Y =-3x + b solve for b

Answer:

C

Step-by-step explanation:

6/9 simplified is 2/3

Hope this helps

Answer:

i think, x equal 12 and y equal 20

Answer:

See below

Step-by-step explanation:

The area (triangle) marked 'x' in the diagram below

Answer: Circumference equals = 27.004
              Area equals = 58.0586

We can write the area and circumferance of the given circle as 18.49π square units and 8.6π units.

Given is that a circle with a radius of 4.3.

We can write the area of the given circle as -

Area = πr²

Area = π x 4.3 x 4.3

Area = 18.49π square units

We can write the circumferance of the given circle as -

circumferance = 2πr

circumferance = 2 x π x 4.3  

circumferance  = 8.6π units

Therefore, we can write the area and circumferance of the given circle as 18.49π square units and 8.6π units.

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Yes these triangles are congruent.

What is congruent triangles?

Two triangles live aforesaid to be congruent if all 3 corresponding sides are equal and every one the 3 corresponding angles are equal in measure. These triangles may be slides, rotated, flipped and turned to be looked identical. If repositioned, they coincide with one another. The image of congruousness is’ ≅’.

Main body:

Firstly we need to find the co-ordinates of each point.

M = (-1,5)                               R= (1,1)

L = (-2,2)                               S= (-5,-1)

N= (5,3)                                Q= (2,-2)

to prove these triangles are congruent we need to show that the distance of their sides are equal.

distance formula= [tex]\sqrt{(x1-x2)^2+(y1- y2)^{2}[/tex]

Now in ΔLMN =

ML = [tex]\sqrt{(-1+2)^{2}+(5-2)^{2} }[/tex]

ML= [tex]\sqrt{10}[/tex] units

LN =[tex]\sqrt{(5+2)^{2}+(3-2)^{2} }[/tex]

LN= [tex]\sqrt{50}[/tex] units

MN =[tex]\sqrt{(5+1)^{2}+(3-5)^{2} }[/tex]

MN=[tex]\sqrt{40}[/tex] units

Now in ΔQRS=

RS= [tex]\sqrt{(1+5)^{2}+(1+1)^{2} }[/tex]

RS = [tex]\sqrt{40}[/tex] units

SQ = [tex]\sqrt{(2+5)^{2}+(1-2)^{2} }[/tex]

SQ = [tex]\sqrt{50}[/tex] units

RQ = [tex]\sqrt{(1-2)^{2}+(1+2)^{2} }[/tex]

RQ = [tex]\sqrt{10}[/tex] units.

We can clearly see on side of each triangle is equal to one side of another one.

Hence ΔLMN≅ΔQRS.

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y + 2 = 5/2 (x - 6) ; 5x-2y=34 ; y=5/2x-17 is the equations of the line that goes through the point (6,-2) and is perpendicular to the line y+2=-2/5(x-10), Hence the correct options are B, C and F.

The standard forms of the equation of a line are:

Slope-intercept form:

y = mx + c

Where m indicates the slope of the line and c is the y-intercept

Intercept form:

x/a + y/b = 1

General form of the equation of the straight line, i.e. Ax+By+C = 0

x/(-C/A) + y/(-C/B) = 1

where a = -C/A and b = – C/B

Normal form:

The equation of the line whose length of the normal from the origin is p and the angle made by the normal with the positive x-axis is given by α is given by:

x cos α+y sin α = p

Given,

Point = (6,-2) = (x2,y2)

Equation of line = y+2=-2/5(x-10)

General equation of the line = y - y1 = m ( x-x1 )

After comparing we get,

Slope of the given line = -2/5

As we know both the lines are perpendicular to each other so, product of their slopes must be equal to -1.

m1 × m2 = -1

-2/5 × m2 = -1

We get m2 = 5/2

So the equation of the line having slope  5/2 and passing through  (6,-2) is:

y - y2 = m2 ( x-x2 )

y -(-2) = 5/2 (x - 6)

y + 2 = 5/2 (x - 6)

Hence, we get equation of the line as y + 2 = 5/2 (x - 6) .

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The function is positive and increasing from 0 to 2.5, at negative and decreasing  from 0 to -2.5,  respectively.

How to find returns to scale?

Returns to scale involves an increase in an output more than when all the inputs increase proportionately.

Using the graph, there is a line segment from the origin to a point. at the middle of the third block making 2.5.  this shows an increase which is positive and on the other hand, there is a line segment from the origin towards left hand side on the number line showing a decrease and a negative from 0 to -2.5.

In conclusion, the line pointing upwards towards right hand side shows both positive and increase while the line pointing leftward shows decrease and negative.

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Using an inequality to represent the problem, Chang must run at least an additional 9 miles or greater than 9 miles

In Mathematics, the relationship between two values that are not equal is defined by inequalities. Inequality means not equal. Generally, if two values are not equal, we use “not equal symbol (≠)”. But to compare the values, whether it is less than or greater than, different inequalities are used.

To find the number of additional miles he will run, let's set the unknown number equals t

12 + t > 21

t > 21 - 12

t >9

Chang will need to run at least 9 miles

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The single fraction in its lowest terms will be;

⇒ - 7(2x - 1)/2

What is mean by Fraction?

A fraction is a part of whole number, and a way to split up a number into equal parts.

Or, A number which is expressed as a quotient is called fraction.

It can be written as the form of p : q, which is equivalent to p / q.

Given that;

The fraction is,

⇒ 3 (2x - 1)/5 - 2 (4x - 2)/2

Now,

Solve the fraction as;

The fraction is,

⇒ 3 (2x - 1)/5 - 2 (4x - 2)/2

⇒ 3 (2x - 1)/5 - (4x - 2)

⇒ 3 (2x - 1)/5 - 2 (2x - 1)

⇒ (2x - 1) (3/5 - 2)

⇒ (2x - 1) (3 - 10)/2

⇒ (2x - 1) (- 7/2)

⇒ - 7(2x - 1)/2

Thus, The single fraction in its lowest terms will be;

⇒ - 7(2x - 1)/2

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The number of 3 / 16 yards pieces that can be cut from 3 / 4 yard of ribbon is 4.

The actual length of the ribbon is 3 / 4 yards.

He wants to cut 3 / 16 yards pieces from the actual length of the ribbon.

Therefore, the number of 3 / 16 yard that can be cut from 3 / 4 yard of ribbon can be calculated as follows;

number of pieces of ribbon = 3 / 4 ÷ 3 / 16

number of pieces of ribbon = 3 / 4 × 16 / 3

number of pieces of ribbon =  48 / 12

Therefore,

number of pieces of ribbon =  4 yards

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Answer:

Step-by-step explanation:

4x(power of 5) divided by x(power of 2)

5y(po7) div by y(po2)

not 100% sure as i havent learnt this before lol

The relationship between the number of years that Simon's money is invested and the account balance can be described as 4:The relationship is linear. His account increases each year by a constant value of $28.

The simple interest due to Simon's account every year is:
= Simple interest rate x Amount invested

= 0.4% x 7, 000

= $28

This means that every year, Simon's account would increase by a value of $28.

This represents a linear relationship because in linear relationships, the value of the variables increases by a constant amount each year or period.

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Answer:

$336

Step-by-step explanation:

[tex]\frac{280}{35} \times 42 \\ \\ =\frac{56}{7} \times 42 \\ \\ =8 \times 42 \\ \\ =\$336[/tex]

The horizontal asymptote is y = [tex]\frac{9}{4}[/tex].

Let f(x) = [tex]\frac{9x^{3}-5x-9}{4x^{3}-9x+4}[/tex]

Line y = L is a horizontal asymptote of the function y=f(x), if either [tex]\lim_{x \to \infty} f(x) = L[/tex] or, [tex]\lim_{x \to -\infty} f(x) =L[/tex] and L is finite.

We will calculate limits :

[tex]\lim_{x \to \infty}(\frac{9x^{3}-5x-9}{4x^{3}-9x+4}) = \frac{9}{4}[/tex]

[tex]\lim_{x \to -\infty}(\frac{9x^{3}-5x-9}{4x^{3}-9x+4}) = \frac{9}{4}[/tex]

Hence, horizontal asymptote is y = [tex]\frac{9}{4}[/tex].

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Answer:

5x-9=26

Step-by-step explanation:

5x=35

5 5

x = 7

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Answer:

x = 7

Step-by-step explanation:

When five times a number is decreased by 9 ​, the result is 26 . What is the​ number?

5x - 9 = 26

add 9 to both sides:

5x - 9 + 9 = 26 + 9

5x =35

divide both sides by 5:

5x/5 =35/5

x = 7

1) The height of one of these cylinders if its radius is 2 inches is

115.207 inches.

2) The height of one of these cylinders if its radius is 3 inches is

51.203 inches.

3) The height of one of these cylinders if its radius is 6 inches is

12.800 inches.

1) when radius is 2 inches then:

πr²h = 1447

h = 1447/ (3.14 x 2²) = 115.207 inches

2)when radius is 3 inches then:

πr²h = 1447

h = 1447/ (3.14 x 9²) = 51.202 inches

3) when radius is 6 inches then:

πr²h = 1447

h = 1447/ (3.14 x {36}²) = 12.800 inches

1) The height of one of these cylinders if its radius is 2 inches is

115.207 inches.

2) The height of one of these cylinders if its radius is 3 inches is

51.203 inches.

3) The height of one of these cylinders if its radius is 6 inches is

12.800 inches.

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For the given right angled triangle, the base of the triangle is 10 units and perpendicular side is 9 units then its side length x is equal to 13.45 units (nearest hundredth).

As given in the question,

Given right angled triangle,

Base of the triangle is equal to 10 units

Perpendicular side of a triangle is equal to 9 units

Side length 'x' is the hypotenuse of the right angled triangle.

Using Pythagoras theorem we get,

(Hypotenuse)² = ( Base)² + ( Perpendicular side)²

⇒ x² = (10)² + (9)²

⇒ x² = 100 + 81

⇒ x² = 181

⇒ x = √181

⇒ x = 13.4536...

⇒ x = 13.45 units ( nearest hundredth)  

Therefore, for the given right angled triangle, the base of the triangle is 10 units and perpendicular side is 9 units then its side length x is equal to 13.45 units (nearest hundredth).

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Answer:

$34.20

Step-by-step explanation:

Since each pie is $12.50 but the assistant gets $1.10 for each pie, Johannes will get $11.40 for each pie sold.

We know that there were 3 pies sold so you must solve the equation below

11.40*3

The answer is $34.20

10.5 miles far upstream can Tom's boat go on the Little River in 1.5 hours.

The relative velocity formula is written as follows. V is equal to  

V → = V A B → + V B C →

Where. VAB is the velocity in relation to A and B, VBC is the velocity in relation to B and C, and VAC is the velocity in relation to A and C.

The current on the Little River is 8 mph.

Tom's boat goes 15 mph in still water.

For Upstream

the Velocity of the boat  = 15 mph - 8mph

                    = 7mph

How far upstream

can Tom's boat go on the Little River in 1.5 hours = 7* 1.5 = 10.5 miles

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According to the questions that are asked in the various Government exams that are held across the nation, the boat and stream concept is one of the most frequently covered subjects.

Boat speed in still water = 1/2 (downstream speed + upstream speed).

Boat's speed in still water equals 1/2 (13+7) = 1/2 × 20 = 10 km/hr.

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Answer:

The Y intercept of this line is -3.

Step-by-step explanation:

The X intercept of the crossing line is about -1.4.
On finding the Y intercept:
Step 1: look at the vertical black line (Y Axis)

Step 2: Locate where the blue line crosses on this line.
Step 3: graph Y function of the point as your answer.

Hope this helped a bunch!
Have a great day!
- Kit-Kat~

Answer:

c is ur answer

I hope it's help◉‿◉

Answer:

yes yes ...................

Answer:

P(x) = 0.7 [tex]x^{4}[/tex] - 4.9x³ + 5.6x² + 11.2x

Step-by-step explanation:

given a polynomial with roots x = a and x = b , then the factors are

(x - a) and (x - b)

If x = a is of multiplicity 2 then factor is (x - a)²

the polynomial is then the product of the factors

p(x) = a(x - a)(x - b) ← a is a multiplier

give x = 4 is a root with multiplicity 2 then (x - 4)² is the factor

x = 0 has factor (x - 0) , that is x

x = - 1 has factor (x - (- 1)) , that is (x + 1)

the polynomial is then the product of the factors

P(x) = ax(x + 1)(x - 4)² ← expand squared factor using FOIL

       = ax(x + 1)(x² - 8x + 16)

       = a(x² + x)(x² - 8x + 16) ← distribute

       = a([tex]x^{4}[/tex] - 8x³ + 16x² + x³ - 8x² + 16x)

      = a([tex]x^{4}[/tex] - 7x³ + 8x² + 16x)

to find a substitute (5, 21 ) into P(x)

21 = a([tex]5^{4}[/tex] - 7(5)³ + 8(5)² + 16(5))

21 = a(625 - 875 + 200 + 80)

21 = 30a ( divide both sides by 30 )

0.7 = a

then

P(x) = 0.7([tex]x^{4}[/tex] - 7x³ + 8x² + 16x) ← distribute parenthesis

P(x) = 0.7[tex]x^{4}[/tex] - 4.9x³ + 5.6x² + 11.2x

The 95% confidence interval for the distribution of the difference of proportions, using the z-distribution, is given as follows:

(0.11, 0.146).

The first step is finding the proportion and standard error for each sample, as follows:

For the distribution of differences, the mean and the standard error are given as follows:

The z-distribution is used as we are working with proportions, hence the bounds of the interval are given as follows:

p ± zs.

The critical value for a 95% confidence interval with the z-distribution is of z = 1.96.

Hence the lower bound of the interval is:

0.128 - 1.96 x 0.0092 = 0.11.

The upper bound of the interval is:

0.128 + 1.96 x 0.0092 = 0.146.

The information regarding each sample is given by the image at the end of the answer, and the problem asks for the 95% confidence interval for the differences.

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The area of the city block is 13.23 kilometers².

The city block is 3 times as long as it is wide. In this case, the width can be represented by w. The length will be 3w.

Therefore, perimeter will be:

= 2(length + width)

= 2(3w + w) = 16.8

8w = 16.8

Divide

w = 16.8 / 8

w = 2.1

Length = 3w = 3 × 2.1 = 6.3km

The area will be:

= Length × Width

= 6.3 × 2.1

= 13.23km²

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Answer:

The area of the city block is 13.23 kilometers².

Step-by-step explanation:

The solution to the given equation is 5.630.

What is a logarithmic equation?

An equation using the logarithm of an expression containing a variable is referred to as a logarithmic equation. Check to verify if you can write both sides of the equation as powers of the same number before attempting to solve an exponential equation.

Here, we have

2^(x+1) = 3^(2x-5)

Taking logarithms on both sides, we get

(x+1)log2 = (2x - 5)log3

xlog2 + log2 = 2xlog3 - 5log3

log2 + log3⁵ = 2xlog3 - xlog2

log 2* 243 = x(log6 - log2)

log486 = x(log6/2)

log486 = xlog3

x = log486/log3

x = 5.630

Hence, the solution to the given logarithmic equation is 5.630.

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The distance from Kano to Lagos is 1200 km

The problem involves addition of fractions

The fraction required are:

let the distance form kano to Lagos be x

it was discovered that a driver has travelled 3/8 = 3x/8

another driver had travelled 3/10 of that distance = 3x/10

The drivers are still 390 km apart

total distance, x

x = 390 + 3x/8 + 3x/10

x - 3x/8 - 3x/10 = 390

0.325x = 390

x = 390 / 0.325

x = 1200 km

From the driving distance information 1200 km is the distance from Kano to Lagos

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