × 10⁻³ mol

Answer:

The ozone layer is a shield district of Earth's stratosphere that ingests a large portion of the Sun's bright radiation. It contains a high grouping of ozone (). It contains atoms of oxygen that keep the environment from hurtful beams that are available in space and boundless by the sun, for instance, bright beams.  

Scientists from the Copernicus Atmosphere Monitoring Service confirm that the 2021 Antarctic ozone hole has almost reached its end, following a season with a considerably large and prolonged ozone hole. Its closure will occur only a few days earlier than in 2020, which was the longest-lived since 1979.

It closed on 23 December, the third latest date after 1999 and 2020. The extent and longevity of the 2021 ozone hole can be explained by very cold temperatures in the stratosphere and a very stable polar vortex. This video shows the evolution of the 2021 Antarctic ozone hole.

Learn more about The Ozone Hole at

https://brainly.com/question/18883493

#SPJ2

Answer:

6. (2.7*[tex]10^{5}[/tex])

8. (1.0*[tex]10^{4}[/tex])

Explanation:

Answer:

This question is incomplete. There is no highlight in red bolded text in the question but the answer to both the independent and dependent variables will be provided and explained in details.

Independent variable: decrease in temperature

Dependent variable: lifespan of battery

Explanation:

The independent variable of an experiment refers to the variable that is changed or manipulated by the experimenter in order to bring about an outcome. In this experiment, the DECREASE IN TEMPERATURE is the independent variable because it is what is being changed to effect a response in the battery lifespan.

On the contrary, the dependent variable is the variable that responds to the manipulation of the independent variable. In other words, the dependent variable is the outcome. In this experiment, the LIFESPAN OF THE BATTERY is the dependent variable because it is what is responding to the changes made by decreasing the temperature (independent variable)

Answer:

2.81 × 10⁶ mm³

2.81 × 10⁻³ m³

Explanation:

Step 1: Given data

Length (l): 250 mm

Width (w): 225 mm

Thickness (t): 50 mm

Step 2: Calculate the volume of the textbook

The book is a cuboid so we can find its volume (V) using the following expression.

V = l × w × t = 250 mm × 225 mm × 50 mm = 2.81 × 10⁶ mm³

Step 3: Convert the volume to cubic meters

We will use the relationship 1 m³ = 10⁹ mm³.

2.81 × 10⁶ mm³ × 1 m³ / 10⁹ mm³ = 2.81 × 10⁻³ m³

Answer: The molarity of solution is 0.453 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in ml

moles of [tex]C_2H_5OH[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{1.77g}{46g/mol}=0.0385mol[/tex]

Now put all the given values in the formula of molality, we get

[tex]Molarity=\frac{0.0385\times 1000}{85.0}[/tex]

[tex]Molarity=0.453[/tex]

Therefore, the molarity of solution is 0.453 M

Answer:

1.67 × 10⁻⁷ mol H₂O

3.14 × 10¹³ atoms deuterium

Explanation:

How many moles of water were injected?

We have 3.00 μg of gaseous H₂O. To calculate the number of moles of water we will use the following relationships:

[tex]3.00 \mu g \times \frac{1g}{10^{6}\mu g } \times \frac{1mol}{18.02g} = 1.67 \times 10^{-7} mol[/tex]

If the sample contains 0.0156% deuterium, how many deuterium atoms were injected?

We will use the following relationships:

1 mole of water contains 6.02 × 10²³ molecules of water.

There are 2 hydrogen atoms per water molecule.

0.0156% of hydrogen atoms are deuterium atoms.

[tex]1.67 \times 10^{-7} molH_2O \times \frac{6.02 \times 10^{23}moleculesH_2O }{1molH_2O} \times \frac{2atomsH}{1moleculeH_2O} \times 0.0156 \% = 3.14 \times 10^{13} atomsD[/tex]

Answer:

a) HCN and NaCN

Explanation:

Buffer solution is made by mixing either a weak base and its salt like ammonia and ammonium chloride or weak acid and its salt like HCN and its salt NaCN or acetic acid and sodium acetate .

In the given option , all of the rest of option has either strong acid or strong base or both  . In the last option both are salt so it can not form buffer solution .

It is capable of keeping the pH of the solution constant .

Answer:

d) 2, 4-Dimethylpentane

Explanation:

2, 4-Dimethylpentane is the c_7 compound that gives 3 signals in the broadband proton decoupled ¹³C spectrum.

This compound is classified as an alkane and it's chemical formula is [(CH3C)2CH]2CH2. It is a hydrocarbon that has no odor. When it is combined with other gas compounds it gives high octane fuel.

Answer:

Significant figures (also called significant digits) are an important part of scientific and mathematical calculations, and deals with the accuracy and precision of numbers. It is important to estimate uncertainty in the final result, and this is where significant figures become very important.

Explanation:

Answer:

Kindly check explanation

Explanation:

pm = picometer

Radius of platinum atom = 139 pm

1 pm = 1 × 10^-12 m

Hence,

139 pm = 139 × 10^-12 m

1 pm = 1 × 10^-10 cm

Hence,

139 pm = 139 × 10^-10 cm

B) mass of a single platinum atom = 3.24 × 10²² g

To obtain the diameter of 1 platinum atom in cm:

139 × 10^-10 cm

Number of atoms required :

48.1 cm / 1.39 × 10^-8 cm = 34.60 × 10^8 atoms

Mass in gram of P(t) :

(3.24 × 10²²) × (34.60 × 10^8) = 112.117 × 10^(22+8)

= 112.12 × 10^30 g

C) density (d) = 21.4 g/cm^3, diameter = 1.50 mm

V = πr^2h

h = 48.1cm ; r = 1.5 / 2 = 0.75 mm = 0.075cm

Density = mass / volume

Volume = π * 0.075^2 * 48.1 = 0.8499971cm³

Mass = density × volume

Mass = 21.4g/cm³ × 0.8499971cm³

= 18.19g

Answer:

Dual nature of matter is an important concept in JEE physics and is basically the study of different nature that a matter possesses or exhibits. ... Hence, the matter is said to possess dual nature, i.e., it has both the properties of a particle and as well as a wave.

Answer:

This states principle helps explain that an aircraft can achieve lift due to  the shape of its wings.

They wings are  shaped that way  so that that air flows faster over the top of the wing and slower underneath the wing .

In simple terms ;

Fast moving air equals low air pressure while slow moving air equals high air pressure

Explanation:

Answer:

pH = 12.35

Explanation:

The HCl reacts with NaOH, thus:

HCl + NaOH → NaCl + H₂O

1 mole of HCl reacts per mole of NaOH

To know the pH we must know the moles of NaOH and the moles of HCl that reacts

Moles NaOH and HCl

NaOH: 0.0280L * (0.230mol / L) = 6.44x10⁻³ moles

HCl: 0.0230L * (0.230mol / L) = 5.29x10⁻³

As moles NaOH > Moles HCl, the moles that remains of NaOH are:

Moles NaOH = 6.44x10⁻³ - 5.29x10⁻³ = 1.15x10⁻³ moles NaOH = Moles OH⁻

In 23.0mL + 28.0mL = 51.0mL = 0.0510L:

1.15x10⁻³ moles OH⁻ / 0.0510L =

0.0225M OH⁻

pOH = -log [OH⁻]

pOH = 1.647

And pH = 14 - pOH

Answer:

Be the anode

Explanation:

The standard hydrogen electrode is regarded as the standard reference electrode and it has been assigned an electrode potential of 0.0V.

If any substance has an electrode potential that is more negative than hydrogen, then that half cell will function as the anode when connected to the standard hydrogen electrode.

Similarly, any substance that has a more positive electrode potential than hydrogen will serve as the cathode when its half cell is connected to the standard hydrogen electrode.

Answer:

0.719M AgNO₃

Explanation:

Based on the reaction:

MgBr₂ + 2AgNO₃ ⇄ 2AgBr + Mg(NO₃)₂

1 mole of magnesium bromide reacts completely with 2 moles of AgNO₃

To find molarity of AgNO₃ solution we need to determine moles of AgNO₃ and, as molarity is the ratio of moles over liter (13.9mL = 0.0139L). Now, to determine moles of AgNO₃ we need to use the reaction, thus:

Moles AgNO₃:

Moles of MgBr₂ are:

50.0mL = 0.050L * (0.100mol / L) = 0.00500 moles of MgBr₂.

As the silver nitrate reacts completely and 2 moles of AgNO₃ reacts per mole of MgBr₂:

0.00500 moles MgBr₂ * (2 moles AgNO₃ / 1 mole MgBr₂) =

0.0100 moles of AgNO₃ are in the solution.

And molarity is:

0.0100 moles AgNO₃ / 0.0139L =